Random numbers without repetition - iphone

I am making Quiz app in which i want to generate random numbers without repetition.
I have searched many things and got the idea but i think i am doing something wrong that's why not getting correct output.
Here is the code that i used.
-(int)generater{
NSMutableArray *temp;
srand([[NSDate date] timeIntervalSince1970]);
r = 1 + (arc4random() % 11);
if ([temp count] ==0) {
[temp addObject:[NSNumber numberWithInteger:questionnumber]];
return r;
}
if ([temp count] >= 1 ){
if (![temp containsObject:[NSNumber numberWithInteger:questionnumber]]) {
return r;
}
else{
int next=[self generater];
return next;
}
}
return r;
}
For next Question,
-(void)askQuestion{
[self generater];
questionnumber = r;
NSInteger row = 0;
if(questionnumber == 1)
{
row = questionnumber - 1;
}
else
{
row = ((questionnumber - 1) * 11);
}
Can any one suggest me where i am wrong ?

arryRandomNumber=[[NSMutableArray alloc]init];
while (arryRandomNumber.count<12) {
NSInteger randomNumber=1+arc4random()%12;
if (![arryRandomNumber containsObject:[NSString stringWithFormat:#"%d",randomNumber]]) {
[arryRandomNumber addObject:[NSString stringWithFormat:#"%d",randomNumber]];
}
continue;
}
NSLog(#"%#",arryRandomNumber);

Surely the best approach is to put all the questions (or question numbers) sequentially into an array, and then shuffle them.
See What's the Best Way to Shuffle an NSMutableArray?
Some additional guidance (NB all code written in the browser and not actually compiled and tested; but should still get the gist):
1) Set up an ivar NSMutableArray *randomQuestionNumbers. Initialise the contents of the array with the number of questions, so if you have 5 questions put the numbers 1-5 in. To do it manually it would be:
randomQuestionNumbers = [NSMutableArray arrayWithObjects:[NSNumber numberWithInt:1], [NSNumber numberWithInt:2], [NSNumber numberWithInt:3], [NSNumber numberWithInt:4], [NSNumber numberWithInt:5], nil];
2) After that, you need to shuffle, by using one of the methods given in the link above.
That will transform [1,2,3,4,5] -> [4,1,5,3,2] for example
3) So now create your method to get the next question number:
- (NSInteger) nextQuestionNumber {
NSInteger nextQuestionNumber = -1;
if ([randomQuestionNumbers count] > 0) {
nextQuestionNumber = (NSInteger) [randomQuestionNumbers objectAtIndex:0];
[randomQuestionNumbers removeObjectAtIndex:0];
}
return nextQuestionNumber;
}
What's happening here is we retrieve the first int in the array. Then we remove that element from the array. Finally, we return the int, e.g., 4. The next time the method is called, there is one fewer element, and the first element is the int 1, and so on. I'm rather crudely using -1 to show when the array is empty, but to be honest you should be able to ensure you don't call the method more times that necessary.

Hope this code will help you...
Here limit should be set by your requirement.
Benefit of this code is it won't repeat the same random number which is already been got. (No repetitive numbers)
srand(time(NULL));
int randomIndex = rand() % limit;
[reportIDTextField setText:[NSString stringWithFormat:#"%i", randomIndex]];
Enjoy coding :)

Random number between two numbers method:
- (int)randomFromSmallest: (int) smallest toLargest: (int) largest
{
int random = smallest + arc4random() % (largest + 1 - smallest);
return random;
}
And that's how I filling an array of non-repeating numbers:
NSMutableArray *randNrArray = [[NSMutableArray alloc] init];
while ([randNrArray count] < 25)
{
int rndNumber = [self randomFromSmallest:0 toLargest:25 - 1];
if (![randNrArray containsObject:[NSNumber numberWithInt:rndNumber]])
{
[randNrArray addObject:[NSNumber numberWithInt:rndNumber]];
//NSLog(#"___ %d ___", rndNumber);
}
}
I hope this helps.

