Imagine I have a file that has the following type of line:
FIXED_DATA1 VARIABLE_DATA FIXED_DATA2
I want to change the fixed data and leave the variable data as is. For various reasons, using two sed operations to replace the fixed data will not work. For instance, the fixed fields might be double-quotes, and the line has other areas containing them, thus really the regex is written to match a pattern in the variable data and the fixed data.
If I'm bent on using sed, is there a way to change both fixed data fields at once while leaving the variable field unchanged?
Thanks.
You need to partition the line into the three pieces, replace the outer two and leave the middle alone:
sed 's/^FIX1 \(.*\) FIX2$/New \1 End/'
You can make the beginning and end matches more complex as needed.
Related
I have an issue where extracting data from database it sometimes (quite often) adds spaces in between strings of texts that should not be there.
What I'm trying to do is create a small script that will look at these strings and remove the spaces.
The problem is that the spaces can be in any position in the string, and the string is a variable that changes.
Example:
"StaffID": "0000 25" <- The space in the number should not be there.
Is there a way to have the script look at this particular line, and if it finds spaces, to remove them.
Or:"DateOfBirth": "23-10-199 0" <-It would also need to look at these spaces and remove them.
The problem is that the same data also has lines such as:
"Address": " 91 Broad street" <- The spaces should be here obviously.
I've tried using TRIM, but that only removes spaces from start/end.
Worth mentioning that the data extracted is in json format and is then imported using API into the new system.
You should think about the logic of what you want to do, and whether or not it's programmatically possible to determine if you can teach your script where it is or is not appropriate to put spaces. As it is, this is one of the biggest problems facing AI research right now, so unfortunately you're probably going to have to do this by hand.
If it were me, I'd specify the kind of data format that I expect from each column, and try my best to attempt to parse those strings. For example, if you know that StaffID doesn't contain spaces, you can have a rule that just deletes them:
$staffid = $staffid.replace("\s+",'')
There are some more complicated things that you can do with forced formatting (.replace) that have already been covered in this answer, but again, that requires some expectation of exactly what data is going to come out of what column.
You might want to look more closely at where those spaces are coming from, rather than process the output like this. Is the retrieval script doing it? Maybe you can optimize the database that you're drawing from?
I'm working to build an import tool that utilizes a quoted CSV file. However, several of the fields in the CSV file are reported as such:
"=""38000"""
Where 38000 is the data I need. The data integration software I use (Talend 6.11) already strips the leading and trailing double quotes for me (so, "38000" becomes 38000), but I can't find a way to get rid of those others.
So, essentially, I need "=""38000""" to become "38000" where the leading "=" is removed and the trailing "" is removed.
Is there a TRIM function that can accomplish this for me? Perhaps there is a method in Talend that can do this?
As the other answer stated, you could do that operation in SQL. Or, you could do it in Java, Groovy, etc, within Talend. However, if there is an existing Talend component which does the job, my preference is to use it. That leads to faster development, potentially less testing, and easier maintenance. Having said that, it is important to review all the components which are available, so you know what's available to you.
You can use the Talend component tReplace, to inspect each of the input columns you want to trim of quotes and equal signs. A single tReplace component can do search and replace operations on multiple input columns. If all the of the replaces are related to each other, I would keep them within a single tReplace. When it gets to the point of doing unrelated replacements, I might place those within a new tReplace so that logical operations are organized and grouped together.
tReplace
For a given Input Column
search for "=", replace with ""
search for "\"", replace with ""
Something like that:
SELECT format( '"%s"', trim( both '"=' from '"=""38000"""' ) );
-[ RECORD 1 ]---
format | "38000"
1st: trim() function removes all " and = chars. Result is simply 38000
2nd: with format can add double quote back to get wishful end result
Alternatively, can use regexp and other Postgres string functions.
