I have a long String:
1;#Subject:SW|
vti_parserversion:SR|14.0.0.4762
vti_folderitemcount:IR|0
_Category:SW|
vti_author:SR|SHAREPOINT\\system
_dlc_DocIdItemGuid:SW|8435986b-4ff2-4e03-9879-d15568d88f0b
vti_approvallevel:SR|
vti_categories:VW|
vti_foldersubfolderitemcount:IR|0
vti_modifiedby:SR|SHAREPOINT\\system
vti_assignedto:SR|
Keywords:SW|
_Status:SW|
vti_cachedcustomprops:VX|vti_approvallevel vti_categories Subject vti_assignedto Keywords _Status vti_title _Author _Category _dlc_DocId _Comments _dlc_DocIdUrl _dlc_DocIdItemGuid
ContentTypeId:SW|0x01010013CD7B577B3AC84B8467BC0F2B82B30D
_dlc_DocId:SW|5VQNHKQHD5Z4-9-1
vti_cachedtitle:SR|SharePoint 2010 Deployment Guide
vti_title:SR|SharePoint 2010 Deployment Guide
_Author:SW|
_dlc_DocIdUrl:SW|http://blub.com/_layouts/DocIdRedir.aspx?ID=5VQNHKQHD5Z4-9-2, 5VQNHKQHD5Z4-9-1
_Comments:SW|
And I want to parse the DocIdUrl (the String between "_dlc_DocIdUrl:SW|" and ",") , I am using RegexKitLite with: String stringByMatching:regExP
This is my first RegExpression: NSString* regExp = #"(?=\_dlc_DocIdUrl:SW|)(.*?)(?=\,)";
But it gives me: _dlc_DocIdUrl:SW|http://blub.com/_layouts/DocIdRedir.aspx?ID=5VQNHKQHD5Z4-9-2
I only want the URL, how can i solve that?
I am confused!
Here is the regex solving your problem:
_dlc_DocIdUrl:SW\|(?<value>[^,]*),+
You will find the requested URL in the group named "value"
(?<=_dlc_DocIdUrl:SW\|)[^,]*(?=,)
this give you what you need directly, without grouping.
Related
Currently I'm working in a project with flutter, but I realize there is a need in the management of the variables I'm using.
Basically I want to delete the last character of a string I'm concatenating, something like this:
string varString = 'My text'
And with the help of some method or function, the result I get:
'My tex'
Am I clear about it? I'm looking for some way which helps me to 'pop' the last character of a text (like pop function in javascript)
Is there something like that? I search in the Dart docs, but I didn't find anything about it.
Thank you in advance.
You can take a substring, like this:
string.substring(0, string.length - 1)
If you need the last character before popping, you can do this:
string[string.length - 1]
Strings in dart are immutable, so the only way to do the operation you are describing is by constructing a new instance of a string, as described above.
var str = 'My text';
var newStr = (str.split('')..removeLast()).join();
print(newStr);
Another way:
var newStr2 = str.replaceFirst(RegExp(r'.$') , '');
print(newStr2);
I have this string: "C:\Procesos\rrhh\CorteDocumentos\Cortados\10001662-1_20060301_29_1_20190301.pdf" and im trying to get this part : "20190301". The problem is the lenght is not always the same. It would be:
"9001662-1_20060301_4_1_20190301".
I've tried this: item.ToString.Substring(66,8), but it doesn't work sometimes.
What can I do?.
This is a code example of what I said in my comment.
Sub Main()
Dim strFileName As String = ""
Dim di As New DirectoryInfo("C:\Users\Maniac\Desktop\test")
Dim aryFi As FileInfo() = di.GetFiles("*.pdf")
Dim fi As FileInfo
For Each fi In aryFi
Dim arrname() As String
arrname = Split(Path.GetFileNameWithoutExtension(fi.Name), "_")
strFileName = arrname(arrname.Count - 1)
Console.WriteLine(strFileName)
Next
End Sub
You could achieve this using a simple regular expressions, which has the added benefit of including pattern validation.
If you need to get exactly eight numbers from the end of file name (and after an underscore), you can use this pattern:
_(\d{8})\.pdf
And then this VB.NET line:
Regex.Match(fileName, "_(\d{8})\.pdf").Groups(1).Value
It's important to mention that Regex is by default case sensitive, so to prevent from being in a situations where "pdf" is matched and "PDF" is not, the patter can be adjusted like this:
(?i)_(\d{8})\.pdf
You can than use it directly in any expression window:
PS: You should also ensure that System.Text.RegularExpressions reference is in the Imports:
You can achieve it by this way as well :)
Path.GetFileNameWithoutExtension(Str1).Split("_"c).Last
Path.GetFileNameWithoutExtension
Returns the file name of the specified path string without the extension.
so with your String it will return to you - 10001662-1_20060301_29_1_20190301
then Split above String i.e. 10001662-1_20060301_29_1_20190301 based on _ and will return an array of string.
