For command using devenv.exe runs too quickly - command-line

So I have a command I want to run which looks like the following:
for /r %n in ("*.vdproj") do "C:/Program Files/Microsoft
Visual Studio 10.0/Common7/IDE/devenv.exe" %n /build "BuildServer"
It seems to work in that it runs devenv on each .vdproj file; however, it seems to run them in parallel and immediately return. This is a problem; I need to wait until they are all finished before the next step in the .bat file runs. How can I either
1- Get for to 'wait' on each devenv to finish before running the next one
or
2- Wait until devenv.exe is all done before moving on afterwards?

The trick is to use devenv.com instead of devenv.exe. devenv.com will return output to the console and achieve exactly the desired result.

Invoke devenv.exe using start, e.g.
start /wait "" "C:/Program Files/Microsoft Visual Studio 10.0/Common7/IDE/devenv.exe" %n /build "BuildServer"
Use start /? for usage.

Related

Why is the termination behaviour of vscode different with other GUI program (WinMerge) when invoking from PowerShell?

In Windows PowerShell 5.1, after run & code ., a VSCode window opens, and the control returns back to PowerShell immediately. After the PowerShell exists, the VSCode will not be terminated.
On the other hand, when invoke other external program, such as WinMerge, after run & WinMergeU, a WinMerge window opens, and the control does not return back to PowerShell until WinMerge window is closed. And If PowerShell exists, WinMerge will be terminated.
Why the behaviour is different?
the difference is what is actuall happening:
when you run the command code, you are not really running code.exe. its starting a cmd script that spawns a new code.exe process with whatever arguments you passed it.
to see what a command actually executes, use the command get-command 'yourcommand', or with code get-command code.
this will show the follwing source: C:\Users\{username}\AppData\Local\Programs\Microsoft VS Code\bin\code.cmd.
Opening up this will show you:
#echo off
setlocal
set VSCODE_DEV=
set ELECTRON_RUN_AS_NODE=1
"%~dp0..\Code.exe" "%~dp0..\resources\app\out\cli.js" --ms-enable-electron-run-as-node %*
endlocal
so this means that in both cases you are waiting for execution to end, but for code its a code.cmd script and not actually code.exe.
If you want to start new processes and don't wait for them, you can use the command start-process winmergeu

How to exit Command Prompt after launching VSCode

Here are the steps to reproduce the problem:
Open Command Prompt. ( cmd )
Run code . to launching VSCode.
Type exit and hit Enter in the Command Prompt.
Then the Command Prompt is just paused. I have to wait VSCode exit to let Command Prompt window closed.
Does anyone know why? How can I close Command Prompt window without exiting VSCode?
I found a solution here: https://github.com/Microsoft/vscode/issues/6608. It involves changing the code.cmd file (usually found under "C:\Users\yourUsername\AppData\Local\Programs\Microsoft VS Code\bin").
Changing the fifth line in that file from
call "%~dp0..\Code.exe" "%~dp0..\resources\app\out\cli.js" %*
to
start "" "%~dp0..\Code.exe" "%~dp0..\resources\app\out\cli.js" %*
will make the cmd window close right away. But that change will apparently break some other things (specifically the --wait flag), so I figure it's wiser to leave the code.cmd file alone.
Instead I made a copy ("codeNoCommandPrompt.cmd") right beside it and changed the line in there. That works fine for my usecase, namely having VS Code start on a specific folder alongside a bunch of other programms via a script.
I just tested it (using the latest VSCode 1.24.1), and it does work: the CMD shell session closes immediately when typing "exit".
Try calling the code.cmd script with its full path to see if the issue persists:
"C:\Program Files\Microsoft VS Code\bin\code.cmd" .
Try also the same command after having simplified the PATH (for testing)
set PATH=C:\Program Files\Microsoft VS Code\bin;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\WINDOWS\System32\WindowsPowerShell\v1.0\
code .
Simply use this
code . && exit
Check your PATH variable, maybe you have duplicate entries for VS Code
Go System Properties -> Envieronment variables -> select PATH variable then click Edit.
Remove "C:**\Microsoft VS Code".
Leave intact "C:**\Microsoft VS Code\bin"
This happens when you reinstall vscode with "add to PATH" checked