See more:
https://www.postgresql.org/docs/current/static/functions-string.html
I am using Scala to parse CSV files. Some of these files have fields which are non-textual data like images or octet-streams. I would like to use Apache Spark's textFile() method to split up the CSV into rows, and
split(",[ ]*(?=([^\"]*\"[^\"]*\")*[^\"]*$)")
to split the row into fields. Unfortunatly this does not work with files that have these mentioned binary fields. There are two problems: 1) The octet-streams can contain newlines which make textFile() split rows which should be one, and 2) The octet-streams contain commas and/or double quotes which are not escaped and mess up my schema.
The files are usually big, couple of MBs up to couple of 100MBs. I have to take the CSV's as they are, although I could preprocess them.
All I want to achieve is a working split function so I can ignore the field with the octet-stream. Nevertheless, a great bonus would be to extract the textual information in the octet-stream.
So how would I go forward to solve my problems?
Edit: A typical record obtained with cat, the newlines are from the file, not for cosmetic purposes (shortened):
7,url,user,02/24/2015 02:29:00 AM,03/22/2015 03:12:36 PM,octet-stream,27156,"MSCF^#^#^#^#�,^#^#^#^#^#^#D^#^#^#^#^#^#^#^C^A^A^#^C^#^D^#^#^#^#^#^T^#^#^#^#^#^P^#�,^#^#^X=^#^#^#^#^#^#^#^#^#^#�^#^#^#^E^#^A^#��^A^#^#^#^#^#^#^#WF6�!^#Info.txt^#=^B^#^#��^A^#^#^#WF7�^#^#List.xml^#^�^#^#��^A^#^#^#WF:�^#^#Filename.txt^#��>��
^#�CK�]�r��^Q��T�^O�^#�-�j�]��FI�Ky��Ei�Je^K""!�^Qx #�*^U^?�^_�;��ħ�^LI^#$(�^Q���b��\N����t�����+������ȷgvM�^L̽�LǴL�^L��^ER��w^Ui^M��^X�Kޓ�^QJȧ��^N~��&�x�bB��D]1�^B|^G���g^SyG�����:����^_P�^T�^_�����U�|B�gH=��%Z^NY���,^U�^VI{��^S�^U�!�^Lpw�T���+�a�z�l������b����w^K��or��pH� ��ܞ�l��z�^\i=�z�:^C�^S!_ESCW��ESC""��g^NY2��s�� u���X^?�^R^R+��b^]^Ro�r���^AR�h�^D��^X^M�^]ޫ���ܰ�^]���0^?��^]�92^GhCx�DN^?
mY<{��L^Zk�^\���M�^V^HE���-Ե�$f�f����^D�e�^R:�u����� ^E^A�Ȑ�^B�^E�sZ���Yo��8Eސ�}��&JY���^A9^P������^P����~Jʭy��`�^9«�""�U� �:�}3���6�Hߧ�v���A7^Xi^L^]�sA�^Q�7�5d�^Xo˛�tY
Bp��4�Y���7DkV_���\^_q~�w�|�a�s̆���#�g�ӳu�^�!W}�n��Rgż_2�]�p�2}��b�G9�M^Q
�����:�X����bR[ԳZV!^G����^U�tq�&�Y6b��GR���s#mn6Z=^ZH^]�b��R^G�C�0R��{r1��4�#�
=r/X2�^O�����r^M�Rȕ�goG^X-����}���P+˥Qf�#��^C�Բ�z1�I�j����6�^Np���ܯ^P�[�^Tzԏ���^F2�e��\�E�6c�%���$�:E�*�*©t�y�J�,�S�2U�S�^X}ME�]��]�i��G�su�""��!�-��!r'ܷe_et Y^K^?0���l^A��^^�m�1/q����|�_r�5$�%�([x��W^E�G^^y���#����Z2^?ڠ�^_��^AҶ�OO��^]�vq%:j�^?�jX��\�]����^S�^^n�^C��>.^CY^O-� �_�\K����:p�<7Sֺnj���-Yk�r���^Q^M�n�J^B��^Z0^?�(^C��^W³!�g�Z�~R�A^M�^O^^�%;��Ԗ�p^S�w���*m^S���jڒ|�����<�^S�;Z^^Fc�1���^O�G_o����8��CS���w��^?��n�2~��m���G;��rx4�(�]�'��^E���eƧ�x��.�w�9WO�^^�י3��0,�y��H�Y�.H�x�""'���h}灢^T�Gm;^XE�̼�J��c�^^;�^A�qZ1ׁBZ^Q�^A^FB�^QbQ�_�3|ƺ�EvZ���^S�w���^P���9^MT��ǩY[+�+�9�Ԩ�^O�^Q���Fy(+�9p�^^Mj�2��Y^?��ڞ��^Ķb�^Z�ψMр}�ڣ�^^S�^?��^U�^Wڻ����z�^#��uk��k^^�>^O�^W�ݤO�h�^G�����Kˇ�.�R|�)-��e^G�^]�/J����U�ϴ�a���i5HO�^L�ESCg�R'���.����d���+~�}��ڝ^Y5]l�3jg54M�������2t�5^Y}�q)��^O;�X\�q^Ox~Vۗ�t�^\f� >k;^G�K5��,��X�t/�ǧ^G""5��4^MiΟ�n��^B^]�|�����V��ߌ֗Q~�H���8��t��5��ܗ�
�Z�^c�6N�ESCG����^_��>��t^L^R�^:�x���^]v�{^#+KM��qԎ�.^S�%&��=^W-�=�^S�����^CI���&^]_�s�˞�y�z�Jc^W�kڠ�^\��^]j�����^O��;�oY^^�^V59;�c��^B��T�nb����^C��^N��s�x�<{�9-�F�T�^N�5�^Se-���^T�Y[���`^ZsL��v�բ<C�+�~�^ۚ��""�Yκ2^_�^VxT�>��/ݳ^U�m�^#���3^Ge�n^Vc�V�^#�NVn�,�q��^^^]gy�R�S��Ȃ$���>A�d����xg�^GB3�M�J�^QJ^]�^\�{.�D��碎�^W�8a����qޠl?,'^R�^X�Cgy�P[����mڞ��H�Z�s�SD&蠤�s�E��nu�O#O<��3wj`C-%w�W�J�^WP^T�^]r^NT�TC�Lq�Z�f�!�;�l�Y��Gb��>�ud�hx�Ԭ^N)9�^N!k�҉s�35v������.�""^]��~4������۴�Z^]u�^Ti^^�i:�)K��P᳕!�#�^?�>��EE^VE-u�^SgV^L��<��^D�O<�+�J.�c�Z#>�.l����^S�
ESC��(��E�j�π쬖���2{^U&b\��P^S�`^O^XdL�^ 6bu��FD��^#^#^#^#","field_x, data",field_y,field_z
Expected output would be an array
("7","url","user","02/24/2015 02:29:00 AM","03/22/2015 03:12:36 PM","octet-stream","27156","field_x, data",field_y",field_z")
Or, but this is probably another question, such an array (like running strings on the octet-stream field):
("7","url","user","02/24/2015 02:29:00 AM","03/22/2015 03:12:36 PM","octet-stream","27156","Info.txt List.xml Filename.txt","field_x, data",field_y",field_z")
Edit 2: Every file that has a binary field also contains a length field for it. So instead of splitting directly I can walk left to right through my record and extract the fields. This is certainly a great improvement of my current situation but problem 1) still persists. How can I split those files reliably?
I took a closer look at the files and a header looks like this:
RecordId, Field_A, Content_Type, Content_Length, Content, Field_B
(Where Content_Type can be "octet-stream", Content_Length the number of bytes in the Content field, and Content obviously the data). And good for me, the value of Field_B is predictable, let's assume for a certain file it's always "Hello World".
