I'm developing iPhone web based app - iphone

Question

So when I type something in the search bar of my app, it should send my latitude and longitude to the web server, so it can return me the nearest place where I can get the searched tag. I'm new to Titanium so can anyone help me?

Answer 1

You are basically sending a request via HTTP to your webservice and use the result (Take the function from #Muhammad Zeeshan to get longitude/latitude):
var xhr = Titanium.Network.createHTTPClient();
// write file on success
xhr.onload = function(){
var f = Titanium.Filesystem.getFile(Titanium.Filesystem.applicationDataDirectory,this.apiFile);
f.write(this.responseData);
};
// error handling
xhr.onerror = function(){
Ti.API.error(this.status + ' - ' + this.statusText);
};
// open the client (and test HTTPS)
xhr.open('GET','http://example.com/api/?longitude=' + longitude + '&latitude=' + latitude);
// send the data
xhr.send();
// read file and return json
var f = Titanium.Filesystem.getFile(Titanium.Filesystem.applicationDataDirectory, this.apiFile);
var contents = f.read();
var yourJson = JSON.parse(contents);
On the server Side you need some Webservice to talk to (you didn't specify a language you use on the server), but I presume you get the data via a MySQL database (others should be similar):
SELECT ((ACOS(SIN($lat * PI() / 180) * SIN(lat * PI() / 180) + COS($latitude * PI() / 180) * COS(lat * PI() / 180) * COS(($longitude – lon) * PI() / 180)) * 180 / PI()) * 60 * 1.1515) AS `distance` FROM `locations` HAVING `distance`<=’10′ ORDER BY `distance` ASC
Add additional WHERE clauses to filter by tag as well.

Answer 2

If you are using TiStudio instead of TiDeveloper you can use the sample project GPS to start with. It's bundled in the download so just fire it up and use that code as a working copy to learn from.