Can't connect UIButton to Method on iPhone - iphone

Ok, so this has been driving me mad for a while, but it occasionally self corrects so I've dealt with it, but it's time to fix it!
Situation is as follows:
View created in Interface Builder for iOS. Contains a UIButton referenced as 'banana015'
Method in my implementation .m as follows:
- (IBAction)draggedOut: (id)sender withEvent: (UIEvent *) event {
if ([[NSUserDefaults standardUserDefaults] integerForKey:#"edittingmode"] == 3) {
UIButton *selected = (UIButton *)sender;
selected.center = [[[event allTouches] anyObject] locationInView:self.view];
if ([[NSUserDefaults standardUserDefaults] integerForKey:#"changeskin"] == 1) {
[self scifiTempSave];
}
else if ([[NSUserDefaults standardUserDefaults] integerForKey:#"changeskin"] == 2) {
[self bananaTempSave];
}
else if ([[NSUserDefaults standardUserDefaults] integerForKey:#"changeskin"] == 3) {
[self orangeTempSave];
}
}
else{}
}
And declared in my .h Header as
-(IBAction)draggedOut:(id)sender;
Now, when I connect the button to the 'draggedOut:' method in Interface Builder using the Touch Drag Inside event, I can drag the button around when I build and run the project (expected behaviour) however when I release the app crashes.
In the past I've been able to connect to a method that appears as "draggedout: withevent" which works beautifully. This evening I've connected some 50 items up to this 'draggedout: withevent' option and it works beautifully for each one - I have however got two UIButtons (identical in almost every way (different referencing outlets) that I have yet to connect to it, and I'll be damned if it'll let me.
Can anyone help? This has been infuriating for some time. The option disappears, yet all those that I previously connected to it still work perfectly, I just can't hook anything new up to it...or the old ones if I disconnect them.

The one problem I can see is that your method declaration in the header is not the same as your implementation. The header declaration should be the first line of the method in the implementation plus a semicolon:
- (IBAction)draggedOut: (id)sender withEvent: (UIEvent *) event;
To get more info on the crash, you should try setting NSZombieEnabled to true.
To answer your question in the comment, I don't know why you would get the option of a draggedout: method in addition to the one including withEvent if it's not declared in your code.

Related

How can I stop views on screen from multiplying? (touchesBegan,touchesMoved,touchesEnded)

I am new to Objective C and I am trying to make a basic puzzle game. I am using multiple UIImage objects, some labels and a button. It consists in moving the pieces to its correct position. If the user fails to put a piece in a place, the piece goes back to its original location.
That part works perfectly, the problem begins once I 'remove' that view and continue on the other screens. Whenever I click ANYWHERE on screen the views get multiplied endlessly. Why is that happening?
What should I do?, I am so desperate, I've tried almost everything including ignoring touches, blocking touches, etc. And this only creates more trouble.
I have already tried setting using interactions to no, ignoring interaction events, autoreleasing the view, and I have not reached a solution.
Any help will be very much appreciated. Greetings!
---> I tried posting an image but given that I am a newbie I wasn't able to, however I can send the image to anyone if needed to show you the weird effect I get.
-(void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event {
[self touchesCancelled:touches withEvent:event];
}
-(IBAction) navigationConversation: (id)sender{
//[self.view.superview setUserInteractionEnabled:NO];
//[[UIApplication sharedApplication] endIgnoringInteractionEvents];
if (nextButton.hidden == NO) {
conversation *navigationConversationController=[[conversation alloc] initWithNibName:#"conversation" bundle:nil];
[self.view addSubview:navigationConversationController.view];
if (self.view.superview == nil)
[navigationConversationController autorelease];
}
return;
}
Thank God, the problem is solved now. This are the changes I made, and this corrected the mistake. :)
-(IBAction) navigationConversation: (id)sender{
if (nextButton.hidden == NO) {
//I disabled the interactions with the puzzle view in here, thus eliminating the problem
[self.view.superview setUserInteractionEnabled:NO];
conversation *navigationConversationController=[[conversation alloc] initWithNibName:#"conversation" bundle:nil];
[self.view addSubview:navigationConversationController.view];
if (self.view.superview == nil)
[navigationConversationController autorelease];
}
return;
}
Thanks to everyone who looked! and wanted to help! I hope this works for other people having the same issues.

