PowerShell outputting array items when interpolating within double quotes - powershell

I found some strange behavior in PowerShell surrounding arrays and double quotes. If I create and print the first element in an array, such as:
$test = #('testing')
echo $test[0]
Output:
testing
Everything works fine. But if I put double quotes around it:
echo "$test[0]"
Output:
testing[0]
Only the $test variable was evaluated and the array marker [0] was treated literally as a string. The easy fix is to just avoid interpolating array variables in double quotes, or assign them to another variable first. But is this behavior by design?

So when you are using interpolation, by default it interpolates just the next variable in toto. So when you do this:
"$test[0]"
It sees the $test as the next variable, it realizes that this is an array and that it has no good way to display an array, so it decides it can't interpolate and just displays the string as a string. The solution is to explicitly tell PowerShell where the bit to interpolate starts and where it stops:
"$($test[0])"
Note that this behavior is one of my main reasons for using formatted strings instead of relying on interpolation:
"{0}" -f $test[0]

EBGreen's helpful answer contains effective solutions, but only a cursory explanation of PowerShell's string expansion (string interpolation):
Only variables by themselves can be embedded directly inside double-quoted strings ("...") (by contrast, single-quoted strings ('...'), as in many other languages, are for literal contents).
This applies to both regular variables and variables referencing a specific namespace; e.g.:
"var contains: $var", "Path: $env:PATH"
If the first character after the variable name can be mistaken for part of the name - which notably includes : - use {...} around the variable name to disambiguate; e.g.:
"${var}", "${env:PATH}"
To use a $ as a literal, you must escape it with `, PowerShell's escape character; e.g.:
"Variable `$var"
Any character after the variable name - including [ and . is treated as a literal part of the string, so in order to index into embedded variables ($var[0]) or to access a property ($var.Count), you need $(...), the subexpression operator (in fact, $(...) allows you to embed entire statements); e.g.:
"1st element: $($var[0])"
"Element count: $($var.Count)"
"Today's date: $((Get-Date -DisplayHint Date | Out-String).Trim())"
Stringification (to-string conversion) is applied to any variable value / evaluation result that isn't already a string:
Caveat: Where culture-specific formatting can be applied, PowerShell chooses the invariant culture, which largely coincides with the US-English date and number formatting; that is, dates and numbers will be represented in US-like format (e.g., month-first date format and . as the decimal mark).
In essence, the .ToString() method is called on any resulting non-string object or collection (strictly speaking, it is .psobject.ToString(), which overrides .ToString() in some cases, notably for arrays / collections and PS custom objects)
Note that this is not the same representation you get when you output a variable or expression directly, and many types have no meaningful default string representations - they just return their full type name.
However, you can embed $(... | Out-String) in order to explicitly apply PowerShell's default output formatting.
For a more comprehensive discussion of stringification, see this answer.
As stated, using -f, the string-formatting operator (<format-string> -f <arg>[, ...]) is an alternative to string interpolation that separates the literal parts of a string from the variable parts:
'1st element: {0}; count: {1:x}' -f $var[0], $var.Count
Note the use of '...' on the LHS, because the format string (the template) is itself a literal. Using '...' in this case is a good habit to form, both to signal the intent of using literal contents and for the ability to embed $ characters without escaping.
In addition to simple positional placeholders ({0} for the 1st argument. {1} for the 2nd, ...), you may optionally exercise more formatting control over the to-string conversion; in the example above, x requests a hex representation of the number.
For available formats, see the documentation of the .NET framework's String.Format method, which the -f operator is based on.
Pitfall: -f has high precedence, so be sure to enclose RHS expressions other than simple index or property access in (...); e.g., '{0:N2}' -f 1/3 won't work as intended, only '{0:N2}' -f (1/3) will.
Caveats: There are important differences between string interpolation and -f:
Unlike expansion inside "...", the -f operator is culture-sensitive:
Therefore, the following two seemingly equivalent statements do not
yield the same result:
PS> [cultureinfo]::CurrentCulture='fr'; $n=1.2; "expanded: $n"; '-f: {0}' -f $n
expanded: 1.2
-f: 1,2
Note how only the -f-formatted command respected the French (fr) decimal mark (,).
Again, see the previously linked answer for a comprehensive look at when PowerShell is and isn't culture-sensitive.
Unlike expansion inside "...", -f stringifies arrays as <type-name>[]:
PS> $arr = 1, 2, 3; "`$arr: $arr"; '$arr: {0}' -f (, $arr)
$arr: 1 2 3
$arr: System.Object[]
Note how "..." interpolation created a space-separated list of the stringification of all array elements, whereas -f-formatting only printed the array's type name.
(As discussed, $arr inside "..." is equivalent to:
(1, 2, 3).psobject.ToString() and it is the generally invisible helper type [psobject] that provides the friendly representation.)
Also note how (, ...) was used to wrap array $arr in a helper array that ensures that -f sees the expression as a single operand; by default, the array's elements would be treated as individual operands.

