For Loop Objective C - iphone

Why do I get this as a result to this code?
CODE
ids = 0;
for (NSString *s in golferThreeIconCounter) {
ids++;
NSLog(#"%i", ids);
}
RESULT
2012-05-24 16:30:35.194 Dot Golf Scoring[673:f803] 4
2012-05-24 16:30:35.196 Dot Golf Scoring[673:f803] 8
2012-05-24 16:30:35.196 Dot Golf Scoring[673:f803] 12
2012-05-24 16:30:35.197 Dot Golf Scoring[673:f803] 16
2012-05-24 16:30:35.197 Dot Golf Scoring[673:f803] 20
2012-05-24 16:30:35.198 Dot Golf Scoring[673:f803] 24
2012-05-24 16:30:35.199 Dot Golf Scoring[673:f803] 28
2012-05-24 16:30:35.199 Dot Golf Scoring[673:f803] 32
2012-05-24 16:30:35.200 Dot Golf Scoring[673:f803] 36
2012-05-24 16:30:35.200 Dot Golf Scoring[673:f803] 40
2012-05-24 16:30:35.201 Dot Golf Scoring[673:f803] 44
2012-05-24 16:30:35.201 Dot Golf Scoring[673:f803] 48
2012-05-24 16:30:35.202 Dot Golf Scoring[673:f803] 52
2012-05-24 16:30:35.202 Dot Golf Scoring[673:f803] 56
2012-05-24 16:30:35.203 Dot Golf Scoring[673:f803] 60
It makes absolutely no sense to me why ids goes up 4 times instead of just once...

When you declare an int, you do not add *: it's not an <id> type. What you have is a pointer to an int; on a 32-bit platform it increments by 4.
int ids = 0;

You're printing the "position" count of a pointer which is referenced in an array.
So let me try to clarify that.
A pointer is four bytes. In this case you have an array of pointers. So when you loop over you are printing the int value of the index of the pointer.

You need to increment by using: *ids++ since you've declared it as a reference. Or else you need to declare it as a primitive variable: int ids = 0;

int ids = 0;
for (NSString *s in golferThreeIconCounter) {
ids++;
NSLog(#"%i", ids);
}
Try this. You never declared the type of variable that ids is.

Related

kdb - nested functions within nested dictionaries

All,
I'm testing whether or not I can build a robust data model using nested dictionaries
of data and f(x). The namespace/dot notation works well for what I'm attempting and we can reference the dictionary well but I'm unable to get the functions to execute when called as I thought.
I was hoping to reference the dictionary in the functions recursively to execute and recalculate when called and reduce incredible long functions.
Keeping the functions as part of the dictionary is an objective as we expect to have various functions for different dictionaries of data.
Here is a simple example of a nested dictionary and functions with the objective to calculate total rev based on the data in the inventory for prodA and prodB.
Many thanks in advance!
.inv.prodA.qty: 10 #10;
.inv.prodA.price: 10 #2.75;
.inv.prodA.cogs: 10 # 1.35;
.inv.prodA.net_price: {[x] x[`price] - x[`cogs]};
.inv.prodA.net_price [.inv.prodA];
.inv.prodA.rev: {[x] x[`qty] * (inv.net_price[ x[`price] - x[`cogs]])};
.inv.prodB.qty: 20 #2.50;
.inv.prodB.price: 20 #1.50;
.inv.prodB.cogs: 20 # 0.25;
.inv.prodB.net_price: {[x] x[`price] - x[`cogs]};
.inv.prodB.net_price [.inv.prodB];
.inv.prodB.rev: {[x] x[`qty] * (inv.net_price[ x[`price] - x[`cogs]])*.5}; //Note that the rev f(x) are unique for each prodA and prodB
.inv.total.rev: {[x] x[`prodA`rev] + x[`prodB`rev]};
I think you want something like:
.inv.prodA.net_price:{.inv[x;`price] - .inv[x;`cogs]};
.inv.prodA.rev:{.inv[x;`qty] * .inv[x;`net_price]x};
.inv.prodB.net_price:{.inv[x;`price] - .inv[x;`cogs]};
.inv.prodB.rev:{.inv[x;`qty] * .inv[x;`net_price][x] *.5};
.inv.total.rev:{.inv[`prodA;`rev][`prodA] , .inv[`prodB;`rev]`prodB};
q).inv.total.rev[]
14 14 14 14 14 14 14 14 14 14 1.5625 1.5625 1.5625 1.5625 1.5625 1.5625 1.562..
Changed your last function to an append because they're not the same length for addition. If you want to change the .inv into a variable too then you can modify the functions to pass those through as follows:
.inv.prodA.net_price:{y[x;`price] - y[x;`cogs]};
.inv.prodA.rev:{y[x;`qty] * y[x;`net_price][x;y]};
.inv.prodB.net_price:{y[x;`price] - y[x;`cogs]};
.inv.prodB.rev:{y[x;`qty] * y[x;`net_price][x;y] *.5};
.inv.total.rev:{x[`prodA;`rev][`prodA;x] , x[`prodB;`rev][`prodB;x]};
q).inv.total.rev[`.inv]
14 14 14 14 14 14 14 14 14 14 1.5625 1.5625 1.5625 1.5625 1.5625 1.5625 1.562..

