I'm trying to get ordinance by the current date from a table. this query does what I want but it seems overkill:
WITH dates
AS (SELECT Month,
FQ,
FY,
MonthDisplay,
CAST (datepart(yyyy, [Month]) AS VARCHAR) + '-' + RIGHT(CAST ((datepart(MM, [Month]) + 100) AS VARCHAR), 2) AS YM,
fh,
LEFT(CONVERT (VARCHAR, [Month], 100), 3) + ' ' + RIGHT(fy, 4) AS MY,
LEFT(CONVERT (VARCHAR, [Month], 100), 3) AS ShortMonthName
FROM Pipeline.DimTime AS dt),
datesafter
AS (SELECT dt.FH,
dt.FQ,
dt.FY,
dt.MY,
dt.Month,
dt.MonthDisplay,
dt.ShortMonthName,
dt.YM,
ROW_NUMBER() OVER ( ORDER BY [Month]) AS RowNum
FROM dates AS dt
WHERE dt.[Month] >= (SELECT TOP 1 DATEADD(MONTH, DATEDIFF(MONTH, 0, ds.SnapshotDate), 0)
FROM dbo.vw_DimSnapshot AS ds
WHERE ds.SnapshotWeek = 'Current')),
datesbefore
AS (SELECT dt.FH,
dt.FQ,
dt.FY,
dt.MY,
dt.Month,
dt.MonthDisplay,
dt.ShortMonthName,
dt.YM,
(ROW_NUMBER() OVER ( ORDER BY [Month] DESC)) * -1 AS RowNum
FROM dates AS dt
WHERE dt.[Month] < (SELECT TOP 1 DATEADD(MONTH, DATEDIFF(MONTH, 0, ds.SnapshotDate), 0)
FROM dbo.vw_DimSnapshot AS ds
WHERE ds.SnapshotWeek = 'Current'))
SELECT *
FROM datesafter
UNION ALL
SELECT *
FROM datesbefore
ORDER BY [month];
I think you can do it in a single query by using datediff. Pass current date as one parameter and the table date as another. This will work if you are ok with skipping missing dates. For example if current date is Nov 21, then Nov 20 will show up as -1 and Nov 18 will show up as -3 even if Nov 19 is missing in the data. I am not sure what your business requirement is, so cannot comment beyond that.
And by the way if you are looking for ordinance based on months instead of day, you can use still use datediff but use the correct datepart (See: http://msdn.microsoft.com/en-us/library/ms189794.aspx).
HTH.
-Tabrez
Related
How do I find the first, second, third and fourth saturday of the month?
Ex.: I want to end up with this format...
Blockquote
YYYY, MM, Week#1
Blockquote
YYYY, MM, Week#2
Blockquote
Thanks,
This solution does not depend on Datefirst setting.
declare #d datetime = getdate();
select
dateadd(dd, n, firstSaturday)
from (
select
firstSaturday = dateadd(day, 7-(##datefirst+datepart(weekday, dateadd(day,-1, convert(char(6),#d,112)+'01')))%7, dateadd(day,-1, convert(char(6),#d,112)+'01'))
) t
cross apply (values (0), (7), (14), (21)) q(n)
Here is one way to do it, using a stacked cte to create an inline tally table, with another cte on top of that to generate the months calendar.
Please note that you can change the GETDATE() in the first row code to any date you want (even if it's in the middle of the month) and the code will produce all the Saturdays in that month.
-- Get the current month's start date
DECLARE #MonthStart datetime = DATEADD(MONTH, (DATEDIFF(MONTH, 0, GETDATE())), 0)
;WITH lv0 AS (SELECT 0 g UNION ALL SELECT 0)
,lv1 AS (SELECT 0 g FROM lv0 a CROSS JOIN lv0 b) -- 4
,lv2 AS (SELECT 0 g FROM lv1 a CROSS JOIN lv1 b) -- 16
,lv3 AS (SELECT 0 g FROM lv2 a CROSS JOIN lv2 b) -- 256
,Tally (n) AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM lv3)
-- gets all the dates in the current month
,CurrentMonth AS (SELECT TOP (32) dateadd(day, n-1, #MonthStart) As TheDate
FROM Tally
WHERE MONTH(dateadd(day, n-1, #MonthStart)) = MONTH(#MonthStart)
ORDER BY n)
-- gets all the Saturday dates of the current month
SELECT TheDate, DATENAME(WEEKDAY, TheDate)
FROM CurrentMonth
WHERE DATEPART(WEEKDAY, TheDate) = 7 -- Depending on server settings!
If you already have a numbers table, you can use it instead of the stacked cte. If you don't know what is a numbers table and why you should have one, read The "Numbers" or "Tally" Table: What it is and how it replaces a loop by Jeff Moden
You can try this.