In such cases you have to do:
echo "$($test[0])"
Another alternative is to use string formatting
echo "this is {0}" -f $test[0]
Note that this will be the case when you are accessing properties in strings as well. Like "$a.Foo" - should be written as "$($a.Foo)"

Related

PowerShell date time not combining strings System.Collections.Hashtable.allshift [duplicate]

This question already has an answer here:
PowerShell :: Microsoft.Azure.Commands.Sql.Database.Model.AzureSqlDatabaseModel.DatabaseName [duplicate]
(1 answer)
Closed 5 months ago.
I am attempting to make a string the contains the bellow hash table object strings and the $today variable and resulting with System.Collections.Hashtable.allshift.
$today = (Get-Date).ToString('yyyyMMdd')
$saturday = #{
allshift = "All_Shifts_Checklist_Saturday.xlsx";
elements = "Elements_Weekend.xlsx";
night = "Night_Shift_Saturday.xlsx"
}
Write-Host $today$saturday.allshift
###ACTUAL 20220923System.Collections.Hashtable.allshift
###EXPECTED 20220923All_Shifts_Checklist_Saturday.xlsx
Building on the helpful comments:
Because argument $today$saturday.allshift is implicitly treated as if it were enclosed in "...", the interpolation rules of expandable strings apply.
Inside "..." strings, only stand-alone variable references are expanded as-is by default, e.g., $saturday, and not also expressions, which includes property access, e.g. $saturday.allshift. In the latter case, $saturday is expanded as a whole, and .allshift is printed verbatim.
In order to embed expressions such as $saturday.allshift inside "...", you need $(...), the subexpression operator:
# "..." isn't strictly necessary, but is conceptually clearer.
Write-Host "$today$($saturday.allshift)"
See this answer for more information, and this answer for a comprehensive overview of the string-interpolation rules.
What makes your example tricky are the subtleties around how PowerShell decides whether a given command argument is implicitly treated as if it were "..."-enclosed:
A few examples (Write-Output is used instead of Write-Host, to make it more obvious when a compound token is actually passed as two arguments):
# Argument is treated as an *expression*
# -> 'All_Shifts_Checklist_Saturday.xlsx'
Write-Output $saturday.allshift
# The compound token treats $saturday.allshift as an *expression*,
# and $today therefore becomes a *separate argument*.
# -> 'All_Shifts_Checklist_Saturday.xlsx', '20220923'
Write-Output $saturday.allshift$today
# Your case:
# Because the compound token starts with a stand-alone variable reference
# *followed by additional characters* that do not constitute a property
# access or method call, the whole token is considered a single, expandable
# string:
# * $today expands as intended
# * $saturday expands *as a whole* - resulting in just the *type name* of
# the hashtable, 'System.Collections.Hashtable' (try `#{}.ToString()`)
# * and '.allshift' is treated as a literal.
# -> '20220923System.Collections.Hashtable.allshift'
Write-Output $today$saturday.allshift
That is, if a compound token starts with a variable-based expression that is a property access or method call, the expression is recognized as such, and whatever follows becomes a separate argument.
The exact rules are complex; this answer discusses them.
Therefore, it is best to form a habit to enclose compound tokens that are meant to be a single string argument in "...", and use $(...) to enclose any embedded expressions or commands.

