I am developing an application in which, I can initialize a call from the application. Is it possible to come back to the same place in the application where I was before the call, after the call is terminated? If it is possible, then how? Thank you in advance.
I believe you can not do what you are trying to do. Because once the user attends the call and terminates the call, the application currently active would be Dialer and you can not in no way make you application active.
Implement the following methods from the UIApplicationDelegate protocol:
applicationWillResignActive is called when the phone receives an incoming call
applicationWillTerminate is called when the user answers the call
applicationDidBecomeActive is called if the user choose not to answer the call
applicationWillTerminate will give a few seconds to save your apps current state.
Use NSUserDefaults to save state . When the app starts again you read your state from NSUserDefaults and restore the app to its previous state.
If you want to come back to your application after a phone call, need to change
[UIApplication sharedApplication] openURL:telURL];
to
UIWebView PhoneCallWebView = [[UIWebView alloc] init];
[PhoneCallWebView loadRequest:[NSURLRequest requestWithURL:telURL]];
and it works.
I hope this will help you...and this will back after in application after call ended.
NSString *aPhoneNo = #"9876543210";
NSURL *url= [NSURL URLWithString:aPhoneNo];
NSString *osVersion = [[UIDevice currentDevice] systemVersion];
if ([osVersion floatValue] >= 3.1)
{
UIWebView *webview = [[UIWebView alloc] initWithFrame:[UIScreen mainScreen].applicationFrame];
[webview loadRequest:[NSURLRequest requestWithURL:url]];
webview.hidden = YES;
// Assume we are in a view controller and have access to self.view
[self.view addSubview:webview];
[webview release];
}
else
{
// On 3.0 and below, dial as usual
[[UIApplication sharedApplication] openURL: url];
}
Related
I am trying to learn Xcode by making a simple app.
But I been looking on the net for hours (days) and I cant figure it out how I make a button that open a UIWebView in another ViewController :S
first let me show you some code that I have ready:
I have a few Buttons om my main Storyboard that each are title some country codes like UK, CA and DK.
When I press one of those Buttons I have an IBAction like this:
- (IBAction)ButtonPressed:(UIButton *)sender {
// Google button pressed
NSURL* allURLS;
if([sender.titleLabel.text isEqualToString:#"DK"]) {
// Create URL obj
allURLS = [NSURL URLWithString:#"http://google.dk"];
}else if([sender.titleLabel.text isEqualToString:#"US"])
{
allURLS = [NSURL URLWithString:#"http://google.com"];
}else if([sender.titleLabel.text isEqualToString:#"CA"])
{
allURLS = [NSURL URLWithString:#"http://google.ca"];
}
NSURLRequest* req = [NSURLRequest requestWithURL:allURLS];
[myWebView loadRequest:req];
}
How do I make this open UIWebview on my other Viewcontroller named myWebView?
please help a lost man :D
Well, you've firstViewController already designed and coded, now you've to create secondViewController with a UIWebView binded in IB it self, also it have a setter NSString variable like strUrl that you need to pass at the time of pushing or presenting secondViewController, and assign it to UIWebView in viewDidLoad of secondViewController. See my answer about how to pass a NSString? Also UIWebView has its delegates method (What's delegate & datasource methods? - Apple Doc) Which you can use to handle URL request.
These are the delegate of UIWebView, if you'll going to use it, you need to give UIWebView delegate to self.
- (void)webViewDidStartLoad:(UIWebView *)webView;
- (void)webViewDidFinishLoad:(UIWebView *)webView;
- (void)webView:(UIWebView *)webView didFailLoadWithError:(NSError *)error;
firstViewController.m
- (IBAction)ButtonPressed:(UIButton *)sender {
NSURL* allURLS;
//get your URL
secondViewControlelr *secondView=[[secondViewControlelr alloc]init];
second.urlToLoad=allURLS;
[self.navigationController pushViewController:secondView animated:YES];
}
secondViewControlelr.h
//declare url and set property
NSURL *urlToLoad;
secondViewControlelr.m
- (void)viewDidLoad
{
myWebView=[[UIWebView alloc]initWithFrame:CGRectMake(0, 0, 320, 460)];
[self.view addSubview:myWebView];
NSURLRequest *urlReq=[NSURLRequest requestWithURL:self.urlToLoad cachePolicy:NSURLCacheStorageNotAllowed timeoutInterval:10];
[myWebView loadRequest:urlReq];
}
I'm trying to block the main thread until a UIWebView finishes loading, but calling [NSThread sleepForTimeInterval:] after calling [UIWebView loadRequest:] makes the loading never complete: The webViewDidFinishLoad delegate is called after the sleep finishes.
