I've "users" collection with a "watchlists" field, which have many inner fields too, one of that is "arrangeable_values" (the second field within "watchlists").
I need to find for each user in "users" collection, each "arrangeable_values" within "watchlists".
How can I do that with mongodb shell ?
Here is an example of data model :
> db.users.findOne({'nickname': 'superj'})
{
"_id" : ObjectId("4f6c42f6018a590001000001"),
"nickname" : "superj",
"provider" : "github",
"user_hash" : null,
"watchlists" : [
{
"_id" : ObjectId("4f6c42f7018a590001000002"),
"arrangeable_values" : {
"description" : "My introduction presentation to node.js along with sample code at various stages of building a simple RESTful web service with journey, cradle, winston, optimist, and http-console.",
"tag" : "",
"html_url" : "https://github.com/indexzero/nodejs-intro"
},
"avatar_url" : "https://secure.gravatar.com/avatar/d43e8ea63b61e7669ded5b9d3c2e980f?d=https://a248.e.akamai.net/assets.github.com%2Fimages%2Fgravatars%2Fgravatar-140.png",
"created_at" : ISODate("2011-02-01T10:20:29Z"),
"description" : "My introduction presentation to node.js along with sample code at various stages of building a simple RESTful web service with journey, cradle, winston, optimist, and http-console.",
"fork_" : false,
"forks" : 13,
"html_url" : "https://github.com/indexzero/nodejs-intro",
"pushed_at" : ISODate("2011-09-12T17:54:58Z"),
"searchable_values" : [
"description:my",
"description:introduction",
"description:presentation",
"html_url:indexzero",
"html_url:nodejs",
"html_url:intro"
],
"tags_array" : [ ],
"watchers" : 75
},
{
"_id" : ObjectId("4f6c42f7018a590001000003"),
"arrangeable_values" : {
"description" : "A Backbone alternative idea",
"tag" : "",
"html_url" : "https://github.com/maccman/spine.todos"
},
"avatar_url" : "https://secure.gravatar.com/avatar/baf018e2cc4616e4776d323215c7136c?d=https://a248.e.akamai.net/assets.github.com%2Fimages%2Fgravatars%2Fgravatar-140.png",
"created_at" : ISODate("2011-03-18T11:03:42Z"),
"description" : "A Backbone alternative idea",
"fork_" : false,
"forks" : 31,
"html_url" : "https://github.com/maccman/spine.todos",
"pushed_at" : ISODate("2011-11-20T22:59:45Z"),
"searchable_values" : [
"description:a",
"description:backbone",
"description:alternative",
"description:idea",
"html_url:https",
"html_url:github",
"html_url:com",
"html_url:maccman",
"html_url:spine",
"html_url:todos"
],
"tags_array" : [ ],
"watchers" : 139
}
]
}
For the document above, the following find() query would extract both the "nickname" of the document, and its associated "arrangeable_values" (where the document is in the users collection):
db.users.find({}, { "nickname" : 1, "watchlists.arrangeable_values" : 1 })
The result you get for your single document example would be:
{ "_id" : ObjectId("4f6c42f6018a590001000001"), "nickname" : "superj",
"watchlists" : [
{ "arrangeable_values" : { "description" : "My introduction presentation to node.js along with sample code at various stages of building a simple RESTful web service with journey, cradle, winston, optimist, and http-console.", "tag" : "", "html_url" : "https://github.com/indexzero/nodejs-intro" } },
{ "arrangeable_values" : { "description" : "A Backbone alternative idea", "tag" : "", "html_url" : "https://github.com/maccman/spine.todos" } }
] }
MongoDB queries return entire documents. You are looking for a field inside an array inside of the document and this will break the find().
The problem here is that any basic find() query, will return all matching documents. The find() does have the option to only return specific fields. But that will not work with your array of sub-objects. You could returns watchlists, but not watchlist entries that match.
As it stands you have two options:
Write some client-side code that loops through the documents and does the filtering. Remember that the shell is effectively a javascript driver, so you can write code in there.
Use the new aggregation framework. This will have a learning curve, but it can effectively extract the sub-items you're looking for.