EGORefreshTableHeaderView checking connection

I use EGORefreshTableHeaderView to update my tableview.
Here I call my method to download the database:
- (void)reloadTableViewDataSource
{
[self downloadNewsDatabase];
_reloading = YES;
}
In this method (downloadNewsDatabase) I check internet connection. If the device is connected, I download my xml, I saved datas, ecc. Then I call this method
[self performSelector:#selector(doneLoadingTableViewData)];
And this works!
The problem is if the device is not connected. In fact, in that case I call immediately the doneLoadingTableViewData method but when I try to update one more time the tableview the EGOOPullRefreshLoading state is not set.
I think there is a problem with the contentOffset.y of the tableview (in egoRefreshScrollViewDidEndDragging the scrollView.contentOffSet is now 0.0 so the condition scrollView.contentOffset.y <= - 65.0f doesn't work anymore) but... what is wrong in my simple code?
just add a delay on it, like:
[self performSelector:#selector(doneLoadingTableViewData) withObject:nil afterDelay:1.0];
Then it will work.

alert view present on iPhone

I want to check whether the UIALertView is present on the screen or not, though I have done it by using the following method:
-(BOOL) isAlertShowing
{
for (UIWindow* window in [UIApplication sharedApplication].windows) {
NSArray* subviews = window.subviews;
if ([subviews count] > 0)
if ([[subviews objectAtIndex:0] isKindOfClass:[UIAlertView class]])
return YES;
}
return NO;
}
but I came to know that it is undocumented one. So, please tell me authenticate way of doing it.
In an app I submitted (and is approved), I have used a similar approach (see iPhone: detecting if a UIAlert/UIActionSheet are open)...
I don't see why you think it's not a valid method - I'd try it.

iOS: How to access the `UIKeyboard`?