Last
It will return you the last element of an array returned by Split..
Regards..!!
AKsh
I'm hoping this is an easy question, and that I'm just not seeing the forest due to all the trees.
I have a string in flutter than came from a REST API that looks like this:
"What\u0027s this?"
The \u is causing a problem.
I can't do a string.replaceAll("\", "\") on it as the single slash means it's looking for a character after it, which is not what I need.
I tried doing a string.replaceAll(String.fromCharCode(0x92), "") to remove it - That didn't work.
I then tried using a regex to remove it like string.replaceAll("/(?:\)/", "") and the same single slash remains.
So, the question is how to remove that single slash, so I can add in a double slash, or replace it with a double slash?
Cheers
Jase
I found the issue. I was looking for hex 92 (0x92) and it should have been decimal 92.
I ended up solving the issue like this...
String removeUnicodeApostrophes(String strInput) {
// First remove the single slash.
String strModified = strInput.replaceAll(String.fromCharCode(92), "");
// Now, we can replace the rest of the unicode with a proper apostrophe.
return strModified.replaceAll("u0027", "\'");
}
When the string is read, I assume what's happening is that it's being interpreted as literal rather than as what it should be (code points) i.e. each character of \0027 is a separate character. You may actually be able to fix this depending on how you access the API - see the dart convert library. If you use utf8.decode on the raw data you may be able to avoid this entire problem.
However, if that's not an option there's an easy enough solution for you.
What's happening when you're writing out your regex or replace is that you're not escaping the backslash, so it's essentially becoming nothing. If you use a double slash, that solve the problem as it escapes the escape character. "\\" => "\".
The other option is to use a raw string like r"\" which ignores the escape character.
Paste this into https://dartpad.dartlang.org:
String withapostraphe = "What\u0027s this?";
String withapostraphe1 = withapostraphe.replaceAll('\u0027', '');
String withapostraphe2 = withapostraphe.replaceAll(String.fromCharCode(0x27), '');
print("Original encoded properly: $withapostraphe");
print("Replaced with nothing: $withapostraphe1");
print("Using char code for ': $withapostraphe2");
String unicodeNotDecoded = "What\\u0027s this?";
String unicodeWithApostraphe = unicodeNotDecoded.replaceAll('\\u0027', '\'');
String unicodeNoApostraphe = unicodeNotDecoded.replaceAll('\\u0027', '');
String unicodeRaw = unicodeNotDecoded.replaceAll(r"\u0027", "'");
print("Data as read with escaped unicode: $unicodeNotDecoded");
print("Data replaced with apostraphe: $unicodeWithApostraphe");
print("Data replaced with nothing: $unicodeNoApostraphe");
print("Data replaced using raw string: $unicodeRaw");
To see the result:
Original encoded properly: What's this?
Replaced with nothing: Whats this?
Using char code for ': Whats this?
Data as read with escaped unicode: What\u0027s this?
Data replaced with apostraphe: What's this?
Data replaced with nothing: Whats this?
Data replaced using raw string: What's this?
I am struggling with this regular expression.
$glossary_search[] = "/(^|>|\\s)".$glossary["glossary_name"]."($|<|\\s)/i";
$glossary_replace[] = "\$1<a href='/jargon-buster/".tapestry_hyphenate($glossary["glossary_name"]).".html' title='".$glossary["glossary_name"]."' target='_blank'>".$glossary["glossary_name"]."</a>\$2";
return preg_replace($glossary_search,$glossary_replace,$text);
I am trying to replace words in a product description with a hyperlink. The code above works if the word has a space either side but does not work if it has a full stop, comma or "<". Can anyone spot my mistake?
Thanks,
Simon
I think you might need to use preg_quote and htmlentities?
$glossary_search[] = "/(^|>|\\s)".preg_quote(htmlentities($glossary["glossary_name"],ENT_COMPAT,'UTF8'))."($|<|\\s)/i";
$glossary_replace[] = "\$1<a href='/jargon-buster/".tapestry_hyphenate($glossary["glossary_name"]).".html' title='".$glossary["glossary_name"]."' target='_blank'>".$glossary["glossary_name"]."</a>\$2";
return preg_replace($glossary_search,$glossary_replace,$text);
Is there a way to search for specific words within a string in Objective-C?
Let's say I have the following sentence:
thequickbrownfox
If I wanted to search for "quick" within the sentence. What would be the best way to achieve this?
Thanks for your help.
if ([myString rangeOfString:stringToSearch].location != NSNotFound) {
// stringToSearch is present in myString
}
You can use NSString::rangeOfString for this.
From the docs -
Return Value
An NSRange structure giving the location and length in the receiver of the first occurrence of aString. Returns {NSNotFound, 0} if aString is not found or is empty (#"").