Put all your question numbers in a NSMutableArray (1, 2, 3, 4, 5, 6, 7, 8), then perform a number of permutations on this array.
I use this approach to scramble a numeric keypad:
// Randomize keys: exchange two random keys, ten times.
for (int i = 0; i < 10; i++)
{
int a = 0, b = 0;
while (a == b)
{
a = arc4random() % 10;
b = arc4random() % 10;
}
UIButton *btnA = (UIButton *)[_scrambledKeypad viewWithTag:a + 10];
UIButton *btnB = (UIButton *)[_scrambledKeypad viewWithTag:b + 10];
CGRect frame = btnA.frame;
btnA.frame = btnB.frame;
btnB.frame = frame;
}

Maybe :
r = [self generater];
questionnumber = r;

Related

Random number generation from an NSMutable array [duplicate]

This question already has answers here:
Non repeating random numbers in Objective-C
(6 answers)
Generating non-repeating random numbers
(5 answers)
Closed 9 years ago.
I need to generate random numbers from an array i have tried this inside the for loop
rnd = arc4random_uniform(arr.count);
it generated random numbers but some numbers get repeated also tried Random() in math.h
still the same problem persists please help me out..
Thanks in advance..
if i understood
"I need to generate random numbers from an array"
correctly, you want the numbers to be taken from an array randomly, if so then
first store the numbers in an NSMutableArray
NSMutableArray *arr=//store your numbers in this array.
-(void)getRandomNumberFromArray:(NSMutableArray *)arr{
int r = arc4random() % arr.count;
int number=[arr objectAtIndex:r];
[arr removeObjectAtIndex:r];
}
Generate a random number for each element, and then check to make sure it's not the same as one of the existing ones. If it already exists, try again.
for(int i = 0; i < arr.count;i++)
{
BOOL isRandom = YES;
int rand = -1;
while(!isRandom )
(
isRandom = YES;
rand = arc4random() % 5;
for(int j = 0; j < i; j++)
{
int existingNumber = arr[j];
if(existingNumber == rand)
{
isRandom = NO;
break;
}
}
}
arr[i] = rand;
}
Another option is to first just assign them to have incrementing values, and then shuffle the mutable array. What's the Best Way to Shuffle an NSMutableArray?
If I understood your problem , then you dont need random numbers , you need to shuffle the elements in the Array ?
Then you need to use this method ,
-(void)shuffleWithArray:(NSArray*)cardsArray
{
NSMutableArray *shuffleArray =[[NSMutableArray alloc]initWithArray:cardsArray];
// NSUInteger count1=[shuffleArray count];
for (NSUInteger i= 0; i<[shuffleArray count]; i++)
{
int nElement=[shuffleArray count] -i;
int n=(arc4random()%nElement + i);
[shuffleArray exchangeObjectAtIndex:i withObjectAtIndex:n];
}
}
You can make use of the following function.
#property (nonatomic,strong) NSMutableArray * numbers;
- (NSInteger) nonRepeatedNumber
{
if(_numbers == nil)
{
_numbers = [[NSMutableArray alloc]init];
}
NSInteger number = arc4random()% arr.count;
while ([_numbers containsObject:[NSNumber numberWithInt:number]])
{
number = arc4random()% arr.count;;
}
[_numbers addObject:[NSNumber numberWithInt:number]];
return number;
}
Check the below Tutorial. it must help for you.
iOS Random Number generator
Try the following method
-(NSMutableArray*)randomNumbersfromArray:(NSArray*)array {
NSArray *numbers = array;
int count = [numbers count];
NSMutableArray *addedIndexes = [[NSMutableArray alloc]initWithCapacity:count];
NSMutableArray *addedObjects = [[NSMutableArray alloc]initWithCapacity:count];
int i = 0;
while ([addedIndexes count] != [numbers count]) {
int random = arc4random() % count ;
if (![addedIndexes containsObject:[NSString stringWithFormat:#"%i",random]]) {
[addedIndexes addObject:[NSString stringWithFormat:#"%i",random]];
[addedObjects addObject:[numbers objectAtIndex:random]];
i++;
}
}
return addedObjects;
}
#include <stdlib.h>
int r = 0;
if (arc4random_uniform != NULL)
r = arc4random_uniform (arr.count);
else
r = (arc4random() % arr.count);
int randomNumberFromArray=[arr objectAtIndex:r];
EDIT
Bingo.After some thinking i made it working
-(NSArray *)randomizeArray:(NSArray *)inputArray
{
NSMutableArray *checkArray=[[NSMutableArray alloc]initWithCapacity:3];
NSMutableArray *outputArray=[[NSMutableArray alloc]initWithCapacity:3];
while ([outputArray count]<[inputArray count])
{
int r=[self getRandomNumber:[inputArray count]];
if ([checkArray containsObject:[NSNumber numberWithInt:r]])
{
}
else
{
[checkArray addObject:[NSNumber numberWithInt:r]];
[outputArray addObject:[inputArray objectAtIndex:r]];
}
}
return outputArray;
}
-(int)getRandomNumber:(int)maxValue
{
int r = 0;
if (arc4random_uniform != NULL)
r = arc4random_uniform (maxValue);
else
r = (arc4random() % maxValue);
return r;
}
This randomizeArray: method will give you the whole array randomized

