I'd like to use an iCloud, but when I compile the app on iOS 4.3 Simulator it crashes.
dyld: Symbol not found: _OBJC_CLASS_$_NSMetadataQuery
What should I do to make it working on iOS 3, 4, and 5?
my sulotion is:
Where have NSMetadataQuery change to id: ex
normal : - (void)loadData:(NSMetadataQuery *)query;
change to: - (void)loadData:(id)query;
normal: #property (retain, nonatomic) NSMetadataQuery *query;
change to: #property (retain, nonatomic) id query;
and check iCloud available:
if ([[NSFileManager defaultManager] respondsToSelector:#selector(URLForUbiquityContainerIdentifier:)]) {
NSURL *ubiq = [[NSFileManager defaultManager] URLForUbiquityContainerIdentifier:nil];
if (ubiq) {
// Code for access iCloud here
}
}
When use NSMetadataQuery:
id _query = [[NSClassFromString(#"NSMetadataQuery") alloc] init];
// Some code here
[_query startQuery];
Have fun (^_^)
The usual way would be to compile it with iOS 5 SDK and setting the deployment target to the oldest iOS Version you'd like it to work with. It's up to you though to check at runtime on which classes and methods are available to the current system. A user on iOS 4 for example will not be able to use functions that only ship with iOS 5.
To check the availability of classes do:
if ( NSClassFromString(#"NSMetadataQuery") != nil ) {
//do stuff with NSMetadataQuery here
}
To check the availability of methods do:
if ( [myObject respondsToSelector:#selector(doSomething)] ) {
//call doSomething on myObject
}
These API has been launched with the ios5 so you cann't run it on the simulator 4 or below but for posting you can set the minimum deployment target of ios family it should support .
Related
I have looked everywhere for examples on how to initialize a view from a .SKS file. Every example I found seems to now be broken with the introduction of Swift 2 and Xcode 7. I am using Xcode 7 GM.
Could someone please provide an example of how to do this in the quickest way possible?
Edit* Please be aware of both the iOS version and Xcode version before you mark this as a duplicate.
I copied my code off of the SpriteKit sample project. I'm at work now, I can convert it to Swift this weekend if you need me to. Runs in Xcode 7, on iOS 9.1.
#implementation SKScene (Archiving)
+ (instancetype)unarchiveFromFile:(NSString *)file {
/* Retrieve scene file path from the application bundle */
NSString *nodePath = [[NSBundle mainBundle] pathForResource:file ofType:#"sks"];
/* Unarchive the file to an SKScene object */
NSData *data = [NSData dataWithContentsOfFile:nodePath
options:NSDataReadingMappedIfSafe
error:nil];
NSKeyedUnarchiver *arch = [[NSKeyedUnarchiver alloc] initForReadingWithData:data];
[arch setClass:self forClassName:#"SKScene"];
SKScene *scene = [arch decodeObjectForKey:NSKeyedArchiveRootObjectKey];
[arch finishDecoding];
return scene;
}
#end
// ...
#implementation VTMillScene
+ (instancetype)loadMill {
return [self unarchiveFromFile:#"mill"]; // loads "mill.sks"
}
#end
Does anybody knows if the technique used to ask the user to rate our app and open for him the App Store directly on the rating page is still working on iOS 7 ?
I used to open this url from my app :
itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=353372460&onlyLatestVersion=true&pageNumber=0&sortOrdering=1&type=Purple+Software
But it looks like it's not working anymore (AppStore show a blank page). I have also tried this url wihout luck:
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?pageNumber=0&sortOrdering=1&type=Purple+Software&mt=8&id=353372460
Starting with iOS7 the URL has changed and cannot direct for the review page but only to the app
itms-apps://itunes.apple.com/app/idAPP_ID
Where APP_ID need to be replaced with your Application ID. Based on the App ID from the question it would be the following
itms-apps://itunes.apple.com/app/id353372460
Notice the id in front of the number ... that string is is id353372460, not just 353372460
For anything pre iOS7 the 'old' URL needs to be used, only those could get you straight to the review page. You should also take note that these calls will only work on devices. Running them in the simulator will do nothing since the simulator does not have the App Store app installed.