When should I pick using a const over a variable in PowerShell? [duplicate]

When I study PowerShell scripting language, I try to use "Write-Output" command to display variable.
I use a different method to create variables.
Example:
$myvariable = 0x5555
Set-Variable -Name myvariable2 -Value 0x5555
The data type of these two variables is Int32.
When I use the command as below,
Write-Output $myvariable $myvariable2
the result is 21845 and 0x5555.
What's different between these two variables?
How can I display format result like printf %d %x?
PetSerAl, as many times before, has given the crucial pointer in a comment (and later helped improve this answer):
Written as of PowerShell Core 6.2.0.
PowerShell parses an unquoted literal argument that looks like a number as a number and wraps it in a "half-transparent" [psobject] instance, whose purpose is to also preserve the exact argument as specified as a string.
By half-transparent I mean that the resulting $myVariable2:
primarily is a number - a regular (unwrapped) [int] instance - for the purpose of calculations; e.g., $myVariable2 + 1 correctly returns 21846
additionally, it shows that it is a number when you ask for its type with .GetType() or via the Get-Member cmdlet; in other words: in this case PowerShell pretends that the wrapper isn't there (see below for a workaround).
situationally behaves like a string - returning the original argument literal exactly as specified - in the context of:
output formatting, both when printing directly to the console and generally with Out-* cmdlets such as Out-File (but not Set-Content) and Format-* cmdlets.
string formatting with -f, PowerShell's format operator (which is based on .NET's String.Format() method; e.g., 'The answer is {0}' -f 42 is equivalent to [string]::Format('The answer is {0}', 42)).
Surprisingly, it does not behave like a string inside an expandable string ("$myVariable2") and when you call the .ToString() method ($myVariable2.ToString()) and (therefore also) with Set-Content.
However, the original string representation can be retrieved with $myVariable2.psobject.ToString()
Note that specifying number literals as command arguments is inherently ambiguous, because even string arguments generally don't need quoting (unless they contain special characters), so that, for instance, an argument such as 1.0 could be interpreted as a version string or as a floating-point number.
PowerShell's approach to resolving the ambiguity is to parse such a token as a number, which, however, situationally acts as a string[1], as shown above.
The ambiguity can be avoided altogether by typing parameters so as to indicate whether an argument bound to it is a string or a number.
However, the -Value parameter of the Set-Variable and New-Variable cmdlets is - of necessity - [object] typed, because it must be able to accept values of any type, and these cmdlets don't have a parameter that would let you indicate the intended data type.
The solution is to force the -Value argument to be treated as the result of an expression rather than as an unquoted literal argument, by enclosing it in (...):
# Due to enclosing in (...), the value that is stored in $myvariable2
# is *not* wrapped in [psobject] and therefore behaves the same as
# $myvariable = 0x55555
Set-Variable -Name myvariable2 -Value (0x5555)
Conversely, if you don't apply the above solution, you have two choices for unwrapping $myvariable2's value on demand:
# OK: $myvariable isn't wrapped in [psobject], so formatting it as a
# hex. number works as expected:
PS> 'hex: 0x{0:x}' -f $myvariable
hex: 0x5555 # OK: Literal '0x' followed by hex. representation of the [int]