Why is this happening? and How can I block the main thread?
I'm calling loadPage from [ViewController willRotateToInterfaceOrientation:], what I'm trying to do is to prevent the iOS interface to rotate until the webview with the other orientation is loaded.
- (void)loadPage {
UIWebView* webview2 = [[UIWebView alloc] initWithFrame:rect];
webview2.delegate = self;
NSString* htmlPath = ..... ; // Path to local html file
NSURL *newURL = [[[NSURL alloc] initFileURLWithPath: htmlPath] autorelease];
NSURLRequest *newURLRequest = [[[NSURLRequest alloc] initWithURL: newURL] autorelease];
[webview2 loadRequest:newURLRequest];
[NSThread sleepForTimeInterval:10.0f]; // Why this blocks the uiwebview thread ??
[self.view addSubview:webview2];
}
- (void)webViewDidFinishLoad:(UIWebView *)webView {
NSLog(#"Finished loading!");
}
I think you're trying to solve the wrong problem.
You don't want to block the main thread. Firstly, the entire UI is drawn on the main thread, so it will appear as though your app has hung. Secondly, a UIWebView is part of the UI (which is probably why what you're doing doesn't work).
So, what to do?
Have a look at the following method:
- (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation
When you start loading your page you can return NO from this method. When it's finished loading you can return values normally. UIWebView has a delegate that tells you the status.
Have a look at the class reference for NSURLRequest, there is a sync method in there.
+ (NSData *)sendSynchronousRequest:(NSURLRequest *)request returningResponse:(NSURLResponse **)response error:(NSError **)error
I am making an application in which i want features like as when i run my app on device then it will closed immediately without showing any screen.But Application works in background. When user click on icon of application then it will not show any screen but work in background. After 2 minutes gap it will show a alert message. How do that?
I have used code for this given below:-
-(void)applicationDidFinishLaunching:(UIApplication *)application{
[application cancelAllLocalNotifications];
[self applicationWillTerminate:application];}-(void)applicationWillTerminate:(UIApplication *)application{
/*
Called when the application is about to terminate.
Save data if appropriate.
See also applicationDidEnterBackground:.
*/
UILocalNotification* ln = [[UILocalNotification alloc] init];
ln.fireDate =[NSDate dateWithTimeIntervalSinceNow:30];
ln.alertBody = [NSString stringWithFormat:#"Now app is working in Background."];
ln.soundName = UILocalNotificationDefaultSoundName;
[[UIApplication sharedApplication] scheduleLocalNotification:ln];
ln.hasAction=NO;
[ln release];
exit(0);}
But this is not working as i want. So what is bug in this code? How do that?
Thanks in advance...
You can't put your app away by manually calling [self applicationWillTerminate:application];. It's a delegate method that gets called when your application is about to be terminated, not a method to terminate the app.
You could try to schedule a local notification in didFinishLaunchingWithOptions: and call exit(0); afterwards. Some kind of splah screen (or black screen) will probably be shown for a moment.
- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
[application cancelAllLocalNotifications];
UILocalNotification* ln = [[UILocalNotification alloc] init];
ln.fireDate =[NSDate dateWithTimeIntervalSinceNow:30];
ln.alertBody = [NSString stringWithFormat:#"Now app is working in Background."];
ln.soundName = UILocalNotificationDefaultSoundName;
[[UIApplication sharedApplication] scheduleLocalNotification:ln];
ln.hasAction=NO;
[ln release];
exit(0); //this line kills the app (and gets your app rejected)
return NO; //this line is just to make compiler happy
}
Please note that this will most definetly not be approved for App Store.
