I am try to remove time from date how to do this i try this code it not working proper where i am wrong
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *todaysDate = [NSDate date];
//NSDateComponents *dateComponents = [[NSDateComponents alloc] init];
NSDateComponents*dateComponents = [gregorian components:NSDayCalendarUnit fromDate:todaysDate];
[dateComponents setDay:1];
app.selectionData.fromDateSelected = [gregorian dateByAddingComponents:dateComponents toDate:todaysDate options:0];
//[dateComponents release];
[gregorian release];
Are you trying to do this?
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
int comps = NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit;
NSDateComponents *dateComponents = [gregorian components:comps fromDate:[NSDate date]];
[dateComponents setDay:[dateComponents day] + 1];
app.selectionData.fromDateSelected = [gregorian dateFromComponents:dateComponents];
[gregorian release];
To only get the date, you can use NSDateFormatter
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
[dateFormatter setTimeStyle:NSDateFormatterNoStyle];
NSString* currentDate = [dateFormatter stringFromDate:[NSDate date]];
[dateFormatter release];
You can also supply your own format for the date.
For ex:
[dateFormattter setDateFormat:#"yyyy-mm-dd"];
You can refer to UTS #35 and Date Formatting Guide for more options on formatting.
Try this out. This works for me
NSDate *todaysDate = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSString *stringDate = [dateFormat stringFromDate:todaysDate];
NSLog(#"stringDate: %#",stringDate);
[dateFormat release];
EDIT:
NSDate *today = [NSDate date];
NSTimeInterval secondsPerDay = 24 * 60 * 60;
NSDate *date = [today addTimeInterval:secondsPerDay];
//Change NSDate *date = [tomorrow addTimeInterval:-secondsPerDay]; for yesterday
NSDate *tomorrow = date;
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSString *stringDate = [dateFormat stringFromDate:tomorrow];
NSLog(#"stringDate: %#",stringDate);
[dateFormat release];
Hope this helps you.
Related
I basically want to convert a particular date (x) to the previous day date(x - 1 day) and also to the next day date (x + 1 day). I am using the following code for this :
NSDate *datePlusOneDay = [currentDate dateByAddingTimeInterval:(60 * 60 * 24)];
However I have my date (x) in NSString format, and I need to convert the NSString(myDateString) to NSDate(myDate) before applying the above code.
I have a NSString containing date in format MM-dd-yyyy.
For converting I am using the following code , but I am getting absurd values.
NSLog(#"myDateString=%#",myDateString);//output:myDateString=10-25-2012//all correct
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM-dd-yyyy"];
NSDate *myDate=[formatter dateFromString:myDateString];
NSLog(#"myDate=%#",myDate);//output:myDate=2012-10-24 18:30:00 +0000 // I only want the date to be shown // and why has the format changed
NSDate *datePlusOneDay = [currentDate dateByAddingTimeInterval:(60 * 60 * 24)];
NSLog(#"datePlusOneDay=%#",datePlusOneDay);//output:datePlusOneDay=2012-10-25 18:30:00 +0000// I only want the date to come , not time // and why has the format changed
Later again I need to convert the NSDate to NSString
NSString *curentString=[formatter stringFromDate:datePlusOneDay];
NSLog(#"curentString=%#",curentString); //output:curentString=10-26-2012
Similarly I also want to get the previous date.
Please help guys !! and ho ho MERRY CHRISTMAS !!
Do as: componets.day = 1 to obtain the next, -1 for the previous day.
