I use modules layout to structure my controllers:
:module/:controller/:action
I would like to add a new custom route so that the following url will work.
domain.com/username
where username is a username of any registered user on the website.
Can anyone point me in the right direction?
Thank you
See this blog post for a detailed explanation of how to do this in ZF:
http://tfountain.co.uk/blog/2010/9/9/vanity-urls-zend-framework
Not sure if you can make something like domain.com/username. Instead you could do domain.com/u/username or domain.com/user/username. For example, to make the second route in you application.ini you could put something similar to the following:
resources.router.routes.user.route = "/user/:user"
resources.router.routes.user.type = "Zend_Controller_Router_Route"
resources.router.routes.user.defaults.module = default
resources.router.routes.user.defaults.controller = user
resources.router.routes.user.defaults.action = user
resources.router.routes.user.defaults.user =
resources.router.routes.user.reqs.user = "\s+"
http://framework.zend.com/manual/en/zend.controller.router.html covers quite well all the different ways you can add routes. Keep in mind, once you add custom routes, the default one will not work anymore unless you explicitly define it (as well as in url view helpers etc.).
Related
I've got a view (phase4) with some custom content type content in it, where the users may comment on.
When the users want to comment, the comment form should appear in a modal form. I solved this by using the admin overlay.
Adding following function to my custom module:
function phase2_admin_paths_alter(&$paths) {
$paths['comment/reply/*'] = TRUE;
}
and using following link:
Comment
to open the comment form in a modal way. So far so good... but....
How do I redirect the user back to the page, the user was coming from.
I know that I have to overwrite the #action of the form in the template_form_FORMID_alter, like
$form['#action'] = $lasturl;
but how do I get the last url, so that it is reusable (so hardcoding the url isn't an option)?
My first idea was that I transfer the last url by adding it to the url as a $_GET-parameter, but it looks like this:
www.example.com/phase4#overlay=comment/reply/161%3Furl%3Dphase4
I also tried it with drupal_get_destination(), but either with no success, because of the tranformation of the "?" and the "=" in the url.
Are there other ways to find out where the user was coming from?
Note: phase4 isn't the alias of node 161. Phase 4 is a view, where node 161 is an element of.
Cheers
Tom
You have to use the drupal_get_destination() function with l() function to create such links.
$destination = drupal_get_destination(); // Store current path
Comment
i have this parsed object
$xmlObj = new SimpleXMLElement($XMLToParse, LIBXML_DOTTED_VERSION, FALSE, "http://SOME/schema/universal_v17_0");
that has the stucture like this inside it
<universal:UniversalR LocatorCode="somecode" Version="2" Status="Active">
<common_v17_0:Book Key="some" TravelerType="some">
so i can access the first element(its attributes) like this $VariableX=$xmlObj->UniversalR->attributes();//then $VariableX["Status"];
but when i want access his child i cant $tm=$xmlObj->UniversalR->Book->attributes();
it doesnt want to enter probably because of the different namespace...can any one help me . THX
I found something here http://blog.sherifmansour.com/?p=302
foreach ($xmlObj->UniversalRecord as $entry){
$namespaces = $entry->getNameSpaces(true);
$cmm = $entry->->children($namespaces['common_v17_0']);
$aa=$cmm->Book->attributes();
echo $aa["TravelerType"]."ddddd";
}
That should do it :)
$tm=$xmlObj->UniversalRecord->Book->attributes(); is this typo (UniversalRecord instead of UniversalR) only present in this post or is it also present in your code?
(I'd have liked to post this as a comment.. but it looks like i'm not allowed to, or am too stupid to find the button. :/)
the thing is these this lines:
$loginUrl = $this->view->url(array('controller'=>'auth', 'action'=>'index'));
$registerUrl = $this->view->url(array('controller'=>'register', 'action'=>'index'));
based on rob allens' Zend_Auth login/logout tutorial (win7/apache),
are placed in a view helper, and this one:
echo $this->url(array('controller'=>'index','action'=>'add'));
is placed in the index view script.
The generated links Do work fine in LOCAL, but in REMOTE only the 3rd line works.
ANY IDEAS? Where should i look for this? wich way to follow?
I was tempt to think in the remote server conf but the 3rd line works fine, so..
thanks!
Try this helper instead of view Zend_Controller_Action_Helper_Url:
//simple($action, $controller = null, $module = null, array $params = null)
//so your lines will look like:
$loginUrl = $this->_helper->url->simple('index','auth');
$registerUrl = $this->_helper->url->simple('index','register');
P.S. your lines work properly on Win7 and Ubuntu servers check registry of the lines
I found out that was the server. (.htacces and mod_rewrite) was not included in the package.
I think the third line was working because it was in the index controller, but when calling the others, then happened the object not found.
To work out this, i found an example using zend debug (was in german) so i inferred it (and then wrote to the hosting service), but still not quite sure how to check (phpinfo?) if a host have this features available or not in your package.
Because of the problems I experienced here: Zend_ Controller_ Router_Exception: “xyz” is not specified
I want to have this route:
":module/:controller/:id"
and map it onto this:
":module/:controller/:action/id/$id"
Is there any possibility to do this with Zend Framework? I do not want to forward the browser to that URL. I just want to tell Zend Framework how to handle this route.
As for reasons why I would like to do this, you can find them in that linked SO question.
Yes it is possible. In my application.ini I specify my routes using regex this way:
resources.router.routes.something.type = "Zend_Controller_Router_Route_Regex"
resources.router.routes.something.route = "mymodule/mycontroller/([0-9]+)"
resources.router.routes.something.defaults.module = "mymodule"
resources.router.routes.something.defaults.controller = "mycontroller"
resources.router.routes.something.defaults.action = "myaction"
resources.router.routes.something.map.1 = "id"
I am not familiar with the ":variable" way of defining routes, but you can take from my example the ability to set default controllers, modules, and actions, without the need to explicitly define them in the url.
I am making a customer portal application using ZF. And the portal needs to work for different company brands. So I need to use all of the same backend code/controllers/etc, but dynamically change the view directory based off of the hostname.
Right now my view directory structure looks something like this:
/application/views/scripts/brand1/
/application/views/scripts/brand1/index/index.phtml
/application/views/scripts/brand1/error/error.phtml
/application/views/scripts/brand2/
/application/views/scripts/brand2/index/index.phtml
/application/views/scripts/brand2/error/error.phtml
/application/views/scripts/brand3/
/application/views/scripts/brand3/index/index.phtml
/application/views/scripts/brand3/error/error.phtml
and so on.
I am using the addScriptPath() function in bootstrap.php like so
protected function _initView()
{
$view = new Zend_View();
$view->doctype('XHTML1_STRICT');
$view->env = APPLICATION_ENV;
$view->addScriptPath(APPLICATION_PATH . '/views/scripts/brand1');
$view->addHelperPath(APPLICATION_PATH . '/views/helpers');
...
}
However when this is run, it is looking for all views using /views/scripts/brand1/(action).phtml instead of looking for views using the correct scheme /view/scripts/brand1/(controller)/(action).phtml
tl;dr is it possible to dynamically choose the view directory and have it work like the default /views/scripts/(controller)/(action).phtml behavior?
I knew I would find the answer after I posted here. In case anyone else encounters the same problem, the solution was using:
$view->setBasePath(APPLICATION_PATH . '/views/brand1');
And then modifying the directory structure to:
/application/views/brand1/scripts/...