Generating a unique number [closed]

It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I'm trying to generate a unique number for a bingo app, now its choses at 90 random numbers between 1-90 and adds them to a NSMutableSet. That all works, but I get the number picked from the set to be unique, so the same number is pulled out twice.
Here is what I have so far:
NSMutableSet * numberSet1 = [NSMutableSet setWithCapacity:90];
while ([numberSet1 count] < 90 ) {
NSNumber * randomNumber1 = [NSNumber numberWithInt:(arc4random() % 90 + 1)];
[numberSet1 addObject:randomNumber1];
}
//NSLog(#"numberWithSet : %# \n\n",numberSet1);
NSArray * numbers = [numberSet1 allObjects];
//to display
int r = arc4random() % [numbers count];
if(r<[numbers count]){
numberLabel.text = [NSString stringWithFormat:#"%#", [numbers objectAtIndex:r]];
}
How can I stop it from giving me duplicates?
Thanks in advance
As an alternative to picking random numbers with arc4random() (which samples with replacement, which you probably don't want for a Bingo game):
Take an array of numbers 1 through 90.
Shuffle that array.
Pick the first number from the array, then the second, and so on.
Keep an index of the currently selected element in the array. To get the next number, increment and check if you are dereferencing the 90th element.
Some pseudo-code:
#define SIZE 90
unsigned int index;
unsigned int elements[SIZE];
/* step 1 -- populate the array with elements 1 through 90 */
for (index = 0; index < SIZE; index++)
elements[index] = index + 1;
/* step 2 -- shuffle the array */
fisher_yates_shuffle(elements);
/* step 3 -- read from the array */
for (index = 0; index < SIZE; index++)
fprintf(stdout, "element at index %u is %u\n", index, elements[index]);
This creates and shuffles an array.
// array to shuffle
NSMutableArray *array = [NSMutableArray array];
for(int i=1; i<91; i++){
[array addObject:[NSNumber numberWithInt:i]];
}
// shuffle
for (int i = [array count]-1; i>0; i--) {
[array exchangeObjectAtIndex:i withObjectAtIndex:arc4random()%(i+1)];
}
Not sure if this is what you want since picking 90 numbers at random from 1-90 with no duplicates and adding them to a mutable set is no different from adding everything to a mutable set. But if you want a subset of the 90 numbers just take up to n elements from the array.
From a lottery app I wrote a while back, also applicable here-
int ball[6], counter, check, similarity;
for ( counter = 1; counter <= 6; counter++ )
{
for (;;)
{
similarity = 0;
ball[counter] = 1 + arc4random() % 6;
for (check = counter-1; check >= 1;check--)
{
if ( ball[check] == ball[counter] )
{
similarity = 1;
break;
}
}
if(similarity == 0)
break;
}
printf("%i\n", ball[counter]);
}
Checks the chosen ball with all previous balls, will never get the same number twice.
Create a category on NSMutableArray
#implementation NSMutableArray (RandomUtils)
-(void)shuffle
{
NSUInteger count = [self count];
for (NSUInteger i = 0; i < count; ++i) {
NSUInteger nElements = count - i;
NSUInteger n = (arc4random() % nElements) + i;
[self exchangeObjectAtIndex:i withObjectAtIndex:n];
}
}
#end
You can also wrap it for a NSArray version
#implementation NSArray (RandomUtils)
-(NSMutableArray *)mutableArrayShuffled
{
NSMutableArray *array = [[self mutableCopy] autorelease];
[array shuffle];
return array;
}
-(NSArray *)arrayShuffled
{
return [NSArray arrayWithArray:[self mutableArrayShuffled]];
}
#end
Where needed, import the category, and do:
NSMutableArray *array = [NSMutableArray array];
for(int i=0; i<90; i++){
[array addObject:[NSNumber numberWithInt:i+1]];
}
[array shuffle];
NSArray *newarray = [array subarrayWithRange:NSMakeRange(0,6)];
Another approach could be to fill a set with 6 random picks.
in the Category:
#implementation NSArray (RandomUtils)
-(id)randomElement
{
if ([self count] < 1) return nil;
NSUInteger randomIndex = arc4random() % [self count];
return [self objectAtIndex:randomIndex];
}
#end
use it like:
NSMutableSet *mset = [NSMutableSet set];
while ([mset count]<6) {
[mset addObject:[array randomElement]];
}