I want to get a pointer reference to UIKeyboard *keyboard to the keyboard on screen so that I can add a transparent subview to it, covering it completely, to achieve the effect of disabling the UIKeyboard without hiding it.
In doing this, can I assume that there's only one UIKeyboard on the screen at a time? I.e., is it a singleton? Where's the method [UIKeyboard sharedInstance]. Brownie points if you implement that method via a category. Or, even more brownie points if you convince me why it's a bad idea to assume only one keyboard and give me a better solution.
Try this:
// my func
- (void) findKeyboard {
// Locate non-UIWindow.
UIWindow *keyboardWindow = nil;
for (UIWindow *testWindow in [[UIApplication sharedApplication] windows]) {
if (![[testWindow class] isEqual:[UIWindow class]]) {
keyboardWindow = testWindow;
break;
}
}
// Locate UIKeyboard.
UIView *foundKeyboard = nil;
for (UIView *possibleKeyboard in [keyboardWindow subviews]) {
// iOS 4 sticks the UIKeyboard inside a UIPeripheralHostView.
if ([[possibleKeyboard description] hasPrefix:#"<UIPeripheralHostView"]) {
possibleKeyboard = [[possibleKeyboard subviews] objectAtIndex:0];
}
if ([[possibleKeyboard description] hasPrefix:#"<UIKeyboard"]) {
foundKeyboard = possibleKeyboard;
break;
}
}
}
How about using -[UIApplication beginIgnoringInteractionEvents]?
Also, another trick to get the view containing the keyboard is to initialize a dummy view with CGRectZero and set it as the inputAccessoryView of your UITextField or UITextView. Then, get its superview. Still, such shenanigans is private/undocumented, but I've heard of apps doing that and getting accepted anyhow. I mean, how else would Instagram be able to make their comment keyboard interactive (dismiss on swipe) like the Messages keyboard?
I found that developerdoug's answer wasn't working on iOS 7, but by modifying things slightly I managed to get access to what I needed. Here's the code I used:
-(UIView*)findKeyboard
{
UIView *keyboard = nil;
for (UIWindow* window in [UIApplication sharedApplication].windows)
{
for (UIView *possibleKeyboard in window.subviews)
{
if ([[possibleKeyboard description] hasPrefix:#"<UIPeripheralHostView"])
{
keyboard = possibleKeyboard;
break;
}
}
}
return keyboard;
}
From what I could make out, in iOS 7 the keyboard is composed of a UIPeripheralHostView containing two subviews: a UIKBInputBackdropView (which provides the blur effect on whatever's underneath the keyboard) and a UIKeyboardAutomatic (which provides the character keys). Manipulating the UIPeripheralHostView seems to be equivalent to manipulating the entire keyboard.
Discaimer: I have no idea whether Apple will accept an app that uses this technique, nor whether it will still work in future SDKs.
Be aware, Apple has made it clear that applications which modify private view hierarchies without explicit approval beforehand will be rejected. Take a look in the Apple Developer Forums for various developers' experience on the issue.
If you're just trying to disable the keyboard (prevent it from receiving touches), you might try adding a transparent UIView that is the full size of the screen for the current orientation. If you add it as a subview of the main window, it might work. Apple hasn't made any public method of disabling the keyboard that I'm aware of - you might want to use one of your support incidents with Apple, maybe they will let you in on the solution.
For an app I am currently developing I am using a really quick and easy method:
Add this in the header file:
// Add in interface
UIWindow * _window;
// Add as property
#property (strong, nonatomic) IBOutlet UIView * _keyboard;
Then add this code in the bottom of the keyboardWillShow function:
-(void) keyboardWillShow: (NSNotification *) notification {
.... // other keyboard will show code //
_window = [UIApplication sharedApplication].windows.lastObject;
[NSTimer scheduledTimerWithTimeInterval:0.05
target:self
selector:#selector(allocateKeyboard)
userInfo:nil
repeats:NO];
}
This code look for when the keyboard is raised and then allocates the current window. I have then added a timer to allocate the keyboard as there were some issues when allocated immediately.
- (void)allocateKeyboard {
if (!_keyboard) {
if (_window.subviews.count) {
// The keyboard is always the 0th subview
_keyboard = _window.subviews[0];
}
}
}
We now have the keyboard allocated which gives you direct "access" to the keyboard as the question asks.
Hope this helps
Under iOS 8 it appears you have to jump down the chain more than in the past. The following works for me to get the keyboard, although with custom keyboards available and such I wouldn't rely on this working unless you're running in a controlled environment.
- (UIView *)findKeyboard {
for (UIWindow* window in [UIApplication sharedApplication].windows) {
UIView *inputSetContainer = [self viewWithPrefix:#"<UIInputSetContainerView" inView:window];
if (inputSetContainer) {
UIView *inputSetHost = [self viewWithPrefix:#"<UIInputSetHostView" inView:inputSetContainer];
if (inputSetHost) {
UIView *kbinputbackdrop = [self viewWithPrefix:#"<_UIKBCompatInput" inView:inputSetHost];
if (kbinputbackdrop) {
UIView *theKeyboard = [self viewWithPrefix:#"<UIKeyboard" inView:kbinputbackdrop];
return theKeyboard;
}
}
}
}
return nil;
}
- (UIView *)viewWithPrefix:(NSString *)prefix inView:(UIView *)view {
for (UIView *subview in view.subviews) {
if ([[subview description] hasPrefix:prefix]) {
return subview;
}
}
return nil;
}

How to disable multitouch?

