My code ,
-(NSString *)trimDateStringInRequiredFormat:(NSString *)dateInString{
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"yyyy-MM-dd hh:mm:ss"];
NSDate *date = [dateFormatter dateFromString:dateInString];
[dateFormatter setDateFormat:#"hh:mm aaa"];
NSString *dateDisplay = [dateFormatter stringFromDate:date];
return dateDisplay;
}
The above worked properly when my date is 2012-06-06 12:00:00 and I got appropriate output like 12:00 AM. But when I send my date like 2012-06-06 15:00:00 it doesn't return me appropriate output, instead, it returns me null output. When I'm trying to trace this function the 2012-06-06 15:00:00 date on NSDate *date = [dateFormatter dateFromString:dateInString]; this line not properly converted. Why did this happen? where am I wrong in this code???
try doing:
[dateFormatter setDateFormat:#"yyyy-MM-dd HH:mm:ss"];
With hh you have the 12h format, with HH you use 24h format
This is because for 24 Hr format you need to use HH instead of hh
Related
When i am
[dateFormatter setDateFormat:#"HH:mm"]
using to fetch the current hour
i am getting correct time till 12:59 but after that it again starts from 1:00 i.e. 12:59 is displayed as 12:59 but 14:00 is displyed as 2:00.
Please let me if anyone is also having a similar problem and suggest a solution.
Thanks
Please check the code below.
NSDateFormatter *dateFormator = [[NSDateFormatter alloc] init];
dateFormator.dateStyle = NSDateFormatterMediumStyle;
dateFormator.dateFormat=#"HH:mm:ss";
NSCalendar * calender=[[NSCalendar alloc]initWithCalendarIdentifier:[NSGregorianCalendar autorelease]];
NSDateComponents * component=[calender components:NSHourCalendarUnit|NSMinuteCalendarUnit fromDate:date];
I agree with
[dateFormatter setDateFormat:#"HH:mm"]
should give you the time in 24 Hours. But this doesn't work if the user set 24 hour to off. Despite using HH in a format string, the user setting overrides this. This might be the problem in your case!
Use this one
NSDate *date = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"YYYY-MM-dd kk:mm:ss"];
[dateFormatter setLocale:[NSLocale currentLocale]];
NSString *dateString = [dateFormatter stringFromDate:date];
You can use
[dateFormatter setDateFormat:#"H:mm"]
for 24 hour time format
Set your dateformat to
[dateFormatter setDateformat:#"HH:MM a"];
Try this code
[dateFormatter setDateFormat:#"hh:mm:ss"];
HH : 24 hour format
hh : 12 hour format
So in your case
//after conversion to date
if ON
[formatter setDateFormat:#"YYYY-MM-dd HH:mm:ss"];
if OFF
[formatter setDateFormat:#"YYYY-MM-dd hh:mm:ss a"];
Hope it works for you.
I am trying to convert NSString into NSDate in 12 hours format. (in iOS 6)
Code :
NSString *Bdt = #"05/23/2012 08:00 AM"
NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease];
[df setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
[df setDateFormat:#"MM/dd/yyyy hh:mm a"];
NSDate *bd = [df dateFromString:Bdt];
NSLog(#"%#",bd);
Output:
2012-05-23 08:00:00 +0000 it should be 2012-05-23 08:00 AM
Whats wrong in the code ?
Thanks
If you want date in 2012-05-23 08:00 AM style
Create a dateformatter and setDateFormat as yyyy-MM-dd hh:mm a
NSString *Bdt = #"05/23/2012 08:00 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init] ;
[df setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
[df setDateFormat:#"MM/dd/yyyy hh:mm a"];
NSDate *bd = [df dateFromString:Bdt];
NSDateFormatter *dateFormatter=[NSDateFormatter new];
[dateFormatter setDateFormat:#"yyyy-MM-dd hh:mm a" ];
NSString *datestr=[dateFormatter stringFromDate:bd];
NSLog(#"%#",datestr);
*Note : I am using ARC, so objects are not released/autoreleased.
EDIT:
NSDate will be in this format ONLY : 2012-05-23 08:00:00 +0000.
For any other format you need to use NSString.
Nothing is wrong with it. You are printing an NSDate in NSLog which is very different than creating an NSString with a specific format.
It seems your confusing the internal NSDate representation with string formatting. NSDate stores the date internally in a way different from how it is represented by humans. Just like NSString stores strings in a format that may not be what you ultimately want it encoded as, eg. ASCII or UTF-8. When you are calling NSLog you are getting a diagnostic message showing the date according to the string returned by - (NSString *)description or possibly - (NSString *)debugDescription.
One simple thing on conversion from NSString to NSDate. How can I convert Mon, 27 August 2012 01:30 AM to NSDate in this same format. I tried with NSDateFormatter. But I am not getting it in this required format. Can anyone help? This is what I tried.
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEEE,dd MM yyyy HH:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
NSDateFormatter is to specify the format that will appear in the date-string when extracting string from date or the format that is in the date-string when extracting date from string
So whenever you extract NSDate from a NSString, NSDate is always obtained in default date format(eg 2012-08-27 00:30:00 +0000)... only the when you extract NSString from NSDate, NSString can be obtained in desired(custom) format that you set in NSDateFormatter.
I hope this will help you sure!
