quartz cron trigger first fire time - quartz-scheduler

Question

Is there any way setting crontrigger to begin after a specific date .That is crontrigger going to fire after a specific date using its cron expression.I try using crontrigger starttime and firstfire time but not worked.I can do this with using another trigger but i think there should be another way.
this is cron expression
0 0/5 * * * ?
i.e. at minutes (5,10,15,...00) not at now+5
this is log program writes
Trigger should start at Fri May 27 21:03:31 EEST 2011 // i expect it run on this time
Job start at Fri May 27 20:55:00 EEST 2011 //it ignore start time
Job start at Fri May 27 21:00:00 EEST 2011
Job start at Fri May 27 21:05:00 EEST 2011
public CronTrigger scheduleJob(RemoteJob job, String cronExpression,Date firstFireTime) throws SchedulerException, ParseException {
JobDetail jobDetail = new JobDetail(job.getDescription(), job.getName(), job.getClass());
CronTrigger crTrigger = new CronTrigger(
"cronTrigger", job.getName(), cronExpression);
scheduler.scheduleJob(jobDetail, crTrigger);
try{
Calendar c=Calendar.getInstance();
c.add(Calendar.MINUTE, 10);
firstFireTime=c.getTime();
FileWriter writer=new FileWriter("/opt/scheduler.cron",true);
writer.write("Trigger should start at " +c.getTime().toString()+"\n\n");
writer.close();
}catch(Exception e){
}
crTrigger.setStartTime(firstFireTime);
crTrigger.setMisfireInstruction(CronTrigger.MISFIRE_INSTRUCTION_DO_NOTHING);
return crTrigger;
}
this is job executed by trigger .
public class ExternalJob extends RemoteJob {
private static final Logger _logger = Logger.getLogger(ExternalJob.class.getName());
private static ExternalStorageProcessor processor = new ExternalStorageProcessor();
private ExternalTask task;
private static final String tempPath = "/opt/itaptemp/";
private String name;
private String description;
private static final long MARK=1L;
public ExternalJob(String name, String description) {
public void execute(JobExecutionContext context) throws JobExecutionException {
try{
Calendar c=Calendar.getInstance();
FileWriter writer=new FileWriter("/opt/scheduler.cron",true);
writer.write("Job start at " +c.getTime().toString()+"\n");
writer.close();
}catch(Exception e){
}

Answer 1

The problem is that you are using a cron which fires a every even minute beginng a 0 minute (0 0/5 * * * ? ).
You should set the start date alse to even minutes. Therefore you can use DateBuilder.EvenMinuteDateBefore(StartTime).
So if your startime was... Fri May 27 20:55:31 ... the method DateBuilder.EvenMinuteDateBefore(StartTime) will convert it to ...
Fri May 27 20:55:00.
Then your schedule will look like:
Job start at Fri May 27 20:55:00 EEST 2011
Job start at Fri May 27 21:00:00 EEST 2011
Job start at Fri May 27 21:05:00 EEST 2011

Answer 2

Set the startTime property to the future Date at which you want the schedule (expression) to start applying.
I see you say that you tried that and it didn't work, but it certainly should, so please try again.
CronTrigger ct = new CronTrigger("foo", "goo", "0 0/10 * * * ?"); // fire every ten minutes, all day every day
// construct a date of March 17, 2012 10:03:00
Calendar futureDate = Calendar.getInstance();
futureDate.set(Calendar.YEAR, 2012);
futureDate.set(Calendar.MONTH, GregorianCalendar.MARCH);
futureDate.set(Calendar.DAY_OF_MONTH, 17);
futureDate.set(Calendar.HOUR_OF_DAY, 10);
futureDate.set(Calendar.MINUTE, 3);
futureDate.set(Calendar.SECOND, 0);
futureDate.set(Calendar.MILLISECOND, 0);
// use the date as the startTime
ct.setStartTime(futureDate.getTime());
// check what time the trigger will first fire
List fireTimes = TriggerUtils.computeFireTimes(ct, null, 1);
Date firstFireTime = (Date) fireTimes.iterator().next();
System.out.println("First fire time: " + firstFireTime);
This results in:
First fire time: Sat Mar 17 10:10:00 MDT 2012