How to check unique int number in iphone

How can we check if the number generated through
I am trying to generate a unique number in between 0 to 10.
randomNumber = arc4random() % 10;
is unique or not??
i am able to generate a random number, but not able to check,whether its unique or not?
Thanks
To avoid duplication, refer a following random number generation code. When you run the following code also does not overlap any number. If you mean you want it unique.
#define COUNT 1000
#define RANGE 1000
int num[COUNT];
bool isNew(int idx, int val)
{
for (int i=0; i<idx; i++)
{
if (num[i] == val) return false;
}
return true;
}
for (int i=0; i<COUNT; i++)
{
do
{
num[i]=arc4random()%RANGE;
}
while (!isNew(i, num[i]));
NSLog(#"%d ", num[i]);
}
You can save all generated numbers in an array and check whether there are two duplicates.
The more number you have, the more is sure that the generated numbers are unique.
Try this code...this will give you all the possible unique number set in Mutable array...
-(NSInteger) randomNumber {
NSInteger newRandomNumber = (NSInteger) arc4random() % 10;
NSInteger uniqueNumber;
if ([self.arrayContainingNumbers containsObject: [NSNumber numberWithInteger:newRandomNumber]]) {
[self randomNumber];
} else {
[self.arrayContainingNumbers addObject: [NSNumber numberWithInteger:newRandomNumber]];
}
uniqueNumber = [[self.mutableArrayContainingNumbers lastObject]integerValue];
NSLog(#"new Unique Number is %ld",(long)uniqueNumber);
return uniqueNumber; }
Don't forget to add this method :)
-(NSMutableArray *) arrayContainingNumbers {
if (!_mutableArrayContainingNumbers) {
_mutableArrayContainingNumbers = [[NSMutableArray alloc] init];
}
return _mutableArrayContainingNumbers; }