Have a look at for instance Appirater for an implementation. https://github.com/arashpayan/appirater
Can't help you with phonegap specifics (never used it). But it basically comes down to checking the iOS version your user is running and then either use the old URL or then new iOS7 URL.
The following URL works perfectly on iOS 7.1:
http://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=xxxxxxxx&pageNumber=0&sortOrdering=2&type=Purple+Software&mt=8
where the xxxxxxxx is your app ID.
UPDATE. Works on iOS 9.3.4 and iOS 10 GM (by Jeet)
This works on my end (Xcode 5 - iOS 7 - Device!):
itms-apps://itunes.apple.com/app/idYOUR_APP_ID
For versions lower than iOS 7 use the old one:
itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=YOUR_APP_ID
One-Line-of-Code Simple Alternative: ** Also See Simulator Comments Below **
http://itunes.apple.com/app/idAPP_ID
EDIT: Now that iOS 7.1 allows direct-link to the Reviews tab in the App Store, it's worth investing the extra lines of code to get there directly: see other answers for the rest.
here we are using http: instead of itms-apps:, let iOS do the rest of the work
I get the same results testing on iOS 6.1 & 7 devices (iPad/iPhone/iPod touch 4)
Specifically, this shortcut, for iOS 6 takes the user to the Details tab and not the Reviews tab.
The Purple+Software link gets the user all the way to the Reviews tab in iOS 6, which is obviously preferred if you know how to check the OS.
Important note: This will cause error in the simulator for iOS 5.1, 6.1 and 7.Cannot Open Page Safari can not open the page because the address is invalid (we know it is a valid URL outside the simulator, on any browser)
Just to be clear: On iOS 7: http:// provides the same experience as itms-apps: with no noticeable delay. * keep in mind that the simulator behavior noted above. This is not entire dissimilar from trying to access the camera via a simulator: the simulator is not the place to test it. *
It's not clear which versions of iOS this is supported by, but as part of iOS 10.3 there's a new query parameter that can be added to the URL: action=write-review. I have tested this on iOS 10.2 and 9.3.5 and it works. However, it does not work on iOS 7.1.2, so support was added between iOS 8.0 and 9.3.5. Further investigation is required!
Example: https://itunes.apple.com/app/id929726748?action=write-review&mt=8
This will open the "Write a Review" dialogue, rather than just showing the review tab.
Opening review page directly from app is possible in iOS7.
Please use the following url...
itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=YOUR_APP_ID
This will definitely works.. :)
+ (NSString *)getReviewUrlByAppId:(int)appId
{
NSString *templateReviewURL = #"itms-apps://ax.itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=APP_ID";
NSString *templateReviewURLiOS7 = #"itms-apps://itunes.apple.com/app/idAPP_ID";
NSString *templateReviewURLiOS8 = #"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=APP_ID&onlyLatestVersion=true&pageNumber=0&sortOrdering=1&type=Purple+Software";
//ios7 before
NSString *reviewURL = [templateReviewURL stringByReplacingOccurrencesOfString:#"APP_ID" withString:[NSString stringWithFormat:#"%d", appId]];
// iOS 7 needs a different templateReviewURL #see https://github.com/arashpayan/appirater/issues/131
if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 7.0 && [[[UIDevice currentDevice] systemVersion] floatValue] < 7.1)
{
reviewURL = [templateReviewURLiOS7 stringByReplacingOccurrencesOfString:#"APP_ID" withString:[NSString stringWithFormat:#"%d", appId]];
}
// iOS 8 needs a different templateReviewURL also #see https://github.com/arashpayan/appirater/issues/182
else if ([[[UIDevice currentDevice] systemVersion] floatValue] >= 8.0)
{
reviewURL = [templateReviewURLiOS8 stringByReplacingOccurrencesOfString:#"APP_ID" withString:[NSString stringWithFormat:#"%d", appId]];
}
return reviewURL;
}
The review link has once again broken in iOS9. In doing some experimenting, I figured out that Apple reverted it back to how it was before iOS7. So you have to do:
itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=247423477&onlyLatestVersion=true&pageNumber=0&sortOrdering=1&type=Purple+Software
Where 247423477 is your 9 digit app ID (the main difference is you have to append &onlyLatestVersion=true&pageNumber=0&sortOrdering=1&type=Purple+Software after the app ID).
