Is there an existing macro or plugin which will turn this
Config.MyData1 = Data++;
Config.MyData10 = Data++;
Config.MyData100 = Data++;
Config.MyData1000 = Data++;
into this?
Config.MyData1 = *Data++;
Config.MyData10 = *Data++;
Config.MyData100 = *Data++;
Config.MyData1000 = *Data++;
Using Delphi with GExpert I used to use "Align Line" (ctrl+alt+z). Is there a similar tool for Netbeans/MPLAB-X?
I haven't seen any similar function in MPLABX. But you may try putting a tab character before the '=' using the replace function.
First, write a tabulation using tab key, and copy this.
Then press 'CTRL+H' and replace all the requires '=' by ' ='.
(The wait space is a tab, it seems to be that it doesn't support writing \t for a tab).
Regards
Related
Sorry, I ran into another question about using PetitParser. I've figured out my recursive issues, but now I have a problem with parentheses. If I need to be able to parse the following two expressions:
'(use = "official").empty()'
'(( 5 + 5 ) * 5) + 5'
I've tried doing something like the following:
final expression = (char('(') & any().starGreedy(char(')')).flatten() & char(')')).map((value) => ParenthesesParser(value));
But that doesnt' work on the first expression.
If I try this:
final expression = (char('(') & any().starLazy(char(')')).flatten() & char(')')).map((value) => ParenthesesParser(value));
It doesn't work on the second expression. Any suggestions on how to parse both?
I think neither of the parsers does what you want: The first parser, the greedy one with starGreedy, will consume up to the last closing parenthesis. The second parser, the lazy one with starLazy, will consume up to the first closing parenthesis.
To parse a balanced parenthesis you need recursion, so that each opening parenthesis is followed by a matching closing one:
final inner = undefined();
final parser = char('(') & inner.star().flatten() & char(')');
inner.set(parser | pattern('^)'));
In the snippet above, the inner parser is recursively trying to either parse another parenthesis pair, or otherwise it simply consumes any character that is not a closing parenthesis.
How can I remove newline character from a string in powerbuilder? I have a column where I can write something and when I press enter it inserts a newline character. I want to remove it when I press save.
Thanks
To remove the Newline character...
ll_pos = PosA(ls_text, "~n")
do while(ll_pos > 0)
ls_text = ReplaceA(ls_text, ll_pos, 1, "")
ll_pos = PosA(ls_text, "~n")
loop
If you need to remove the Carriage Return as well...
ll_pos = PosA(ls_text, "~r~n")
do while(ll_pos > 0)
ls_text = ReplaceA(ls_text, ll_pos, 2, "")
ll_pos = PosA(ls_text, "~r~n")
loop
Another, completely different way to solve the problem is to make your Save button a Default button (third check box in the General tab). This way, when the user presses Enter, that button is actually activated. This prevents you from further processing. Of course, it remains to see if that behaviour is normal / desired.
I want to strip a string of all new lines and commas (and place it into an array), so I created this:
let results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: ",\n"))
However, the newlines are still existing in my array (the commas are being removed). What's the correct way of adding newline to the NSCharacterSet? Or, how to add comma to NSCharacterSet.newLineCharacterSet.
Thanks.
Here is janky solution, but still looking for a more elegant one.
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: ","))
text = results.joinWithSeparator(" ")
results = text.componentsSeparatedByCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
(one-line) SOLUTION:
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: " ,\u{000A}\u{000B}\u{000C}\u{000D}\u{0085}"))
Explanation is below.
You can unite two NSCharacterSet by first using an NSMutableCharacterSet, for example:
let charset = NSMutableCharacterSet(charactersInString: ",")
charset.formUnionWithCharacterSet(NSCharacterSet.newlineCharacterSet())
let results = text.componentsSeparatedByCharactersInSet(charset)
So MartinR brought to my attention that there are more line feeds than just "\n".
