I have used this code for replacing "\n" with "", but it is not working.
How can I do it?
NSString *descString = [values objectForKey:#"description"];
descString = [descString stringByReplacingOccurrencesOfString:#"\n" withString:#""];
NSLog(#"Description String ---->>> %#",descString);
catlog.description = descString;
[webview loadHTMLString:catlog.description baseURL:nil];
webview.opaque = NO;
try this
NSString *s = #"foo/bar:baz.foo";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:#"/:."];
s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: #""];
NSLog(#"%#", s);
descString = [descString stringByReplacingOccurrencesOfString:#"\\n" withString:#""];
For more information refer to stringByReplacingOccurrencesOfString:withString: method
Hope this helps you.
UPDATE
Swift 3.0
descString.replacingOccurrences(of: "\\n", with: "");
and If I am not wring it will also work for Swift 4.0
Related
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
iphone sdk - Remove all characters except for numbers 0-9 from a string
i have string with a phone number as
mynumber = #"(334)687-6619";
I am using
NSString *phoneURLString = [NSString stringWithFormat:#"tel:%#", phoneNumber];
NSURL *phoneURL = [NSURL URLWithString:phoneURLString];
[[UIApplication sharedApplication] openURL:phoneURL];
to make a call.
But due to "(" , ")" my method is not able to make a call.
Please suggest me to make a right string
something like
"1-800-555-1212" or something like that.
Thanks
You can Use
NSString *s = #"(334)687-6619";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:#"("];
s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: #""];
s = [s stringByReplacingOccurrencesOfString:#")" withString:#"-"];
NSLog(#"%#", s);
So, It will replace "(" with "" & replace ")" with "-".
Thanks.
use this code
NSString *str = #"(334)687-6619";
str = [str stringByReplacingCharactersInRange:NSMakeRange(0, 1) withString:#""];
str = [str stringByReplacingCharactersInRange:NSMakeRange(3, 1) withString:#"-"];
NSLog(#"%#",str);
OUTPUT is: 334-687-6619
To remove characters from a string:
NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:#"()"];
NSArray *comps = [string componentsSeparatedByCharactersInSet:set];
NSString *newString = [comps componentsJoinedByString:#""];
Im having a issue with removing special characters from the string .I used the following code.But dint work.Please suggest me better logic
- (NSString *)trimmedReciString:(NSString *)stringName
{
NSCharacterSet *myCharSet = [NSCharacterSet characterSetWithCharactersInString:#"-/:;()$&#\".,?!\'[]{}#%^*+=_|~<>€£¥•."];
for (int i = 0; i < [stringName length]; i++) {
unichar c = [stringName characterAtIndex:i];
if ([myCharSet characterIsMember:c]) {
NSLog(#"%#",[NSString stringWithFormat:#"%c",[stringName characterAtIndex:i]]);
stringName = [stringName stringByReplacingOccurrencesOfString:[NSString stringWithFormat:#"%c",[stringName characterAtIndex:i]] withString:#""];
}
}
return stringName;
}
NSString *s = #"$$$hgh$g%k&fg$$tw/-tg";
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:#"-/:;()$&#\".,?!\'[]{}#%^*+=_|~<>€£¥•."];
s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: #""];
NSLog(#"String is: %#", s);
Try this...
NSString *unfilteredString = #"!##$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:#"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
NSLog (#"Result: %#", resultString);
Try starting from the end of the string and work backwards instead of going from front to back, since you're likely to accidentally (and unintentionally) skip characters when the previous character gets deleted.
I have problem with string. The string shows: ~00000000:termometr2: +26.9 st.C and I want to use only this part: +26.9 st.C in my textfield.text.
Thanks
NSString *fullStr = #"00000000:termometr2: +26.9 st.C";
NSArray *parts = [fullStr componentsSeparatedByString:#" "];
textField.text =[NSString stringWithFormat:#"%#",[parts objectAtIndex:1]];
it might help you:
NSArray *_array = [yourString componentsSeparatedByString:#":"];
[myTextField setText:[_array lastObject]]; // or any other component you want
Just do it this way, using the method stringByReplacingOccurrencesOfString: withString::
NSString *originalString = #"~00000000:termometr2: +26.9 st.C";
NSString *filteredString = [originalString stringByReplacingOccurrencesOfString:#"~00000000:termometr2: " withString:#""];
Consider this code:
NSString *aString = #"\tThis is a sample string";
NSString *trimmedString = [aString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSLog(#"The trimmed string: %#",trimmedString);
trimmedString = [aString stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"string"]];
NSLog(#"The trimmed string: %#",trimmedString);
Here if I use characterSetWithCharactersInString: on the same NSString object trimmedString, my previous whitespace trimming effect gets removed..
My question is,
Is there any possibility to use more than one NSCharacterSet object to the same NSString???
or Suggest me some other way to do this please, but the NSString object should be one and the same..
The problem is not because of character sets. Its because you are using aString while trimming the string second time. You should use trimmedString instead. Your code should look like,
trimmedString = [trimmedString stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"string"]];
What about this:
NSString *aString = #"\tThis is a sample string";
NSMutableCharacterSet *customSet = [[NSMutableCharacterSet alloc] init];
[customSet formUnionWithCharacterSet:[NSCharacterSet whitespaceCharacterSet]];
[customSet addCharactersInString:#"string"];
NSString *trimmedString = [aString stringByTrimmingCharactersInSet:customSet];
[customSet release];
I have an NSString *str, having value #"I like Programming and gaming."
I have to remove "I" "like" & "and" from my string so it should look like as "Programming gaming"
How can I do this, any Idea?
NSString *newString = #"I like Programming and gaming.";
NSString *newString1 = [newString stringByReplacingOccurrencesOfString:#"I" withString:#""];
NSString *newString12 = [newString1 stringByReplacingOccurrencesOfString:#"like" withString:#""];
NSString *final = [newString12 stringByReplacingOccurrencesOfString:#"and" withString:#""];
Assigned to wrong string variable edited now it is fine
NSLog(#"%#",final);
output : Programming gaming
NSString * newString = [#"I like Programming and gaming." stringByReplacingOccurrencesOfString:#"I" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"like" withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#"and" withString:#""];
NSLog(#"%#", newString);
More efficient and maintainable than doing a bunch of stringByReplacing... calls in series:
NSSet* badWords = [NSSet setWithObjects:#"I", #"like", #"and", nil];
NSString* str = #"I like Programming and gaming.";
NSString* result = nil;
NSArray* parts = [str componentsSeparatedByString:#" "];
for (NSString* part in parts) {
if (! [badWords containsObject: part]) {
if (! result) {
//initialize result
result = part;
}
else {
//append to the result
result = [NSString stringWithFormat:#"%# %#", result, part];
}
}
}
It is an old question, but I'd like to show my solution:
NSArray* badWords = #[#"the", #"in", #"and", #"&",#"by"];
NSMutableString* mString = [NSMutableString stringWithString:str];
for (NSString* string in badWords) {
mString = [[mString stringByReplacingOccurrencesOfString:string withString:#""] mutableCopy];
}
return [NSString stringWithString:mString];
Make a mutable copy of your string (or initialize it as NSMutableString) and then use replaceOccurrencesOfString:withString:options:range: to replace a given string with #"" (empty string).