How to send an email from an ASP.NET MVC view page with an attachment? - asp.net-mvc-2

Question

I have to send an email from my ASP.NET MVC 2 contact form view page.I need a detail answer that describes how to create the model , the controller and the view for that purpose .. Here is the code i have given in my controller class's action method..
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult SendEMail(CareersEMailModel careersEMailModel,HttpPostedFileBase upload)
{
if (ModelState.IsValid)
{
bool isOK = false;
try
{
MailMessage msg = new MailMessage();
msg.From = new MailAddress("no-reply#abc.com", "Website contact form");
msg.To.Add("info#abc.com");
msg.Subject = "Resume";
string body = "Name:" + careersEMailModel.Name + "\n" + "Phone:" + careersEMailModel.Phone + "\n" + "Email:" + careersEMailModel.Email;
string file = careersEMailModel.Resume;
msg.Body = body;
msg.IsBodyHtml = false;
SmtpClient smtp = new SmtpClient("mailserver_url.net", 25);
smtp.Send(msg);
msg.Dispose();
isOK = true;
CareersMessageModel rcpt = new CareersMessageModel();
rcpt.Title = "Email sent successfully!!";
rcpt.Content = "Your details has been received with great thanks.We'll contact you as soon as possible.";
return View("CareersMessage", rcpt);
}
catch (Exception ex)
{
CareersMessageModel err = new CareersMessageModel();
err.Title = "Sorry,Email sending failed!!!";
err.Content = "The website is having an error with sending this mail at this time.You can send an email to our address provided in our contact us form.Thank you.";
return View("CareersMessage", err);
}
}
else
{
return View();
}
}

Answer 1

For retrieving the uploaded file, you will need to do this
foreach (string file in Request.Files)
{
var uploadFile = Request.Files[file];
if (uploadFile.ContentLength == 0) continue;
string fileLocation = //File Location with file name, needs to be stored for temporary purpose
uploadFile.SaveAs(fileLocation);
}
Then with help of following code you can attach file
Attachment data = new Attachment(fileLocation, MediaTypeNames.Application.Octet);
message.Attachments.Add(data);
Once done with the email delete the file created on server.
Hope this answers your question

Answer 2

from MSDN
public static void CreateMessageWithAttachment(string server)
{
// Specify the file to be attached and sent.
// This example assumes that a file named Data.xls exists in the
// current working directory.
string file = "data.xls";
// Create a message and set up the recipients.
MailMessage message = new MailMessage(
"jane#contoso.com",
"ben#contoso.com",
"Quarterly data report.",
"See the attached spreadsheet.");
// Create the file attachment for this e-mail message.
Attachment data = new Attachment(file, MediaTypeNames.Application.Octet);
// Add time stamp information for the file.
ContentDisposition disposition = data.ContentDisposition;
disposition.CreationDate = System.IO.File.GetCreationTime(file);
disposition.ModificationDate = System.IO.File.GetLastWriteTime(file);
disposition.ReadDate = System.IO.File.GetLastAccessTime(file);
// Add the file attachment to this e-mail message.
message.Attachments.Add(data);
//Send the message.
SmtpClient client = new SmtpClient(server);
// Add credentials if the SMTP server requires them.
client.Credentials = CredentialCache.DefaultNetworkCredentials;
try {
client.Send(message);
}
catch (Exception ex) {
Console.WriteLine("Exception caught in CreateMessageWithAttachment(): {0}",
ex.ToString() );
}
// Display the values in the ContentDisposition for the attachment.
ContentDisposition cd = data.ContentDisposition;
Console.WriteLine("Content disposition");
Console.WriteLine(cd.ToString());
Console.WriteLine("File {0}", cd.FileName);
Console.WriteLine("Size {0}", cd.Size);
Console.WriteLine("Creation {0}", cd.CreationDate);
Console.WriteLine("Modification {0}", cd.ModificationDate);
Console.WriteLine("Read {0}", cd.ReadDate);
Console.WriteLine("Inline {0}", cd.Inline);
Console.WriteLine("Parameters: {0}", cd.Parameters.Count);
foreach (DictionaryEntry d in cd.Parameters)
{
Console.WriteLine("{0} = {1}", d.Key, d.Value);
}
data.Dispose();
}
EDIT:
the Attachment class accepts a stream. So try this. (i haven't tested it but it should give you the gist of what you need to do)
foreach (string fileName in Request.Files)
{
HttpPostedFile file = Request.Files[fileName];
Attachment data = new Attachment(file.InputStream, fileName);
// do stuff to attach it to the Mail Message
}