All the answers above have now been deprecated (iOS 7, but may work) thus, I provide the new way Apple recommends to provide links to the Apps.
The link for your App is the one from iTunes (use Copy Link), this one is recommended for use in code:
Swift 3.0
let path = URL(string: "https://itunes.apple.com/us/app/calcfast/id876781417?mt=8")
UIApplication.shared.open(path!)
Or better -- treat the optional correctly and handle the possibility of not being able to reach the link:
if let path = URL(string: "https://itunes.apple.com/us/app/calcfast/id876781417?mt=8") {
UIApplication.shared.open(path) {
(didOpen:Bool) in
if !didOpen {
print("Error opening:\(path.absoluteString)")
}
}
}
Objective-C
#define APP_URL_STRING #"https://itunes.apple.com/us/app/calcfast/id876781417?mt=8"
then you can call APP_URL_STRING in your code:
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: APP_URL_STRING] options:#{} completionHandler:nil];
Note, that this is the recommended way now by Apple, as the previous method of processing redirect links has been deprecated and are not supported.
The link for all your Apps, if you have more than one:
#define MYCOMPANY_URL_PATH #"http://appstore.com/mycompany"
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: MYCOMPANY_URL_PATH] options:#{} completionHandler:nil];
The App link above is recommended for use in code or links that are not seen directly by the user. If you want to provide link that may be seen and remembered by the user then use the following:
http://appstore.com/calcfast
Using this URL was the perfect solution for me. It takes the user directly to the Write a Review section. Credits to #Joseph Duffy.
For a sample code try this :
Swift 3, Xcode 8.2.1 :
let openAppStoreForRating = "itms-apps://itunes.apple.com/gb/app/id1136613532?action=write-review&mt=8"
if UIApplication.shared.canOpenURL(URL(string: openAppStoreForRating)!) {
UIApplication.shared.openURL(URL(string: openAppStoreForRating)!)
} else {
showAlert(title: "Cannot open AppStore",message: "Please select our app from the AppStore and write a review for us. Thanks!!")
}
Here showAlert is a custom function for an UIAlertController.
I have this to get the Product ID automatically and generate App Store Review and Product page links.
- (void) getAppStoreLinks {
productID = [[NSUserDefaults standardUserDefaults] objectForKey:#"productID"]; //NSNumber instance variable
appStoreReviewLink = [[NSUserDefaults standardUserDefaults] objectForKey:#"appStoreReviewLink"]; //NSString instance variable
appStoreLink = [[NSUserDefaults standardUserDefaults] objectForKey:#"appStoreLink"]; //NSString instance variable
if (!productID || !appStoreReviewLink || !appStoreLink) {
NSString *iTunesServiceURL = [NSString stringWithFormat:#"https://itunes.apple.com/lookup?bundleId=%#", [NSBundle mainBundle].bundleIdentifier];
NSURLSession *sharedSes = [NSURLSession sharedSession];
[[sharedSes dataTaskWithURL:[NSURL URLWithString:iTunesServiceURL]
completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
NSInteger statusCode = ((NSHTTPURLResponse *)response).statusCode;
if (data && statusCode == 200) {
id json = [[NSJSONSerialization JSONObjectWithData:data options:(NSJSONReadingOptions)0 error:nil][#"results"] lastObject];
//productID should be NSNumber but integerValue also work with NSString
productID = json[#"trackId"];
if (productID) {
appStoreReviewLink = [NSString stringWithFormat:#"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=%d&pageNumber=0&sortOrdering=2&type=Purple+Software&mt=8",productID.integerValue];
appStoreLink = [NSString stringWithFormat:#"itms-apps://itunes.apple.com/app/id%d",productID.integerValue];
[[NSUserDefaults standardUserDefaults] setObject:productID forKey:#"productID"];
[[NSUserDefaults standardUserDefaults] setObject:appStoreReviewLink forKey:#"appStoreReviewLink"];
[[NSUserDefaults standardUserDefaults] setObject:appStoreLink forKey:#"appStoreLink"];
}
} else if (statusCode >= 400) {
NSLog(#"Error:%#",error.description);
}
}
] resume];
}
}
Open app's Review Page
- (IBAction) rateButton: (id)sender {
NSString *appStoreReviewLink = appStoreReviewLink;
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:appStoreReviewLink]];
}
Open app's App Store page
- (IBAction) openAppPageButton: (id)sender {
NSString *appStoreLink = appStoreLink;
[[UIApplication sharedApplication] openURL:[NSURL URLWithString: appStoreLink]];
}
It is said that this bug will be fixed on iOS7.1. Read here on the corona forum, and here on the iPhoneDevSDK.
