Given the following code
#Entity
public class Invoice {
#GeneratedValue(strategy = GenerationType.AUTO)
#Id
public Long id;
#Embedded
private InvoiceData data = new InvoiceData();
}
#Embeddable
public class InvoiceData {
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
public Collection<InvoiceLineItem> lineItems;
}
#Entity
public abstract class InvoiceLineItem {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
#Column
private String description;
}
#Entity
public class GoodsLineItem extends InvoiceLineItem {
}
#Entity
public class CostLineItem extends InvoiceLineItem {
}
How would I write a criteria api query that returns all Invoices with a CostLinesItem that's description is 'TAX'?
I am using the metadata API. I have tried various approaches most of which are variations of the 2 listed below. Any pointers/help or 'go read this's will be greatly appreciated.
Attempt 1 (of many):
#Test
public void criteria_api_and_collections() throws Exception {
CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Invoice> query = builder.createQuery(Invoice.class);
Root<Invoice> root = query.from(Invoice.class);
Join<InvoiceData, InvoiceLineItem> lineItems = root.join(Invoice_.data).join(InvoiceData_.lineItems);
query.where(builder.equal(lineItems.get(InvoiceLineItem_.description), ""));
List<Invoice> resultList = em.createQuery(query).getResultList();
System.out.println(resultList);
}
Attempt 2 (of a many):
#Test
public void criteria_api_and_collections() throws Exception {
CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Invoice> query = builder.createQuery(Invoice.class);
Root<Invoice> root = query.from(Invoice.class);
Join<InvoiceData, InvoiceLineItem> lineItems = root.join(Invoice_.data).join(InvoiceData_.lineItems, JoinType.LEFT);
Subquery<CostLineItem> subquery = query.subquery(CostLineItem.class);
Root<CostLineItem> fromLineItem = subquery.from(CostLineItem.class);
subquery.select(fromLineItem);
subquery.where(builder.equal(lineItems.get(InvoiceLineItem_.description), "TAX"));
query.where(builder.in(lineItems).value(subquery));
List<Invoice> resultList = em.createQuery(query).getResultList();
}
Both attempts causes a SQL grammer Exception. An alias is referred to in the resulting SQL that is never created. It looks like the alias should have been assigned to a join in the SQL that does not exist. In other words the InvoiceLineItems are not fetched in the query.
I am not able to make a test right now, but sticking to the Java EE 6 Tutorial, we see that
Embeddable classes may also contain relationships to other entities or
collections of entities. If the embeddable class has such a
relationship, the relationship is from the target entity or collection
of entities to the entity that owns the embeddable class.
This makes me think that the Join Predicate should be defined with the starting Entity Invoice instead of InvoiceData. And this is supported also by the fact that normally the starting Entity should be the query root itself. I would try with something like this:
Join<Invoice, InvoiceLineItem> lineItems = root.join(Invoice_.data).join(InvoiceData_.lineItems);
I swapped out Hibernate 4.1.0.Final for EclipseLink 2.0.0 and it worked.
Related
Given this very simple DTO:
#Entity
public class Employee implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String name;
#OneToOne
private Employee boss;
}
I'd like to make a query that gathers all employee names and their boss' id, put in a nice clean POJO:
public class EmployeeInfo {
private String name;
private Long bossId;
public EmployeeInfo(String name, Long bossId) {
this.name = name;
this.bossId = bossId;
}
}
This query should be of use:
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<EmployeeInfo> query = cb.createQuery(EmployeeInfo.class);
Root<Employee> root = query.from(Employee.class);
query.select(
cb.construct(EmployeeInfo.class,
root.get("name").as(String.class),
root.get("boss").get("id").as(Long.class)));
result = em.createQuery(query).getResultList();
When a bossId is present in the employee column this works just fine. But when no boss id is set the record will be completly ignored. So how do i treat this non existing boss relation as null or 0 for the construct/multiselect?
In pure SQL it is easy:
SELECT name, COALESCE(boss_id, 0) FROM EMPLOYEE;
But for the love of god i cannot make the criteria api do this.
cb.construct(EmployeeInfo.class,
root.get("name").as(String.class),
cb.coalesce(root.get("boss").get("id").as(Long.class), 0L)));
The problem is that root.get("boss") generate query with cross join like this from Employee employee, Employee boss where employee.boss.id=boss.id. So records where employee.boss.id is null are ignored.
