I am trying to use emoticons for my chat application. I am comparing the string I get or I send with a local string. If I am get the result as true I want to replace the string with an image. For that matter I am not using may emoticons.
I am trying this:
NSRange textRange;
textRange =[text rangeOfString:#":)"];
if(textRange.location != NSNotFound)
{
//Does contain the substring
}
else
{
// replace string with image.
}
But I am not able to figure out how to replace image at the string position.
I assumed you want to put smileys.
So you can try this :
NSRange range = {NSNotFound, 0};
NSString *s = #"This is a smiley :) face";
range.location = 0;
range.length = [s length];
s = [s stringByReplacingOccurrencesOfString:#":)"
withString:#"\ue415"
options:NSCaseInsensitiveSearch
range:range];
For more detail please refer this link.
Related
In my app I download a file from amazon's s3, which does not work unless the file name has no spaces in it. For example, one of the files is "HoleByNature". I would like to display this to the user as "Hole By Nature", even though the file name will still have no spaces in it.
I was thinking of writing a method to search through the string starting at the 1st character (not the 0th) and every time I find a capital letter I create a new string with a substring until that index with a space and a substring until the rest.
So I have two questions.
If I use NSString's characterAtIndex, how do I know if that character is capital or not?
Is there a better way to do this?
Thank you!
Works for all unicode uppercase and titlecase letters
- (NSString*) spaceUppercase:(NSString*) text {
NSCharacterSet *set = [NSCharacterSet uppercaseLetterCharacterSet];
NSMutableString *result = [NSMutableString new];
for (int i = 0; i < [text length]; i++) {
unichar c = [text characterAtIndex:i];
if ([set characterIsMember:c] && i!=0){
[result appendFormat:#" %C",c];
} else {
[result appendFormat:#"%C",c];
}
}
return result;
}
I would not go to that approach because I know you can download files with spaces try this please when you construct the NSUrl object
#"my_web_site_url\sub_domain\sub_folder\My%20File.txt
this will download "My File.txt" from the URL provided. so basically you can replace all spaces in the URL with %20
reference:
http://www.w3schools.com/tags/ref_urlencode.asp
Got it working with Jano's answer but using the isupper function as suggested by Richard J. Ross III.
- (NSString*) spaceUppercase:(NSString*) text
{
NSMutableString *result = [NSMutableString new];
[result appendFormat:#"%C",[text characterAtIndex:0]];
for (int i = 1; i < [text length]; i++)
{
unichar c = [text characterAtIndex:i];
if (isupper(c))
{
[result appendFormat:#" %C",c];
}
else
{
[result appendFormat:#"%C",c];
}
}
return result;
}
I have a problem with this code:
textRange = [[html lowercaseString] rangeOfString:[substring lowercaseString]];
I'd like to find some words (substrings) in a HTML page. Using this method, I can find the words that are defined in "substring" but I want to find only entire words which are the substring to be searched for, and not any arbitrary (unbounded) occurrences of the substring. So I tried this method but nothing has changed:
textRange = [html rangeOfString:substring options:NSLiteralSearch];
Here's the entire code:
NSRange textRange;
textRange = [[html lowercaseString] rangeOfString:[substring lowercaseString]];
if (textRange.location != NSNotFound) {
check++;
} else {
// webView.hidden = NO;
}
Use NSRegularExpression and include \b at the start and end of the pattern to match word boundaries.
i have text message and I want to check whether it is containing text "http" or URL exists in that.
How will I check it?
NSString *string = #"xxx http://someaddress.com";
NSString *substring = #"http:";
Case sensitive example:
NSRange textRange = [string rangeOfString:substring];
if(textRange.location != NSNotFound){
//Does contain the substring
}else{
//Does not contain the substring
}
Case insensitive example:
NSRange textRange = [[string lowercaseString] rangeOfString:[substring lowercaseString]];
if(textRange.location != NSNotFound){
//Does contain the substring
}else{
//Does not contain the substring
}
#Cyprian offers a good option.
You could also consider using a NSRegularExpression which would give you far more flexibility assuming that's what you need, e.g. if you wanted to match http:// and https://.
Url usually has http or https in it
You can use your custom method containsString to check for those strings.
- (BOOL)containsString:(NSString *)string {
return [self containsString:string caseSensitive:NO];
}
- (BOOL)containsString:(NSString*)string caseSensitive:(BOOL)caseSensitive {
BOOL contains = NO;
if (![NSString isNilOrEmpty:self] && ![NSString isNilOrEmpty:string]) {
NSRange range;
if (!caseSensitive) {
range = [self rangeOfString:string options:NSCaseInsensitiveSearch];
} else {
range = [self rangeOfString:string];
}
contains = (range.location != NSNotFound);
}
return contains;
}
Example :
[yourString containsString:#"http"]
[yourString containsString:#"https"]
I know NSString has methods that determine the frame size for it, using NSString UIKit Additions, sizeWithFont......
How about the other way around? I mean if I have a fixed frame size, how do I know how many characters or words for a NSString that can fit into it?
