I'm trying to convert nvarchar to decimal (18,2) and I'm receiving the following message:
Msg 8115, Level 16, State 6, Line 2
Arithmetic overflow error converting nvarchar to data type numeric.
The CAST is: CAST(bm_onnet AS decimal(18,2)) as bm_onnet_corr,
it works only if the value has only maximum 3 decimals, doesn't work for value below:
21.8333333333333333333333333333333333333
How should I modify my SELECT?
Use the round function
example
declare #v nvarchar(100) = '21.8333333333333333333333333333333333333'
select convert(decimal(18,2),round(#v,2))
a select would look like this
SELECT CAST(round(bm_onnet,2) AS decimal(18,2)) as bm_onnet_corr
select
case when charindex('.',bm_onnet)) > = 2 then
convert(decimal(18,2),substring(bm_onnet,0,charindex('.',bm_onnet)+3))
else
convert(decimal(18,2),bm_onnet)
end
too early in the morning use this instead.
Related
I have varchar data then i want to convert it to integer so i can using the number to order my data this is my varchar
No.SKF.4-04/2021/CBO-ODSP
No.SKF.5-04/2021/CBO-ODSP
No.SKF.6-04/2021/CBO-ODSP
`
i want to take the number so i can select order the data
SELECT varchar from account_information order by CAST(substring(left("NO_SURAT", "length"("NO_SURAT")-17),8)as integer)
but it show some error
SELECT CAST(substring(left("NO_SURAT", "length"("NO_SURAT")-17),8)as integer) from account_information
ERROR: invalid input syntax for type integer: ""
how do i covert substring result to int?
Avoiding an expensive regular expression, you could use:
SELECT CAST(
substr(
'No.SKF.5-04/2021/CBO-ODSP',
8,
position('-' IN 'No.SKF.5-04/2021/CBO-ODSP') - 8
) AS integer
);
substr
════════
5
(1 row)
I need to decode a base64 string and take a chunk of binary.
Is there a SQL function in Postgres to simply convert a bytea into a binary string representation?
(Like "00010001010101010".)
If your Postgres installation runs with the default setting bytea_output = 'hex', there is a very simple hack:
SELECT right(bytea_col::text, -1)::varbit;
Example:
SELECT right((bytea '\xDEADBEEF')::text, -1)::varbit;
Result:
'11011110101011011011111011101111'
right(text, -1) is just the cheapest way to remove the leading backslash from the text representation.
varbit (standard SQL name bit varying) is for bit strings of arbitrary length. Cast the result to text or varchar if you like.
Related, with explanation:
Convert hex in text representation to decimal number
demo:db<>fiddle
You could put the following code into a function:
WITH byte AS ( -- 1
SELECT E'\\xDEADBEEF'::bytea as value
)
SELECT
string_agg( -- 5
get_byte(value, gs)::bit(8)::text -- 4
, ''
)
FROM
byte,
generate_series( -- 3
0,
length(value) - 1 -- 2
) gs
I demonstrated the development of the query within the fiddle.
The WITH clause encapsulates the bytea value for double usage in further code
length() calculates the binary length of the bytea value
generate_series() creates a list from 0 to length - 1 (0 - 3 in my example)
get_byte() takes the bytea value a second time and gives out the byte at position gs (the previous calculated values 0-3). This gives an integer representation of the the byte. After that the cast to bit(8) type converts the result of this function to its binary representation (1 byte = 8 bit)
string_agg() finally aggregates all for binary strings into one. (taking its text representations instead of bit type, with no delimiters)
A function could look like this:
CREATE OR REPLACE FUNCTION to_bit(value bytea) RETURNS SETOF text AS
$$
BEGIN
RETURN QUERY
SELECT
string_agg(get_byte(value, gs)::bit(8)::text, '')
FROM
generate_series(0, length(value) - 1) gs;
END;
$$ LANGUAGE plpgsql;
After that you could call it:
SELECT to_bit(E'\\xDEADBEEF'::bytea)
You could try it using get_bit() instead of get_byte(). This safes you the ::bit(8) cast but of course you need to multiply the length with factor 8 indeed.
The resulting bit string has another bit order but maybe it fits your use case better:
WITH byte AS (
SELECT E'\\xDEADBEEF'::bytea as value
)
SELECT
string_agg(get_bit(value, gs)::text, '')
FROM
byte,
generate_series(0, length(value) * 8 - 1) gs
demo:db<>fiddle
I am attempting to run a simple UPDATE script on an integer field, whereby the trailing 2 numbers are "kept", and the leading numbers are removed. For example, "0440" would be updated as "40." I can get the desired data in a SELECT statement, such as
SELECT RIGHT(field_name::varchar, 2)
FROM table_name;
However, I run into an error when I try to use this same functionality in an UPDATE script, such as:
UPDATE schema_name.table_name
SET field_name = RIGHT(field_name::varchar, 2);
The error I receive reads:
column . . . is of type integer but expression is of type text . . .