To solve the problem you should use root.join("boss", JoinType.LEFT) instead of root.get("boss")
I have a question about usage of nested list projection interface. I have two entity (Parent and child) (they have Unidirectional association)
Parent =>
#Table(name = "parent")
#Entity
public class ParentEntity {
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
private String name;
// other fields........
}
Child =>
#Table(name = "child")
#Entity
public class ChildEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
#NonNull
private String name;
#NonNull
#ManyToOne(fetch = FetchType.LAZY)
private ParentEntity parent;
// other fields........
}
I have two projection interface for select specific columns.
ParentProjection =>
public interface ParentProjection {
String getName();
Set<ChildProjection> getChild();
}
ChildProjection =>
public interface ChildProjection {
String getId();
String getName();
}
I want to take list of ParentProjection which includes with list of ChildProjection.
Repository query like that =>
#Query("select p.name as name, c as child from ParentEntity p left join ChildEntity as c on p.id = c.parent.id")
List<ParentProjection> getParentProjectionList();
This query works, but it selects all columns of ChildEntity, and map only id, name propeties to ChildProjection. (generated query selects all columns, but i want to select only id and name columns)
How can i select only id and name columns (select specific columns for nested list projection interface) and map to ChildProjection fields (using with #Query) ?
Note: I don't need to use class type projection.
You need to add the OneToMany relation to ParentEntity and annotate with Lazy.
Hope it helps (i have tried this).
I am using springboot and springdata with Mysql.
I have 2 entities, Customer & Order:
#Entity
#Table(name = "customers")
public class Customer {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#Column(name = "name")
private String name;
}
#Entity
#Table(name = "orders")
public class Order {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#Column(name="customer_id")
private long customerId;
}
I also have a repository:
#Repository
public interface OrdersRepository extends JpaRepository<Order, Long> {
#Query("select o from Order o, Customer c where o.customerId = c.id")
Page<Order> searchOrders(final Pageable pageable);
}
The method has some more arguments for searching, but the problem is when I send a PageRequest object with sort that is a property of Customer.
e.g.
Sort sort = new Sort(Sort.Direction.ASC, "c.name");
ordersRepository.search(new PageRequest(x, y, sort));
However, sorting by a field of Order works well:
Sort sort = new Sort(Sort.Direction.ASC, "id");
ordersRepository.search(new PageRequest(x, y, sort));
The error I get is that c is not a property of Order (but since the query is a join of the entities I would expect it to work).
Caused by: org.hibernate.QueryException: could not resolve property c of Order
Do you have any idea how I can sort by a field of the joined entity?
Thank you
In JPA , the thing that you sort with must be something that is returned in the select statement, you can't sort with a property that is not returned
You got the error because the relationship is not modeled properly. In your case it is a ManyToOne relation. I can recomend the wikibooks to read further.
#Entity
#Table(name = "orders")
public class Order {
#Id
#GeneratedValue(strategy= GenerationType.IDENTITY)
#Column(name="id", nullable = false)
protected long id;
#ManyToOne
#JoinColumn(name="customer_id", referencedColumnName = "id")
private Customer customer;
}
The query is not needed anymore because the customer will be fetched.
#Repository
public interface OrdersRepository extends PagingAndSortingRepository<Order, Long> {
}
Now you can use nested properties.
Sort sort = new Sort(Sort.Direction.ASC, "customer.name");
ordersRepository.findAll(new PageRequest(x, y, sort));
I have the following entities and would like to seek help on how to query for selected attributes from both side of the relationship. Here is my model. Assume all tables are properly created in the db. JPA provider I am using is Hibernate.
#Entity
public class Book{
#Id
private long id;
#Column(nullable = false)
private String ISBNCode;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = false)
private Person<Author> author;
#ManyToOne(cascade = CascadeType.DETACH, fetch = FetchType.LAZY, optional = true)
private Person<Borrower> borrower;
}
#Inheritance
#DiscriminatorColumn(name = "personType")
public abstract class Person<T>{
#Id
private long id;
#OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private Info information;
}
#Entity
#DiscriminatorValue(PersonType.Author)
public class Author extends Person<Author> {
private long copiesSold;
}
#Entity
#DiscriminatorValue(PersonType.Borrower)
public class Borrower extends Person<Borrower> {
.....