Call multiple .bat from another .bat without waiting for one to finish

So, I want to make a script that will execute 2 .bat files and start some .exe files.
However, the .bat files are supposed to keep running.
I have something like this :
pushd tools\wamp64
start wampmanager.exe
pushd ..\..\server\login
call startLoginServer.bat
pushd ..\test
call startTestServer.bat
start "C:\DEV\P2\Test\client" P2.bin
The problem is that call startLoginServer.bat will not exit and therefore, I'm stucked here.
How can I run my 2 .bat files and let them keep running.
(Ideally, I want them to run in 2 different command prompt windows)
Also, there is probably a better way to handle relative path than using pushd if you can correct me on this.
Thanks
You could use:
start "Wamp Manager" /B /D "%~dp0tools\wamp64" wampmanager.exe
start "Login Server" /B /D "%~dp0server\login" startLoginServer.bat
start "Test Server" /B /D "%~dp0server\test" startTestServer.bat
start "Text Client" /B /D "%~dp0" "C:\DEV\P2\Test\client.exe" P2.bin
Run in a command prompt window start /? for help on this command explaining the options.
"..." ... title for new console window which is optional, but must be often specified on program to start is or must be enclosed in double quotes. The START command in last command line in batch file code in question interprets C:\DEV\P2\Test\client as window title. It is also possible to use an empty window title, i.e. "" which is best if the started application is a Windows GUI application on which no console window is opened at all.
/B ... run without opening a new window, i.e. in "background". This option can be omitted to see what the started applications and batch files output to console if the executables are not Windows GUI applications.
/D "..." or also /D"..." defines the directory to set first as current directory before running the command specified next. %~dp0 references the directory of the batch file containing these commands. This path always ends with a backslash. Therefore no backslash must be added on concatenating the directory of the batch file with a file or folder name or path.
Run in a command prompt window call /? for help on %~dp0 explaining how arguments of a batch file can be referenced from within a batch file.
See also the answer on How to call a batch file that is one level up from the current directory? explaining in total four different methods to call or run a batch file from within a batch file.
Finally read also the Microsoft documentations about the Windows kernel library function CreateProcess and the structure STARTUPINFO used by cmd.exe on every execution of an executable without or with usage of its internal command start. The options of start become more clear on having full knowledge about the kernel function and the structure used on Windows to run a program.

Batch start command not opening program

When I enter the following from a command prompt:
start myprog.exe
It opens the program in a command window, but it doesn't start the actual program itself.
Does anyone know what I'm doing wrong with this?
try this:
start /b "" "myprog.exe"
See start /? for more help.
You don't need START just have myprog.exe, make sure that the program can be found. Put the directory for it in the PATH environment variable if necessary.
If you want to continue processing more commands in the batch file use the /B switch for START, see syntax here Microsoft DOS start command.

Cygwin - run script silenty from "run command"