HINT: You will need to rewrite or cast the expression
You're casting the integer to varchar but you're not casting the result back to integer.
UPDATE schema_name.table_name
SET field_name = RIGHT(field_name::TEXT, 2)::INTEGER;
The error is quite straight forward - right returns textual data, which you cannot assign to an integer column. You could, however, explicitly cast it back:
UPDATE schema_name.table_name
SET field_name = RIGHT(field_name::varchar, 2)::int;
1 is a digit (or a number - or a string), '123' is a number (or a string).
Your example 0440 does not make sense for an integer value, since leading (insignificant) 0 are not stored.
Strictly speaking data type integer is no good to store the "trailing 2 numbers" - meaning digits - since 00 and 0 both result in the same integer value 0. But I don't think that's what you meant.
For operating on the numeric value, don't use string functions (which requires casting back and forth. The modulo operator % does what you need, exactly: field_name%100. So:
UPDATE schema_name.table_name
SET field_name = field_name%100
WHERE field_name > 99; -- to avoid empty updates
I have a table with a varchar column, and I want to find values that match a certain number. So lets say that column contains the following entries (except with millions of rows in real life):
123456789012
2345678
3456
23 45
713?2
00123456789012
So I decide I want all the rows which are numerically 123456789012 write a statement that looks something like this:
SELECT * FROM MyTable WHERE CAST(MyColumn as bigint) = 123456789012
It should return the first and last row, but instead the whole query blows up because it can't convert the "23 45" and "713?2" to bigint.
Is there another way to do the conversion that will return NULL for values that can't convert?
SQL Server does NOT guarantee boolean operator short-circuit, see On SQL Server boolean operator short-circuit. So all solution using ISNUMERIC(...) AND CAST(...) are fundamentally flawed (they may work, but hey can arbitrarily fail later dependiong on the generated plan). A better solution is using CASE, as Thomas suggests: CASE ISNUMERIC(...) WHEN 1 THEN CAST(...) ELSE NULL END. But, as gbn pointed out, ISNUMERIC is notoriously finicky in identifying what 'numeric' means and many cases where one would expect it to return 0 it returns 1. So mixing the CASE with the LIKE:
CASE WHEN MyRow NOT LIKE '%[^0-9]%' THEN CAST(MyRow as bigint) ELSE NULL END
But the real problem is that if you have millions of rows and you have to search them like this, you'll always end up scanning end-to-end since the expression is not SARG-able (no matter how we rewrite it). The real issue here is data purity, and should be addressed at the appropriate level, where the data is populated. Another thing to consider is if is possible to create a persisted computed column with this expression and create a filtered index on it which eliminates NULL (ie. non-numeric). That would speed up things a little.
If you are using SQL Server 2012 you can use the 2 new methods:
TRY_CAST()
TRY_CONVERT()
Both methods are equivalent. They return a value cast to the specified data type if the cast succeeds; otherwise, returns null. The only difference is that CONVERT is SQL Server specific, CAST is ANSI. using CAST will make your code more portable (although not sure if any other database provider implements TRY_CAST)
ISNUMERIC will accept empty string and values like 1.23 or 5E-04 so could be unreliable.
And you don't know what order things will be evaluated in so it could still fail (SQL is declarative, not procedural, so the WHERE clause probably won't be evaluated left to right)
So:
you want to accept value that consist only of the characters 0-9
you need to materialise the "number" filter so it's applied before CAST
Something like:
SELECT
*
FROM
(
SELECT TOP 2000000000 *
FROM MyTable
WHERE MyColumn NOT LIKE '%[^0-9]%' --double negative rejects anything except 0-9
ORDER BY MyColumn
) foo
WHERE
CAST(MyColumn as bigint) = 123456789012 --applied after number check
Edit: quick example that fails.
CREATE TABLE #foo (bigintstring varchar(100))
INSERT #foo (bigintstring )VALUES ('1.23')
INSERT #foo (bigintstring )VALUES ('1 23')
INSERT #foo (bigintstring )VALUES ('123')
SELECT * FROM #foo
WHERE
ISNUMERIC(bigintstring) = 1
AND
CAST(bigintstring AS bigint) = 123
SELECT *
FROM MyTable
WHERE ISNUMERIC(MyRow) = 1
AND CAST(MyRow as float) = 123456789012
The ISNUMERIC() function should give you what you need.
