I know this been asked for so many times but I always end up getting null in my NSDate. I have a string like this "January 16, 2012 21:44:56" I want to convert it to "January 16, 2012 09:44:56 PM". I want to add a PM in the converted date and convert the 24 hour time format to 12 hour time format. Here's my code.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMMM dd, YYYY HH:ii:ss a"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
As Ali3n correctly pointed out, you should first set the format of dateString to the formatter to get a valid date object. Next you should set the formatter's format to the desired one and continue. Do the following:
NSString *dateString = #"January 16, 2012 21:44:56";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMMM dd, yyyy HH:mm:ss"];
NSDate *dateFromString;
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter setDateFormat:#"MMMM dd, YYYY HH:mm:ss a"];
NSString *stringFromDate = [dateFormatter stringFromDate:dateFromString];
#"MMMM dd, YYYY HH:ii:ss a" this format should match with the date the ypu are passing to the date formatter ..
There is an error in your format string an also you need to tell the formatter the Locale in which your date string is presented.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setLocale:[[[NSLocale alloc] initWithLocaleIdentifier:#"en_US"] autorelease]];
[dateFormatter setDateFormat:#"MMMM dd, yyyy HH:mm:ss a"];
NSDate *dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release], dateFormatter = nil;
Setting the Local is very important since you have an name of a date in your input. You will need to tell the NSDateFormatter is wich language the name will be. In the example given it is in english. I've you run you code without setting the local on a device where the language is not set to english it wil fail to parse the date.
Try to escape literals in the format string.
[dateFormatter setDateFormat:#"MMMM dd',' YYYY HH:ii:ss a"];
As for your requirements you have to change the dateFormatter.Check this link for more.
NSDateFormatter* dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMMM dd, YYYY hh:mm:ss a"];
NSString *dateString = [dateFormatter stringFromDate:[NSDate date]];
[dateFormatter release];
NSLog(#"%#",dateString);
Related
I wish to change the date format from "2013-01-21 11:55:00" to "Jan 21, 2013 5:30 AM".
I tried the below code. But it gives a constant date.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
[dateFormatter setTimeStyle:NSDateFormatterMediumStyle];
NSDate *myDate = [NSDate dateWithTimeIntervalSinceReferenceDate:162000];
NSLog(#"%#",[dateFormatter stringFromDate:myDate]);
The above code gives constant output : Jan 3, 2001 2:30:00 AM
But in my case, date is dynamic.
NSString *firstDate = #"2013-01-21 11:55:00";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy'-'MM'-'dd HH':'mm':'ss"];
NSDate *date = [dateFormatter dateFromString:firstDate];
[dateFormatter setDateFormat:#"MMM d, yyyy h:mm a"];
NSLog(#"Expected Result___ %#",[dateFormatter stringFromDate:date]);
Try this
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMM d, yyyy h:mm a"];
NSDate *myDate = [NSDate dateWithTimeIntervalSinceReferenceDate:162000];
NSLog(#"%#",[dateFormatter stringFromDate:myDate];
Try [NSDate date] instead [NSDate dateWithTimeIntervalSinceReferenceDate:162000].
well you get constant output since you give constant input as 162000 !!!
First get the date from the string using its format then use the new format to get string from the obtained date
use this to output format as
#"MMM d, yyyy h:mm a"
NSDateFormatter *dateFormatter=[[NSDateFormatter alloc]init];
[dateFormatter setDateFormat:#"MMM d, yyyy h:mm a"];
NSLog(#"%#",[dateFormatter stringFromDate:[NSDate date]]);
I want to convert date 2012-12-26 to december 26, 2012 in iOS?
I am using websrvice and the data comes in this format 1990-12-26.
I want to change this to december 26, 2012 format.
This is what I am doing:
lbl_Rightside.text = [rootElement stringValueForNode:#"date"];
NSLog(#"lbl_Rightside is %#",lbl_Rightside.text);
[lbl_Rightside release];
Getting date to this label on 1990-12-26. Now I want to change date to december 26, 2012 format.
Any hints from experts would be very welcome.
you can use NSDateFormatter to do this kind of things. First
convert your date String to a date object using dateFromString:
method.
from date convert to string you want using stringFromDate: method
Different format strings can be found here.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd"];
NSDate *orignalDate = [dateFormatter dateFromString:YOUR_ORIGINAL_STRING];
[dateFormatter setDateFormat:#"MMMM dd, yyyy"];
NSString *finalString = [dateFormatter stringFromDate:orignalDate];
[dateFormatter release]; //if not using ARC
Check the official Apple documentation about NSDateFormatter. You should use this class to do this kind of formatting.
by using NSDateFormatter
NSString to NSDate
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
// this is imporant - we set our input date format to match our input string
// if format doesn't match you'll get nil from your string, so be careful
[dateFormatter setDateFormat:#"yyyy-MM-dd"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release];
NSDate convert to NSString:
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMMM dd, yyyy"];
NSString *strDate = [dateFormatter stringFromDate:[NSDate date]];
NSLog(#"%#", strDate);
[dateFormatter release];
Try to look at NSDateFormatter Class,
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd"]; // this is your input date format
NSDate *newDate = [dateFormatter dateFromString:dateString];//converting string to date object
The format you are looking for is something like:
[dateFormatter setDateFormat:#"MMM dd,yyy"]; // setting new format
NSLog(#"The date is = %#",[dateFormatter stringFromDate:newDate])
One simple thing on conversion from NSString to NSDate. How can I convert Mon, 27 August 2012 01:30 AM to NSDate in this same format. I tried with NSDateFormatter. But I am not getting it in this required format. Can anyone help? This is what I tried.
