Understanding implicit in Scala - scala

I was making my way through the Scala playframework tutorial and I came across this snippet of code which had me puzzled:
def newTask = Action { implicit request =>
taskForm.bindFromRequest.fold(
errors => BadRequest(views.html.index(Task.all(), errors)),
label => {
Task.create(label)
Redirect(routes.Application.tasks())
}
)
}
So I decided to investigate and came across this post.
I still don't get it.
What is the difference between this:
implicit def double2Int(d : Double) : Int = d.toInt
and
def double2IntNonImplicit(d : Double) : Int = d.toInt
other than the obvious fact they have different method names.
When should I use implicit and why?

I'll explain the main use cases of implicits below, but for more detail see the relevant chapter of Programming in Scala.
Implicit parameters
The final parameter list on a method can be marked implicit, which means the values will be taken from the context in which they are called. If there is no implicit value of the right type in scope, it will not compile. Since the implicit value must resolve to a single value and to avoid clashes, it's a good idea to make the type specific to its purpose, e.g. don't require your methods to find an implicit Int!
example:
// probably in a library
class Prefixer(val prefix: String)
def addPrefix(s: String)(implicit p: Prefixer) = p.prefix + s
// then probably in your application
implicit val myImplicitPrefixer = new Prefixer("***")
addPrefix("abc") // returns "***abc"
Implicit conversions
When the compiler finds an expression of the wrong type for the context, it will look for an implicit Function value of a type that will allow it to typecheck. So if an A is required and it finds a B, it will look for an implicit value of type B => A in scope (it also checks some other places like in the B and A companion objects, if they exist). Since defs can be "eta-expanded" into Function objects, an implicit def xyz(arg: B): A will do as well.
So the difference between your methods is that the one marked implicit will be inserted for you by the compiler when a Double is found but an Int is required.
implicit def doubleToInt(d: Double) = d.toInt
val x: Int = 42.0
will work the same as
def doubleToInt(d: Double) = d.toInt
val x: Int = doubleToInt(42.0)
In the second we've inserted the conversion manually; in the first the compiler did the same automatically. The conversion is required because of the type annotation on the left hand side.
Regarding your first snippet from Play:
Actions are explained on this page from the Play documentation (see also API docs). You are using
apply(block: (Request[AnyContent]) ⇒ Result): Action[AnyContent]
on the Action object (which is the companion to the trait of the same name).
So we need to supply a Function as the argument, which can be written as a literal in the form
request => ...
In a function literal, the part before the => is a value declaration, and can be marked implicit if you want, just like in any other val declaration. Here, request doesn't have to be marked implicit for this to type check, but by doing so it will be available as an implicit value for any methods that might need it within the function (and of course, it can be used explicitly as well). In this particular case, this has been done because the bindFromRequest method on the Form class requires an implicit Request argument.

WARNING: contains sarcasm judiciously! YMMV...
Luigi's answer is complete and correct. This one is only to extend it a bit with an example of how you can gloriously overuse implicits, as it happens quite often in Scala projects. Actually so often, you can probably even find it in one of the "Best Practice" guides.
object HelloWorld {
case class Text(content: String)
case class Prefix(text: String)
implicit def String2Text(content: String)(implicit prefix: Prefix) = {
Text(prefix.text + " " + content)
}
def printText(text: Text): Unit = {
println(text.content)
}
def main(args: Array[String]): Unit = {
printText("World!")
}
// Best to hide this line somewhere below a pile of completely unrelated code.
// Better yet, import its package from another distant place.
implicit val prefixLOL = Prefix("Hello")
}