How can I efficiently convert the output of one KDB function into three table columns?

I have a function that takes as input some of the values in a table and returns a tuple if you will - three separate return values, which I want to transpose into the output of a query. Here's a simplified example of what I want to achieve:
multiplier:{(x*2;x*3;x*3)};
select twoX:multiplier[price][0]; threeX:multiplier[price][1]; fourX:multiplier[price][2] from data;
The above basically works (I think I've got the syntax right for the simplified example - if not then hopefully my intention is clear), but is inefficient because I'm calling the function three times and throwing away most of the output each time. I want to rewrite the query to only call the function once, and I'm struggling.
Update
I think I missed a crucial piece of information in my explanation of the problem which affects the outcome - I need to get other data in the query alongside the output of my function. Here's a hopefully more realistic example:
multiplier:{(x*2;x*3;x*4)};
select average:avg price, total:sum price, twoX:multiplier[sum price][0]; threeX:multiplier[sum price][1]; fourX:multiplier[sum price][2] by category from data;
I'll have a go at adapting your answers to fit this requirement anyway, and apologies for missing this bit of information. The real function if a proprietary and fairly complex algorithm and the real query has about 30 output columns, hence the attempt at simplifying the example :)
If you're just looking for the results themselves you can extract (exec) as lists, create dictionary and then flip the dictionary into a table:
q)exec flip`twoX`threeX`fourX!multiplier[price] from ([]price:til 10)
twoX threeX fourX
-----------------
0 0 0
2 3 4
4 6 8
6 9 12
8 12 16
10 15 20
12 18 24
14 21 28
16 24 32
18 27 36
If you need other columns from the original table too then its trickier but you could join the tables sideways using ,'
q)t:([]price:til 10)
q)t,'exec flip`twoX`threeX`fourX!multiplier[price] from t
An apply # can also achieve what you want. Here data is just a table with 10 random prices. # is then used to apply the multiplier function to the price column while also assigning a column name to each of the three resulting lists:
q)data:([] price:10?100)
q)multiplier:{(x*2;x*3;x*3)}
q)#[data;`twoX`threeX`fourX;:;multiplier data`price]
price twoX threeX fourX
-----------------------
80 160 240 240
24 48 72 72
41 82 123 123
0 0 0 0
81 162 243 243
10 20 30 30
36 72 108 108
36 72 108 108
16 32 48 48
17 34 51 51

How to convert alphabets to numerical values with spaces and return it back to alphabets?

Want to convert the alphabet to numerical values and transform it back to alphabets using some mathematical techniques like fast Fourier transform in MATLAB.
Example:
The following is the text saved in "text2figure.txt" file
Hi how r u am fine take care of your health
thank u very much
am 2.0
Reading it in MATLAB:
data=fopen('text2figure.txt','r')
d=fscanf(data,'%s')
temp = fileread( 'text2figure.txt' )
temp = regexprep( temp, ' {6}', ' NaN' )
c=cellstr(temp(:))'
Now I wish to convert cell array with spaces to numerical values/integers:
coding = 'abcdefghijklmnñopqrstuvwxyz .,;'
str = temp %// example text
[~, result] = ismember(str, coding)
y=result
result =
Columns 1 through 18
0 9 28 8 16 24 28 19 28 22 28 1 13 28 6 9 14 5
Columns 19 through 36
28 21 1 11 5 28 3 1 19 5 28 16 6 28 26 16 22 19
Columns 37 through 54
28 8 5 1 12 21 8 28 0 0 21 8 1 14 11 28 22 28
Columns 55 through 71
23 5 19 26 28 13 22 3 8 0 0 1 13 28 0 29 0
Now I wish to convert the numerical values back to alphabets:
Hi how r u am fine take care of your health
thank u very much
am 2.0
How to write a MATLAB code to return the numerical values in the variable result to alphabets?
Most of the code in the question doesn't have any useful effects. These three lines are the ones that lead to result:
str = fileread('test2figure.txt');
coding = 'abcdefghijklmnñopqrstuvwxyz .,;';
[~, result] = ismember(str, coding);
ismember returns, in the second output argument, the indices into coding for each element of str. Thus, result are indices that we can use to index into coding:
out = coding(result);
However, this does not work because some elements of str do not occur in coding, and for those elements ismember returns 0, which is not a valid index. We can replace the zeros with a new character:
coding = ['*',coding];
out = coding(result+1);
Basically, we're shifting each code by one, adding a new code for 1.
One of the characters we're missing here is the newline character. Thus the three lines have become one line. You can add a code for the newline character by adding it to the coding table:
str = fileread('test2figure.txt');
coding = ['abcdefghijklmnñopqrstuvwxyz .,;',char(10)]; % char(10) is the newline character
[~, result] = ismember(str, coding);
coding = ['*',coding];
out = coding(result+1);
All of this is easier to achieve just using the ASCII code table:
str = fileread('test2figure.txt');
result = double(str);
out = char(result);

