I am using the following JPA query and i am getting the java.lang.IllegalArgumentException: Cannot create TypedQuery for query with more than one return Exception.
TypedQuery<RaBdrRating> uQuery =
(TypedQuery<RaBdrRating>)entityManager.createQuery("
SELECT r.activePackage,SUM(r.duration),SUM(r.charge),COUNT(r)
FROM RaBdrRating r WHERE r.callType = :callType
and r.startDate between :startDate and :endDate
GROUP BY r.activePackage",RaBdrRating.class);
uQuery.setParameter("callType", model.getCallType());
uQuery.setParameter("startDate",startDate);
uQuery.setParameter("endDate",endDate);
List<RaBdrRating> listOfPackages = uQuery.getResultList();
Can any one tell me what is wrong in my query.....I am new to JPA and i am not getting what is the problem and strucked up here.If any one have idea please tell me.
I go the same error:
Cannot create TypedQuery for query with more than one return using requested result type
Solution:
Having a Query like this:
Select e.fieldA, e.fieldB, e.fieldC From Entity e
You have to declare a constructor with the parameters specified on query:
package somepackage;
public class Entity {
...
public class Entity() {}
public class Entity(Type fieldA, Type fieldB, Type fieldC) {
this.fieldA = fieldA;
this.fieldB = fieldB;
this.fieldC = fieldC;
}
....
}
Finally, modify your query
Select NEW somepackage.Entity(e.fieldA, e.fieldB, e.fieldC) From Entity e
You are indicating how the objectes will be created.
This seems to be this bug: https://hibernate.onjira.com/browse/HHH-6304
It is apparently fixed in version 4.1.5.
Related
I have a PagingAndSorting JPA repository declared. I am using the #Query annotation.
I am getting an exception when I call the get() method on an Optional object from the findById(id) method of the repository.
The weird thing is it only happens when I use JPQL.
The code works if my query is native:
#Override
public BatchDto findById(String id) {
Optional<Batch> findResult = this.batchRepository.findById(id);
if (!findResult.isPresent()) return null;
Batch entity = findResult.get(); **<-------- Cast Exception Here**
BatchDto dto = this.mapper.toDto(entity, BatchDto.class);
List<BatchTransaction> transactions = entity.getTransactions();
dto.setTransactionDtos(mapper.toListDto(transactions, TransactionDto.class));
return dto;
}
Inspecting the findResult object with a breakpoint - I can see:
Optional[net.domain.data.batch#4b8bb6f]
when I have nativeQuery = true in the #Query annotation.
#Query(value = Sql.FindBatchById, nativeQuery = true)
Here is the query being used:
SELECT DISTINCT(B.batchNumber), COUNT(B.batchNumber) as TransactionCount FROM BATCH B WHERE B.batchReferenceNumber = :id GROUP BY B.batchNumber
However if I change it to JPQL and remove the nativeQuery=true attribute - the findResult is
Optional[[Ljava.lang.Object;#76e04327].
and I get a ClassCastException:
java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to net.domain.data.batch
So bottom line - this works when specify nativeQuery=true and fails when I try to use JPQL.
I would prefer not to specify nativeQuery as we will eventually port this db to Oracle.
First of all the query shown below doesn't return a single Batch instance. Since there are distinct and count aggregate functions, the query will return a List of aggregates.
To be able to read that statistics you can add appropriate method into the batchRepository. Something like this:
#Query("SELECT DISTINCT(B.batchNumber) as dist, COUNT(B.batchNumber) as cnt FROM BATCH B GROUP BY B.batchNumber")
List<Map<Long, Long>> findStatistics();
and then iterate through the list.
UPD
If the id parameter exactly guarantee that will return a single record, you can change a return type to a Map
#Query("SELECT DISTINCT(B.batchNumber) as dist, COUNT(B.batchNumber) as cnt FROM BATCH B WHERE B.batchReferenceNumber = :id GROUP BY B.batchNumber")
Map<Long, Long> findStatisticsById(#Param("id") Long id);
I'm currently working with a JPA project from my university. I'm having problems with a Query, especifically a Method on a #Service class that receives numerous parameters.
First of all, I'm trying just to make the query work with a two parameters.
Here is the method.
#Override
#Transactional ( readOnly = true )
public List<Candidate> obtainCandidatesOps(String name, String firstName,
String secondName, String passport, CandidateType candidateType,
Area area, Country country) {
List<Candidate> resultList = new ArrayList<Candidate>();
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Candidate> cq = cb.createQuery(Candidate.class);
Root<Candidate> r = cq.from(Candidate.class);
cq.where(cb.and(cb.equal(r.get("name"), cb.parameter(String.class, "name")),cb.equal(r.get("firstLastName"), cb.parameter(String.class, "firstName"))));
cq.select(r);
resultList = em.createQuery(cq).getResultList();
return resultList;
}
While I try to execute this Query I receive this error:
WARNING: #{searchBean.fillCandidatesOps}: java.lang.IllegalArgumentException: org.hibernate.QueryException: Not all named parameters have been set: [firstName, name] [select generatedAlias0 from Candidate as generatedAlias0 where ( generatedAlias0.name=:name) and ( generatedAlias0.firstLastName=:firstName)]
Where is the mistake/problem?