In scala implicit works as:
Converter
Parameter value injector
Extension method
There are some uses of Implicit
Implicitly type conversion : It converts the error producing assignment into intended type
val x :String = "1"
val y:Int = x
String is not the sub type of Int , so error happens in line 2. To resolve the error the compiler will look for such a method in the scope which has implicit keyword and takes a String as argument and returns an Int .
so
implicit def z(a:String):Int = 2
val x :String = "1"
val y:Int = x // compiler will use z here like val y:Int=z(x)
println(y) // result 2 & no error!
Implicitly receiver conversion: We generally by receiver call object's properties, eg. methods or variables . So to call any property by a receiver the property must be the member of that receiver's class/object.
class Mahadi{
val haveCar:String ="BMW"
}
class Johnny{
val haveTv:String = "Sony"
}
val mahadi = new Mahadi
mahadi.haveTv // Error happening
Here mahadi.haveTv will produce an error. Because scala compiler will first look for the haveTv property to mahadi receiver. It will not find. Second it will look for a method in scope having implicit keyword which take Mahadi object as argument and returns Johnny object. But it does not have here. So it will create error. But the following is okay.
class Mahadi{
val haveCar:String ="BMW"
}
class Johnny{
val haveTv:String = "Sony"
}
val mahadi = new Mahadi
implicit def z(a:Mahadi):Johnny = new Johnny
mahadi.haveTv // compiler will use z here like new Johnny().haveTv
println(mahadi.haveTv)// result Sony & no error
Implicitly parameter injection: If we call a method and do not pass its parameter value, it will cause an error. The scala compiler works like this - first will try to pass value, but it will get no direct value for the parameter.
def x(a:Int)= a
x // ERROR happening
Second if the parameter has any implicit keyword it will look for any val in the scope which have the same type of value. If not get it will cause error.
def x(implicit a:Int)= a
x // error happening here
To slove this problem compiler will look for a implicit val having the type of Int because the parameter a has implicit keyword.
def x(implicit a:Int)=a
implicit val z:Int =10
x // compiler will use implicit like this x(z)
println(x) // will result 10 & no error.
Another example:
def l(implicit b:Int)
def x(implicit a:Int)= l(a)
we can also write it like-
def x(implicit a:Int)= l
Because l has a implicit parameter and in scope of method x's body, there is an implicit local variable(parameters are local variables) a which is the parameter of x, so in the body of x method the method-signature l's implicit argument value is filed by the x method's local implicit variable(parameter) a implicitly.
So
def x(implicit a:Int)= l
will be in compiler like this
def x(implicit a:Int)= l(a)
Another example:
def c(implicit k:Int):String = k.toString
def x(a:Int => String):String =a
x{
x => c
}
it will cause error, because c in x{x=>c} needs explicitly-value-passing in argument or implicit val in scope.
So we can make the function literal's parameter explicitly implicit when we call the method x
x{
implicit x => c // the compiler will set the parameter of c like this c(x)
}
This has been used in action method of Play-Framework
in view folder of app the template is declared like
#()(implicit requestHreader:RequestHeader)
in controller action is like
def index = Action{
implicit request =>
Ok(views.html.formpage())
}
if you do not mention request parameter as implicit explicitly then you must have been written-
def index = Action{
request =>
Ok(views.html.formpage()(request))
}
Extension Method
Think, we want to add new method with Integer object. The name of the method will be meterToCm,
> 1 .meterToCm
res0 100
to do this we need to create an implicit class within a object/class/trait . This class can not be a case class.
object Extensions{
implicit class MeterToCm(meter:Int){
def meterToCm={
meter*100
}
}
}
Note the implicit class will only take one constructor parameter.
Now import the implicit class in the scope you are wanting to use
import Extensions._
2.meterToCm // result 200

Why and when you should mark the request parameter as implicit:
Some methods that you will make use of in the body of your action have an implicit parameter list like, for example, Form.scala defines a method:
def bindFromRequest()(implicit request: play.api.mvc.Request[_]): Form[T] = { ... }
You don't necessarily notice this as you would just call myForm.bindFromRequest() You don't have to provide the implicit arguments explicitly. No, you leave the compiler to look for any valid candidate object to pass in every time it comes across a method call that requires an instance of the request. Since you do have a request available, all you need to do is to mark it as implicit.
You explicitly mark it as available for implicit use.
You hint the compiler that it's "OK" to use the request object sent in by the Play framework (that we gave the name "request" but could have used just "r" or "req") wherever required, "on the sly".
myForm.bindFromRequest()
see it? it's not there, but it is there!
It just happens without your having to slot it in manually in every place it's needed (but you can pass it explicitly, if you so wish, no matter if it's marked implicit or not):
myForm.bindFromRequest()(request)
Without marking it as implicit, you would have to do the above. Marking it as implicit you don't have to.
When should you mark the request as implicit? You only really need to if you are making use of methods that declare an implicit parameter list expecting an instance of the Request. But to keep it simple, you could just get into the habit of marking the request implicit always. That way you can just write beautiful terse code.