NSDateFormatter *dateformater=[[[NSDateFormatter alloc] init]autorelease];
[dateformater setDateFormat:#"EEEE,dd MMMM yyyy HH:mm a"];
NSDate *todayTmp=[NSDate date];
NSString *conversionDate=[dateformater stringFromDate:todayTmp];
Note : (Upper case) HH for 24h time format, (Lower case) hh for 12h time format
NSString *myDateAsAStringValue = #"Mon, 27 August 2012 01:30 AM";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSDate *myDate = [[NSDate alloc]init];
myDate = [df dateFromString:myDateAsAStringValue];
[df release];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"EEE, dd MMM yyyy HH:mm a"];
NSString *strDate = [dateFormatter stringFromDate:myDate];
NSLog(#"%#", strDate);
[dateFormatter release];
please use below code
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
your formatter is wrong
check this one
NSLog will return NSDate in a fixed format, i guess.
If we need Date in different format, we should have to format it via NSDateFormatter and get it as NSString.
Just a guess.
Don't forget to set the correct locale! If your device does not use an english locale NSDateFormatter can have problems to convert Mon and August into useful information because Mon is not the correct abbreviation for Monday in your language. For example in Germany the correct three letter abbreviation for Monday is Mon..
If you parse dates that have words in it you have to set the correct locale.
This should work:
NSDateFormatter *df=[[NSDateFormatter alloc] init];
[df setDateFormat:#"EEE,dd MMMM yyyy hh:mm a"];
NSLocale *posixLocale = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[df setLocale:posixLocale];
NSDate *date1 = [df dateFromString:#"Mon,27 August 2012 01:30 AM"];
NSLog(#"%#",date1);
EEE is the dateformatter code for a three letter weekday abbreviation.
hh is the dateformatter code for Hours between 1 and 12. HH means 0-23
MMMM is the full month, MM would be the numeric value (= 08) of the month.
I have stuck in issue in which i have to convert date format is Thu, 28 Jul 2011 22:33:57 +0000 into yyyy-mm-dd hh:mm:ss
please give me some idea how to do this?
What you want is to use the NSDateFormatter. Something like this:
NSDateFormatter* f = [[[NSDateFormatter alloc] init] autorelease];
[f setDateFormat:#"yyyy-MM-dd hh:mm:ss"];
NSString* dateString = [f stringFromDate:date];
Do note that the hours will still follow the users selected locale. Use kk:mm:ss to enforce a 24-hour time.
what have you tried? it's difficult to answer questions like this...
first you have to parse the date into an NSDate, use an NSDateFormatter, the incoming format looks like POSIX date format so should be easy.
then you want to output to the format you specify with another NSDateFormatter
You need to use an NSDateformatter to convert the first date to a string with the following syntax.
NSDateFormatter * dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSString *dateString = [dateFormatter stringFromDate: [NSDate date]]; //Put whatever date you want to convert
Then if you want the date as an NSDate and you have the string generated above just put the following code.
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat: #"yyyy-MM-dd hh:mm:ss"];
NSDate * date = [dateFormatter dateFromString: dateString]; //String generated above
NSDate *My_StartDate,*My_EndDate ;
NSDateFormatter * df= [[NSDateFormatter alloc]init];
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
My_StartDate = [df dateFromString:#"01/05/2010 10:15:33"];
My_EndDate = [df dateFromString:#"01/05/2010 10:45:33"];
NSLog(#"%#",My_StartDate);
NSLog(#"%#",My_EndDate);
In the log i get something like this for the my_startdate as 2010-05-01 04:45:33 +0000 and end date as 2010-05-01 05:15:33 +0000 instead i should have got value as for start date as 2010-05-01 10:15:33 +0000 and end date as 2010-05-01 10:45:33 +0000
Try with below function:
-(NSString *)getDateStringFromDate :(NSDate *)dateValue{
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setTimeStyle:NSDateFormatterShortStyle];
[timeFormat setDateFormat:#"HH:mm:ss"];
//[timeFormat setDateFormat:#"HH:mm"];
//[timeFormat setDateFormat:#"HH:mm a"];
////
NSString *theDate = [dateFormat stringFromDate:dateValue];
NSString *theTime = [timeFormat stringFromDate:dateValue];
NSLog(#"\n"
"theDate: |%#| \n"
"theTime: |%#| \n"
, theDate, theTime);
return theDate;
}
Change Format of data as per your need.
Let me know in case of any difficulty.
Cheers.
This shows date which follow American standard time string but by this reason you don't get any problem in making your logic.Also
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
this format using 12 hour format (means 2:03 pm and 2:03 am) and date object never use am and pm for showing date object value but when you convert it correctly then it gives you right date and time.
If you feel you get any problem then use different locale for that.
It is displaying asper the GMT+4.30 time.It displays like that only.When you are converting that date to string using the DateFormatter it gives the same date(Whichever you want like start date as 01/05/2010 10:15:33 and end date as 01/05/2010 10:45:33).
NSDateFormatter * dateformatter= [[NSDateFormatter alloc]init];
[dateformatter setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
NSString *dat = [dateformatter stringfromDate:My_StartDate];
then you will get the output as 01/05/2010 10:15:33
You might want to set the time zone of the date formatter to GMT here. Do it using
[df setTimeZone:[NSTimeZone timeZoneWithName:#"GMT"]];
before you do dateFromString: calls. This will give you what you want.
Just need to update here in your code:
I might be like that your time would be in 24 hours format, so at that time you need to use this ....other than that you need to set the timezone.
Follow this link for All zone : http://unicode.org/reports/tr35/tr35-6.html#Date%5FFormat%5FPatterns
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
to
[df setDateFormat:#"dd/MM/yyyy HH:mm:ss"];
You are Done ;)