I have script lets say:
C:\foo.bsh
I want to be able to run this command via the windows run command:
Start -> Run
Windows Key + R
and type something small like 'foo' and hitting return.
However, I do not want a cmd prompt to be visible. This script does some preprocessing for an IDE. I do not want the cmd prompt to be open for the lifetime of the IDE process.
I have tried:
1) Creating a bat file with the following contents:
c:\cygwin\bin\bash --login "C:\foo.bsh" (this fails because it keeps a cmd open)
2) Converting the above bat file to an exe using bat_2_exe_converter (does not make the cmd silent)
thoughts?
EDIT: The solution so far suggests something to type from an actual cygwin shell. I am trying to get a faster solution by having something short I can type in the Windows run command. Also, the nohup command; exit doesn't automatically kill the box - however I can manually kill it without killing the IDE process. The run command accepts shortcuts (.lnk's), bat's, exe's.
Try the run.exe command of cygwin. It is a big install, a complete unix environment for your Windows machine. Suppose you installed it at c:\cygwin\.
No mystery, just run c:\cygwin\bin\run.exe <your command here> and you will have your no dos window execution.
You can run it from any DOS window (run cmd.exe from the start menu). You don't need to run it from cygwin.
To make it easier, append C:\cygwin\bin to your %PATH% env var (My Computer → Properties → Advanced → Environment Variables) (Kudos to Felipe Alvarez comment).
Now you can just type
c:\cygwin\bin\run.exe "C:\foo.bsh"
You must create a link in your Start Menu with this command so will be able to run it with Win-R.
Here is the man page of the runcommand:
$ man run
RUN(1) run 1.3.0 RUN(1)
NAME
run - start programs with hidden console window
SYNOPSIS
run [ -p path ] command [ -wait ] arguments
runcommand [ -p path ] [ -wait ] arguments
DESCRIPTION
Windows programs are either GUI programs or console programs. When
started console programs will either attach to an existing console
or create a new one. GUI programs can never attach to an exiting con‐
sole. There is no way to attach to an existing console but hide it if
started as GUI program.
run will do this for you. It works as intermediate and starts a pro‐
gram but makes the console window hidden.
With -p path you can add path to the PATH environment variable.
Issuing -wait as first program argument will make run wait for program
completition, otherwise it returns immediately.
The second variant is for creating wrappers. If the executable is
named runcommand (eg runemacs), run will try to start the program (eg
emacs).
EXAMPLES
run -p /usr/X11R6/bin xterm
run emacs -wait
runemacs -wait
run make -wait
AUTHORS
Charles S. Wilson
Harold L Hunt II
Jehan Bing
Alexander Gottwald
Version 1.3.0 November 2005 RUN(1)
You can use either...
c:\cygwin\bin\bash -l /path/to/script_to_interpret.sh
...or...
c:\cygwin\bin\bash -l -c /path/to/executable_script.sh
Note: the -l flag tell bash to "act as if it had been directly invoked by login" and use Bash Startup Files. This is important in that it sets your $PATH and other things you rely on when you launch a cygwin terminal. If you don't include -l or --login you will get "command not found" when you try to call anything except of a bash builtin.
The difference between the 2 is like the difference between doing...
bash script_to_interpret.sh
...and...
./executable_script.sh
...in *nix. The former interprets the script using bash. The latter executes the script (only if it has chmod +x executable_script.sh) and interprets it according to its "shebang" line. The latter method is also what you want to do if your executable is not a script at all, like a *nix binary compiled from source.)
It has been bugging me for a while I couldn't find the solution for this, but I finally got the right mix together.
You can simply do the following if you have cygwin on your PATH:
run bash test.js
If cygwin is not on your path, you can do this:
c:\cygwin\bin\run.exe -p /bin bash test.js
If you are looking for more control over the created window (maximize, etc) it looks like you can use cygstart also.
Sources:
- neves answer above (though that wasn't enough by itself for me personally to figure it out)
- http://cygwin.com/ml/cygwin/2008-09/msg00156.html
As the terminal can't close while your script is still running, try the command:
"nohup C:\foo.bsh; exit"
This way your script will be backgrounded and detached from the terminal, and it should exit quickly so the terminal goes away. I think that the window may still 'flash' with this approach, but the results should be better than what you're getting.
I'm running Cygwin64 and the xwin server link points to:
C:\cygwin64\bin\run.exe /usr/bin/bash.exe -l -c /usr/bin/startxwin.exe
This creates an icon AND a notification on the taskbar. I don't like that. The icon is rather useless, the notification has all your menu options from .XWinrc.
So... I wrote a .vbs script to silently run this command and make the icon go away:
Set objShell = CreateObject("WScript.Shell")
objShell.Run("C:\cygwin64\bin\run.exe /usr/bin/bash.exe -l -c /usr/bin/startxwin.exe"), 0
Another imperfect possibility is to run the script via a shortcut and set the shortcut's Run option to "minimized".
Go to the directory where you have installed cygwin(on my machine it is c:/cygwin64/bin)
Once there simply type "bash.exe"