Also, in the above case there should be only one implicit function whose type is double => Int. Otherwise, the compiler gets confused and won't compile properly.
//this won't compile
implicit def doubleToInt(d: Double) = d.toInt
implicit def doubleToIntSecond(d: Double) = d.toInt
val x: Int = 42.0

I had the exact same question as you had and I think I should share how I started to understand it by a few really simple examples (note that it only covers the common use cases).
There are two common use cases in Scala using implicit.
Using it on a variable
Using it on a function
Examples are as follows
Using it on a variable. As you can see, if the implicit keyword is used in the last parameter list, then the closest variable will be used.
// Here I define a class and initiated an instance of this class
case class Person(val name: String)
val charles: Person = Person("Charles")
// Here I define a function
def greeting(words: String)(implicit person: Person) = person match {
case Person(name: String) if name != "" => s"$name, $words"
case _ => "$words"
}
greeting("Good morning") // Charles, Good moring
val charles: Person = Person("")
greeting("Good morning") // Good moring
Using it on a function. As you can see, if the implicit is used on the function, then the closest type conversion method will be used.
val num = 10 // num: Int (of course)
// Here I define a implicit function
implicit def intToString(num: Int) = s"$num -- I am a String now!"
val num = 10 // num: Int (of course). Nothing happens yet.. Compiler believes you want 10 to be an Int
// Util...
val num: String = 10 // Compiler trust you first, and it thinks you have `implicitly` told it that you had a way to covert the type from Int to String, which the function `intToString` can do!
// So num is now actually "10 -- I am a String now!"
// console will print this -> val num: String = 10 -- I am a String now!
Hope this can help.

A very basic example of Implicits in scala.
Implicit parameters:
val value = 10
implicit val multiplier = 3
def multiply(implicit by: Int) = value * by
val result = multiply // implicit parameter wiil be passed here
println(result) // It will print 30 as a result
Note: Here multiplier will be implicitly passed into the function multiply. Missing parameters to the function call are looked up by type in the current scope meaning that code will not compile if there is no implicit variable of type Int in the scope.
Implicit conversions:
implicit def convert(a: Double): Int = a.toInt
val res = multiply(2.0) // Type conversions with implicit functions
println(res) // It will print 20 as a result
Note: When we call multiply function passing a double value, the compiler will try to find the conversion implicit function in the current scope, which converts Int to Double (As function multiply accept Int parameter). If there is no implicit convert function then the compiler will not compile the code.

Related

Clarification over Scala polymorphism

On a recent worksheet I was presented with the question asking what would be the output of the following code:
class A { def m(x:Double) = x+x }
class B[Any] extends A{ def m(x: Any) = print(x) }
class C[Any] { def m (x:Double) = x+x; def m (x: Any) = print(x) }
val obj1 = new B[Int]; val obj2 = new C[Any]
obj1.m(1); obj1.m(2.3); obj2.m(4); obj2.m(5.6)
I'm quite confused as to what having a concrete type in the square brackets after the class name would mean (i.e. class B[Any]). Is the later expression val obj1 = new B[Int] valid because Int <: Any, Int being a subclass of Any?
When later running the code snippet, the result given was simply "1" being printed. This was not what I had expected the call to obj.m(2.3) to resolve at def m(x: any), where it seems in actuality the compiler went up to A and called the m in class A.
The later expressions, obj2.m(4) and obj2.m(5.6) seems to make sense as both 4 and 5.6 would land in the function with def m(x: Double), thus not print anything out.
In what order exactly does the compiler traverse to find what to call? I'd be very grateful if someone could clear up my confusions with how polymorphism is handled here by Scala, thank you very much :)
When you do class B[Any], you define a class with a type parameter called Any. Don't confuse the type parameter name with the actual class Any. You are just shadowing its name.
You could just as fine do this:
class B[Int]
val obj = new B[String]
You may see why it is bad practice to name type parameters after actual types. Usually, people use single letter names for their type parameters, like this:
class B[T] // I just changed the name of the type parameter from "Int" to "T".
val obj = new B[String]