I am new in iOS. I want to use CAEmitterLayer, which is only support by iOS 5, but my app should support iOS 4 and above. I am using [UIDevice currentDevice].systemVersion
to check the version, but it crashes.
Here is the code:
#class CAEmitterLayer;
#interface FireView : UIView
#property (strong) CAEmitterLayer *fireEmitter;
#property (strong) CAEmitterLayer *smokeEmitter;
- (void) setFireAmount:(float)zeroToOne;
#end
// create the FireView if iOS>=5.0
if ([[UIDevice currentDevice].systemVersion doubleValue] >=5.0) {
FireView *fireView = [[[FireView alloc] initWithFrame:CGRectMake(0, 95, 100, 280)] autorelease];
[self.view addSubview:fireView];
}
The problem is it crash before I create the FireView.
error:dyld: Symbol not found: _OBJC_CLASS_$_CAEmitterCell
even I don't include the FireView.h file, still crashes.
Should I create both iOS4 and iOS5 version?
Can you give me some advice?
Please help. Thank you very much.
You can check to see if CAEmitterLayer class is available on current device's iOS version by:
if (NSClassFromString(#"CAEmitterLayer"))
{
// available
}
I'm running up against problems trying to incorporate some iOS5-specific libraries into an app targeted at both iOS5 and iOS4.3. I've gone through the following steps:
weakly-linked the Twitter framework by setting it as optional in 'Link Binary with Libraries"
added it as a framework for the iOS5.0 SDK in Other Linker Flags with `-framework Twitter.framework'
conditionally linked the framework in the class header:
#if defined(__IPHONE_5_0) && __IPHONE_OS_VERSION_MAX_ALLOWED >= __IPHONE_5_0
#import <Twitter/Twitter.h>
#import <Accounts/Accounts.h>
#endif
then in the method itself, I'm then checking whether the user's set up for Twitter:
if ([TWTweetComposeViewController class]) {
self.canTweet = [TWTweetComposeViewController canSendTweet];
}
This works beautifully on both the 5.0 and 4.3 simulators. However, I've got problems getting it to run on, or archive for, actual devices.
When I've got either a 3GS running 5.0, or a 4 running 5.0 attached, both show up twice in the Scheme dropdown. Selecting the top one, and attempting build or run the project fails with an Use of unidentified identifier 'TWTweetComposeViewController' error.
Using the second device entry, the build fails with a ld: framework not found Twitter.framework error.
I'm sure there's something I'm missing here, but I'm stumped. Can anyone advise?
If you are using a week linking then you have to check first availability of API using
NSClassFromString, respondsToSelector, instancesRespondToSelector etc.
So, change your if condition. First try to get your class object using above specified runtime function.
here is a link explaining in detail how to do such.
link
The code for presenting twitter controller
Before this you have to add the frameworks as optional and make the import in h file if iOS is min iOS 5
Class TWTweetComposeViewControllerClass = NSClassFromString(#"TWTweetComposeViewController");
if (TWTweetComposeViewControllerClass != nil) {
if([TWTweetComposeViewControllerClass respondsToSelector:#selector(canSendTweet)]) {
UIViewController *twitterViewController = [[TWTweetComposeViewControllerClass alloc] init];
[twitterViewController performSelector:#selector(setInitialText:)
withObject:NSLocalizedString(#"TwitterMessage", #"")];
[twitterViewController performSelector:#selector(addURL:)
withObject:url];
[twitterViewController performSelector:#selector(addImage:)
withObject:[UIImage imageNamed:#"yourImage.png"]];
[self.navigationController presentModalViewController:twitterViewController animated:YES];
[twitterViewController release];
}
}
Further digging into the error thrown back by the compiler suggested that it was ignoring the weak link flag. Although I've no idea how or why, it was fixed by a reinstallation of XCode.