}
#Entity
public class Info {
#Id
private long id;
#Column(nullable=false)
private String firstName;
#Column(nullable=false)
private String lastName;
......;
}
As you can see, the book table has a many to one relation to Person that is not nullable and Person that is nullable.
I have a requirement to show, the following in a tabular format -
ISBNCode - First Name - Last Name - Person Type
How can I write a JPA query that will allow me to select only attributes that I would want. I would want to get the attributes ISBN Code from Book, and then first and last names from the Info object that is related to Person Object that in turn is related to the Book object. I would not want to get all information from Info object, interested only selected information e.g first and last name in this case.
Please note that the relation between the Borrower and Book is marked with optional=true, meaning there may be a book that may not have been yet borrowed by someone (obviously it has an author).
Example to search for books by the author "Marc":
Criteria JPA Standard
CriteriaQuery<Book> criteria = builder.createQuery( Book.class );
Root<Book> personRoot = criteria.from( Book.class );
Predicate predicate = builder.conjunction();
List<Expression<Boolean>> expressions = predicate.getExpressions();
Path<Object> firtsName = personRoot.get("author").get("information").get("firstName");
expressions.add(builder.equal(firtsName, "Marc"));
criteria.where( predicate );
criteria.select(personRoot);
List<Book> books = em.createQuery( criteria ).getResultList();
Criteria JPA Hibernate
List<Book> books = (List<Book>)sess.createCriteria(Book.class).add( Restrictions.eq("author.information.firstName", "Marc") ).list();
We recommend using hibernate criterias for convenience and possibilities.
Regards,
Got GlassFish v3. I have an one-to-many entity. The problem is, that EclipseLink seems to ignore the fetch EAGER mode.
Here is my entities.
#Entity
public class Person implements Serializable
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
#OneToMany(mappedBy = "person", fetch = FetchType.EAGER)
private List<Hobby> hobbies;
// getter and setter
}
A 1:n relationship
#Entity
public class Hobby
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
#ManyToOne
#JoinColumn
private Person person;
// getter and setter
}
And the bean
#javax.ejb.Remote
public interface Testing
{
public void addTestData();
public List<Person> getTestData();
}
#javax.ejb.Stateless
public class TestingBean implements Testing
{
#javax.persistence.PersistenceContext
private EntityManager entityManager;
public void addTestData()
{
Person p = new Person();
p.setName("JOE");
entityManager.persist(p);
Hobby h1 = new Hobby();
h1.setName("h1");
h1.setPerson(p);
entityManager.persist(h1);
}
public List<Person> getTestData()
{
TypedQuery<Person> gridQuery = entityManager.createQuery("SELECT e FROM Person e", Person.class);
return gridQuery.getResultList();
}
}
EDIT Client:
InitialContext context = new InitialContext();
Testing test = (Testing)context.lookup("java:global/dst2_1/TestingBean");
test.addTestData();
for(Person p: test.getTestData()) {
System.out.println(p.getName());
for(Hobby b : p.getHobbys()) {
System.out.println(b.getName());
}
}
context.close();
Using MySQL - Storing the data works. But if I fetch the data only the person is returned - not hobbies. Coudld you tell me what is wrong in my code?
EDIT sorry have tried so many things ... The code shown as above produces:
Exception Description: An attempt was made to traverse a
relationship using indirection that had a null Session. This often
occurs when a n entity with an uninstantiated LAZY relationship is
serialized and that lazy relationship is traversed after
serialization. To avoid this issue, ins tantiate the LAZY
relationship prior to serialization.
But the Person is returned correctly. Why does it specify LAZY while I am using EAGER?
You code looks correct. I can't see any way that the EAGER could be ignored.
Are you sure you get the error with this attribute, not another one?
Also ensure you recompile and deployed your code correctly. You most like have an old version deployed.
Make the eager object Serializable