SET DATEFIRST 1
DECLARE #MonthId INT = 5
DECLARE #FirstDayOfTheMonth DATE = CONCAT(YEAR(GETDATE()), RIGHT(CONCAT('00', #MonthId),2), '01')
DECLARE #SaturdayId INT = 6
SELECT
DATEADD(DAY, #SaturdayId + WK.ID - DATEPART(WEEKDAY, #FirstDayOfTheMonth), #FirstDayOfTheMonth)
FROM ( VALUES(0),(7),(14),(21),(28)) AS WK(ID)
WHERE
MONTH(DATEADD(DAY, #SaturdayId + WK.ID- DATEPART(WEEKDAY, #FirstDayOfTheMonth),#FirstDayOfTheMonth)) = #MonthId
I have 2 same queries (to return "MonthName Year" and count) as below, but only the date range in the WHERE condition is different. Query 1 gets only the June month count, while Query 2 gets count from Apr to Jul, where the Jun month count (in Query 2) is not same as June month count from Query 1. Please advise.
Query 1:
SELECT DATENAME(MONTH, SubmissionDate) + ' ' + DateName(Year, SubmissionDate) AS MonthNumber, COUNT(1) AS InquiryCount
, Cast(Datename(MONTH,SubmissionDate) + ' ' + Datename(YEAR,SubmissionDate) AS DATETIME) AS tmp
FROM [dbo].[InvestigationDetails] (nolock)
WHERE SubmissionDate>= '06/01/2016'
AND SubmissionDate <= '06/30/2016'
GROUP BY DATENAME(MONTH, SubmissionDate) + ' ' + DateName(Year, SubmissionDate), DateName(Year, SubmissionDate)
ORDER BY tmp ASC
Query 2:
SELECT DATENAME(MONTH, SubmissionDate) + ' ' + DateName(Year, SubmissionDate) AS MonthNumber, DateName(Year, SubmissionDate), COUNT(1) AS InquiryCount
, Cast(Datename(MONTH,SubmissionDate) + ' ' + Datename(YEAR,SubmissionDate) AS DATETIME) AS tmp
FROM [dbo].[InvestigationDetails] (nolock)
WHERE SubmissionDate>= '04/01/2016'
AND SubmissionDate <= '07/31/2016'
GROUP BY DATENAME(MONTH, SubmissionDate) + ' ' + DateName(Year, SubmissionDate), DateName(Year, SubmissionDate)
ORDER BY tmp ASC
Thanks,
Jay
SubmissionDate must be of type DATETIMEand thus, you are missing all values for your last day, 06/30/2016, since this equates to 06/30/2016 00:00:00. This means any records that have SubmissionDate with a time > 00:00:00 on 6/30/2016 will be excluded. For example, 6/30/2016 12:44:22 wouldn't be included in your results with your current logic.
Use one of these instead:
AND SubmissionDate < '07/01/2016'
AND SubmissionDate <= '06/30/2016 23:59:59.999'
The first method is preferred since you will get all records before 7/1/2016, which includes 6/30/2016 23:59:59.999. Of course, you should be aware of how precise DATETIME can be in SQL Server. Run the code below to see what I mean.
declare #dt datetime2 = getdate()
select #dt --more precise with datetime2
select getdate() --not as precise
I'm trying to query data within a range of start year and month and end year and month. But SQL returnes onty the year and the month chosen. Can anyone identify the problem with my approach.
Thanks!
ALTER PROCEDURE xxx
(#JaarBegin AS int
, #JaarEind AS int
, #MaandBegin AS int
, #MaandEind AS int)
AS
BEGIN
WITH
CTE AS
(
SELECT [D_Medewerker_ID]
,[Gebruikersnaam]
,[Naam]
,[Afdelingscode]
,CONVERT(date, [Datum_uit_dienst]) AS DatumIn
,CONVERT(date, [Datum_in_dienst]) AS DatumUit
FROM [DM].[dm].[D_Medewerker] AS M
),
CTE2 AS(
SELECT F.[D_Functie_ID]
,[Generieke_Functie]
,[Specifieke_Functie]
,Fo.[D_Medewerker_ID]
FROM [DM].[dm].[D_Functie] AS F
JOIN dm.dm.F_FormatieBezetting AS Fo
ON F.D_Functie_ID = Fo.D_Functie_ID
)
SELECT DISTINCT CTE.[Gebruikersnaam]
, CTE.Naam
, CTE.Afdelingscode
, CTE.DatumIn
, CTE.DatumUit
, CTE2.Generieke_Functie
, CTE2.Specifieke_Functie
FROM CTE
JOIN CTE2
ON CTE.D_Medewerker_ID = CTE2.D_Medewerker_ID
WHERE DATEPART(year,CTE.DatumUit) BETWEEN #JaarBegin AND #JaarEind
AND DATEPART(MONTH, CTE.DatumUit) >= #MaandBegin AND DATEPART(MONTH, CTE.DatumUit) <= #MaandEind
ORDER BY CTE.DatumUit DESC;
END
You need to convert the int values you get to a date value.
