Powershell - Export Multiple CSV's into unique folders - powershell

Question

I have been working on a PowerShell script for the better part of well a week or two. I've been able to get some parts of it working however I'm unable to fully get this automated.
I deal with a lot of CSV files on a daily basis, I have been tasked with uploading them into our software however sometimes they're too large to handle so I break them down based upon their "type" (it's a column in the CSV) and I export it to a single CSV per "type". I've been able to accomplish this with the following:
$file = gci -Filter "*.csv";
Import-Csv $file `
| Group-Object –Property “type” `
| Foreach-Object `
{
$path=$_.name+”.csv” ; $_.group `
| Export-Csv –Path $path –NoTypeInformation
}
So this works wonderfully, for each individual CSV. Unfortunately I don't have the time to do this for each individual CSV. Now I come to my other PowerShell script:
get-childitem -Filter "*.csv" `
| select-object basename `
| foreach-object{ $path=$_.basename+".csv" #iterate through files.
if(!(Test-Path -path $_.basename)) #If the folder of the file can't be found then it will attempt to create it.
{
New-Item $_.basename -type directory; $file=$_.basename+".csv";
Import-Csv $file `
| Group-Object -Property "Type" `
| Foreach-Object {
$path=$_.name+".csv"; $_.group `
| `
if(!(Test-Path -path $path2))
{
New-Item $path2 -type directory
Export-Csv -Path $path2 + "\" + $path -NoTypeInformation
}
else
{
"Failed on: " + $_.basename
#Export-Csv -Path $_.basename + "\" + $path -NoTypeInformation
}
}
}
else
{
Import-Csv $path `
| Group-Object -Property "Type" `
| Foreach-Object {$path=$_.basename+".csv" ; $_.group
if(Test-Path -path $._)
{
New-Item $path2 -type directory
Export-Csv -Path $path2 + "\" + $path -NoTypeInformation
}
#else
#{
Write-Host "Failed on: $_.basename"
#Export-Csv -Path $_.basename + "\" + $path -NoTypeInformation
#}
}
}
}
I just can't wrap my head around "why" this isn't working effectively. I have two conditionals. Is there a folder for the CSV? If no create one. I have to have another one because one of the "types" contains a \ which errors out if I don't have the folder, so I automatically try to create it. When I run the script I get the Path is null.
The Error is:
The term ' ' is not recognized as the name of a cmdlet, function,
script file, or operable program. Check the spelling of the name, or
if a path was included, verify that the path is correct and try again.
At C:\Users\c.burkinshaw\foldermake.ps1:11 char:26
+ | ` <<<<
+ CategoryInfo : ObjectNotFound: ( :String) [], CommandNotFoundException
+ FullyQualifiedErrorId : CommandNotFoundException
Test-Path : Cannot bind argument to parameter 'Path' because it is null.
At C:\Users\c.burkinshaw\foldermake.ps1:12 char:45
+ if(!(Test-Path -path <<<< $path2))
+ CategoryInfo : InvalidData: (:) [Test-Path], ParameterBindingValidationException
+ FullyQualifiedErrorId : ParameterArgumentValidationErrorNullNotAllowed,Microsoft.PowerShell.Commands.TestPathCommand
Any help would be greatly appreciated, if you have questions please don't hesitate to ask.

Answer 1

You have not defined $path2 anywhere, so something like test-path -path $path2 will say path is null. And in one place you are using $._ which will again give errors.
Edit after question updated with error message:
Your error message also says the same
Test-Path : Cannot bind argument to parameter 'Path' because it is
null. At C:\Users\c.burkinshaw\foldermake.ps1:12 char:45
+ if(!(Test-Path -path <<<< $path2))
Also the other error is in:
$path=$_.name+".csv"; $_.group `
| `
what are you trying to do here with the $_.group?
It is not proper. You cannot do $_.group | and provide some if statement.
Other comments:
Why are using $_.basename and then appending .csv? You could have just used $_.name. Try to not use the select-object basename - I don't see the value.
Extract the common import-csv and export-csv part into a function.