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEEE,dd MM yyyy HH:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
NSDateFormatter is to specify the format that will appear in the date-string when extracting string from date or the format that is in the date-string when extracting date from string
So whenever you extract NSDate from a NSString, NSDate is always obtained in default date format(eg 2012-08-27 00:30:00 +0000)... only the when you extract NSString from NSDate, NSString can be obtained in desired(custom) format that you set in NSDateFormatter.
I hope this will help you sure!
NSDateFormatter *dateformater=[[[NSDateFormatter alloc] init]autorelease];
[dateformater setDateFormat:#"EEEE,dd MMMM yyyy HH:mm a"];
NSDate *todayTmp=[NSDate date];
NSString *conversionDate=[dateformater stringFromDate:todayTmp];
Note : (Upper case) HH for 24h time format, (Lower case) hh for 12h time format
NSString *myDateAsAStringValue = #"Mon, 27 August 2012 01:30 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSDate *myDate = [[NSDate alloc]init];
myDate = [df dateFromString:myDateAsAStringValue];
[df release];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSString *strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
[dateFormatter release];
please use below code
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
your formatter is wrong
check this one
NSLog will return NSDate in a fixed format, i guess.
If we need Date in different format, we should have to format it via NSDateFormatter and get it as NSString.
Just a guess.
Don't forget to set the correct locale! If your device does not use an english locale NSDateFormatter can have problems to convert Mon and August into useful information because Mon is not the correct abbreviation for Monday in your language. For example in Germany the correct three letter abbreviation for Monday is Mon..
If you parse dates that have words in it you have to set the correct locale.
This should work:
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSLocale *posixLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[df setLocale:posixLocale];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
EEE is the dateformatter code for a three letter weekday abbreviation.
hh is the dateformatter code for Hours between 1 and 12. HH means 0-23
MMMM is the full month, MM would be the numeric value (= 08) of the month.
Output format: date and day format is in the form of 05 March 2012, MondayNSDate *selected = [picker date];
In this code I got output in the form of 1989-07-03, I need to print the corresponding day.
NSDateFormatter* formatter = [[[NSDateFormatter alloc] init] autorelease];
//Set the required date format
[formatter setDateFormat:#"yyyy-MM-dd"];
// [formatter setDateFormat:#"dd %b YYYY, %a"];
//Get the string date
NSString* date = [formatter stringFromDate:selected];
//Display on the console
NSLog(#"%#",date);
Use this:
NSDateFormatter *formatter = [[[NSDateFormatter alloc] init] autorelease];
[formatter setDateFormat:#"dd %b YYYY, %a"];
NSString *theString = [formatter stringFromDate:theDate];
%b is the name of the month, %a is the name of the day
More info here:
https://developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSDateFormatter_Class/Reference/Reference.html
dd MM yyyy,EEE like this ?
you can see more info about dateformatter Date_Format_Patterns
use this
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"dd MMMM yyyy,EEEE"];
NSLog(#"%#",[formatter stringFromDate:[NSDate date]]);
[formatter release];
Instead of using a fixed format, you should chose a style which will be localized:
[format setDateStyle:NSDateFormatterFullStyle];
This way the user will see the date in the date format that he's used to without you needing to worry about it. For example, Americans would get dates like "Tuesday, April 12, 1952 AD" while Germans would get
"Dienstag, 12. April 1952".
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"dd MMMM yyyy"];
NSLog(#"%#",[formatter stringFromDate:[NSDate date]]);
[formatter release];
Getting a NSString as follows:
NSString *lastSyncDate = [[items objectAtIndex:0] objectForKey:#"LastSyncDate"];
This value is: 1/1/2010 12:00:00 AM
I am using the following to convert to a date:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeStyle:NSDateFormatterFullStyle];
[df setDateFormat:#"MMMM d, y HH:mm:ss ZZZ"];
NSDate *mySyncDate = [df dateFromString:lastSyncDate];
This gives me a null value?
Your date format doesn't match the format of the string.
Try
[df setDateFormat:#"M/d/y hh:mm:ss a"];
or
[df setDateFormat:#"M/d/y h:mm:ss a"]; // if the hours aren't zero-padded
The format strings are a Unicode standard described at http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns
I agree with Seamus Campbell. However, be aware that setting the time style on the formatter (NSDateFormatter) will have no effect on the result returned by dateFromString.