My app has several buttons which trigger different events. The user should NOT be able to hold down several buttons. Anyhow, holding down several buttons crashes the app.
And so, I'm trying to disable multi-touch in my app.
I've unchecked 'Multiple Touch' in all the xib files, and as far as I can work out, the properties 'multipleTouchEnabled' and 'exclusiveTouch' control whether the view uses multitouch. So in my applicationDidFinishLaunching I've put this:
self.mainViewController.view.multipleTouchEnabled = NO;
self.mainViewController.view.exclusiveTouch = YES;
And in each of my view controllers I've put this in the viewDidLoad
self.view.multipleTouchEnabled = NO;
self.view.exclusiveTouch = YES;
However, it still accepts multiple touches. I could do something like disable other buttons after getting a touch down event, but this would be an ugly hack. Surely there is a way to properly disable multi-touch?
If you want only one button to respond to touches at a time, you need to set exclusiveTouch for that button, rather than for the parent view. Alternatively, you could disable the other buttons when a button gets the "Touch Down" event.
Here's an example of the latter, which worked better in my testing. Setting exclusiveTouch for the buttons kind-of worked, but led to some interesting problems when you moved your finger off the edge of a button, rather than just clicking it.
You need to have outlets in your controller hooked up to each button, and have the "Touch Down", "Touch Up Inside", and "Touch Up Outside" events hooked to the proper methods in your controller.
#import "multibuttonsViewController.h"
#implementation multibuttonsViewController
// hook this up to "Touch Down" for each button
- (IBAction) pressed: (id) sender
{
if (sender == one)
{
two.enabled = false;
three.enabled = false;
[label setText: #"One"]; // or whatever you want to do
}
else if (sender == two)
{
one.enabled = false;
three.enabled = false;
[label setText: #"Two"]; // or whatever you want to do
}
else
{
one.enabled = false;
two.enabled = false;
[label setText: #"Three"]; // or whatever you want to do
}
}
// hook this up to "Touch Up Inside" and "Touch Up Outside"
- (IBAction) released: (id) sender
{
one.enabled = true;
two.enabled = true;
three.enabled = true;
}
#end
- (void)viewDidLoad {
[super viewDidLoad];
for(UIView* v in self.view.subviews)
{
if([v isKindOfClass:[UIButton class]])
{
UIButton* btn = (UIButton*)v;
[btn setExclusiveTouch:YES];
}
}
}
- (void)viewDidLoad {
[super viewDidLoad];
for(UIView* v in self.view.subviews)
{
if([v isKindOfClass:[UIButton class]])
{
UIButton* btn = (UIButton*)v;
[btn setExclusiveTouch:YES];
}
}
}
This code is tested and working perfectly for me.there is no app crash when pressing more than one button at a time.
Your app crashes for a reason. Investigate further, use the debugger, see what's wrong instead of trying to hide the bug.
Edit:
OK, ok, I have to admit I was a bit harsh. You have to set the exclusiveTouch property on each button. That's all. The multipleTouchEnabled property is irrelevant.
To disable multitouch in SWIFT:
You need first to have an outlet of every button and afterwards just set the exclusive touch to true.Therefore in you viewDidLoad() would have:
yourButton.exclusiveTouch = true.
// not really necessary but you could also add:
self.view.multipleTouchEnabled = false
If you want to disable multi touch throughout the application and don't want to write code for each button then you can simply use Appearance of button. Write below line in didFinishLaunchingWithOptions.
UIButton.appearance().isExclusiveTouch = true
Thats great!! UIAppearance
You can even use it for any of UIView class so if you want to disable multi touch for few buttons. Make a CustomClass of button and then
CustomButton.appearance().isExclusiveTouch = true
There is one more advantage which can help you. In case you want to disable multi touch of buttons in a particular ViewController
UIButton.appearance(whenContainedInInstancesOf: [ViewController2.self]).isExclusiveTouch = true
Based on neoevoke's answer, only improving it a bit so that it also checks subviews' children, I created this function and added it to my utils file:
// Set exclusive touch to all children
+ (void)setExclusiveTouchToChildrenOf:(NSArray *)subviews
{
for (UIView *v in subviews) {
[self setExclusiveTouchToChildrenOf:v.subviews];
if ([v isKindOfClass:[UIButton class]]) {
UIButton *btn = (UIButton *)v;
[btn setExclusiveTouch:YES];
}
}
}
Then, a simple call to:
[Utils setExclusiveTouchToChildrenOf:self.view.subviews];
... will do the trick.
This is quite often issue being reported by our testers. One of the approach that I'm using sometimes, although it should be used consciously, is to create category for UIView, like this one:
#implementation UIView (ExclusiveTouch)
- (BOOL)isExclusiveTouch
{
return YES;
}
Pretty much simple you can use make use of ExclusiveTouch property in this case
[youBtn setExclusiveTouch:YES];
This is a Boolean value that indicates whether the receiver handles touch events exclusively.
Setting this property to YES causes the receiver to block the delivery of touch events to other views in the same window. The default value of this property is NO.
For disabling global multitouch in Xamarin.iOS
Copy&Paste the code below:
[DllImport(ObjCRuntime.Constants.ObjectiveCLibrary, EntryPoint = "objc_msgSend")]
internal extern static IntPtr IntPtr_objc_msgSend(IntPtr receiver, IntPtr selector, bool isExclusiveTouch);
static void SetExclusiveTouch(bool isExclusiveTouch)
{
var selector = new ObjCRuntime.Selector("setExclusiveTouch:");
IntPtr_objc_msgSend(UIView.Appearance.Handle, selector.Handle, isExclusiveTouch);
}
And set it on AppDelegate:
public override bool FinishedLaunching(UIApplication app, NSDictionary options)
{
...
SetExclusiveTouch(true); // setting exlusive to true disables the multitouch
...
}
My experience is that, by default, a new project doesn't even allow multitouch, you have to turn it on. But I suppose that depends on how you got started. Did you use a mutlitouch example as a template?
First of all, are you absolutely sure multitouch is on? It's possible to generate single touches in sequence pretty quickly. Multitouch is more about what you do with two or more fingers once they are on the surface. Perhaps you have single touch on but aren't correctly dealing with what happens if two buttons are pressed at nearly the same time.
I've just had exactly this problem.
The solution we came up with was simply to inherit a new class from UIButton that overrides the initWithCoder method, and use that where we needed one button push at a time (ie. everywhere):
#implementation ExclusiveButton
(id)initWithCoder: (NSCoder*)decoder
{
[self setExclusiveTouch:YES];
return [super initWithCoder:decoder]
}
#end
Note that this only works with buttons loaded from nib files.
I created UIView Class Extension and added this two functions. and when i want to disable view touch i just call [view makeExclusiveTouch];
- (void) makeExclusiveTouchForViews:(NSArray*)views {
for (UIView * view in views) {
[view makeExclusiveTouch];
}
}
- (void) makeExclusiveTouch {
self.multipleTouchEnabled = NO;
self.exclusiveTouch = YES;
[self makeExclusiveTouchForViews:self.subviews];
}
If you want to disable multitouch programmatically, or if you are using cocos2d (no multipleTouchEnabled option), you can use the following code on your ccTouches delegate:
- (BOOL)ccTouchesBegan:(NSSet *)touches
withEvent:(UIEvent *)event {
NSSet *multiTouch = [event allTouches];
if( [multiTouch count] > 1) {
return;
}
else {
//else your rest of the code
}
Disable all the buttons on view in "Touch Down" event and enable them in "Touch Up Inside" event.
for example
- (void) handleTouchDown {
for (UIButton *btn in views) {
btn.enable = NO;
}
}
- (void) handleTouchUpInside {
for (UIButton *btn in views) {
btn.enable = Yes;
}
------
------
}
I decided this problem by this way:
NSTimeInterval intervalButtonPressed;
- (IBAction)buttonPicturePressed:(id)sender{
if (([[NSDate date] timeIntervalSince1970] - intervalButtonPressed) > 0.1f) {
intervalButtonPressed = [[NSDate date] timeIntervalSince1970];
//your code for button
}
}
I had struggled with some odd cases when dragging objects around a view, where if you touched another object at the same time it would fire the touchesBegan method. My work-around was to disable user interaction for the parent view until touchesEnded or touchesCancelled is called.
override func touchesMoved(touches: Set<UITouch>, withEvent event: UIEvent?) {
// whatever setup you need
self.view.userInteractionEnabled = false
}
override func touchesEnded(touches: Set<UITouch>, withEvent event: UIEvent?) {
// whatever setup you need
self.view.userInteractionEnabled = true
}
override func touchesCancelled(touches: Set<UITouch>?, withEvent event: UIEvent?) {
// whatever setup you need
self.view.userInteractionEnabled = true
}
A Gotcha:
If you are using isExclusiveTouch, be aware that overriding point(inside:) on the button can interfere, effectively making isExclusiveTouch useless.
(Sometimes you need to override point(inside:) for handling the "button not responsive at bottom of iPhone screen" bug/misfeature (which is caused by Apple installing swipe GestureRecognizers at the bottom of the screen, interfering with button highlighting.)
See: UIButton fails to properly register touch in bottom region of iPhone screen
Just set all relevant UIView's property exclusiveTouch to false do the trick.