Related
I am new to MongoDB and am attempting a query using Spring Boot Data Mongo Templates. Below is the sample data that I’m using for this application:
{
"book" : {
"isbn" : "ABCD1234",
"publisher" : "Penguin",
"dateCheckedOutLast" : "2019-12-22",
"library" : "Pickwah"
},
"isLost" : false,
},
{
"book" : {
"isbn" : "ABCD1234",
"publisher" : "Penguin",
"dateCheckedOutLast" : "2018-12-22",
"library" : "BlueRidge"
},
"isLost" : false,
},
{
"book" : {
"isbn" : "DECF1234",
"publisher" : "Marvel",
"dateCheckedOutLast" : "2019-07-22",
"library" : "Pickwah"
},
"isLost" : false
},
{
"book" : {
"isbn" : "DECF1234",
"publisher" : "Marvel",
"dateCheckedOutLast" : "2020-01-07",
"library" : "BlueRidge"
},
"isLost" : false
}
I would like the query to return all the books in BlueRidge library such that the dateCheckedOutLast at BlueRidge library is greater than the dateCheckedOutLast at Pickwah library. The association between the books in the collection is the isbn attribute which uniquely identifies the books.
I have attempted the following code (BookData is the name of the Mongo Collection), it appears that when I try to compare the two date fields (dateCheckedOutLast) after the lookup, it fails.
Aggregation agg = newAggregation(
match(Criteria.where("book.library").is("BlueRidge")),
lookup("BookData", "book.isbn”, " book.isbn" , "anotherLib"),
unwind("anotherLib"),
match(Criteria.where("anotherLib.book.library").is("Pickwah")),
match(Criteria.where("book.dateCheckedOutLast")
.gt("anotherLib.book.dateCheckedOutLast"));
The correct query output should return 1 document (given the sample data) with "isbn = DECF1234".
Any feedback is appreciated. Thank you!
> db.movmodels.findOne()
{
"_id" : ObjectId("55320b0e0e9e0d9d0540593c"),
"username" : "punk",
"favMovies" : [
{
"alternate_ids" : {
"imdb" : "0137523"
},
"abridged_cast" : [
{
"characters" : [
"Tyler"
],
"id" : "162652627",
"name" : "Brad Pitt"
},
{
"characters" : [
"Narrator"
],
"id" : "162660884",
"name" : "Edward Norton"
},
{
"characters" : [
"Robert"
],
"id" : "162676383",
"name" : "Meat Loaf"
},
{
"characters" : [
"Angel Face"
],
"id" : "162653925",
"name" : "Jared Leto"
},
{
"characters" : [
"Boss"
],
"id" : "770706064",
"name" : "Zach Grenier"
}
],
"synopsis" : "",
"ratings" : {
"audience_score" : 96,
"audience_rating" : "Upright",
"critics_score" : 80,
"critics_rating" : "Certified Fresh"
},
"release_dates" : {
"dvd" : "2000-06-06",
"theater" : "1999-10-15"
},
"critics_consensus" : "",
"runtime" : 139,
"mpaa_rating" : "R",
"year" : 1999,
"title" : "Fight Club",
**"id" : "13153"**
}
],
"__v" : 0
}
This is my data in mongodb.
As I am new to mongodb I wanted to know query to get movie with a particular id.
The query that I tried is. I need to get the movie based on id so that I can remove it from my database
db.movmodels.findOne({username:"punk"},{favMovies:{id:13153}})
but this gives me error.
2015-04-18T05:41:26.221-0400 E QUERY Error: error: {
"$err" : "Can't canonicalize query: BadValue ported projection option: favMovies: { id: 13153.0 }",
"code" : 17287
}
at Error (<anonymous>)
at DBQuery.next (src/mongo/shell/query.js:259:15)
at DBCollection.findOne (src/mongo/shell/collection.js:188:22)
at (shell):1:14 at src/mongo/shell/query.js:259
There are several problems with your query:
The second parameter to find() is a projection, not part of the query. What you want is to supply one document for the query that has two properties: {"username" : "punk", favMovies : { ... } }
However, you also don't want to compare the entire sub-document favMovies, but you only want to match on one of its properties, the id, which requires to 'reach into the object' using the dot operator: {username:"punk", "favMovies.id" : 13153}.