# !! Does NOT work as expected, because $myvariable2 is treated as a *string*
# !! That is, {0:x} is effectively treated as just {0}, and the string
# !! representation stored in the [psobject] wrapper is used as-is.
PS> 'hex: 0x{0:x}' -f $myvariable2
hex: 0x0x5555 # !! Note the extra '0x'
# Workaround 1: Use a *cast* (with the same type) to force creation of
# a new, *unwrapped* [int] instance:
PS> 'hex: 0x{0:x}' -f [int] $myvariable2
hex: 0x5555 # OK
# Workaround 2: Access the *wrapped* object via .psobject.BaseObject.
# The result is an [int] that behaves as expected.
PS> 'hex: 0x{0:x}' -f $myvariable2.psobject.BaseObject
hex: 0x5555 # OK
Note: That -f, the format operator, unexpectedly treats a [psobject]-wrapped number as a string is the subject of GitHub issue #17199; sadly, the behavior was declared to be by design.
Detecting a [psobject]-wrapped value:
The simplest solution is to use -is [psobject]:
PS> $myvariable -is [psobject]
False # NO wrapper object
PS> $myvariable2 -is [psobject]
True # !! wrapper object
(PetSerAl offers the following, less obvious alternative: [Type]::GetTypeArray((, $myvariable2)), which bypasses PowerShell's hiding-of-the-wrapper trickery.)
[1] Preserving the input string representation in implicitly typed numbers passed as command arguments:
Unlike traditional shells, PowerShell uses rich types, so that an argument literal such as 01.2 is instantly parsed as a number - a [double] in this case, and if it were used as-is, it would result in a different representation on output, because - once parsed as a number - default output formatting is applied on output (where the number must again be turned into a string):
PS> 01.2
1.2 # !! representation differs (and is culture-sensitive)
However, the intent of the target command may ultimately be to treat the argument as a string and in that case you do not want the output representation to change.
(Note that while you can disambiguate numbers from strings by using quoting (01.2 vs. '01.2'), this is not generally required in command arguments, the same way it isn't required in traditional shells.)
It is for that reason that a [psobject] wrapper is used to capture the original string representation and use it on output.
Note: Arguably, a more consistent approach would have been to always treat unquoted literal arguments as strings, except when bound to explicitly numerically typed parameters in PowerShell commands.
This is a necessity for invoking external programs, to which arguments can only ever be passed as strings.
That is, after initial parsing as a number, PowerShell must use the original string representation when building the command line (Windows) / passing the argument (Unix-like platforms) as part of the invocation of the external program.
If it didn't do that, arguments could inadvertently be changed, as shown above (in the example above, the external program would receive string 1.2 instead of the originally passed 01.2).
You can also demonstrate the behavior using PowerShell code, with an untyped parameter - though note that is generally preferable to explicitly type your parameters:
PS> & { param($foo) $foo.GetType().Name; $foo } -foo 01.2
Double # parsed as number - a [double]
01.2 # !! original string representation, because $foo wasn't typed
$foo is an untyped parameter, which means that the type that PowerShell inferred during initial parsing of literal 01.2 is used.
Yet, given that the command (a script block ({ ... }) in this case) didn't declare a parameter type for $foo, the [psobject] wrapper that is implicitly used shows the original string representation on output.
The first question is already answered by #PetSerAl in the comments. Your second question:
How can I display format result like printf %d %x
Use PowerShell string formatting to obtain the desired results.