Error in lifting method to function

I have a method that with the implicit parameter. i get a error when i convert it to function in 2 case :
1:
def action(implicit i:Int) = i + " in action"
val f = action _
then i get a StackOverflowError.
2:
def action(implicit i:Int) = i + " in action"
val f = action(_)
then i get a error: missing parameter type
I must write like this :
val f = (i:Int) => action(i)
that's ok. And if the parameter of 'action' is not the implicit , all case are right. So how to explain , and what i miss ?
If you specify a parameter to a function to be implicit, you are inviting the compiler to supply the value of that parameter for you. So how does the compiler find those values? It looks for values of the same type (Int in your case) that have been declared as implicit values in a variety of scopes.
(For simplicity, I'll just use a local scope in this example, but you might want to read up on this topic. Programming in Scala, 3rd Ed is a good first step.)
Note that the names of the implicit values are ignored and have no bearing on proceedings, the compiler only looks at the types of implicit values. If multiple implicit values with the required type are found in the same scope, then the compiler will complain about ambiguous implicit values.
For example, the following provides a function with an implicit parameter and a default value for that parameter within the current scope:
def greetPerson(name: String)(implicit greeting: String) = s"$greeting $name!"
implicit val defaultGreeting = "Hello" // Implicit value to be used for greeting argument.
val y = greetPerson("Bob") // Equivalent to greetPerson("Bob")(defaultGreeting).
val z = greetPerson("Fred")("Hi")
Note that y is just a String value of "Hello Bob!", and z is a string with the value "Hi Fred!"; neither of them are functions.
Also note that greetPerson is a curried function. This is because implicit parameters cannot be mixed with regular, non-implicit parameters in the same parameter list.
In general, it's bad practice to use common types (Int, Boolean, String, etc.) as values for implicit parameters. In a big program, there might be a lot of different implicit values in your scope, and you might pick up an unexpected value. For that reason, it's standard practice to wrap such values in a case class instead.
If you're trying to create a value that supplies some of the arguments of another function (that is, a partially applied function), then that would look something like this:
def greetPerson(greeting: String, name: String) = s"$greeting $name!"
val sayHello = greetPerson("Hello", _: String)
val y = sayHello("Bob") // "Hello Bob!"
val sayHi = greetPerson("Hi", _: String)
val z = sayHi("Fred") // "Hi Fred!"
In both cases, we're creating partially applied functions (sayHi and sayHello) that call greetPerson with the greeting parameter specified, but which allow us to specify the name parameter. Both sayHello and sayHi are still only values, but their values are partially applied functions rather than constants.
Depending upon your circumstances, I think the latter case may suit you better...
I would also read up on how the underscore character (_) is used in Scala. In a partially applied function declaration, it corresponds to the arguments that will be provided later. But it has a lot of other uses too. I think there's no alternative to reading up on Scala and learning how and when to use them.