Permutations/Anagrams in Objective-C -- I am missing something

(code below regarding my question)
Per this stack overflow question I used Pegolon's approach to generating all possible permutations of a group of characters inside an NSString. However, I am now trying to get it to not just generate an ANAGRAM which is all permutations of the same length, but all possible combinations (any length) of the characters in a string.
Would anyone know how i would alter the following code to get it to do this? This is much like: Generate All Permutations of All Lengths -- but (for fear of them needing answer to homework) they did not leave code. I have a sample of what I thought would do it at the bottom of this post... but it did not.
So, the code, as is, generates the, teh, hte, het, eth and eht when given THE.
What I need is along the lines of: t,h,e,th,ht,te,he (etc) in addition to the above 3 character combinations.
How would I change this, please. (ps: There are two methods in this. I added allPermutationsArrayofStrings in order to get the results back as strings, like I want them, not just an array of characters in another array). I am assuming the magic would happen in pc_next_permutation anyway -- but thought I would mention it.
In NSArray+Permutation.h
#import <Foundation/Foundation.h>
#interface NSArray(Permutation)
- (NSArray *)allPermutationsArrayofArrays;
- (NSArray *)allPermutationsArrayofStrings;
#end
in NSArray+Permutation.m:
#define MAX_PERMUTATION_COUNT 20000
NSInteger *pc_next_permutation(NSInteger *perm, const NSInteger size);
NSInteger *pc_next_permutation(NSInteger *perm, const NSInteger size)
{
// slide down the array looking for where we're smaller than the next guy
NSInteger pos1;
for (pos1 = size - 1; perm[pos1] >= perm[pos1 + 1] && pos1 > -1; --pos1);
// if this doesn't occur, we've finished our permutations
// the array is reversed: (1, 2, 3, 4) => (4, 3, 2, 1)
if (pos1 == -1)
return NULL;
assert(pos1 >= 0 && pos1 <= size);
NSInteger pos2;
// slide down the array looking for a bigger number than what we found before
for (pos2 = size; perm[pos2] <= perm[pos1] && pos2 > 0; --pos2);
assert(pos2 >= 0 && pos2 <= size);
// swap them
NSInteger tmp = perm[pos1]; perm[pos1] = perm[pos2]; perm[pos2] = tmp;
// now reverse the elements in between by swapping the ends
for (++pos1, pos2 = size; pos1 < pos2; ++pos1, --pos2) {
assert(pos1 >= 0 && pos1 <= size);
assert(pos2 >= 0 && pos2 <= size);
tmp = perm[pos1]; perm[pos1] = perm[pos2]; perm[pos2] = tmp;
}
return perm;
}
#implementation NSArray(Permutation)
- (NSArray *)allPermutationsArrayofArrays
{
NSInteger size = [self count];
NSInteger *perm = malloc(size * sizeof(NSInteger));
for (NSInteger idx = 0; idx < size; ++idx)
perm[idx] = idx;
NSInteger permutationCount = 0;
--size;
NSMutableArray *perms = [NSMutableArray array];
do {
NSMutableArray *newPerm = [NSMutableArray array];
for (NSInteger i = 0; i <= size; ++i)
[newPerm addObject:[self objectAtIndex:perm[i]]];
[perms addObject:newPerm];
} while ((perm = pc_next_permutation(perm, size)) && ++permutationCount < MAX_PERMUTATION_COUNT);
free(perm);
return perms;
}
- (NSArray *)allPermutationsArrayofStrings
{
NSInteger size = [self count];
NSInteger *perm = malloc(size * sizeof(NSInteger));
for (NSInteger idx = 0; idx < size; ++idx)
perm[idx] = idx;
NSInteger permutationCount = 0;
--size;
NSMutableArray *perms = [NSMutableArray array];
do {
NSMutableString *newPerm = [[[NSMutableString alloc]initWithString:#"" ]autorelease];