How to reference an index in a string array [duplicate]

I found some strange behavior in PowerShell surrounding arrays and double quotes. If I create and print the first element in an array, such as:
$test = #('testing')
echo $test[0]
Output:
testing
Everything works fine. But if I put double quotes around it:
echo "$test[0]"
Output:
testing[0]
Only the $test variable was evaluated and the array marker [0] was treated literally as a string. The easy fix is to just avoid interpolating array variables in double quotes, or assign them to another variable first. But is this behavior by design?
So when you are using interpolation, by default it interpolates just the next variable in toto. So when you do this:
"$test[0]"
It sees the $test as the next variable, it realizes that this is an array and that it has no good way to display an array, so it decides it can't interpolate and just displays the string as a string. The solution is to explicitly tell PowerShell where the bit to interpolate starts and where it stops:
"$($test[0])"
Note that this behavior is one of my main reasons for using formatted strings instead of relying on interpolation:
"{0}" -f $test[0]
EBGreen's helpful answer contains effective solutions, but only a cursory explanation of PowerShell's string expansion (string interpolation):
Only variables by themselves can be embedded directly inside double-quoted strings ("...") (by contrast, single-quoted strings ('...'), as in many other languages, are for literal contents).
This applies to both regular variables and variables referencing a specific namespace; e.g.:
"var contains: $var", "Path: $env:PATH"
If the first character after the variable name can be mistaken for part of the name - which notably includes : - use {...} around the variable name to disambiguate; e.g.:
"${var}", "${env:PATH}"
To use a $ as a literal, you must escape it with `, PowerShell's escape character; e.g.:
"Variable `$var"
Any character after the variable name - including [ and . is treated as a literal part of the string, so in order to index into embedded variables ($var[0]) or to access a property ($var.Count), you need $(...), the subexpression operator (in fact, $(...) allows you to embed entire statements); e.g.:
"1st element: $($var[0])"
"Element count: $($var.Count)"
"Today's date: $((Get-Date -DisplayHint Date | Out-String).Trim())"
Stringification (to-string conversion) is applied to any variable value / evaluation result that isn't already a string:
Caveat: Where culture-specific formatting can be applied, PowerShell chooses the invariant culture, which largely coincides with the US-English date and number formatting; that is, dates and numbers will be represented in US-like format (e.g., month-first date format and . as the decimal mark).
In essence, the .ToString() method is called on any resulting non-string object or collection (strictly speaking, it is .psobject.ToString(), which overrides .ToString() in some cases, notably for arrays / collections and PS custom objects)
Note that this is not the same representation you get when you output a variable or expression directly, and many types have no meaningful default string representations - they just return their full type name.
However, you can embed $(... | Out-String) in order to explicitly apply PowerShell's default output formatting.
For a more comprehensive discussion of stringification, see this answer.
As stated, using -f, the string-formatting operator (<format-string> -f <arg>[, ...]) is an alternative to string interpolation that separates the literal parts of a string from the variable parts:
'1st element: {0}; count: {1:x}' -f $var[0], $var.Count
Note the use of '...' on the LHS, because the format string (the template) is itself a literal. Using '...' in this case is a good habit to form, both to signal the intent of using literal contents and for the ability to embed $ characters without escaping.
In addition to simple positional placeholders ({0} for the 1st argument. {1} for the 2nd, ...), you may optionally exercise more formatting control over the to-string conversion; in the example above, x requests a hex representation of the number.
For available formats, see the documentation of the .NET framework's String.Format method, which the -f operator is based on.
Pitfall: -f has high precedence, so be sure to enclose RHS expressions other than simple index or property access in (...); e.g., '{0:N2}' -f 1/3 won't work as intended, only '{0:N2}' -f (1/3) will.
Caveats: There are important differences between string interpolation and -f:
Unlike expansion inside "...", the -f operator is culture-sensitive:
Therefore, the following two seemingly equivalent statements do not
yield the same result:
PS> [cultureinfo]::CurrentCulture='fr'; $n=1.2; "expanded: $n"; '-f: {0}' -f $n
expanded: 1.2
-f: 1,2
Note how only the -f-formatted command respected the French (fr) decimal mark (,).
Again, see the previously linked answer for a comprehensive look at when PowerShell is and isn't culture-sensitive.
Unlike expansion inside "...", -f stringifies arrays as <type-name>[]:
PS> $arr = 1, 2, 3; "`$arr: $arr"; '$arr: {0}' -f (, $arr)
$arr: 1 2 3
$arr: System.Object[]
Note how "..." interpolation created a space-separated list of the stringification of all array elements, whereas -f-formatting only printed the array's type name.
(As discussed, $arr inside "..." is equivalent to:
(1, 2, 3).psobject.ToString() and it is the generally invisible helper type [psobject] that provides the friendly representation.)
Also note how (, ...) was used to wrap array $arr in a helper array that ensures that -f sees the expression as a single operand; by default, the array's elements would be treated as individual operands.
In such cases you have to do:
echo "$($test[0])"
Another alternative is to use string formatting
echo "this is {0}" -f $test[0]
Note that this will be the case when you are accessing properties in strings as well. Like "$a.Foo" - should be written as "$($a.Foo)"

What's different between "$myvariable =" and Set-Variable in PowerShell?