implement conversion parameters function with scala

I'm trying to implement something like clever parameters converter function with Scala.
Basically in my program I need to read parameters from a properties file, so obviously they are all strings and I would like then to convert each parameter in a specific type that I pass as parameter.
This is the implementation that I start coding:
def getParam[T](key : String , value : String, paramClass : T): Any = {
value match {
paramClass match {
case i if i == Int => value.trim.toInt
case b if b == Boolean => value.trim.toBoolean
case _ => value.trim
}
}
/* Exception handling is missing at the moment */
}
Usage:
val convertedInt = getParam("some.int.property.key", "10", Int)
val convertedBoolean = getParam("some.boolean.property.key", "true", Boolean)
val plainString = getParam("some.string.property.key", "value",String)
Points to note:
For my program now I need just 3 main type of type: String ,Int and Boolean,
if is possible I would like to extends to more object type
This is not clever, cause I need to explicit the matching against every possibile type to convert, I would like an more reflectional like approach
This code doesn't work, it give me compile error: "object java.lang.String is not a value" when I try to convert( actually no conversion happen because property values came as String).
Can anyone help me? I'm quite newbie in Scala and maybe I missing something
The Scala approach for a problem that you are trying to solve is context bounds. Given a type T you can require an object like ParamMeta[T], which will do all conversions for you. So you can rewrite your code to something like this:
trait ParamMeta[T] {
def apply(v: String): T
}
def getParam[T](key: String, value: String)(implicit meta: ParamMeta[T]): T =
meta(value.trim)
implicit case object IntMeta extends ParamMeta[Int] {
def apply(v: String): Int = v.toInt
}
// and so on
getParam[Int](/* ... */, "127") // = 127
There is even no need to throw exceptions! If you supply an unsupported type as getParam type argument, code will even not compile. You can rewrite signature of getParam using a syntax sugar for context bounds, T: Bound, which will require implicit value Bound[T], and you will need to use implicitly[Bound[T]] to access that values (because there will be no parameter name for it).
Also this code does not use reflection at all, because compiler searches for an implicit value ParamMeta[Int], founds it in object IntMeta and rewrites function call like getParam[Int](..., "127")(IntMeta), so it will get all required values at compile time.
If you feel that writing those case objects is too boilerplate, and you are sure that you will not need another method in these objects in future (for example, to convert T back to String), you can simplify declarations like this:
case class ParamMeta[T](f: String => T) {
def apply(s: String): T = f(s)
}
implicit val stringMeta = ParamMeta(identity)
implicit val intMeta = ParamMeta(_.toInt)
To avoid importing them every time you use getParam you can declare these implicits in a companion object of ParamMeta trait/case class, and Scala will pick them automatically.
As for original match approach, you can pass a implicit ClassTag[T] to your function, so you will be able to match classes. You do not need to create any values for ClassTag, as the compiler will pass it automatically. Here is a simple example how to do class matching:
import scala.reflect.ClassTag
import scala.reflect._
def test[T: ClassTag] = classTag[T].runtimeClass match {
case x if x == classOf[Int] => "I'm an int!"
case x if x == classOf[String] => "I'm a string!"
}
println(test[Int])
println(test[String])
However, this approach is less flexible than ParamMeta one, and ParamMeta should be preferred.

Strange implicit def with function parameter behaviour in Scala

I've written a simple code in Scala with implicit conversion of Function1 to some case class.
object MyApp extends App{
case class FunctionContainer(val function:AnyRef)
implicit def cast(function1: Int => String):FunctionContainer = new FunctionContainer(function1)
def someFunction(i:Int):String = "someString"
def abc(f : FunctionContainer):String = "abc"
println(abc(someFunction))
}
But it doesn't work. Compiler doesn't want to pass someFunction as an argument to abc. I can guess its reasons but don't know exactly why it doesn't work.
When you use a method name as you have, the compiler has to pick how to convert the method type to a value. If the expected type is a function, then it eta-expands; otherwise it supplies empty parens to invoke the method. That is described here in the spec.
But it wasn't always that way. Ten years ago, you would have got your function value just by using the method name.
The new online spec omits the "Change Log" appendix, so for the record, here is the moment when someone got frustrated with parens and introduced the current rules. (See Scala Reference 2.9, page 181.)
This has not eliminated all irksome anomalies.
Conversions
The rules for implicit conversions of methods to functions (§6.26) have been tightened. Previously, a parameterized method used as a value was always implicitly converted to a function. This could lead to unexpected results when method arguments were forgotten. Consider for instance the statement below:
show(x.toString)
where show is defined as follows:
def show(x: String) = Console.println(x)
Most likely, the programmer forgot to supply an empty argument list () to toString. The previous Scala version would treat this code as a partially applied method, and expand it to:
show(() => x.toString())
As a result, the address of a closure would be printed instead of the value of s. Scala version 2.0 will apply a conversion from partially applied method to function value only if the expected type of the expression is indeed a function type. For instance, the conversion would not be applied in the code above because the expected type of show’s parameter is String, not a function type. The new convention disallows some previously legal code. Example:
def sum(f: int => double)(a: int, b: int): double =
if (a > b) 0 else f(a) + sum(f)(a + 1, b)
val sumInts = sum(x => x) // error: missing arguments
The partial application of sum in the last line of the code above will not be converted to a function type. Instead, the compiler will produce an error message which states that arguments for method sum are missing. The problem can be fixed by providing an expected type for the partial application, for instance by annotating the definition of sumInts with its type:
val sumInts: (int, int) => double = sum(x => x) // OK
On the other hand, Scala version 2.0 now automatically applies methods with empty parameter lists to () argument lists when necessary. For instance, the show expression above will now be expanded to
show(x.toString())
Your someFunction appears as a method here.
You could try either
object MyApp extends App{
case class FunctionContainer(val function:AnyRef)
implicit def cast(function1: Int => String):FunctionContainer = new FunctionContainer(function1)
val someFunction = (i:Int) => "someString"
def abc(f : FunctionContainer):String = "abc"
println(abc(someFunction))
}
or
object MyApp extends App{
case class FunctionContainer(val function:AnyRef)
implicit def cast(function1: Int => String):FunctionContainer = new FunctionContainer(function1)
def someFunction(i:Int): String = "someString"
def abc(f : FunctionContainer):String = "abc"
println(abc(someFunction(_: Int)))
}
By the way: implicitly casting such common functions to something else can quickly lead to problems. Are you absolutely sure that you need this? Wouldn't it be easier to overload abc?
You should use eta-expansion
println(abc(someFunction _))