If I know this, I can cut off the NSString easily.
thanks
It might not be the most elegant solution, but you could do something like this:
- (NSString *)string:(NSString *)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont *)font {
if ([sourceString sizeWithFont:font].width <= width)
return sourceString;
NSMutableString *string = [NSMutableString string];
for (NSInteger i = 0; i < [sourceString length]; i++) {
[string appendString:[sourceString substringWithRange:NSMakeRange(i, 1)]];
if ([string sizeWithFont:font].width > width) {
if ([string length] == 1)
return nil;
[string deleteCharactersInRange:NSMakeRange(i, 1)];
break;
}
}
return string;
}
Then call it like this:
NSString *test = #"Hello, World!";
CGFloat width = 40.0;
UIFont *font = [UIFont systemFontOfSize:[UIFont labelFontSize]];
NSString *reducedString = [self string:test reducedToWidth:width withFont:font];
NSLog(#"%#", reducedString);
You cannot know/determine the number of characters that fits in a UILabel with fixed width because some characters are smaler than others, eg l and m.
There are two options:
Use Mono-Space-Fonts (each character has also a fixed width). Then determine the width for one char in your font with your font-size and calculate the number of chars
Allow any number of characters and check on insert if the inserted characters fit.
You have to know what behaviour you want to have. What should happen if there is text that does not fit. If you only want to truncate (like the solution of mortenfast does) then just use UILineBreakModeTailTruncation for the lineBreakMode-property of your UILabel (there are more options, like TruncateHead, Clip, Word Wrap)
Or you just just use the lineBreak property and set it to NSLineBreakByCharWrapping and move on with your life. https://stackoverflow.com/a/29088337/951349
Thanks #Morten. I've updated the sample code to handle word separation. It also eliminates extra spaces in between words. It has not been tested in the field, but my tests have, thus far, proven OK. Please update at your leisure if you find improvements or bug/glitch fixes.
-(NSString*)string:(NSString*)sourceString reducedToWidth:(CGFloat)width withFont:(UIFont*)font {
// if full string is within bounds, simply return the full string
if( [sourceString sizeWithFont:font].width <= width ) return sourceString;
// break up string into words. if <= 1 word, return original string
NSArray* words = [sourceString componentsSeparatedByString:#" "];
NSInteger numWords = [words count];
if( numWords <= 1 ) return sourceString;
// our return var. we populate as we go
NSMutableString* str = [NSMutableString string];
// temp var to test with before adding to return string
NSMutableString* strTemp = [NSMutableString string];
// string to hold word LESS spaces
NSString* strWordTemp = nil;
// the word we're currently on
NSInteger numWord = 0;
// whether we need to add a space (when not last word)
Boolean addSpace = NO;
// loop through our words....
for( NSString* strWord in words ) {
// which word we're on
numWord++;
// eliminate white space
strWordTemp = [strWord stringByReplacingOccurrencesOfString:#" " withString:#""];
// if this word is empty or was a space(s), skip it
if( [strWordTemp isEqualToString:#""] ) continue;
// append to temp string
[strTemp appendString:strWordTemp];
// if we're still within the bounds...
if( [strTemp sizeWithFont:font].width <= width ) {
// default = no extra space
addSpace = NO;
// if we're not the last word, add a space & check for length
if( numWord < numWords ) {
[strTemp appendString:#" "];
// if adding space made it too long, then just don't add it!
if( [strTemp sizeWithFont:font].width > width ) {
// it was too long with space, so we'll just add word
[str appendString:strWordTemp];
break;
}
// otherwise, it's OK to add the space
else addSpace = YES;
}
// append to return string and continue
[str appendFormat:#"%#%#", strWordTemp, ( addSpace ? #" " : #"" )];
}
// otherwise, we're done
else break;
}
// return our result
return str;
}
I would like to test a string to see if anywhere it contains the text "hello". I would like the test to not take into account capitalization. How can I test this string?
Use the below code as reference to find check for a substring into a string.
NSString* string = #"How to test a string for text" ;
NSString* substring = #"string for" ;
NSRange textRange;
textRange =[string rangeOfString:substring options:NSCaseInsensitiveSearch];
if(textRange.location != NSNotFound)
{
//Does contain the substring
}
-[NSString rangeOfString: options:] will do it.
NSRange range = [string rangeOfString:#"hello" options:NSCaseInsensitiveSearch];
BOOL notFound = range.location==NSNotFound;
I am assuming all words are separated by a space, and that there is no punctuation. If there is punctuation.
NSArray *dataArray = [inputString componentsSeparatedByString:#" "];
for(int i=0; i<[dataArray count]){
if([[dataArray objectAtIndex:i] isEqualToString:#"hello"]){
NSLog(#"hello has been found!!!");
}
}
I haven't tested this but it should work in theory.
Check out the docs for ways to remove punctuation and make the string all lower case. This should be pretty straight-forward.
Other solutions here are good but you should really use a regex,
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"^(hello)*$"
options:NSRegularExpressionCaseInsensitive
error:&error];
Docs are here: http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSRegularExpression_Class/Reference/Reference.html