According to Apple's documentation, in order to make phone call from my app, I need to implement the following protocols:
HTML link:
1-408-555-5555
Native application URL string:
tel:1-408-555-5555
However, upon completion of a phone call initiated from an HTML link inside a UIWebView, I am redirected right back to my application. But upon completion of a phone call made from a native application URL string, my iphone stays in the iphone's regular phone application, and if I want to return to my application I have to do so manually.
As far as I can tell from reading what others have said, there is no way to change this behavior.
Here is my question:
Is it true that it's impossible
to return to an application after
making a phone call from a native
application URL string?
Would there be any downside to
implementing a UIWebView instead of
a UILabel in situations where I
really wanted the user to be
redirected back to my application
after completing a phone call?
The simplest way seems to be:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:#"telprompt:0123456789"]];
You will get a prompt and your app will regain focus after the call is finished.
Behavior does differ between calling -[UIApplication openURL:] with a tel: URL, and clicking a link to the same URL in a UIWebView.
Using a UIWebView instead of a UILabel might have some downsides, but you don't have to actually display the UIWebView to get its tel URL handling behavior. Instead, just load a tel URL request in an instance of UIWebView without adding it to your view hierarchy.
For example:
#import <Foundation/Foundation.h>
#import <UIKit/UIKit.h>
#interface PhoneCaller : NSObject
{
#private
UIWebView *webview;
}
- (void)callTelURL:(NSURL *)url;
#end
#implementation
- (id)init
{
self = [super init];
if (self)
{
webview = [[UIWebView alloc] init];
}
return self;
}
- (void)callTelURL:(NSURL *)url
{
[webview loadRequest:[NSURLRequest requestWithURL:url]];
}
- (void)dealloc
{
[webview release];
[super dealloc];
}
#end
Allow me to simplify a bit. All you need is this little snippet:
UIWebView *callWebview = [[UIWebView alloc] init];
NSURL *telURL = [NSURL URLWithString:#"tel:number-to-call"];
[callWebview loadRequest:[NSURLRequest requestWithURL:telURL]];
which I got here.
*Recently tested successfully on iOS 5.0.
The Eric's Brotto method still works in 5.1. You have to add the webview to the main view before the loadRequest, like this:
NSString *cleanedString = [[phoneNumber componentsSeparatedByCharactersInSet:[[NSCharacterSet characterSetWithCharactersInString:#"0123456789-+()"] invertedSet]] componentsJoinedByString:#""];
NSString *escapedPhoneNumber = [cleanedString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *telURL = [NSURL URLWithString:[NSString stringWithFormat:#"tel://%#", escapedPhoneNumber]];
UIWebView *mCallWebview = [[UIWebView alloc] init] ;
[self.view addSubview:mCallWebview];
[mCallWebview loadRequest:[NSURLRequest requestWithURL:telURL]];
(I added a phone number cleaner, to delete any non-number char that blocks this method)
I have one view holding a list of videos(buttons which can be clicked, each hold a url) which currently bring up a new view which holds the UIWebview, the only problem is I cant pass the url to the webview depending on which button was clicked.
At the moment I just get an empty UIWebview.
How can the url string be passed to the webview so it can load the correct url for each button?
Regards
NSURL *videoURL = [NSURL URLWithString:#"http://..."];
[webView loadRequest:[NSURLRequest requestWithURL:videoURL]];
UPDATE:
In response to comment #3, here's what you can do:
This goes without saying, but keep a reference to the UIWebView instance in Browser
Add an NSString or NSURL #property to Browser
Pass the URL to the Browser instance right after init
In viewDidLoad:, call loadRequest:
So your code might look like this:
- (void)buttonClicked {
Browser *browser = [[Browser alloc] initWithNibName:nil bundle:nil];
browser.URL = [NSURL URLWithString:#"http..."];
[self presentModalViewController:browser animated:YES];
[browser release];
}
and in Browser's viewDidLoad:
- (void)viewDidLoad {
[super viewDidLoad];
[webView loadRequest:[NSURLRequest requestWithURL:URL]];
}