SELECT * FROM MyTable
WHERE ISNUMERIC(MyRow) = 1
AND CAST(MyRow as bigint) = 123456789012
And to add a case statement like Thomas suggested:
SELECT * FROM MyTable
WHERE CASE(ISNUMERIC(MyRow)
WHEN 1 THEN CAST(MyRow as bigint)
ELSE NULL
END = 123456789012
http://msdn.microsoft.com/en-us/library/ms186272.aspx
SELECT *
FROM MyTable
WHERE (ISNUMERIC(MyColumn) = 1) AND (CAST(MyColumn as bigint) = 123456789012)
Additionally you can use a CASE statement in order to get null values.
SELECT
CASE
WHEN (ISNUMERIC(MyColumn) = 1) THEN CAST(MyColumn as bigint)
ELSE NULL
END AS 'MyColumnAsBigInt'
FROM tableName
If you require additional filtering, for numerics which are not valid to be cast to bigint, you can use the following instead of ISNUMERIC:
PATINDEX('%[^0-9]%',MyColumn)) = 0
If you need decimal values instead of integers, cast to float instead and change the regex to '%[^0-9.]%'
I've got a query that I've just found in the database that is failing causing a report to fall over. The basic gist of the query:
Select *
From table
Where IsNull(myField, '') <> ''
And IsNumeric(myField) = 1
And Convert(int, myField) Between #StartRange And #EndRange
Now, myField doesn't contain numeric data in all the rows [it is of nvarchar type]... but this query was obviously designed such that it only cares about rows where the data in this field is numeric.
The problem with this is that T-SQL (near as I understand) doesn't shortcircuit the Where clause thus causing it to ditch out on records where the data is not numeric with the exception:
Msg 245, Level 16, State 1, Line 1
Conversion failed when converting the nvarchar value '/A' to data type int.
Short of dumping all the rows where myField is numeric into a temporary table and then querying that for rows where the field is in the specified range, what can I do that is optimal?
My first parse purely to attempt to analyse the returned data and see what was going on was:
Select *
From (
Select *
From table
Where IsNull(myField, '') <> ''
And IsNumeric(myField) = 1
) t0
Where Convert(int, myField) Between #StartRange And #EndRange
But I get the same error I did for the first query which I'm not sure I understand as I'm not converting any data that shouldn't be numeric at this point. The subquery should only have returned rows where myField contains numeric data.
Maybe I need my morning tea, but does this make sense to anyone? Another set of eyes would help.
Thanks in advance
IsNumeric only tells you that the string can be converted to one of the numeric types in SQL Server. It may be able to convert it to money, or to a float, but may not be able to convert it to an int.
Change your
IsNumeric(myField) = 1
to be:
not myField like '%[^0-9]%' and LEN(myField) < 9
(that is, you want myField to contain only digits, and fit in an int)
Edit examples:
select ISNUMERIC('.'),ISNUMERIC('£'),ISNUMERIC('1d9')
result:
----------- ----------- -----------
1 1 1
(1 row(s) affected)
You'd have to force SQL to evaluate the expressions in a certain order.
Here is one solution
Select *
From ( TOP 2000000000
Select *
From table
Where IsNumeric(myField) = 1
And IsNull(myField, '') <> ''
ORDER BY Key
) t0
Where Convert(int, myField) Between #StartRange And #EndRange
and another
Select *
From table
Where
CASE
WHEN IsNumeric(myField) = 1 And IsNull(myField, '') <> ''
THEN Convert(int, myField) ELSE #StartRange-1
END Between #StartRange And #EndRange
The first technique is "intermediate materialisation": it forces a sort on a working table.
The 2nd relies on CASE ORDER evaluation is guaranteed
Neither is pretty or whizzy
SQL is declarative: you tell the optimiser what you want, not how to do it. The tricks above force things to be done in a certain order.
Not sure if this helps you, but I did read somewhere that incorrect conversion using CONVERT will always generate error in SQL. So I think it would be better to use CASE in where clause to avoid having CONVERT to run on all rows
Use a CASE statement.
declare #StartRange int
declare #EndRange int
set #StartRange = 1
set #EndRange = 3
select *
from TestData
WHERE Case WHEN ISNUMERIC(Value) = 0 THEN 0
WHEN Value IS NULL THEN 0
WHEN Value = '' THEN 0
WHEN CONVERT(int, Value) BETWEEN #StartRange AND #EndRange THEN 1
END = 1