scalaquery retrieve values - scala

Question

I have few tables, lets say 2 for simplicity. I can create them in this way,
...
val tableA = new Table[(Int,Int)]("tableA"){
def a = column[Int]("a")
def b = column[Int]("b")
}
val tableB = new Table[(Int,Int)]("tableB"){
def a = column[Int]("a")
def b = column[Int]("b")
}
Im going to have a query to retrieve value 'a' from tableA and value 'a' from tableB as a list inside the results from 'a'
my result should be:
List[(a,List(b))]
so far i came upto this point in query,
def createSecondItr(b1:NamedColumn[Int]) = for(
b2 <- tableB if b1 === b1.b
) yield b2.a
val q1 = for (
a1 <- tableA
listB = createSecondItr(a1.b)
) yield (a1.a , listB)
i didn't test the code so there might be errors in the code. My problem is I cannot retrieve data from the results.
to understand the question, take trains and classes of it. you search the trains after 12pm and you need to have a result set where the train name and the classes which the train have as a list inside the train's result.

Answer 1

I don't think you can do this directly in ScalaQuery. What I would do is to do a normal join and then manipulate the result accordingly:
import scala.collection.mutable.{HashMap, Set, MultiMap}
def list2multimap[A, B](list: List[(A, B)]) =
list.foldLeft(new HashMap[A, Set[B]] with MultiMap[A, B]){(acc, pair) => acc.addBinding(pair._1, pair._2)}
val q = for (
a <- tableA
b <- tableB
if (a.b === b.b)
) yield (a.a, b.a)
list2multimap(q.list)
The list2multimap is taken from https://stackoverflow.com/a/7210191/66686
The code is written without assistance of an IDE, compiler or similar. Consider the debugging free training :-)