How to find IpAddress of a virtual machine programmatically from hypervisor? - powershell

Question

I am using HyperV WMI provider to to update virtual machine's configuration/settings (like hard ware, disks etc..)
How can I get IpAddress of a VM from HyperV?
How to do the same thing in VMWare?
Regards,
Dreamer!

Answer 1

This article describes how to get the IP address of a virtual
machine from Hyper-V (Windows 2008 R2 Hyper-V) using Powershell.
Using the PowerCli: (get-vm <name of your vm>).guest.ipaddress

Answer 2

For Hyper-V, this is how I usually pull an IP from a host box.
$vm = Get-WmiObject -computerName "." -NameSpace "Root\Virtualization" -query "SELECT * FROM Msvm_KvpExchangeComponent" #pulls VM WMI object ExchangeComponents
$vmitems = $vm.GuestIntrinsicExchangeItems
$ipitem = $vmitems[-4]#yay! a hack that relies on XML schemas!
$xmlip = [xml]$ipitem #convert string format to XML
$ipaddr = $xmlip.INSTANCE.PROPERTY[1].VALUE #playing with XML schemas again hopefully reliably
It's not the neatest/cleanest/nicest code, but it is a way to get that information.

Answer 3

Here's an alternate variation that I cooked up to demonstrate a more robust approach at finding the value for a given name. This doesn't rely on a specific relative ordering inside the schema of Caption, Data, Description, ElementName, Name or Source
$vmParams = #{
NameSpace = 'Root\Virtualization';
Query = 'SELECT * FROM Msvm_KvpExchangeComponent' #pulls VM WMI object ExchangeComponents
}
Get-WmiObject #vmParams |
% {
$xml = [Xml]"<properties>$($_.GuestIntrinsicExchangeItems)</properties>"
$xml.properties.INSTANCE.Property |
% {
$value = ($_.ParentNode.Property | ? { $_.Name -eq 'Data' }).VALUE
if ($_.Value -eq 'FullyQualifiedDomainName')
{
Write-Host "Host: $($value)"
}
if ($_.Value -eq 'RDPAddressIPv4')
{
Write-Host "RDP Address: $($value)"
}
}
}