Inside embedded i18n form i need to get object.
In this example i got ArtistImageTranslation object, but i need ArtistImage.
Can somebody help me, how to get this?
class ArtistImageTranslationForm extends BaseArtistImageTranslationForm
{
public function configure()
{
$this->getObject();
....
}
}
Have you tried the following?
$artistimage = $this->getObject()->getArtistImage();
I spent half of day today on the same problem and looks like I finally found something ;)
First, if you need to access the fields which are in the "Translation" part of the table you can access them directly from the Object contained in the form. Just access the properties without using the getter (I know it's not the nice way but it works). So you can use something like:
$this->getObject()->id;
$this->getObject()->translated_name;
etc.
If you really need the original object you can access it like this:
$this->getObject()->getTable()->getRelation('ArtistImage')
->fetchRelatedFor($this->getObject());
Hope this helps.
Try :
$artistimage = $this->getObject()->artistImage;
or
$artistimage = $this->getObject()->artist_image;
Related
Newbie question. How to handle Storefront Form Submit in Shopware 6? How to save the data from form to database? I have an entity, form shown in storefront and a controller but i have no idea how to save the data to entity. Thanks in advance.
you would have to be more specific with the description, of what exactly you are trying to achieve.
But in general, if you already have a controller, that receives the data, then you can get them from the request like this:
$data = $request->request->all();
By this, you have all the values from your form saved in an array $data. You have written, that you already have an entity, so from that I assume, that your entity is already mapped to your database table. So the only thing you have to do, is to use the repository to save the data. For thta, you just need to inject it into your class and get a context. The context depends on where you currently are, so for the purpose of the example, I have just created the default context.
It should look like this:
class MyClass
{
protected $myEntityRepository;
public function __construct(
MyEntityRepository $myEntityRepository
)
{
$this->myEntityRepository = $myEntityRepository;
$this->context = \Shopware\Core\Framework\Context::createDefaultContext();
}
public function myMethod ($data)
{
$this->myEntityRepository->upsert($data, $this->context);
}
}
Hope this helps. I have actually written an article on repositories in Shopware 6, so if you want to get some more information and examples, you can check it here: https://shopwarian.com/repositories-in-shopware-6/.
I'm new at Apache Isis and I'm stuck.
I want to create my own submit form with editable parameters for search some entities and a grid with search results below.
Firstly, I created #DomainObject(nature=Nature.VIEW_MODEL) with search results collection, parameters for search and #Action for search.
After deeper research, I found out strict implementations for actions (For exapmle ActionParametersFormPanel). Can I use #Action and edit #DomainObject properties(my search parameters for action) without prompts?
Can I implement it by layout.xml?
Then I tried to change a component as described here: 6.2 Replacing page elements, but I was confused which ComponentType and IModel should I use, maybe ComponentType.PARAMETERS and ActionModel or implement my own IModel for my case.
Should I implement my own Wicket page for search and register it by PageClassList interface, as described here: 6.3 Custom pages
As I understood I need to replace page class for one of PageType, but which one should I change?
So, the question is how to implement such issues properly? Which way should I choose?
Thank you!
===================== UPDATE ===================
I've implemented HomePageViewModel in this way:
#DomainObject(
nature = Nature.VIEW_MODEL,
objectType = "homepage.HomePageViewModel"
)
#Setter #Getter
public class HomePageViewModel {
private String id;
private String type;
public TranslatableString title() {
return TranslatableString.tr("My custom search");
}
public List<SimpleObject> getObjects() {
return simpleObjectRepository.listAll();
}
#Action
public HomePageViewModel search(
#ParameterLayout(named = "Id")
String id,
#ParameterLayout(named = "Type")
String type
){
setId(id);
setType(type);
// finding objects by entered parameters is not implemented yet
return this;
}
#javax.inject.Inject
SimpleObjectRepository simpleObjectRepository;
}
And it works in this way:
I want to implement a built-in-ViewModel action with parameters without any dialog windows, smth like this:
1) Is it possible to create smth like ActionParametersFormPanel based on ComponentType.PARAMETERS and ActionModel and use this component as #Action in my ViewModel?
2) Or I should use, as you said, ComponentType.COLLECTION_CONTENTS? As I inderstand my search result grid and my search input panel will be like ONE my stub component?
Thank you.
We have a JIRA ticket in our JIRA to implement a filterable/searchable component, but it hasn't yet made it to the top of the list for implementation.
As an alternative, you could have a view model that provides the parameters you want to filter on as properties, with a table underneath. (I see you asked another question here on SO re properties on view models, so perhaps you are moving in that direction also... I've answered that question).
If you do want to have a stab at implementing that ticket, then the ComponentTYpe to use is COLLECTION_CONTENTS. If you take a look at the isisaddons, eg for excel or gmap3 then it might help get you started.
======= UPDATE TO ANSWER (based on update made to query) ==========
I have some good news for you. v1.15.0-SNAPSHOT, which should be released in the couple of weeks, has support for "inline prompts". You should find these give a user experience very similar to what you are after, with no further work needed on your part.
To try it out, check out the current trunk, and then load the simpleapp (in examples/application/simpleapp). You should see that editing properties and invoking actions uses the new inline prompt style.