However, that will probably not work yet, because 13153 is not the same as "13153", the latter being a string while the former is a number in JSON.
db.movmodels.findOne({username:"punk", "favMovies.id" : "13153"})
Keep in mind, however, that this will find the entire document for the user named "punk". I'm not sure what exactly your data structure should look like, but it appears you'll have to $pull the movie from the user. In general, I'd say you're embedding too much data into the user, but that's hard to tell without knowing the exact use case.
Here you go:
If you just wanted to get first user who has this fav movie:
db.movmodels.findOne({"favMovies.id": 13153});
And, if you want to know if that user has that movie as favorite.
db.movmodels.findOne({"favMovies.id": 13153, username:"punk"});
Second argument in the findOne is used to only return particular field.
You can use also $elemMatch projection operator (not to be confused with the $elemMatch query operator)
db.movmodels.find({username:"punk"},{favMovies:{$elemMatch:{id:"13153"}}});
`
If you want to find a movie that has another movie (with id 13153) in 'favMovies' array, then write the query as below:
db.movmodels.findOne({username:"punk",'favMovies.id':13153})
And if you want to find a movie with _id 55320b0e0e9e0d9d0540593cwrite the following query:
db.movmodels.findOne({username:"punk",'_id':ObjectId("55320b0e0e9e0d9d0540593c")})
I need get a specific object in array of array in MongoDB.
I need get only the task object = [_id = ObjectId("543429a2cb38b1d83c3ff2c2")].
My document (projects):
{
"_id" : ObjectId("543428c2cb38b1d83c3ff2bd"),
"name" : "new project",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b"),
"members" : [
ObjectId("5424ac37eb0ea85d4c921f8b")
],
"US" : [
{
"_id" : ObjectId("5434297fcb38b1d83c3ff2c0"),
"name" : "Test Story",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b"),
"tasks" : [
{
"_id" : ObjectId("54342987cb38b1d83c3ff2c1"),
"name" : "teste3",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
},
{
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
]
}
]
}
Result expected:
{
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
But i not getting it.
I still testing with no success:
db.projects.find({
"US.tasks._id" : ObjectId("543429a2cb38b1d83c3ff2c2")
}, { "US.tasks.$" : 1 })
I tryed with $elemMatch too, but return nothing.
db.projects.find({
"US" : {
"tasks" : {
$elemMatch : {
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2")
}
}
}
})
Can i get ONLY my result expected using find()? If not, what and how use?
Thanks!
You will need an aggregation for that:
db.projects.aggregate([{$unwind:"$US"},
{$unwind:"$US.tasks"},
{$match:{"US.tasks._id":ObjectId("543429a2cb38b1d83c3ff2c2")}},
{$project:{_id:0,"task":"$US.tasks"}}])
should return
{ task : {
"_id" : ObjectId("543429a2cb38b1d83c3ff2c2"),
"name" : "jklasdfa_XXX",
"author" : ObjectId("5424ac37eb0ea85d4c921f8b")
}
Explanation:
$unwind creates a new (virtual) document for each array element
$match is the query part of your find
$project is similar as to project part in find i.e. it specifies the fields you want to get in the results
You might want to add a second $match before the $unwind if you know the document you are searching (look at performance metrics).
Edit: added a second $unwind since US is an array.
Don't know what you are doing (so realy can't tell and just sugesting) but you might want to examine if your schema (and mongodb) is ideal for your task because the document looks just like denormalized relational data probably a relational database would be better for you.
I have two MongoDB collections: The first is a collection that includes frequency information for different IDs and is shown (truncated form) below:
[
{
"_id" : "A1",
"value" : 19
},
{
"_id" : "A2",
"value" : 6
},
{
"_id" : "A3",
"value" : 12
},
{
"_id" : "A4",
"value" : 8
},
{
"_id" : "A5",
"value" : 4
},
...
]
The second collection is more complex and contains information for each _id listed in the first collection (it's called frequency_collection_id in the second collection), but frequency_collection_id may be inside two lists (info.details_one, and info.details_two) for each record:
[
{
"_id" : ObjectId("53cfc1d086763c43723abb07"),
"info" : {
"status" : "pass",
"details_one" : [
{
"frequency_collection_id" : "A1",
"name" : "A1_object_name",
"class" : "known"
},
{
"frequency_collection_id" : "A2",
"name" : "A2_object_name",
"class" : "unknown"
}
],
"details_two" : [
{
"frequency_collection_id" : "A1",
"name" : "A1_object_name",
"class" : "known"
},
{
"frequency_collection_id" : "A2",
"name" : "A2_object_name",
"class" : "unknown"
}
],
}
}
...