In Sql server 2012 or later, you can use the built-in function DATEFROMPARTS to do this:
WHERE CTE.DatumUit >= DATEFROMPARTS ( #JaarBegin , #MaandBegin , 1 )
AND CTE.DatumUit < DATEADD(MONTH, 1, DATEFROMPARTS ( #JaarEind , #MaandBegin , 1 ))
If you are working with an earlier version of sql server, you need to build a string that represents the date (using iso format yyyy-mm-dd) and then cast it to date:
WHERE CTE.DatumUit >= CAST(RIGHT('0000' + CAST(#JaarBegin as varchar(4)), 4) + '-' + RIGHT('00' + CAST(#MaandBegin as varchar(2)), 2) +'-01' as datetime)
AND CTE.DatumUit < DATEADD(MONTH, 1, CAST(RIGHT('0000' +CAST(#JaarEind as varchar(4)), 4) + '-' + RIGHT('00' + CAST(#MaandBegin as varchar(2)), 2) +'-01' as datetime))
I have a query which displays a set of 52 numbers along with the respective dates of that week
SELECT kkk, TO_CHAR (start_date, 'DD-MON-YYYY'),
TO_CHAR (start_date + 6, 'DD-MON-YYYY') AS end_day
FROM (SELECT TRUNC (TRUNC (TO_DATE ('2014', 'YYYY'), 'YYYY') + 1 * 7,
'IW'
)
- 1 start_date,
ROWNUM AS kkk
FROM DUAL
CONNECT BY ROWNUM <= 52);
but the problem with this query is that I am only getting the first week dates but not for the next consecutive weeks.Please help
Try like this,
SELECT kkk,
TO_CHAR(start_date, 'DD-MON-YYYY') start_date,
TO_CHAR(start_date + 6, 'DD-MON-YYYY') end_day
FROM(
SELECT TRUNC(Trunc(to_date('2014', 'YYYY'),'YYYY')+ LEVEL * 7,'IW')-1 start_date ,
ROWNUM kkk
FROM duaL
CONNECT BY LEVEL <= 52
);
Instead of ROWNUM you can also use LEVEL, Like,
SELECT TRUNC(Trunc(to_date('2014', 'YYYY'),'YYYY')+ LEVEL * 7,'IW')-1 start_date ,
level kkk
FROM duaL
CONNECT BY LEVEL <= 52
I'm currently trying to get the first and last day of any year. I have data from 1950 and I want to get the first day of the year in the dataset to the last day of the year in the dataset (note that the last day of the year might not be December 31rst and same with the first day of the year).
Initially I thought I could use a CTE and call DATEPART with the day of the year selection, but this wouldn't partition appropriately. I also tried a CTE self-join, but since the last day or first day of the year might be different, this also yields inaccurate results.
For instance, using the below actually generates some MINs in the MAX and vice versa, though in theory it should only grab the MAX date for the year and the MIN date for the year:
;WITH CT AS(
SELECT Points
, Date
, DATEPART(DY,Date) DA
FROM Table
WHERE DATEPART(DY,Date) BETWEEN 363 AND 366
OR DATEPART(DY,Date) BETWEEN 1 AND 3
)
SELECT MIN(c.Date) MinYear
, MAX(c.Date) MaxYear
FROM CT c
GROUP BY YEAR(c.Date)
You want something like this for the first day of the year:
dateadd(year, datediff(year,0, c.Date), 0)
and this for the last day of the year:
--first day of next year -1
dateadd(day, -1, dateadd(year, datediff(year,0, c.Date) + 1, 0)
try this
for getting first day ,last day of the year && firstofthe next_year
SELECT
DATEADD(yy, DATEDIFF(yy,0,getdate()), 0) AS Start_Of_Year,
dateadd(yy, datediff(yy,-1, getdate()), -1) AS Last_Day_Of_Year,
DATEADD(yy, DATEDIFF(yy,0,getdate()) + 1, 0) AS FirstOf_the_NextYear
so putting this in your query
;WITH CT AS(
SELECT Points
, Date
, DATEPART(DY,Date) DA
FROM Table
WHERE DATEPART(DY,Date) BETWEEN
DATEPART(day,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)) AND
DATEPART(day,dateadd(yy, datediff(yy,-1, getdate()), -1))
)
SELECT MIN(c.Date) MinYear
, MAX(c.Date) MaxYear
FROM CT c
GROUP BY YEAR(c.Date)
I should refrain from developing in the evenings because I solved it, and it's actually quite simple:
SELECT MIN(Date)
, MAX(Date)
FROM Table
GROUP BY YEAR(Date)
I can put these values into a CTE and then JOIN on the dates and get what I need:
;WITH CT AS(
SELECT MIN(Date) Mi
, MAX(Date) Ma
FROM Table
GROUP BY YEAR(Date)
)
SELECT c.Mi
, m.Points
, c.Ma
, f.Points
FROM CT c
INNER JOIN Table m ON c.Mi = m.Date
INNER JOIN Table f ON c.Ma = f.Date