I looked at the values used in NSCharacterSet.newlineCharacterSet and added them all, giving me:
var results = text.componentsSeparatedByCharactersInSet(NSCharacterSet(charactersInString: " ,\u{000A}\u{000B}\u{000C}\u{000D}\u{0085}"))
This got rid of all the whitespace, commas, and new lines. Interestingly - when I used all the newline values separately to see if I could figure out which newline was being used in my case, none of them worked. But when used all together, it strips my new lines.
I'm a neuroscience/biomedical engineering major struggling with this whole MATLAB programming ordeal and so far, this website is the best teacher available to me right now. I am currently having trouble with one of my HW problems. What I need to do is take a phrase, find a specific word in it, then take a specific letter in it and increase that letter by the number indicated. In other words:
phrase = 'this homework is so hard'
word = 'so'
letter = 'o'
factor = 5
which should give me 'This homework is sooooo hard'
I got rid of my main error, though I really don;t know how. I exited MATLAB, then got back into it. Lo and behold, it magically worked.
function[out1] = textStretch(phrase, word, letter, stretch)
searchword= strfind(phrase, word);
searchletter strfind(hotdog, letter); %Looks for the letter in the word
add = (letter+stretch) %I was hoping this would take the letter and add to it, but that's not what it does
replace= strrep(phrase, word, add) %This would theoretically take the phrase, find the word and put in the new letter
out1 = replace
According to the teacher, the ones() function might be useful, and I have to concatenate strings, but if I can just find it in the string and replace it, why do I need to concatenate?
Since this is homework I won't write the whole thing out for you but you were on the right track with strfind.
a = strfind(phrase, word);
b = strfind(word, letter);
What does phrase(1:a) return? What does phrase(a+b:end) return?
Making some assumptions about why your teacher wants you to use ones:
What does num = double('o') return?
What does char(num) return? How about char([num num])?
You can concatenate strings like this:
out = [phrase(1:a),'ooooo',phrase(a+b:end)];
So all you really need to focus on is how to get a string which is letter repeated factor times.
If you wanted to use strrep instead you would need to give it the full word you are searching for and a copy of that word with the repeated letters in:
new_phrase = strrep(phrase, 'so', 'sooooo');
Again, the issue is how to get the 'sooooo' string.
See if this works for you -
phrase_split = regexp(phrase,'\s','Split'); %// Split into words as cells
wordr = cellstr(strrep(word,letter,letter(:,ones(1,factor))));%// Stretched word
phrase_split(strcmp(phrase_split,word)) = wordr;%//Put stretched word into place
out = strjoin(phrase_split) %// %// Output as the string cells joined together
Note: strjoin needs a recent MATLAB version, which if unavailable could be obtained from here.
Or you can just use a hack obtained from the m-file itself -
out = [repmat(sprintf(['%s', ' '], phrase_split{1:end-1}), ...
1, ~isscalar(phrase_split)), sprintf('%s', phrase_split{end})]
Sample run -
phrase =
this homework is so hard and so boring
word =
so
letter =
o
factor =
5
out =
this homework is sooooo hard and sooooo boring
So, just wrap the code into a function wrapper like this -
function out = textStretch(phrase, word, letter, factor)
Homework molded edit:
phrase = 'this homework is seriously hard'
word = 'seriously'
letter = 'r'
stretch = 6
out = phrase
stretched_word = letter(:,ones(1,stretch))
hotdog = strfind(phrase, word)
hotdog_st = strfind(word,letter)
start_ind = hotdog+hotdog_st-1
out(start_ind+stretch:end+stretch-1) = out(start_ind+1:end)
out(hotdog+hotdog_st-1:hotdog+hotdog_st-1+stretch-1) = stretched_word
Output -
out =
this homework is serrrrrriously hard
As again, use this syntax to convert to function -
function out = textStretch(phrase, word, letter, stretch)
Well Jessica first of all this is WRONG, but I am not here to give you the solution. Could you please just use it this way? This surely run.
function main_script()
phrase = 'this homework is so hard';
word = 'so';
letter = 'o';
factor = 5;
[flirty] = textStretchNEW(phrase, word, letter, factor)
end
function [flirty] = textStretchNEW(phrase, word, letter, stretch)
hotdog = strfind(phrase, word);
colddog = strfind(hotdog, letter);
add = letter + stretch;
hug = strrep(phrase, word, add);
flirty = hug
end
I am a newbie to using activex controls in matlab. Am trying to control a word document. I need help translating between VBA syntax and Matlab, I think. How would one code the following in matlab?