NSDate *date = [NSDate date]; // your date from the server will go here.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [[NSDateComponents alloc] init];
components.day = 1;
NSDate *newDate = [calendar dateByAddingComponents:components toDate:date options:0];
NSLog(#"newDate -> %#",newDate);
The below code should get you the previous date:
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
[offsetComponents setDay:-1]; // replace "-1" with "1" to get the datePlusOneDay
NSDate *dateMinusOneDay = [gregorian dateByAddingComponents:offsetComponents toDate:myDate options:0];
Merry Xmas :)
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *components = [cal components:( NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate:[[NSDate alloc] init]];
[components setHour:-[components hour]];
[components setMinute:-[components minute]];
[components setSecond:-[components second]];
NSDate *today = [cal dateByAddingComponents:components toDate:[[NSDate alloc] init] options:0]; //This variable should now be pointing at a date object that is the start of today (midnight);
[components setHour:-24];
[components setMinute:0];
[components setSecond:0];
NSDate *yesterday = [cal dateByAddingComponents:components toDate: today options:0];
Try this simple solution for previous date:-
NSDate *datePlusOneDay = [[NSDate date] dateByAddingTimeInterval:-(60 * 60 * 24)];
NSLog(#"datePlusOneDay=%#",datePlusOneDay);
Swift 5 Solution
let calendar = Calendar.current
calendar.date(byAdding: .day, value: -2, to: Date())
function for previousDay
-(void)previousDay
{
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"dd/MM/yyyy"];
dateString = [dateFormat stringFromDate:today];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *comps = [NSDateComponents new];
comps.day =-1;
NSDate *sevenDays = [calendar dateByAddingComponents:comps toDate:[NSDate date] options:0];
[dateFormat setDateFormat:#"dd/MM/yyyy"];
EndingDate = [dateFormat stringFromDate:sevenDays];
}
function for next day
-(void)nextDay
{
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"dd/MM/yyyy"];
dateString = [dateFormat stringFromDate:today];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *comps = [NSDateComponents new];
comps.day =1;
NSDate *sevenDays = [calendar dateByAddingComponents:comps toDate:[NSDate date] options:0];
[dateFormat setDateFormat:#"dd/MM/yyyy"];
EndingDate = [dateFormat stringFromDate:sevenDays];
}
I'm a iOS developer of the iWorld.
I've developed several iPhone/iPad apps before.
I couldn't get correct time information on iPhone several times. I think that is due to localization.
For example, I have code to get the time-truncated today. (ex : "05-04-2012 00:00:00")
But that code always return 8 hours ago to that I've expected. (ex : "05-03-2012 16:00:00)
The code that I've worked are as following.
NSDate *today = [NSDate date];
NSCalendar *calender = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [calender components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
today = [calender dateFromComponents:components];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM-dd-yyyy hh:mm:ss"];
NSString *todayString = [formatter stringFromDate:today];
NSLog(#"Today is %#", todayString);
I'd like to hear from you to resolve this problem.
Thanks for your time.
Set timezone to UTC
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
NSTimeZone *timeZone = [NSTimeZone timeZoneWithName:#"UTC"];
[dateFormatter setTimeZone:timeZone];
I've found that code that calculates correct midnight time.
Now I find that following code logs "Today is 05-07-2012 00:00:00" rather than "05-06-2012 16:00:00"
NSDate *today = [NSDate date];
NSCalendar *calender = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [calender components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
today = [calender dateFromComponents:components];
today = [today dateByAddingTimeInterval:[[NSTimeZone localTimeZone] secondsFromGMT]];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM-dd-yyyy hh:mm:ss"];
NSString *todayString = [formatter stringFromDate:today];
NSLog(#"Today is %#", todayString);
Thanks for SO.
I've been trying and searching for over two days now.
The only thing I'm trying is to convert a week number "Week 50" to the start date of the week.
I've tried to convert with dateFromString like this:
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"w"];
NSDate *date = [dateFormat dateFromString:dateStr];
NSLog(#"date(%#)", date);
NSDateFormatter *formatting = [[NSDateFormatter alloc] init];
[formatting setDateFormat:#"YYYY/MM/dd"];
NSString *stringDate = [formatting stringFromDate:date];
NSLog(#"date: %#", stringDate);
[dateFormat release];
But both objects return (null) so it isn't of many help.