I've read this topics, and found no solution to my problem.
Caused by: org.hibernate.QueryException: Not all named parameters have been set: [isActive] [from User where isActive = :isActive]
How to solve "org.hibernate.QueryException: Not all named parameters have been set" error?
As the 2 linked threads tell you clear enough (so no idea why you have "looked at them for 5 days" and not noticed this), you need to set the VALUE of the parameters that you have defined in that query.
cq.where(cb.and(cb.equal(r.get("name"), cb.parameter(String.class, "name")),cb.equal(r.get("firstLastName"), cb.parameter(String.class, "firstName"))));
cq.select(r);
Query query = em.createQuery(cq);
query.setParameter("name", name);
query.setParameter("firstName", firstName);
resultList = query.getResultList();
I am trying to retrieve a USER from my database using the ID in the WHERE clause. However I am receiving an error and my program is failing.
This is the error I'm receiving when I run my program:
ERROR [org.jboss.as.ejb3.invocation] (default task-19)
JBAS014134: EJB Invocation failed on component CustomerServiceBeanImpl
for method public abstract package.name.entity.ICustomer
package.name.bean.CustomerServiceBean.getCustomerById(long):
javax.ejb.EJBException: java.lang.IllegalArgumentException:
Parameter value [19533] did not match expected type [package.name.entity.User (n/a)]
Note: [19533] is a test value I used.
This is the method that is having the error in the CustomerServiceBeanImpl.java:
#Override
public Customer getCustomerById (final long id)
{
return Customer.getById (this.em, id);
}
This is the method that's being called by the component CustomerServiceBeanImpl:
public static Customer getById (final EntityManager em, final long id)
{
for (final Customer c : em.createNamedQuery ("Customer.getById", Customer.class)
.setParameter ("id", id).setMaxResults (1).getResultList ())
{
return c;
}
return null;
}
The name query is this:
#NamedQuery (name = "Customer.getById",
query = "SELECT o FROM gnf.Customer o WHERE o.user = :id")
In the Customer.java class itself the relevant column is this one:
#ManyToOne (fetch = FetchType.LAZY)
#JoinColumn (name = "user_id")
private User user;
Doing a quick check of my ERD the "id" column in my "customer" table has a data type of BIGINT. However I'm not sure if that matters. (PostgreSQL database by the way.)
How can I fix this error?
The WHERE clause in your named query seems to be the problem. The attribute user in your Customer.class is of type User and your query expects it to be a type compatible to long.
...
Parameter value [19533] did not match expected type [package.name.entity.User ...
So if you need more help on this it would be great to see the complete entities User and Customer.
It is happening because in your database the parameter will be a #oneToOne object and you have to call the id inside the Object so you have to give the query as following :
"select user from User user where user.customer.id=:param"
I am trying to return a string from a table based on a conditional ID (subid) from an already populated table. The query should return a list of type ItemDataPoint entity. In a JSF managed bean, the list will the be iterated by a an enhaned for loop. If the word "Include" is found by the loop, the method will create a specific type of chart. In simpler terms, I want to return a string based the ID condition being met. I am getting:
javax.ejb.EJBException
at com.sun.ejb.containers.EJBContainerTransactionManager.processSystemException
(EJBContainerTransactionManager.java:748)
at com.sun.ejb.containers.EJBContainerTransactionManager.
completeNewTx(EJBContainerTransactionManager.java:698)
at com.sun.ejb.containers.EJBContainerTransactionManager.postInvokeTx
(EJBContainerTransactionManager.java:503)
at com.sun.ejb.containers.BaseContainer.postInvokeTx(BaseContainer.java:4475)
at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:2009)
at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:1979)
Caused by: java.lang.IllegalArgumentException: You have attempted to set
a parameter at position 2 which does not exist in this query string SELECT p FROM
Itemdatapoint p JOIN p.series s WHERE s.master.item.subs.subid = :subid.
at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:925)
at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:906)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.setParameter(EJBQueryImpl.java:469)
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.setParameter(EJBQueryImpl.java:1)
at com.manaar.clientmods.gazprom.design3.data.facade.ItemdatapointFacade.
chartType(ItemdatapointFacade.java:78)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
The subid value of 2 exists if I run a native SQL query on the relevant parent table in the DB. Also the type of the subid is an int in the main entity class, the JPQL Facade class and the managed bean.