When I study PowerShell scripting language, I try to use "Write-Output" command to display variable.
I use a different method to create variables.
Example:
$myvariable = 0x5555
Set-Variable -Name myvariable2 -Value 0x5555
The data type of these two variables is Int32.
When I use the command as below,
Write-Output $myvariable $myvariable2
the result is 21845 and 0x5555.
What's different between these two variables?
How can I display format result like printf %d %x?
PetSerAl, as many times before, has given the crucial pointer in a comment (and later helped improve this answer):
Written as of PowerShell Core 6.2.0.
PowerShell parses an unquoted literal argument that looks like a number as a number and wraps it in a "half-transparent" [psobject] instance, whose purpose is to also preserve the exact argument as specified as a string.
By half-transparent I mean that the resulting $myVariable2:
primarily is a number - a regular (unwrapped) [int] instance - for the purpose of calculations; e.g., $myVariable2 + 1 correctly returns 21846
additionally, it shows that it is a number when you ask for its type with .GetType() or via the Get-Member cmdlet; in other words: in this case PowerShell pretends that the wrapper isn't there (see below for a workaround).
situationally behaves like a string - returning the original argument literal exactly as specified - in the context of:
output formatting, both when printing directly to the console and generally with Out-* cmdlets such as Out-File (but not Set-Content) and Format-* cmdlets.
string formatting with -f, PowerShell's format operator (which is based on .NET's String.Format() method; e.g., 'The answer is {0}' -f 42 is equivalent to [string]::Format('The answer is {0}', 42)).
Surprisingly, it does not behave like a string inside an expandable string ("$myVariable2") and when you call the .ToString() method ($myVariable2.ToString()) and (therefore also) with Set-Content.
However, the original string representation can be retrieved with $myVariable2.psobject.ToString()
Note that specifying number literals as command arguments is inherently ambiguous, because even string arguments generally don't need quoting (unless they contain special characters), so that, for instance, an argument such as 1.0 could be interpreted as a version string or as a floating-point number.
PowerShell's approach to resolving the ambiguity is to parse such a token as a number, which, however, situationally acts as a string[1], as shown above.
The ambiguity can be avoided altogether by typing parameters so as to indicate whether an argument bound to it is a string or a number.
However, the -Value parameter of the Set-Variable and New-Variable cmdlets is - of necessity - [object] typed, because it must be able to accept values of any type, and these cmdlets don't have a parameter that would let you indicate the intended data type.
The solution is to force the -Value argument to be treated as the result of an expression rather than as an unquoted literal argument, by enclosing it in (...):
# Due to enclosing in (...), the value that is stored in $myvariable2
# is *not* wrapped in [psobject] and therefore behaves the same as
# $myvariable = 0x55555
Set-Variable -Name myvariable2 -Value (0x5555)
Conversely, if you don't apply the above solution, you have two choices for unwrapping $myvariable2's value on demand:
# OK: $myvariable isn't wrapped in [psobject], so formatting it as a
# hex. number works as expected:
PS> 'hex: 0x{0:x}' -f $myvariable
hex: 0x5555 # OK: Literal '0x' followed by hex. representation of the [int]
# !! Does NOT work as expected, because $myvariable2 is treated as a *string*
# !! That is, {0:x} is effectively treated as just {0}, and the string
# !! representation stored in the [psobject] wrapper is used as-is.
PS> 'hex: 0x{0:x}' -f $myvariable2
hex: 0x0x5555 # !! Note the extra '0x'
# Workaround 1: Use a *cast* (with the same type) to force creation of
# a new, *unwrapped* [int] instance:
PS> 'hex: 0x{0:x}' -f [int] $myvariable2
hex: 0x5555 # OK
# Workaround 2: Access the *wrapped* object via .psobject.BaseObject.
# The result is an [int] that behaves as expected.
PS> 'hex: 0x{0:x}' -f $myvariable2.psobject.BaseObject
hex: 0x5555 # OK
Note: That -f, the format operator, unexpectedly treats a [psobject]-wrapped number as a string is the subject of GitHub issue #17199; sadly, the behavior was declared to be by design.
Detecting a [psobject]-wrapped value:
The simplest solution is to use -is [psobject]:
PS> $myvariable -is [psobject]
False # NO wrapper object
PS> $myvariable2 -is [psobject]
True # !! wrapper object
(PetSerAl offers the following, less obvious alternative: [Type]::GetTypeArray((, $myvariable2)), which bypasses PowerShell's hiding-of-the-wrapper trickery.)
[1] Preserving the input string representation in implicitly typed numbers passed as command arguments:
Unlike traditional shells, PowerShell uses rich types, so that an argument literal such as 01.2 is instantly parsed as a number - a [double] in this case, and if it were used as-is, it would result in a different representation on output, because - once parsed as a number - default output formatting is applied on output (where the number must again be turned into a string):
PS> 01.2
1.2 # !! representation differs (and is culture-sensitive)
However, the intent of the target command may ultimately be to treat the argument as a string and in that case you do not want the output representation to change.
(Note that while you can disambiguate numbers from strings by using quoting (01.2 vs. '01.2'), this is not generally required in command arguments, the same way it isn't required in traditional shells.)
It is for that reason that a [psobject] wrapper is used to capture the original string representation and use it on output.
Note: Arguably, a more consistent approach would have been to always treat unquoted literal arguments as strings, except when bound to explicitly numerically typed parameters in PowerShell commands.
This is a necessity for invoking external programs, to which arguments can only ever be passed as strings.
That is, after initial parsing as a number, PowerShell must use the original string representation when building the command line (Windows) / passing the argument (Unix-like platforms) as part of the invocation of the external program.
If it didn't do that, arguments could inadvertently be changed, as shown above (in the example above, the external program would receive string 1.2 instead of the originally passed 01.2).
You can also demonstrate the behavior using PowerShell code, with an untyped parameter - though note that is generally preferable to explicitly type your parameters:
PS> & { param($foo) $foo.GetType().Name; $foo } -foo 01.2
Double # parsed as number - a [double]
01.2 # !! original string representation, because $foo wasn't typed
$foo is an untyped parameter, which means that the type that PowerShell inferred during initial parsing of literal 01.2 is used.
Yet, given that the command (a script block ({ ... }) in this case) didn't declare a parameter type for $foo, the [psobject] wrapper that is implicitly used shows the original string representation on output.
The first question is already answered by #PetSerAl in the comments. Your second question:
How can I display format result like printf %d %x
Use PowerShell string formatting to obtain the desired results.