HTH
Dan
i have this parsed object
$xmlObj = new SimpleXMLElement($XMLToParse, LIBXML_DOTTED_VERSION, FALSE, "http://SOME/schema/universal_v17_0");
that has the stucture like this inside it
<universal:UniversalR LocatorCode="somecode" Version="2" Status="Active">
<common_v17_0:Book Key="some" TravelerType="some">
so i can access the first element(its attributes) like this $VariableX=$xmlObj->UniversalR->attributes();//then $VariableX["Status"];
but when i want access his child i cant $tm=$xmlObj->UniversalR->Book->attributes();
it doesnt want to enter probably because of the different namespace...can any one help me . THX
I found something here http://blog.sherifmansour.com/?p=302
foreach ($xmlObj->UniversalRecord as $entry){
$namespaces = $entry->getNameSpaces(true);
$cmm = $entry->->children($namespaces['common_v17_0']);
$aa=$cmm->Book->attributes();
echo $aa["TravelerType"]."ddddd";
}
That should do it :)
$tm=$xmlObj->UniversalRecord->Book->attributes(); is this typo (UniversalRecord instead of UniversalR) only present in this post or is it also present in your code?
(I'd have liked to post this as a comment.. but it looks like i'm not allowed to, or am too stupid to find the button. :/)
I've been looking on forums for 2 days now and can't find a good answer so I'll just post it.
I appear to be having a problem posting JSON back to the controller to save. The JSON should map to model view but it keeps getting default(constructor)values rather then the values from the POST.
We have a series of JS widgets that contain a data field with json in them. We do all our data manipulation in these widget objects on the client side. When a user wants to save we grab the data we need from the widgets involved and we put it into another JSON object that matches a ViewModel and POST that back to the server.
For example:
$("#Save").click(function () {
if (itemDetails.preparedForSubmit() && itemConnections.preparedForSubmit()) {
itemComposite.data.Details = itemDetails.data;
itemComposite.data.Connections= itemConnections.data;
$.post(MYURL, itemComposite.data);
} else {
alert("failed to save");
}
});
The preparedForSubmit() method simple does stuff like any validation checks or last minute formatting you might need to do client side.
The itemDetails widgets data matches a ViewModel.
The itemConnections widgets data matches a collection of ViewModels.
The Controller looks like this:
[HttpPost]
virtual public JsonResult SaveItemDetailsComposite(ItemComposite inItemData)
{
if (ModelState.IsValid)
{
try
{
_Mapper.Save(itemComposite.Details , itemComposite.Connections);
return Json(true);
}
catch (Exception ex)
{
_log.Error("Exception " + ex.InnerException.Message);
throw;
}
}
return Json(SiteMasterUtilities.CreateValidationErrorResponse(ModelState));
}
The ItemComposite Class is a simple View Model that contains a single itemDetails object and a collection of itemConnections. When it returns data to here it is just getting the default data as if it got a new ItemComposite rather than converting the POST data.
in Firebug I see the data is posted. Although it looks weird not automatically formatted in firebug.
Are you saying that itemComposite.data is formatted as a JSON object? If so, I'm pretty sure you're going to have to de-serialize it before you can cast it to your object. Something like:
ItemComposite ic = jsSerializer.Deserialize<ItemComposite>(this.HttpContext.Request.Params[0]);
You may want to look into a framework like JSON.NET to ensure that your data is being serialized properly when it gets supplied to your Action.
JSON.NET seems like it's one of the main stream frameworks: http://json.codeplex.com/releases/view/43775
Hope this helps.
Cory
You could also use the JSON Serializer in WCF: http://msdn.microsoft.com/en-us/library/system.runtime.serialization.json.datacontractjsonserializer.aspx
SO wouldn't let me put both links in one answer, sorry for the split answer.
Thanks everyone. I think I have solved my problem and I'm pretty sure that I had four issues. For the most part I followed thatSteveguys's suggestion and read more on this article: http://haacked.com/archive/2010/04/15/sending-json-to-an-asp-net-mvc-action-method-argument.aspx
Using jQuery's post() method and specifying json as the type didn't seem to actually send it as json. By using the ajax() method and specifying json it sent it as json.
The JSON.serialize() method was also need to cleanly send over the json.
Also my ViewModel design was a big problem. We are using the MS code analytic build junk and it didn't want me having a setter for my collections in the ViewModel. So me being from a java/hibernate world, thought it didn't need them to bind and it would just come in as a serialized object magically. Once I just suppressed the error and reset up my setters. I am getting the collections now in my controller.
I believe using the MVC2 Future's Value Providers are doing something but it still doesn't convert json dates robustly, So I am still investigating the best way to do that.
I hope my issues help out others.
UPDATE: using this method to update collections of data appears to be super slow. A collection with 200 entries in it and 8 fields per entry takes 3 minutes to get to the controller. Just 1 or 2 entries take very little time. The only thing I know of that is happening between here is data binding to the model view. I don't know if MVC2 provides a easy way to send this much data and bind it.
Well, imagine that we have a register form of a class Customer and we only ask three fields (name,surname,email) and after, when this user logged first time we want to complete this information.
First, we have in lib/form/doctrine a file called 'CustomerForm.class.php' wich is generated automatic on command line. In this file we 'setup' only 3 fields and validators and if we wanna use we do something like that:
$this->form = CustomerForm();
Second, we create manual another form named 'CustomerFormStep1.class.php' where we can setup for validate the other fields. But when we do..
$this->form = CustomerFormStep1();
it returns error: Fatal error: Class 'CustomerFormStep1' not found
What is wrong?
Thanks.
Assuming you have the form defined as:
class CustomerFormStep1 extends sfForm
or similar (sfFormDoctrine etc), and named correctly like you say (CustomerFormStep1.class.php) and in lib/form, then Symfony should just pick the definition up fine. Did you clear the cache after creating and placing it in the right place? (symfony cc).
Create the new CustomerFormStep1 class as #richsage instructed. Then, in your actions you can write something like:
public function executeLogin(){
//before login
$this->form = new CustomerForm();
}
public function executeLoggedIn(){
$this->form = new CustomerFormStep1();
//other steps
}
Haven't you read the tutorial? Extending forms is perfectly described in context with reh admin generator and can of course be applied to any case.