Can an implicit conversion of an implicit value satisfy an implicit parameter?

I'm defining some Scala implicits to make working with a particular unchangeable set of Java classes easier. The following Scala code is a simplified example that obviously looks crazy, in the real world I'm trying to grab particular resources (rather than numeric age) implicitly from the Monkey, Tree & Duck for use in various methods like purchaseCandles():
// actually 3 Java classes I can not change:
case class Monkey(bananas: Int)
case class Tree(rings: Int)
case class Duck(quacks: Seq[String])
// implicits I created to make my life easier...
implicit def monkey2Age(monkey: Monkey): Int = monkey.bananas / 1000
implicit def tree2Age(tree: Tree): Int = tree.rings
implicit def duck2Age(duck: Duck): Int = duck.quacks.size / 100000
// one of several helper methods that I would like to define only once,
// only useful if they can use an implicit parameter.
def purchaseCandles()(implicit age: Int) = {
println(s"I'm going to buy $age candles!")
}
// examples of usage
{
implicit val guest = Monkey(10000)
purchaseCandles()
}
{
implicit val guest = Tree(50)
purchaseCandles()
}
{
implicit val guest = Duck(Seq("quack", "quack", "quack"))
purchaseCandles()
}
The compiler error, which occurs 3 times:
could not find implicit value for parameter age: Int
purchaseCandles()
^
Leaving aside the many different ways in which this sample code is crazy, my real question is: can implicit conversions of implicit values satisfy implicit parameters in Scala?
Short answer: no. Scala's compiler will only ever look to apply a single implicit, so if it fails to spot an implicit int lying around, it will stop and give up.
However, you could write your purchaseCandles method to operate on types that can be converted to an Int, and require a parameter of that type:
def purchaseCandles[A <% Int]()(implicit age : A) = {
val asAge : Int = age
println(s"I'm going to buy $asAge candles!")
}
The asAge part is necessary to force the application of the implicit conversion.
As of yet, I seem to need to specify the type of A in this scenario, though I can't work out why: since there shouldn't be other values around of types that can be implicitly converted to Int (this happens with brand new types as well, so it's not the ubiquity of Int.) But you can do:
{
implicit val guest = Monkey(10000)
purchaseCandles[Monkey]()
}
This use of implicits, however, is probably a bad idea!
You actually can do that: You just have to mark the parameters of your implicit conversion as implicit as well:
implicit def monkey2Age(implicit monkey: Monkey): Int = monkey.bananas / 1000
implicit def tree2Age(implicit tree: Tree): Int = tree.rings
implicit def duck2Age(implicit duck: Duck): Int = duck.quacks.size / 100000
This will chain the implicits they way you want.
As always: Beware, it will also do so in places you don't want it to. By the way, I strongly advise against an implicit parameter of type Int (or an implicit value thereof). It is just too generic. (I'm somewhat assuming this is just like that in your example).