I want to use the SaxParser to parse a string that contains XML code I got using the HTTPUtils.
Can you tell me how to convert the string I got from the HTTPUtils into an InputStream?
I tried to do this but it won't let me compile it:
Sub JobDone (Job As String)
Dim strStringFromWebSite As String
Dim in As InputStream
If HttpUtils.IsSuccess(strUrlToCall) Then
strStringFromWebSite = HttpUtils.GetInputStream(strUrlToCall)
in = strStringFromWebSite
XmlParser.Parse(in, "Parser")
in.Close
Else
ToastMessageShow("There was a problem getting a response from the web site.", False)
End If
End Sub
I get the error on this line of code:
in = strStringFromWebSite
Thanks.
HttpUtils.GetInputStream returns an InputStream (as it's name indicates). Why are you trying to convert it to a string and then back to an InputStream? It seems to me you can go direct and cut out the middleman. :)
in = HttpUtils.GetInputStream(strUrlToCall)
XMLParser.Parse(in, "Parser")
Related
So this is my code
_image1 = File(pickedImage.path);
List<int> imageBytes = _image1.readAsBytesSync();
String base64Image = base64.encode(imageBytes);
_shcpImg = base64Image;
But when I print the string _shcpImg, it just prints a part of the string, because when I copy and paste that base64 into an online converter, it only shows a really tiny piece of the image. So the thing is that the string is not showing completely or somehow the base64 encoder is not working well.
Any suggestions?
From the comments, since you are using VsCode and you can't print the full string (long string)
You can use log from dart: developer,
if the string is REALLY LONG, There is a workaround to fix this, the idea is to divide your long string into small pieces (in the example, 800 length for each piece) using RegExp and then iterate into the result and print each piece.
void printWrapped(String text) {
final pattern = new RegExp('.{1,800}'); // 800 is the size of each chunk
pattern.allMatches(text).forEach((match) => print(match.group(0)));
}
Using Scala, I am grabbing a json response object from a web API and storing the response as a string s. This string is at least several kilobytes. Because sometimes this response can provide some funky stuff hinting at errors or issues with the API I want to print out a preview of the response to our logs. That way I can see the log and tell that the job is either running successfully or has failed. Is there an efficient and safe way to grab the first 100 or so characters from a string? The string may occasionally be very small so grabbing via a slice I think will cause an index out of range issue.
val n = 100
val myString: String = getResponseAsString()//returns small or very large string
logger.warn(s"Data: $myString") //how to print only first 'n' chars?
"long string".take(4) // "long"
"x".take(4) // "x"
take
val n :Int = ...
val myString :String = ...
logger.warn(s"Data: %.${n}s" format myString)
I have this string: "C:\Procesos\rrhh\CorteDocumentos\Cortados\10001662-1_20060301_29_1_20190301.pdf" and im trying to get this part : "20190301". The problem is the lenght is not always the same. It would be:
"9001662-1_20060301_4_1_20190301".
I've tried this: item.ToString.Substring(66,8), but it doesn't work sometimes.
What can I do?.
This is a code example of what I said in my comment.
Sub Main()
Dim strFileName As String = ""
Dim di As New DirectoryInfo("C:\Users\Maniac\Desktop\test")
Dim aryFi As FileInfo() = di.GetFiles("*.pdf")
Dim fi As FileInfo
For Each fi In aryFi
Dim arrname() As String
arrname = Split(Path.GetFileNameWithoutExtension(fi.Name), "_")
strFileName = arrname(arrname.Count - 1)
Console.WriteLine(strFileName)
Next
End Sub
You could achieve this using a simple regular expressions, which has the added benefit of including pattern validation.
If you need to get exactly eight numbers from the end of file name (and after an underscore), you can use this pattern:
_(\d{8})\.pdf
And then this VB.NET line:
Regex.Match(fileName, "_(\d{8})\.pdf").Groups(1).Value
It's important to mention that Regex is by default case sensitive, so to prevent from being in a situations where "pdf" is matched and "PDF" is not, the patter can be adjusted like this:
(?i)_(\d{8})\.pdf
You can than use it directly in any expression window:
PS: You should also ensure that System.Text.RegularExpressions reference is in the Imports:
You can achieve it by this way as well :)
Path.GetFileNameWithoutExtension(Str1).Split("_"c).Last
Path.GetFileNameWithoutExtension
Returns the file name of the specified path string without the extension.
so with your String it will return to you - 10001662-1_20060301_29_1_20190301
then Split above String i.e. 10001662-1_20060301_29_1_20190301 based on _ and will return an array of string.
Last
It will return you the last element of an array returned by Split..
Regards..!!
AKsh
I have:
Raw xml filled by a select query.This xml transformed into a HL7
message
One of the tags of this xml represents a clob column from a table in
the database
I mapped this data (from edit transformer section) as a variable.
Now I am trying to convert this variable into a base64 string then
replace it in my transformed hl7 message.
5.I tried this conversion on a destination channel which is a javascript writer.
I read and tried several conversion methods like
Packages.org.apache.commons.codec.binary.Base64.encodeBase64String();
I have got only error messages like :
EvaluatorException: Can't find method org.apache.commons.codec.binary.Base64.encodeBase64String(java.lang.String);
Code piece:
var ads=$('V_REPORT_CLOB');
var encoded = Packages.org.apache.commons.codec.binary.Base64.encodeBase64String(ads.toString());
It is pretty clear that I am a newbie on that.How can I manage to do this conversion ?
Here is what I use for Base64 encoding a string with your var substituted.
//Encode Base 64//
var ads = $('V_REPORT_CLOB');
var adsLength = ads.length;
var base64Bytes = [];
for(i = 0; i < adsLength;i++){
base64Bytes.push(ads.charCodeAt(i));
}
var encodedData = FileUtil.encode(base64Bytes);
I am trying to write a simple Java program that reads from JBossMQ's jms_messages table using JDBC. I am using JBoss 4.0.4.GA.
I can get the as far as getting a SpyMessage, but how can I get the actual message content (which is an Object in the particular case I'm looking at).
I have a result set "rs" from this statement:
SELECT messageid, messageblob FROM jms_messages WHERE DESTINATION LIKE 'TOPIC.MyTopic%' limit 3"
and then I do this (based on JBoss code):
long messageid = rs.getLong(1);
SpyMessage message = null;
byte[] st = rs.getBytes(2);
ByteArrayInputStream baip = new ByteArrayInputStream(st);
ObjectInputStream ois = new ObjectInputStream(baip);
message = SpyMessage.readMessage(ois);
message.header.messageId = messageid;
String jmstype = message.getJMSType();
String jms_message_id = message.getJMSMessageID();
System.out.println("jmstype=" +jmstype);
System.out.println("jms_message_id=" +jms_message_id);
String propertyName;
Enumeration e = message.getPropertyNames();
while (e.hasMoreElements())
{
propertyName = (String)e.nextElement();
System.out.println("property name = " +propertyName);
}
but I get no properties printed and I don't know how to get my actual object from the SpyMessage (actually a SpyObjectMessage). I'd be grateful for any pointers.
I've tried asking this question on the JBoss forum without reply, so I'm hoping for better luck here.
Thanks.
Sorry - the answer was so obvious I'm not really sure what I was thinking when I posted the question - simply:
Object objMessage = ((SpyObjectMessage)message).getObject();