Suppose I have following collection :
{ _id" : ObjectId("4f1d8132595bb0e4830d15cc"),
"Data" : "[
{ "id1": "100002997235643", "from": {"name": "Joannah" ,"id": "100002997235643"} , "label" : "test" } ,
{ "id1": "100002997235644", "from": {"name": "Jon" ,"id": "100002997235644"} , "label" : "test1" }
]" ,
"stat" : "true"
}
How can I retrieve id1 , name , id ,label or any other element?
I am able to get _id field , DATA (complete array) but not the inner elements in DATA.
You cannot query for embedded structures. You always query for top level documents. If you want to query for individual elements from your array you will have to make those element top level documents (so, put them in their own collection) and maintain an array of _ids in this document.
That said, unless the array becomes very large it's almost always more efficient to simply grab your entire document and find the appropriate element in your app.
I don't think you can do that. It is explained here.
If you want to access specific fields, then following MongoDB Documentation,
you could add a flag parameter to your query, but you should redesign your documents for this to be useful:
Field Selection
In addition to the query expression, MongoDB queries can take some additional arguments. For example, it's possible to request only certain fields be returned. If we just wanted the social security numbers of users with the last name of 'Smith,' then from the shell we could issue this query:
// retrieve ssn field for documents where last_name == 'Smith':
db.users.find({last_name: 'Smith'}, {'ssn': 1});
// retrieve all fields *except* the thumbnail field, for all documents:
db.users.find({}, {thumbnail:0});
Related
Guys help me out mongodb query that I want write that.
skip the row by id and find by name matching row. I put my query below suggest me the right way
db.college.find({"_id" : {$ne: ObjectId("5b965696b8bba46518cbefda")}},{ $and:[{ "Name" : "KK" }]})
here am getting all rows of records. but I want to get only matching recor
Both conditions should be in one object like this:
db.college.find({"_id" : { $ne: ObjectId("5b965696b8bba46518cbefda")}, "Name": "KK" })
Second parameter of find represents projection
My MongoDB has a key-value pair structure, inside my document has a data field which is an array that contains many subdocuments of two fields: name and value.
How do I search for a subdocument e.g ( {"name":"position", "value":"manager"}) and also multiple (e.g. {"name":"age", "value" : {$ge: 30}})
EDIT: I am not looking for a specific subdocument as I mentioned in title (not positional reference), rather, I want to retrieve the entire document but I need it to match the two subdocuments exactly.
Here are 2 queries to find the following record:
{
"_id" : ObjectId("sometobjectID"),
"data" : [
{
"name" : "position",
"value" : "manager"
}
]
}
// Both value and name (in the same record):
db.demo.find({$elemMatch: {"value": "manager", "name":"position"}})
// Both value and name (not necessarily in the same record):
db.demo.find({"data.value": "manager", "data.name":"position"})
// Just value:
db.demo.find({"data.value": "manager"})
Note how the . is used, this works for all subdocuments, even if they are in an array.
You can use any operator you like here, including $gte
edit
$elemMatch added to answer because of #Veeram's response
This answer explains the difference between $elemMatch and .
How can I return a set of documents, each not containing a specific item in an inner array?
My data scheme is:
Posts:
{
"_id" : ObjectId("57f91ec96241783dac1e16fe"),
"votedBy" : [
{
"userId" : "101",
"vote": 1
},
{
"userId" : "202",
"vote": 2
}
],
"__v" : NumberInt(0)
}
I want to return a set of posts, non of which contain a given userId in any of the votedBy array items.
The official documentation implies that this is possible:
MongoDB documentation: Field with no specific array index
Though it returns an empty set (for the more simple case of finding a document with a specific array item).
It seems like I have to know the index for a correct set of results, like:
votedBy.0.userId.
This Question is the closest I found, with this solution (Applied on my scheme):
db.collection.find({"votedBy": { $not: {$elemMatch: {userId: 101 } } } })
It works fine if the only inner document in the array matches the one I wish not to return, but in the example case I specified above, the document returns, because it finds the userId=202 inner document.
Just to clarify: I want to return all the documents, that NONE of their votedBy array items have the given userId.