how I delete combination rows that have the same numbers from matrix and only keeping one of the combinations?

for a=1:50; %numbers 1 through 50
for b=1:50;
c=sqrt(a^2+b^2);
if c<=50&c(rem(c,1)==0);%if display only if c<=50 and c=c/1 has remainder of 0
pyth=[a,b,c];%pythagorean matrix
disp(pyth)
else c(rem(c,1)~=0);%if remainder doesn't equal to 0, omit output
end
end
end
answer=
3 4 5
4 3 5
5 12 13
6 8 10
7 24 25
8 6 10
8 15 17
9 12 15
9 40 41
10 24 26
12 5 13
12 9 15
12 16 20
12 35 37
14 48 50
15 8 17
15 20 25
15 36 39
16 12 20
16 30 34
18 24 30
20 15 25
20 21 29
21 20 29
21 28 35
24 7 25
24 10 26
24 18 30
24 32 40
27 36 45
28 21 35
30 16 34
30 40 50
32 24 40
35 12 37
36 15 39
36 27 45
40 9 41
40 30 50
48 14 50
This problem involves the Pythagorean theorem but we cannot use the built in function so I had to write one myself. The problem is for example columns 1 & 2 from the first two rows have the same numbers. How do I code it so it only deletes one of the rows if the columns 1 and 2 have the same number combination? I've tried unique function but it doesn't really delete the combinations. I have read about deleting duplicates from previous posts but those have confused me even more. Any help on how to go about this problem will help me immensely!
Thank you
welcome to StackOverflow.
The problem in your code seems to be, that pyth only contains 3 values, [a, b, c]. The unique() funcion used in the next line has no effect in that case, because only one row is contained in pyth. another issue is, that the values idx and out are calculated in each loop cycle. This should be placed after the loops. An example code could look like this:
pyth = zeros(0,3);
for a=1:50
for b=1:50
c = sqrt(a^2 + b^2);
if c<=50 && rem(c,1)==0
abc_sorted = sort([a,b,c]);
pyth = [pyth; abc_sorted];
end
end
end
% do final sorting outside of the loop
[~,idx] = unique(pyth, 'rows', 'stable');
out = pyth(idx,:);
disp(out)
a few other tips for writing MATLAB code:
You do not need to end for or if/else stements with a semicolon
else statements cover any other case not included before, so they do not need a condition.
Some performance reommendations:
Due to the symmetry of a and b (a^2 + b^2 = b^2 + a^2) the b loop could be constrained to for b=1:a, which would roughly save you half of the loop cycles.
if you use && for contencation of scalar values, the second part is not evaluated, if the first part already fails (source).
Regards,
Chris
You can also linearize your algorithm (but we're still using bruteforce):
[X,Y] = meshgrid(1:50,1:50); %generate all the combination
C = (X(:).^2+Y(:).^2).^0.5; %sums of two square for every combination
ind = find(rem(C,1)==0 & C<=50); %get the index
res = unique([sort([X(ind),Y(ind)],2),C(ind)],'rows'); %check for uniqueness
Now you could really optimized your algorithm using math, you should read this question. It will be useful if n>>50.