]
What I'm looking to do, is merge the frequency information (from the first collection) into the second collection, in effect creating a collection that looks like:
[
{
"_id" : ObjectId("53cfc1d086763c43723abb07"),
"info" : {
"status" : "pass",
"details_one" : [
{
"frequency_collection_id" : "A1",
"name" : "A1_object_name",
"class" : "known",
**"value" : 19**
},
{
"frequency_collection_id" : "A2",
"name" : "A2_object_name",
"class" : "unknown",
**"value" : 6**
}
],
"details_two" : [
{
"frequency_collection_id" : "A1",
"name" : "A1_object_name",
"class" : "known",
**"value" : 19**
},
{
"frequency_collection_id" : "A2",
"name" : "A2_object_name",
"class" : "unknown",
**"value" : 6**
}
],
}
}
...
]
I know that this should be possible with MongoDB's MapReduce functions, but all the examples I've seen are either too minimal for my collection structure, or are answering different questions than I'm looking for.
Does anyone have any pointers? How can I merge my frequency information (from my first collection) into the records (inside my two lists in each record of the second collection)?
I know this is more or less a JOIN, which MongoDB does not support, but from my reading, it looks like this is a prime example of MapReduce.
I'm learning Mongo as best I can, so please forgive me if my question is too naive.
Just like all MongoDB operations, a MapReduce always operates only on a single collection and can not obtain info from another one. So you first step needs to be to dump both collections into one. Your documents have different _id's, so it should not be a problem for them to coexist in the same collection.
Then you do a MapReduce where the map function emits both kinds of documents for their common key, which is their frequency ID.
Your reduce function will then receive an array of two documents for each key: the two documents you have received. You then just have to merge these two documents into one. Keep in mind that the reduce-function can receive these two documents in any order. It can also happen that it gets called for a partial result (only one of the two documents) or for an already completed result. You need to handle these cases gracefully! A good implementation could be to create a new object and then iterate the input-documents copying all existing relevant fields with their values to the new object, so the resulting object is an amalgamation of the input documents.
I have two collection as bellow products has reference of user. i search product by name & in return i want combine output of product and user using map reduce method
user collection
{
"_id" : ObjectId("52ac5dd1fb670c2007000000"),
"company" : {
"about" : "This is textile machinery dealer",
"contactAddress" : [{
"address" : "abcd",
"city" : "52ac4bc6fb670c1007000000",
"zipcode" : "39as46as80"
},{
"address" : "abcd",
"city" : "52ac4bc6fb670c1007000000",
"zipcode" : "39as46as80"
}],
"fax" : "58784868",
"mainProducts" : "ads,asd,asd",
"mobileNumber" : "9537236588",
"name" : "krishna steels",
}
"user" : ObjectId("52ac4eb7fb670c0c07000000")
}
product colletion
{
"_id" : ObjectId("52ac5722fb670cf806000002"),
"category" : "52a2a9cc48a508b80e00001d",
"deliveryTime" : "10 days after received the ",
"price" : {
"minPrice" : "2000",
"maxPrice" : "3000",
"perUnit" : "5288ac6f7c104203e0976851",
"currency" : "INR"
},
"productName" : "New Mobile Solar Charger with Carabiner",
"rejectReason" : "",
"status" : 1,
"user" : ObjectId("52ac4eb7fb670c0c07000000")
}
This cannot be done. Mongo support Map Reduce only on one collection. You could try to fetch and merge in a java collection. Couple of days back I solved a similar problem using java collection.
Click to see similar response about joins and multi collection not supported in mongo.
This can be done using two map reduces.
You run your first MR and then you reduce out the second MR onto the results of the first.
You shouldn't do this though. JOINs are not designed to be done through MR, in fact it sounds like you are trying to do this MR with inline output which in itself is a very bad idea.
MRs are not designed to run inline to the application.
You would be better off doing the JOIN else where.