I also tried a simpler array, containing only the userId's as an array of Strings, but still, each of them receives an Id and the search process is just the same.
Another solution I tried is using a different collection for uservotes, and applying a lookup to perform a SQL-similar join, but it seems like there is an easier way.
I am using mongoose (node.js).
User $ne on the embedded userId:
db.collection.find({'votedBy.userId': {$ne: '101'}})
It will filter all the documents with at least one element of userId = "101"
I've read the MongoDB documentation on getting the indexes within a collection, and have also searched SO and Google for my question. I want to get the actual indexed values.
Or maybe my understanding of how MongoDB indexes is incorrect. If I've been indexing a field called text that contains paragraphs, am I right in thinking that what gets indexed is each word in the paragraph?
Either case I want to retrieve the values that were indexed, which db.collection.getIndexes() doesn't seem to be returning.
Well yes and no, in summary.
Indexes work on the "values" of the fields they are supplied to index, and are much like a "card index" in that there is a point of reference to look at to find the location of something that matches that term.
What "you" seem to be asking about here is "text indexes". This is a special index format in MongoDB and other databases as well that looks at the "text" content of a field and breaks down every "word" in that content into a value in that "index".
Typically we do:
db.collection.createIndex({ "text": "text" })
Where the "field name" here is "text" as you asked, but more importantly the type of index here is "text".
This allows you to then insert data like this:
db.collection.insert({ "text": "The quick brown fox jumped over the lazy dog" })
And then search like this, using the $text operator:
db.collection.find({ "$text": { "$search": "brown fox" } })
Which will return and "rank" in order the terms you gave in your query depending how they matched the given "text" of your field in the index on your collection.
Note that a "text" index and it's query does not interact on a specific field. But the index itself can be made over multiple fields. The query and the constraints on the "index" itself are that there can "only be one" text index present on any given collection otherwise errors will occur.
As per mongodb's docs:
"db.collection.getIndexes() returns an array of documents that hold index information for the collection. Index information includes the keys and options used to create the index. For information on the keys and index options, see db.collection.createIndex()."
You first have to create the index on the collection, using the createIndex() method:
db.records.createIndex( { userid: 1 } )
Queries on the userid field are supported by the index:
Example:
db.records.find( { userid: 2 } )
db.records.find( { userid: { $gt: 10 } } )
Indexes help you avoid scanning the whole document. They basically are references or pointers to specific parts of your collection.
The docs explain it better:
http://docs.mongodb.org/manual/tutorial/create-an-index/
I need to update multiple records in mongodb.
From frontend logic , i got the array of id's as below.
ids: [ [ '530ac94c9ff87b5215a0d6e6', '530ac89a7345edc214618b25' ] ]
I have an array of ids as above , i need to update the folder field for all the records in that array.
I tried passing the id's to mongodb query as below , but still that doesn't work.
Post.native(function(err, collection) {
collection.update({
_id : {
"$in" : ids
}
}, { folder : 'X'}, {
multi : true
}, function(err, result) {
console.log(result);
});
});
Please help.
There seem to be two possible problems.
1) your ids array is not an array of ids, it's an array which has a single element which is itself an array, which has two elements. An array of ids would be `[ 'idvalue1', 'idvalue2']
2) your id values inside of arrays are strings - is that how you are storing your "_id" values? If they are ObjectId() type then they are not a string but a type ObjectId("stringhere") which is not the same type and won't be equal to "stringhere".
There is no reason to use the native method in this case. Just do:
Post.update({id : ids}, {folder : 'X'}).exec(console.log);
Waterline automatically does an "in" query when you set a criteria property to an array, and Sails-Mongo automatically translates "id" to "_id" and handles ObjectId translation for you.
Those strings look like the string representation of mongod ObjectIds, so probably what you want to do is turn them into ObjectIds before querying. Assuming you've corrected your problem with the extra level of nesting in the array, that is:
ids = ['530ac94c9ff87b5215a0d6e6', '530ac89a7345edc214618b25']
Then you want to do something like this:
oids = []
for (var i in ids)
oids.push(ObjectId(ids[i]))
db.c.find({_id: {$in: oids}})
Does that fix your problem?