Powershell - add variables inside a json string

I have the following json code in my powershell script.
I set the $variable to 1111111111
$jsonfile = '{"Version": "2012-10-17","Statement": {"Effect": "Allow","Action": "sts:AssumeRole","Resource": "arn:aws:iam::$variable:role/xxxxxx"}}'
The output gives ....arn:aws:iam::$variable:role/xxxxxx..... instead of ....arn:aws:iam::1111111111:role/xxxxxx
The problem is that I must use the single quote for the json string otherwise I will get an error. If I use single quote I wont be able to put the variables inside the string. How do I workaround this problem?
There are various ways to solve your problem, but perhaps the easiest approach is to use PowerShell's string interpolation:
use a double-quoted string overall to enable interpolation of embedded variable references and subexpressions ($(...)).
escape embedded " chars. as `" (using backticks)
disambiguate variable references by enclosing the variable name in {...}.
Simplified example:
PS> $variable='111'
PS> "{`"Version`": `"arn:aws:iam::${variable}:role/xxxxxx`"}}"
{"Version": "arn:aws:iam::111:role/xxxxxx"}}
Note that enclosing variable names in {...} in interpolated strings is only necessary if the following char. could be misinterpreted as part of the variable name.
A : following the variable name - as is the case here - is such a case, because PS variables can have a scope specifier preceding the variable name that is separated from the variable name with :, such as in $env:USERNAME.
DAXaholic's helpful answer shows an alternative based on PowerShell's binary -f operator, which is essentially the same as the .NET framework's String.Format method; as such:
it introduces additional complexity, such as needing to know what its escaping rules are ({ chars. must be escape as {{, and how to format its arguments specified on the RHS of -r ({0} refers to the 1st RHS argument, ...)
on the flip side, -f offers many sophisticated formatting options.
Also, consider use of the Convert*-Json cmdlets his answer demonstrates: even though they're less performant, they ultimately make manipulation of JSON much easier and more robust.
Alternatives in the realm of native PowerShell code:
String concatenation with the binary + operator:
'{"Version": "arn:aws:iam::' + $variable + ':role/xxxxxx"}}'
String templating with $ExecutionContext.InvokeCommand.ExpandString():
$variable='111'
$tmpl = '{"Version": "arn:aws:iam::${variable}:role/xxxxxx"}}' # string template *literal*
$ExecutionContext.InvokeCommand.ExpandString($tmpl) # performs on-demand interpolation
Another solution would be
$jsonfile = '{{"Version": "2012-10-17","Statement": {{"Effect": "Allow","Action": "sts:AssumeRole","Resource": "arn:aws:iam::{0}:role/xxxxxx"}}}}' -f $variable
So you have to escape the braces with another brace but in your case you have fewer braces than quotes so it is "less obfuscation" :)
In your case, maybe the simplest solution is just concatenating the strings together instead of using string formatting / interpolation.
In addition you could also go the way with the JSON cmdlets:
$jsonfile |
ConvertFrom-Json |
% { $_.Statement.Resource = "arn:aws:iam::${variable}:role/xxxxxx"; $_ } |
ConvertTo-Json