So instead of using Spark's default behaviour splitting on newlines, how can I achieve that Spark is only splitting on newlines following "Hello World"? (I also edited the question title since the focus of the question changed)
As answered in Spark: Reading files using different delimiter than new line, I used textinputformat.record.delimiter to split on "Hello World\n" because I am a bit lucky that the last column always contains the same value. After that I simply walk left to right through the record and when I reach the length field I skip the next n bytes. Everything works now. Thanks for pointing me in the right direction.
There are two problems: 1) The octet-streams can contain newlines
which make textFile() split rows which should be one, and 2) The
octet-streams contain commas and/or double quotes which are not
escaped and mess up my schema.
Well, actually that csv file is properly escaped:
the multiline field is enclosed in double quotes: "MSCF^# .. ^#^#" (which also handles possible separators inside the field)
double quotes inside the field are escaped with another double quote as it should be: Je^K""!
Of course a simple split will not work in this case (and should never be used on csv data), but any csv reader able to handle multiline fields should parse that data correctly.
Also keep in mind that the double quotes inside the octet-stream have to be unescaped, or that data won't be valid (another reason not to use split, but a csv reader that handles this).
I want to search a file for a specific string and then place a comment at the beginning of that string. But I need an answer that avoids regex, global changes, and all the other fancy stuff.
I wrote this line:
sed -i.bak '/PermitRootLogin no/# PermitRootLogin no/' ./sshd_config
but I get an error:
sed: -e expression #1, char 21: comments don't accept any addresses
I assume the issue is that I need to escape the # character, but I'm not finding any resources on how to do that, or even mentioning it. I've tried various combinations of putting ^ or \ or \^ in front of the # but I'm jut not getting it right.
Please note I am intentionally repeating the text to be replaced. I would like the most simple possible solution to this question: how to replace "XYX" with "# XYZ" in the most obvious possible way.
As indicated in the comments by #mlt , you could try adding an s at the beginning your sed command. Straight from his comment:
s/PermitRootLogin....
I see that you said you're intentionally repeating the test to be replaced. If by that you mean, you want it to be the same, maybe consider grouping your matched text. I understand you may have meant that you just want it hand typed. Anyway, here is how to match the grouped text and add the comment character:
s/(PermitRootLogin)/# \1/
The parens indicated that the matched text should be consider a group, the \1 indicates that you want to put that matched group there.
I hope this was helpful. Happy coding! Leave a comment if you have any questions.
I'm using regular expression lib icucore via RegKit on the iPhone to
replace a pattern in a large string.
The Pattern i'm looking for looks some thing like this
| hello world (P1)|
I'm matching this pattern with the following regular expression
\|((\w*|.| )+)\((\w\d+)\)\|
This transforms the input string into 3 groups when a match is found, of which group 1(string) and group 3(string in parentheses) are of interest to me.
I'm converting these formated strings into html links so the above would be transformed into
Hello world
My problem is the trailing space in the third group. Which when the link is highlighted and underlined, results with the line extending beyond the printed characters.
While i know i could extract all the matches and process them manually, using the search and replace feature of the icu lib is a much cleaner solution, and i would rather not do that as a result.
Many thanks as always
Would the following work as an alternate regular expression?
\|((\w*|.| )+)\s+\((\w\d+)\)\| Where inserting the extra \s+ pulls the space outside the 1st grouping.
Though, given your example & regex, I'm not sure why you don't just do:
\|(.+)\s+\((\w\d+)\)\|
Which will have the same effect. However, both your original regex and my simpler one would both fail, however on:
| hello world (P1)| and on the same line | howdy world (P1)|
where it would roll it up into 1 match.
\|\s*([\w ,.-]+)\s+\((\w\d+)\)\|
will put the trailing space(s) outside the capturing group. This will of course only work if there always is a space. Can you guarantee that?
If not, use
\|\s*([\w ,.-]+(?<!\s))\s*\((\w\d+)\)\|
This uses a lookbehind assertion to make sure the capturing group ends in a non-space character.