Matlab: delete complete line in txt-file if there is a non-ascii-character

I'm currently writing a Matlab code to plot measurement data. Unfortunately there is a hardware problem with serial communication and sometimes i receive just gibberish. My code works only for defined data, so this gibberish has to be removed. I want something like this pseudo code:
for eachLine
if currentLineContainsNonASCII
delete completeLine
end if
end for
the data is read like this
rawdataInputFilename = 'measurementData.txt';
fileID = fopen(rawdataInputFilename);
% load data as string
DataCell = textscan(fileID,'%s %s %s %s %s %s %s %s %s %s %s %s %s %s %s','HeaderLines', 1);
I was thinking about first creating a new 'clean' file with only ASCII chars and then reading that file with my actual plotting code.
Where I stuck is how to identify a non ASCII and then deleting the whole line, not only overwriting that single char.
Some example data, 1. and 3. line are 'clean' and can be handled with the current code. Second Line has non ASCIIs in it and therefore kills my code. Whitespace characters are windows linefeed, tab and space.
61 380 Module03 Slot02 27.01.2015 13:47:13 450 3587 1175 84 101.83 22.30 5.20 1 1
62 386 Module03 Slot03 27.01.2015 13:47:18 450ÆădzШШ 106.83 22.30 25.20 1 1
63 391 Module03 Slot04 27.01.2015 13:47:24 ERROR dgsf 5643332 103.26 22.40 25.20 1 1
You can just check if the received character is in the range [32, 127], otherwise skip it.
The following function will tell you if there is any non-printable character in a given string:
function R = has_non_printable_characters(str)
% Remove non-printable characters
str2 = str(31<str & str<127);
% check if length of resulting string is the same than input string
R = (lenght(str) > length(str2))
end;
If instead of just skipping the entire string you want to remove non-printable characters keeping the printable ones, modify the function and return str2. (And change the function name so it matches the new behaviour)
There are several ways to do it.
Save that to a text file named data.txt:
bla Header bla
61 380 Module03 Slot02 27.01.2015 13:47:13 450 3587 1175 84 101.83 22.30 5.20 1 1
62 386 Module03 Slot03 27.01.2015 13:47:18 450ÆădzШШ 106.83 22.30 25.20 1 1
63 391 Module03 Slot04 27.01.2015 13:47:24 ERROR dgsf 5643332 103.26 22.40 25.20 1 1
Method 1 (using textscan and cellfun):
Removing the non-ASCII line completely:
fileID = fopen('data.txt'); % open file
DataCell = textscan(fileID,'%s','delimiter','','HeaderLines', 1); % read a complete line of text, ignore the first line
fclose(fileID); % close file
DataCell = DataCell{1}; % there is only one string per line
DataCell(cellfun(#(x) any(x>127),DataCell)) = []; % remove line if there is any non-ASCII in it, adjust that to your liking, i.e (x>126 | x<32)
celldisp(DataCell)
DataCell{1} =
61 380 Module03 Slot02 27.01.2015 13:47:13 450 3587 1175 84 101.83 22.30 5.20 1 1
DataCell{2} =
63 391 Module03 Slot04 27.01.2015 13:47:24 ERROR dgsf 5643332 103.26 22.40 25.20 1 1
You could now loop over the cell array or, if you like, start all over again with the updated text (f.e. as input to textscan). To do that join the cells together to one big chunk of text:
strjoin(DataCell','\n')
ans =
61 380 Module03 Slot02 27.01.2015 13:47:13 450 3587 1175 84 101.83 22.30 5.20 1 1
63 391 Module03 Slot04 27.01.2015 13:47:24 ERROR dgsf 5643332 103.26 22.40 25.20 1 1
Method 2 (using regexprep):
I'm loading the whole text file at once and replacing any line with an empty string '', which does not contain a given set of characters.
s = fileread('data.txt');
snew = regexprep(s, '.*[^\w\s.:].*\n', '', 'dotexceptnewline')
snew =
61 380 Module03 Slot02 27.01.2015 13:47:13 450 3587 1175 84 101.83 22.30 5.20 1 1
63 391 Module03 Slot04 27.01.2015 13:47:24 ERROR dgsf 5643332 103.26 22.40 25.20 1 1
The [^\w\s.:] bit bascially translates to:
Match any chararcter which is not (the ^ means not):
alphabetic, numeric or underscore (\w)
whitespace (\s)
a dot . or
a colon :
If you want to exclude any other ASCII character, just add it (to within the brackets).
here is the code which creates a new txt-file whitout the lines with non-ASCII
%% read in via GUI
[inputFilename, inputPathname] = uigetfile('*.txt', ...
'Pick a .txt file from which you want to remove lines with non ASCII characters.');
if isequal(inputFilename, 0)
disp('User selected ''Cancel''')
else
disp(['User selected ', fullfile(inputPathname, inputFilename)])
inputFileID = fopen(fullfile(inputPathname, inputFilename)); %open/load file
end
tempCell = (strsplit(inputFilename,'.'));
inputFilenameWOextension = cell2mat(tempCell(1));
fileExtension = cell2mat(tempCell(2));
outputFileID = fopen([inputFilenameWOextension, '_ASCIIonly.', fileExtension], 'w'); %overwrite existing file
% get a single line of text
tline = fgetl(inputFileID);
while tline ~= -1
% get a single line of text
tline = fgetl(inputFileID);
% Remove non-printable characters
tempStr = tline(tline<127); % not really ASCII, but also tab
%tempStr = tline(31<tline & tline<127); % true ASCII
if (length(tempStr) < length(tline));
continue;
else
fprintf(outputFileID, '%s\r\n', tempStr);
end
end
fclose(inputFileID);
fclose(outputFileID);