The JPQL:
public List<Itemdatapoint> chartType (int subid) {
Query q = em.createQuery("SELECT p FROM Itemdatapoint p JOIN p.series s WHERE s.master.item.subs.subid = :subid");
q.setParameter(subid, "subid");
return q.getResultList();
}
The managed bean:
#Named(value = "reportBean")
#SessionScoped
public class ReportBean implements Serializable {
#Inject
private ItemdatapointFacade facade;
public String typeSwitch1() {
subid = 2;
chartType = facade.chartType(subid);
for(Itemdatapoint e: chartType) {
status = e.getSeries().getMaster().getStatus();
if(status.equals("Include")) {
return "line";
}
}
return null;
}
The xhtml page:
<p:chart type="#{reportBean.typeSwitch1()}" model="#{reportBean.subLineChart1}"/>
I also tried a non Join JPQL just from a single table:
public List<Itemdatapoint> noJoin (int subid) {
Query q = em.createQuery("SELECT p FROM Itemdatapoint p WHERE p.pointid = :subid");
q.setParameter(subid, "subid");
return q.getResultList();
}
Similar problem:
java.lang.IllegalArgumentException: You have attempted to set a
parameter at position 2 which does not exist in this query string
SELECT p FROM Itemdatapoint p WHERE p.pointid = :subid.
I gather that IllegalArgumentException means that the selected entity does not exist or is not the correct type consistent with the query string in the facade class. But in my case the entity exists and the parameter is the correct type.
I would appreciate any help in understanding why i'm getting this error. Thank in advance!
UPDATE
Responding to the answer from lametaweb, I want to better understand the concept of JPA parameters.
According to the JPA documentation, the first argument of the setParameter method is the parameter name or number. The second argument is the object that should be bound to the named parameter. Why does the following work without throwing Illegal ArgumentException?
I tested an xhtml (web page):
<p:dataGrid id="rep1" columns="1" value="#{pageBean.itemPageList1}" var="items1" rows="4">
<p:commandLink value="#{items1.itemname}" action="#{pageBean.showItem1}" ajax="false"/>
</p:dataGrid>
The bean code:
public ListDataModel<Sectionitem> getItemPageList1() {
subid = 1;
reportStatus = "Include";
itemPageList1 = itemFacade.viewItems(subid, reportStatus);
return itemPageList1;
}
The JPA facade:
public ListDataModel<Sectionitem> viewItems(int subid, String stat) {
Query q = em.createQuery("select s from Sectionitem s JOIN s.subs c where c.subid = :subid AND s.status = :stat ORDER BY s.daterec");
q.setParameter("subid", subid);
q.setParameter("stat", stat);
ListDataModel<Sectionitem> res
= new ListDataModel<Sectionitem>(q.getResultList());
return res;
}
Why is it in this case, the object exist but in my original case the subid object does not exist?
You are invoking this method in your code:
setParameter(int position, Object value)
but you have to invoke this one instead:
setParameter(String name, Object value)
So your code should be:
q.setParameter("subid", Integer.valueOf(subid));
But, if you invoke:
q.setParameter(subid, "subid");
here the first parameter represents the position of the argument and the second the value for it. So you are passing a value of "subid" for the parameter in the second (2) position, which doesn't exist, because you only have one parameter in your JPQL query, hence the IllegalArgumentException exception.
Note: Why do you have a primitive type in your entity? Why not an Integer instead an int?
I am trying downloading all records from table in h2 buildin database in playframework.
I am facing an error:
[IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: * near line 1, column 8 [SELECT * FROM TABLE]]
Method CODE i class Table:
#Transactional(readOnly=true)
public static Result view() {
Query query = JPA.em().createQuery("SELECT * FROM TABLE");
List<Table> downloaded_from_db = query.getResultList();
System.out.println(downloaded_from_db.getClass());
return ok(view.render("none"));
}
Please help me. I would like to see downloaded records in console in simple view.
Please give me some tips or good tutorial.
After changing my class loooks like this:
#Transactional(readOnly=true)
public static Result view() {
List<MedicalIncidents> data = JPA.em()
.createNativeQuery("SELECT * FROM MedicalIncident")
//.createQuery("Select m from MedicalIncident m")
.getResultList();
System.out.println(data);
AND I think it works, cause I have 2 entries in that table in database:
But System.out.println(data) return in plaay console:
[[Ljava.lang.Object;#70a0c9be, [Ljava.lang.Object;#4c1d12b6]
But it should return this object by model name like in example: computer-database-jpa:
[models.Computer#214c6fde, models.Computer#63728eb3, models.Computer#75f6bcc6, models.Computer#19e3a7ab, models.Computer#3114d8d4, models.Computer#4fa75f78, models.Computer#756ce822, models.Computer#40fc4c68, models.Computer#73fc612c, models.Computer#3e4fcb31]
So I think that there is something wrong with it. Please help
You mxied SQL queries with JPQL query. The method you used createQuery needs an JPQL query:
SELECT e FROM Entity e
Also please note in JPQL there is no SELECT *. If you want to write a SQL query, use the method em.createNtiveQuery().