TYPO3 TMENU each special.value wrap - typo3

Question

I dont come forth. I want to wrap each given PID in its own unique wrap.
Here my code:
menutab.list = HMENU
menutab.list.special = directory
menutab.list.special.value = 7,8,9,10,11,12,13
menutab.list.1 = TMENU
menutab.list.1.wrap = <div>|</div>
...
So thats working fine. I get every submenu of given PIDs but now i'm searching for something like that:
menutab.list.special.value.wrap = <div id="current PID!"> | </div>
I hope someone understand my issue.
Big thanks!!

Answer 1

It depends which field you would like to display, but basically any field from the page record can be displayed into the output.
menutab.list = HMENU
menutab.list {
special = directory
special.value = 7,8,9,10,11,12,13
1 = TMENU
1 {
# stdWrap2 wraps the whole item, including the link
NO.stdWrap2.dataWrap = <div id="p{field:uid}">|</div>
}
}
This will give the following output:
<div id="p26">Test 0</div>
<div id="p27">Test 1</div>
<div id="p30">Test 2</div>
<div id="p31">Test 3</div>
<div id="p35">Test 4</div>
<div id="p36">Test 5</div>
<div id="p37">Test 6</div>
For more options, please take a look at the TSref and the stdWrap functions.
TSref
http://typo3.org/documentation/document-library/references/doc_core_tsref/4.4.0/view/toc/0/
stdWrap
http://typo3.org/documentation/document-library/references/doc_core_tsref/4.4.0/view/1/5/#id2618234

Answer 2

I think the easiest is to do something like that, not sure of the syntax... :
menutab.list.1 = HMENU
menutab.list.1 {
special = directory
special.value = 7
1 = TMENU
1.wrap = <div id="7"> | </div>
}
menutab.list.2 < menutab.list.1
menutab.list.2.special.value = 8
menutab.list.2.1.wrap = <div id="8"> | </div>
...
Not the best solution, but can work