Is there a command or one-line strategy in MATLAB that will return all the combinations of the components of n cell arrays, taken n at a time?
An example of what I want to accomplish:
A = {'a1','a2'};
B = {'b1','b2','b3'};
C = combinations(A,B)
C = {'a1','b1' ;
'a1','b2' ;
'a1','b3' ;
'a2','b1' ;
'a2','b2' ;
... }
The command would be able to accept an arbitrary number of arguments and the result in the example would have as many columns as there are arguments to the function. (Of course, the syntax above is just meant for illustration and any method that would generate the results whatever the format would fit the bill)
EDIT: Similar questions have been asked for matrices instead of cells, e.g. link. Many solutions point to the FEX submission allcomb, but all such solutions are just wrappers around ndgrid, which only work with doubles. Any suggestions for non numeric sets?
Although I address this in my answer to a related/near duplicate question, I'm posting a different version of my solution here since it appears you want a generalized solution, and my other answer is specific for the case of three input sets. Here's a function that should do what you want for any number of cell array inputs:
function combMat = allcombs(varargin)
sizeVec = cellfun('prodofsize', varargin);
indices = fliplr(arrayfun(#(n) {1:n}, sizeVec));
[indices{:}] = ndgrid(indices{:});
combMat = cellfun(#(c,i) {reshape(c(i(:)), [], 1)}, ...
varargin, fliplr(indices));
combMat = [combMat{:}];
end
And here's how you would call it:
>> combMat = allcombs(A, B)
combMat =
'a1' 'b1'
'a1' 'b2'
'a1' 'b3'
'a2' 'b1'
'a2' 'b2'
'a2' 'b3'
A 2-line strategy:
A = {'a1','a2'};
B = {'b1','b2','b3'};
[a b]=ndgrid(1:numel(A),1:numel(B));
C= [A(a(:))' B(b(:))']
C =
'a1' 'b1'
'a2' 'b1'
'a1' 'b2'
'a2' 'b2'
'a1' 'b3'
'a2' 'b3'
Related
I have the following cell array:
>> tmp0 = {'foo', '%s', 'one'; 'bar', '%d', 3}
tmp0 =
2×3 cell array
'foo' '%s' 'one'
'bar' '%d' [ 3]
I can use it like this with sprintf:
>> sprintf('%s,%d', tmp0{:,3})
ans =
'one,3'
I would like to be able to achieve the same thing with a function call, since if I have a function that generates a cell array, say genCell(), I don't think I can achieve something like genCell(){:} in MATLAB.
So I made this function:
function cellExp(cellIn)
cellIn{:}
end
Although dubious it seems to work as expected so far, since calling cellExp(tmp0(:,3)) seems to be the same as calling tmp0{:,3}
>> cellExp(tmp0(:,3))
ans =
'one'
ans =
3
>> tmp0{:,3}
ans =
'one'
ans =
3
However, ultimately, I cannot use it as desired:
>> sprintf('%s,%d', cellExp(tmp(:,3)))
Error using cellExp
Too many output arguments.
The last error message you are getting is because the output of cellExp(tmp0(:,3)) is comma-separeted list.
I am not sure exactly what you are looking for here, but I think this is one possibility for a function that will return your string based on a myCell = tmp0.
function myStr = mySprintf(myCell)
formatSpec = strjoin(myCell(:,2), ',');
[A1, A2] = myCell{:, 3};
myStr = sprintf(formatSpec, A1, A2);
end
I need to generate all possible subset from a character array in MATLAB with reduced execution time.
For example:
input='ABCA';
output ='A',
'B',
'C',
'AB',
'BC',
'CA',
'ABC',
'BCA',
'ABCA'
You can find all these subsets using straight-forward loops. I don't know if it is worth-while vectorizing these, as any vectorization will require large intermediate arrays.