if you link to 4.2 or later and deploy to 3.1 or later, you can use the new weak linking features to make this check simple.
you have to add Twitter frameworks as optional and then
Class TWTweetComposeViewControllerClass = NSClassFromString(#"TWTweetComposeViewController");
if (TWTweetComposeViewControllerClass != nil)
{
if([TWTweetComposeViewControllerClass respondsToSelector:#selector(canSendTweet)])
{
UIViewController *twitterViewController = [[TWTweetComposeViewControllerClass alloc] init];
[twitterViewController performSelector:#selector(setInitialText:)
withObject:NSLocalizedString(#"TwitterMessage", #"")];
[twitterViewController performSelector:#selector(addURL:)
withObject:url];
[twitterViewController performSelector:#selector(addImage:)
withObject:[UIImage imageNamed:#"yourImage.png"]];
[self.navigationController presentModalViewController:twitterViewController animated:YES];
[twitterViewController release];
}
}
I need to detect if the user is using an iPhone 4, but I need this to work on the simulator (cause Apple forgot my country and there's no sign of iPhone 4 here soon).
I found this
http://www.clintharris.net/2009/iphone-model-via-sysctlbyname/
but running this on the simulator it does not detect the correct version. I mean, Xcode 3.2.3 has two simulators (3G/3GS and 4). I was expecting the detection method to tell me the correct version I am using... but instead it tells me "iphone simulator"...
Is there any way to do that?
thanks.
You don't need to detect the system version in your case.
Suppose an image is named foo.png, then you just need to add
foo~ipad.png for iPad
foo#2x~iphone.png for iPhone 4
and load the image with [UIImage imageNamed:#"foo.png"]. See the iPhone Application Programming Guide for detail.
I think it would be better to check for the feature you require, rather than a specific device. This is certainly what Apple recommends, as it gives you insurance when new devices roll around!
In this case, would it work to check the size of the screen, and use that to determine if you need to scale your image?
[[UIScreen mainScreen] bounds]
Hardware Availability and State
If a hardware feature (for example,
a gyroscope) is not available on a
device, calling a start method related
to that feature has no effect. You can
find out whether a hardware feature is
available or active by checking the
appropriate property; for example, for
gyroscope data, you can check the
value of the gyroAvailable or
gyroActive properties.
Use
#property(readonly, nonatomic, getter=isGyroAvailable) BOOL gyroAvailable
of class CMMotionManager.
See
#property (nonatomic, readonly, retain) NSString *systemVersion;
// It equal to #"4.0" on iOS 4.0
and
#property (nonatomic, readonly, retain) NSString *model;
// Possible examples of model strings are #”iPhone” and #”iPod touch”
of class UIDevice.
From Erica Sudan:
- (NSString *) platform
{
size_t size;
sysctlbyname("hw.machine", NULL, &size, NULL, 0);
char *machine = malloc(size);
sysctlbyname("hw.machine", machine, &size, NULL, 0);
/*
Possible values:
"iPhone1,1" = iPhone 1G
"iPhone1,2" = iPhone 3G
"iPhone2,1" = iPhone 3GS
"iPhone3,1" = iPhone 4
"iPod1,1" = iPod touch 1G
"iPod2,1" = iPod touch 2G
*/
NSString *platform = [NSString stringWithCString:machine];
free(machine);
return platform;
}
Or, if you just need to detect if it's a high res screen, you can use:
UIScreen *screen = [UIScreen mainScreen];
BOOL isHighRes;
if ([screen respondsToSelector:#selector(scale)]) {
isHighRes = ([screen scale] > 1);
} else {
isHighRes = NO;
}
Mike, you can know if the user is using an iPhone 4 by using preprocessor instructions. For example:
#ifdef __IPHONE_4_0
// Do some work for iPhone 4 device
#else
// Do some work for non iPhone 4 device
#endif
I hope it can help you.