In my module, I create a form with a validate and submit handler. The first field is a text input field, and the second is a file upload field.
My validate handler is getting called and exiting fine. My submit handler never executes. I'm taken back to my form, with an error complaining that I need to enter a value in my upload field (as I set it to be required).
I am new to Drupal.
In Drupal 6, file upload fields cannot be required. You should set required = false or else you'll get this error. I think that it's the same in Drupal 7. You should write your own code in the validation handler to check if the file was uploaded.
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I currently have an Angular 2 app where the user can submit a form to create a new item. When the submit button is clicked, it calls a function that sends the data to the server and navigates to a new page when the server confirms that the data has been saved successfully.
My problem comes because the form submission appends the form parameters to the URL. So for example if I had an input named title and submission took me to the route mytitle which is the input for the title field, Angular (or whatever injects the GET parameters) would try to navigate to mysite.com/mytitle?title=mytitle instead of just mysite.com/mytitle. Even adding [ngModelOptions]="{standalone: true}" to all of my inputs still leaves a question mark with no parameters after it.
This is a problem because it causes Angular to reload the app because the given route does not match any routes in my route definitions. Is there a way to disable the GET parameters being injected into the URL entirely? POST doesn't work either because I have nowhere to post to, and my next URL uses data from the form itself.
I found an answer to my question, the "Submit" button defaulted to being of type "submit", so changing it to type "button" removed the GET parameters injection behavior.
Check setValue in your form control. Example: Set value this way this.form.controls['val'].setValue='' rather than assigning an empty value
(i.e. this.form.controls['val'] == 0).
If your problem still exists, kindly add button type submit to the button and manually give the click function access to it.
I'm developing an application in CakePHP 2.7 and I have a form where that sends off an Ajax request from a file input and returns some information. This information is then stored inside a hidden form field.
I have a custom validation rule that checks against the hidden field and another to see if both have been submitted as the system can only handle one. When the validation rule returns false it flags up an invalidate message to notify the user of the issue. However now I am left with an issue where the hidden field still contains a value and so does the other field the user filled out but I can't remove the value from the hidden field.
Is there any way I can remove the value from the hidden field inside the model?
I have looked at this question on StackOverflow but it wasn't successsful in helping and dates back to an earlier version of CakePHP based on the date of the question.
I want to upload some XML files to Alfresco, so the create con tent form has an input file form element.
I need to check if the XML is well-formed, and I already have the backend validation functions triggered on ResourceBehavior.onContentUpdate. If the XML is malformed, I want to notify the user with a dialog window.
So far, I can prevent the user to submit malformed XML by throwing an exception when the XML is malformed, but I can't figure out how to have share to display an error message.
I have been looking at all the validation JS in share, but remember, file input forms need to be submitted first so that you can have a look at its content, thus the validation has to be server-sided.
Any pointers on where should I begin?
The problem you are going to have is that your backend behaviour is not aware of the specific client session that made the changes and what client session it is that needs to be notified.
If you want to display a useful message then you are going to have to write some additional Share customisation. Some options which you can explore are having an action or webscript that returns whether the XML is valid or not and customising the Share upload form to execute this action/webscript after the file has been uploaded and then return the relevant message to the user.
You'll find a pretty detailed post on modifying the upload form here:
http://www.ixxus.com/blog/2011/09/customising-upload-files-dialog-alfresco-share
If you're feeling lazy then I'd consider just aborting the file creation if the XML is invalid during an onCreate behaviour and then the user will see an 'Internal Error'.
I have a simple form without a entity that I use to send emails. Now I was testing in firefox and if I leave a field empty I will get a message. But now if I open the same form in Safari (that ignores required proprty) I won't get any message. The form->isValid() returs true even when I leave all fields blank...
How to validate this?
The in-browser validation is just a time saver to avoid a request to a server when a field is blank, but it's not a proper validation because it can be disabled on the browser level. You still should validate on the server side.
See this section — you need the NotBlank constraint.
I have problem with form submission to a action of different moudule, say e.g I have a module called "mymobile" from I am calling a action in module "register" which will process the registration, if there is any error in form I am setting the error messages and forwarding to "mymobile" module's page from where I called the action of "register", so it is modifying the header and my Japanese text is getting converted to some junk. Is there any way I can show error messages on my form without change of text? Any alternative for $this->forward() method? I am using symfony 1.1 and I tried $this->rediect() it will refresh the page.
Thank you in advnace