With a random input of 500 characters, and maxLen at 20, I got 4207817 unique substrings. It took my computer (with MATLAB R2017a) 12 seconds to find these. Whether that is fast enough or not is up to you, but I would not bother further optimizing this.
input = 'ABCA';
maxLen = 4;
subsets = {};
for len = 1:maxLen
subs = cell(1,numel(input)-len+1);
for start = 1:numel(subs)
subs{start} = input(start:start+len-1);
end
subs = unique(subs);
subsets = [subsets,subs];
end
disp(subsets)
Output:
'A' 'B' 'C' 'AB' 'BC' 'CA' 'ABC' 'BCA' 'ABCA'
If it is important to preserve the order of the substrings, then add the 'stable' argument to the unique call:
subs = unique(subs,'stable');
For example, for input = 'AFCB';, the output without 'stable' is:
'A' 'B' 'C' 'F' 'AF' 'CB' 'FC' 'AFC' 'FCB' 'AFCB'
and with 'stable' it is:
'A' 'F' 'C' 'B' 'AF' 'FC' 'CB' 'AFC' 'FCB' 'AFCB'
I am a novice programmer that is primarily self-taught. I am new to MATLAB and relational mathematics. Currently, I am attempting to perform math operations between rows. I would like to normalize the exp by the corresponding con and then multiply by the constant.
This constant is a laboratory measurement that could be subject to change in future experments. Thus, I have given it a column.
Below is some sample code that I have generated to exemplify my problem and solution. I am trying to get from myTable to rTable.
I recognize my solution is very sloppy and there must be a way to perform these operations that is human-readable and uses less temporary variables. To put it shortly, there must be a simpler way.
rTable = table();
myTable = table(transpose(1:8), ...
transpose({'Con1', 'Con2', 'Exp1', 'Exp2',...
'Con1', 'Con2', 'Exp1', 'Exp2'}),...
transpose({'A', 'A', 'A', 'A', 'B', 'B', 'B', 'B'}),...
ones(8, 1) * 2,...
'VariableNames', {'Values' , 'Condition', 'Group', 'Constant'});
[r, c] = size(myTable)
a = myTable(strcmp(myTable.Group, 'A'), :);
b = myTable(strcmp(myTable.Group, 'B'), :);
aexp1 = a.Values(strcmp(a.Condition, 'Exp1'), :) / a.Values(strcmp(a.Condition, 'Con1'), :) * mean(a.Constant);
aexp2 = a.Values(strcmp(a.Condition, 'Exp2'), :) / a.Values(strcmp(a.Condition, 'Con2'), :) * mean(a.Constant);
bexp1 = b.Values(strcmp(b.Condition, 'Exp1'), :) / b.Values(strcmp(b.Condition, 'Con1'), :) * mean(b.Constant);
bexp2 = b.Values(strcmp(b.Condition, 'Exp2'), :) / b.Values(strcmp(b.Condition, 'Con2'), :) * mean(b.Constant);
aT = table(transpose({aexp1, aexp2}),...
transpose({'Exp1', 'Exp2'}),...
transpose({'A', 'A'}),...
transpose({2, 2,}),...
'VariableNames', {'Values', 'Condition', 'Group', 'Constant'});
bT = table(transpose({bexp1, bexp2}),...
transpose({'Exp1', 'Exp2'}),...
transpose({'B', 'B'}),...
transpose({2, 2,}),...
'VariableNames', {'Values', 'Condition', 'Group', 'Constant'});
rTable = [aT; bT]
Thank you for any input or suggestions. Perhaps, the data structure i am handling is poorly organized.
Here's one solution:
rTable = table();
myTable = table((1:8)',{'Con1', 'Con2', 'Exp1', 'Exp2','Con1', 'Con2', 'Exp1', 'Exp2'}',...
{'A', 'A', 'A', 'A', 'B', 'B', 'B', 'B'}','VariableNames', {'Values' , 'Condition', 'Group', 'Constant'})
conditionrows = contains(myTable.Condition,'Con')
exprows = contains(myTable.Condition,'Exp')
conditionTable = myTable(conditionrows,:)
expTable = myTable(exprows,:)
constant = 2
rValues = expTable.Values./conditionTable.Values * constant
rTable = expTable
rTable.Values = rValues
Since you are trying to get a table of only exprows, you separate your original table into a conditionTable and an expTable. I'm assuming you have one condition row for each exp row, and also that you have a good correspondence in the tables (if not it will require more processing), then you can calculate the rValue simply with a one line expression. The ./ is element-wise division. Also note that you can use ' to perform transpose in matlab (further note that if you want a column vector of 1:10 for example you have to do (1:10)', 1:10' gives you a row vector from 1 to 10 since 1:10' is interpreted as vector from 1 to the transpose of 10.