Sub macro()
With CaptionLabels("Table")
.NumberStyle = wdCaptionNumberStyleArabic
.IncludeChapterNumber = True
.ChapterStyleLevel = 1
.Separator = wdSeparatorHyphen
End With
Selection.InsertCaption Label:="Table", TitleAutoText:="", Title:="", _
Position:=wdCaptionPositionAbove, ExcludeLabel:=0
End Sub
Thanks, I looked at the help and the source but I am still feeling dense. I want to be able to control caption numbering and caption text in an automated report. Am using Tables and figures. I just can't quite get my head around how to code the addition of the captions.
The following code gets me part way there. But I don't have control over numbering style, etc,. I have tried to figure out the activex structure but I can't make sense of it. In particular, In particular the first bit the VB subroutine above.
% Start an ActiveX session with Word
hdlActiveX = actxserver('Word.Application');
hdlActiveX.Visible = true;
hdlWordDoc = invoke(hdlActiveX.Documents, 'Add');
hdlActiveX.Selection.InsertCaption('Table',captiontext);
After some fiddling, I think I got it to work:
%# open Word
Word = actxserver('Word.Application');
Word.Visible = true;
%# create new document
doc = Word.Documents.Add;
%# set caption style for tables
t = Word.CaptionLabels.Item(2); %# 1:Figure, 2:Table, 3:Equation
t.NumberStyle = 0; %# wdCaptionNumberStyleArabic
t.IncludeChapterNumber = false;
t.ChapterStyleLevel = 1;
t.Separator = 0; %# wdSeparatorHyphen
%# insert table caption for current selection
Word.Selection.InsertCaption('Table', '', '', 0, false) %# wdCaptionPositionAbove
%# save document, then close
doc.SaveAs2( fullfile(pwd,'file.docx') )
doc.Close(false)
%# quit and cleanup
Word.Quit
Word.delete
Refer to the MSDN documentation to learn how to use this API. For example, the order of arguments of the InsertCaption function used above.
Note that I had to set IncludeChapterNumber to false, otherwise Word was printing "Error! No text of specified style in document" inside the caption text...
Finally, to find out the integer values of the wd* enums, I am using the ILDASM tool to disassemble the Office Interop assemblies (as this solution suggested). Simply dump the whole thing to text file, and search for the strings you are looking for.
Have a look at the help for actxserver and the source code for xlsread.m in the base MATLAB toolbox. If you're still stuck, then update your question with your progress.
EDIT:
You'll need to check the VBA help, but the first part ought to be possible via something like:
o = hdlWordDoc.CaptionLabels('Table');
o.NumberStyle = <some number corresponding to wdCaptionNumberStyleArabic>;
o.IncludeChapterNumber = true;
o.ChapterStyleLevel = 1;
o.Separator = <some number corresponding to wdSeparatorHyphen>;
In my experience, you have to get the values from the enumerations, such as wdCaptionNumberStyleArabic and wdSeparatorHyphen from a VBA script then hard-code them. You can try the following, but I don't think it works:
o.NumberStyle = 'wdCaptionNumberStyleArabic';
o.Separator = 'wdSeparatorHyphen';
Instead of hard-coding the text values into the code, you can use the enum constants. This will help when a different language of Word is installed.
A list of the Enums can be found here: https://learn.microsoft.com/en-us/office/vba/api/word(enumerations)
So instead of:
Word.Selection.InsertCaption('Table', '', '', 0, false) %# wdCaptionPositionAbove
you can use this:
NET.addAssembly('Microsoft.Office.Interop.Word')
Word.Selection.InsertCaption(...
Microsoft.Office.Interop.Word.WdCaptionLabelID.wdCaptionTable.GetHashCode,...
' My custom table caption text', '', ...
Microsoft.Office.Interop.Word.WdCaptionPosition.wdCaptionPositionAbove.GetHashCode, false)