Regards
Have you tried the following:
NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setYear:2012];
[comps setWeek:50];
NSCalendar *cal = [NSCalendar currentCalendar];
NSDate *week50 = [cal dateFromComponents:comps];
You can try trimming the string to just the week number like "50" and then add the desired year number and use following:
NSString *dateStr=#"50 2011";
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"w YYYY"];
NSDate *date = [dateFormat dateFromString:dateStr];
NSLog(#"date(%#)", date);
i have a "DateTimeArray" this array contain
DateTimeArray[index 0] = 20.05.2011 12:12:50
DateTimeArray[index 1]= 20.05.2011 12:13:20
DateTimeArray[index 2]= 20.05.2011 12:20:10
all the value are in string,and i want to convert this string into NSDate and only want to access time not date
and then this time values will be stored in array and this newly array will be used for drawing line chart
i hope some one know this issue
thank you very much
Code as follows,
for(int index=0;index<[DateTimeArray count];index++)
{
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"HH:mm:ss"];
NSString *timeString=[[[DateTimeArray objectAtIndex:index]componentsSeparatedByString:#" "]objectAtIndex:1];
NSDate *time=[df dateFromString:timeString];
[timeArray addObject:time];
[df release];
}
Try this
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"HH:mm:ss"];
NSDate *formattedDate = [df dateFromString:[DateTimeArray objectAtIndex:requiredIndex]];
[df release];
Best and cleaner approach:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"dd.MM.yyyy HH:mm:ss"];
for(int i=0; i < [DateTimeArray count]; ++i)
{
NSString *string = [DateTimeArray objectAtIndex:i];
NSDate *date = [df dateFromString:string];
[timeArray addObject:time];
}
[df release]; // ALWAYS release unused objects
Then to just access hours, and not days, you should select the required components of each NSDate* instance:
// Get the Gregorian calendar
NSCalendar *cal = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
// Get the date
NSDate* date = [timeArray objectAtIndex:my_index];
// Get the hours, minutes, seconds
NSDateComponents* hour = [cal components:NSHourCalendarUnit fromDate:date];
NSDateComponents* minute = [cal components:NSMinuteCalendarUnit fromDate:date];
NSDateComponents* second = [cal components:NSSecondCalendarUnit fromDate:date];
NSMutableArray *nsdateArray = [NSMutableArray arrayWithCapacity:[DateTimeArray count]];
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"dd.MM.yyyy HH:mm:ss"];
for(NSString *currentString in DateTimeArray){
NSDate *date = [dateFormat dateFromString:currentString];
[nsdateArray addObject:date];
}
[dateFormat release];
NSLog(#"ArrayWithDate:%#",[nsdateArray description]);
Heres the complete set of code.. Hope it helps..
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"HH:mm:ss"];
int i=0;//start for{} loop
NSString *currDate = [formatter dateFromString:[DateTimeArray objectAtIndex:i]];
[formatter release];
Happy iCoding...
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setDateFormat:#"HH:mm:ss"]
NSString *theTime = [timeFormat dateFromString:date];
or
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:(kCFCalendarUnitHour | kCFCalendarUnitMinute) fromDate:date];
NSInteger hour = [components hour];
NSInteger minute = [components minute];
I'm using the code provided below to display time and date. can anyone help me with atuomatically changing the time by seconds and the date by the day?
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setDateFormat:#"HH:mm:ss"];
NSDate *now = [[NSDate alloc] init];
NSString *theDate = [dateFormat stringFromDate:now];
NSString *theTime = [timeFormat stringFromDate:now];
NSLog(#"\n"
"theDate: |%#| \n"
"theTime: |%#| \n"
, theDate, theTime);
[dateFormat release];
[timeFormat release];
[now release];
You can use NSTimer, specifically scheduledTimerWithTimeInterval:target:selector:userInfo:repeats:. You can use 1 as a time interval.
Use the NSDateComponents class. For example, to add one day and one second to a date:
NSDate *startDate = [NSDate date];
unsigned unitFlags = NSDayCalendarUnit | NSSecondCalendarUnit;
NSCalendar *curr = [NSCalendar currentCalendar];
NSDateComponents *oneDay = [[NSDateComponents alloc] init];
oneDay.day = 1;
oneDay.second = 1;
NSDate* adjustedDate = [curr dateByAddingComponents:oneDay
toDate:startDate
options:0];
Date and Time programming guide