I have in Matlab the following cells containing various combinations of the letters a,b,c,d
%all combinations containing 'a' and/or 'b'
G1={'a', 'ab', 'ac', 'ad', 'abc', 'acd', 'abd', 'abcd', 'b', 'bc', 'bd', 'bcd'};
%all combinations containing 'c' and/or 'd'
G2={'c', 'ac', 'bc', 'cd', 'abc', 'acd', 'bcd', 'abcd', 'd', 'ad', 'bd', 'abd'};
%all combinations containing 'c'
G3={'c', 'ac', 'bc', 'cd', 'acd', 'abd', 'bcd', 'abcd'};
I then construct a cell all of dimension
allsize=size(G1,2)*size(G2,2)*size(G3,2);
containing all possible ways to match one element of G1 with one element of G2 with one element of G3.
all=cell(allsize,3);
count=0;
for h=1:size(G1,2)
for k=1:size(G2,2);
for j=1:size(G3,2);
count=count+1;
all(count,1)=G1(h);
all(count,2)=G2(k);
all(count,3)=G3(j);
end
end
end
Question: I want to construct a vector check of dimension allsize x 1 such that check(l)=1 if [all(l,1) contains a and all(l,2) contains c] or [all(l,1) contains b and all(l,2) contains d], and zero otherwise.
I am having problems in writing the if condition
check=zeros(allsize,1);
for l=1:allsize
%if [all(l,1) contains a and all(l,2) contains c] or [all(l,1) contains b and all(l,2) contains d]
check(l)=1;
%end
end
Could you kindly provide some help?
(For the if statement, always best to show what you tried rather than some pseudo code , however...)
Firstly using all as a variable name is bad - it's an important built-in function and one you may want to use... I've renamed it allG below. But you probably want something like this:
check(l) = (any(allG{l,1}=='a') && any(allG{l,2}=='c')) || ...
(any(allG{l,1}=='b') && any(allG{l,2}=='d'))
Note I haven't used an if statement, since the right hand side evaluates to a logical value (a true/false value) which can be generally used in the same way as 1 and 0...
Also above we're treating the strings as arrays of characters, so something like 'abcd'=='b' returns a [0 1 0 0] logical array... We then use any() to see if any of the values are 1 (true).
fullSeq='ABCDEFG'
Inputcell= {'ABC', 'BDEG','DEFG','ABCDEFG','CDEG','BCDF','ABCDEFG'}
I have 2 'ABCDEFG' strings in the above Inputcell. How can I remove those 2 strings? The expected output should be:
Outputcell= {'ABC', 'BDEG','DEFG','CDEG','BCDF'}
You can use logical indexing along with strcmp:
OutputCell = Inputcell(~strcmp(Inputcell,fullSeq))
OutputCell =
'ABC' 'BDEG' 'DEFG' 'CDEG' 'BCDF'
yay!
Simple call to ismember will do the trick combined with logical indexing:
fullSeq='ABCDEFG';
Inputcell= {'ABC', 'BDEG','DEFG','ABCDEFG','CDEG','BCDF','ABCDEFG'};
Outputcell = Inputcell(~ismember(Inputcell, fullSeq));
We get:
>> Outputcell
Outputcell =
'ABC' 'BDEG' 'DEFG' 'CDEG' 'BCDF'
If for some reason you want to automatically delete every element which appears at least twice (rather than having to run the above answers with various values of fullSeq), you can do that too:
iif = #(varargin) varargin{2*find([varargin{1:2:end}], 1, 'first')}(); %define inline 'if'
Inputcell={'ABC', 'BDEG','DEFG','ABCDEFG','CDEG','BCDF','ABCDEFG'};
Tempcell=cellfun(#(x)iif(sum(strcmp(x,Inputcell))>1,[],true,x),Inputcell,...
'uniformoutput',false);
Outputcell=Tempcell(~cellfun('isempty',Tempcell))
Result:
Outputcell =
'ABC' 'BDEG' 'DEFG' 'CDEG' 'BCDF'