It works, but can it be simplified?
timeaccess is updated with php time() - which is a unix timestamp.
select to_date(to_char(to_timestamp(timeaccess),'YYYY-MM-DD'),'YYYY-MM-DD'),
from user_login;
Simpler:
SELECT to_timestamp(timeaccess)::date
FROM user_login
You can cast the resulting timestamp to date, :: being the casting operator.
Related
I have create a datetime with type timestamp. datetime timestamp NOT NULL I am not sure why the output is like this:
I want to extract the day part. I have tried these different approach but in both cases I am getting an error. How can I fix it?
extract(DAY FROM TIMESTAMP min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI'))::timestamp)
EXTRACT(DAY FROM TIMESTAMP min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI')))
date_part('day', min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI')))
As mentioned in response I modified query to be like below and it does work.
extract(day from MIN(datetime)) as Day
All you need is:
select *, extract(day from activated_at) as Day from yourTable;
What you are seeing is a timestamp formatted as text for the display. Underlying data is timestamp as you said, directly use it.
I wanted to get the only the hour of the time and concatenate it with the date.
here's my query
SELECT distinct TOTALIZER_METER_READINGS.date + to_char(TOTALIZER_METER_READINGS.time ,'HH')
FROM TOTALIZER_METER_READINGS
is there any other way to get the hour of the time without turning it into text?
+ is the operator to add numbers, dates or intervals.
The string concatenation operator in SQL is ||.
As you are storing date and time in two columns rather then using a single timestamp column, I would convert them to a single timestamp value, then apply to_char() on the "complete" timestamp:
Adding a time to a date returns a timestamp that can then be formatted as you want:
SELECT distinct to_char(TOTALIZER_METER_READINGS.date + TOTALIZER_METER_READINGS.time, 'yyyy-mm-dd HH')
FROM TOTALIZER_METER_READINGS
You can use EXTRACT (or the date_part function):
SELECT EXTRACT(hour FROM current_timestamp);
The result type is double precision.
I need to convert the value stored in a bigint column to a date field. The first step of the conversion involves converting it to timestamp, and subsequently use the TRUNC method to convert this column to a date value.
However, my query is failing while converting the bigint value to timestamp.
The error that I'm getting is:-
Amazon Invalid operation: cannot cast type bigint to timestamp without time zone;
The query I'm trying for now is something like this:-
select ts::timestamp from events limit 1;
I was able to avoid the time zone error by using the method described in this thread: https://stackoverflow.com/a/36399361
My dates are based on epochs, and I was able to do the following:
SELECT
(TIMESTAMP 'epoch' + contract_start_date * INTERVAL '1 Second ')
FROM
table_name
SELECT TIMESTAMP 'epoch' + {column of bigint}/1000 * INTERVAL '1 second' as adate FROM tbl
If you are starting with a POSIX timestamp, and trying to get a timezone aware datetime value, you will need to supply a timezone - even if you later want to truncate the time part away. I'm not familiar with redshift, but perhaps there is a way to specify you mean UTC.
I want to convert a Date column to a formatted string in DB2. This SQL works fine:
select varchar_format(current timestamp, 'YYYY-MM')
from sysibm.sysdummy1;
but this SQL gives an error:
select varchar_format(current date, 'YYYY-MM')
from sysibm.sysdummy1;
The error is:
[SQL0171] Argument 1 of function VARCHAR_FORMAT not valid.
In the first SQL, the first arg for VARCHAR_FORMAT is a timestamp, and that works. In the second SQL, the first arg for VARCHAR_FORMAT is a date, and that doesn't work.
The IBM doc implies that there's only this one function, VARCHAR_FORMAT (and its synonym, TO_CHAR).
How am I supposed to convert a DATE (not a TIMESTAMP) to a string? Or, do I have to convert the DATE to a TIMESTAMP first, then use VARCHAR_FORMAT?
I am running DB2 7.1 for i Series.
Update: converting to TIMESTAMP_ISO works. But it's ugly:
select varchar_format(timestamp_iso(current date), 'YYYY-MM')
from sysibm.sysdummy1;
That one works.
The documentation for the VARCHAR_FORMAT function in DB2 for i only mentions TIMESTAMP values, not DATE. Some DB2 platforms will implicitly cast a DATE value to a TIMESTAMP when the statement is calling a TIMESTAMP-only function or when comparing the DATE to a TIMESTAMP, but not all do.
Below is my query in postgres
select dns_time,update_time from dns_lookup where update_time=current_date;
Here update_time is of type timestamp with time zone.
I have tried this one also.
select dns_time,update_time from dns_lookup where update_time like current_date;
Then also getting no results.
I have records with current_date values.But it is not showing me any records.How to compare timestamp with time zone value with current_date.please help me
Thank you.
First: LIKE on a date or timestamp column does not make any sense.
A timestamp contains a time part so a comparison with a plain date won't work. You need to remove the time from the timestamp by casting it to a date:
where cast(update_time as date) = current_date;
Note that this will void the usage of an index on update_time. If that is a problem you can create a function based index on that expression.
You might be trying to compare a timestamp field with the Date field.
Try casting timestamp to Date
select dns_time,update_time from dns_lookup where update_time::Date=current_date;
Hope this helps.