for (NSInteger i = 0; i <= size; ++i)
{
[newPerm appendString:[self objectAtIndex:perm[i]]];
}
[perms addObject:newPerm];
} while ((perm = pc_next_permutation(perm, size)) && ++permutationCount < MAX_PERMUTATION_COUNT);
free(perm);
return perms;
}
#end
My code that I thought would fix this:
for ( NSInteger i = 1; i <= theCount; i++) {
NSRange theRange2;
theRange2.location = 0;
theRange2.length = i;
NSLog(#"Location: %i (len: %i) is: '%#'",theRange2.location,theRange2.length,[array subarrayWithRange:theRange2]);
NSArray *allWordsForThisLength = [[array subarrayWithRange:theRange2] allPermutationsArrayofStrings];
for (NSMutableString *theString in allWordsForThisLength)
{
NSLog(#"Adding %# as a possible word",theString);
[allWords addObject:theString];
}
I know it would not be the most efficient..but I was trying to test.
This is what I got:
2011-07-07 14:02:19.684 TA[63623:207] Total letters in word: 3
2011-07-07 14:02:19.685 TA[63623:207] Location: 0 (len: 1) is: '(
t
)'
2011-07-07 14:02:19.685 TA[63623:207] Adding t as a possible word
2011-07-07 14:02:19.686 TA[63623:207] Location: 0 (len: 2) is: '(
t,
h
)'
2011-07-07 14:02:19.686 TA[63623:207] Adding th as a possible word
2011-07-07 14:02:19.687 TA[63623:207] Adding ht as a possible word
2011-07-07 14:02:19.688 TA[63623:207] Location: 0 (len: 3) is: '(
t,
h,
e
)'
2011-07-07 14:02:19.688 TA[63623:207] Adding the as a possible word
2011-07-07 14:02:19.689 TA[63623:207] Adding teh as a possible word
2011-07-07 14:02:19.690 TA[63623:207] Adding hte as a possible word
2011-07-07 14:02:19.691 TA[63623:207] Adding het as a possible word
2011-07-07 14:02:19.691 TA[63623:207] Adding eth as a possible word
2011-07-07 14:02:19.692 TA[63623:207] Adding eht as a possible word
As you can see, no one or two letter words -- I am pulling my hair out! (and I don't have much to spare!)
An easy thing to do would be to take all subsets of size k and use the code you have to generate all permutations of the subset. This is easy, but not the most efficient.
Here's a better approach. You are generating permutations lexicographically in the first routine:
1234
1243
1324
1342
1423
...
Each time you call NSInteger *pc_next_permutation(NSInteger *perm, const NSInteger size), you get the next permutation in lex order by finding the correct position to change. When you do that, truncate from the spot you changed to get the following:
1234 123 12 1
1243 124
1324 132 13
1342 134
1423 142 14
1432 143
2143 214 21 2
...
I hope the idea is clear. Here's one way to implement this (in Objective C-like pseudocode).
-(NSMutableArray *)nextPerms:(Perm *)word {
int N = word.length;
for (int i=N-1; i > 0; ++i) {
if (word[i-1] < word[i]) {
break;
} else if (i==1) {
i = 0;
}
}
// At this point, i-1 is the leftmost position that will change
if (i == 0) {
return nil;
}
i = i-1;
// At this point, i is the leftmost position that will change
Perm *nextWord = word;
for (int j=1; j <= N-i; ++j) {
nextWord[i+j] = word[N-j];
}
nextWord[i] = nextWord[i+1];
nextWord[i+1] = word[i];
// At this point, nextPerm is the next permutation in lexicographic order.
NSMutableArray *permList = [[NSMutableArray alloc] init];
for (int j=i; j<N; ++j) {
[permList addObject:[nextWord subwordWithRange:NSMakeRange(0,i)]];
}
return [permList autorelease];
}
This will return an array with the partial permutations as described above. The input for nextPerms should be the lastObject of the output of nextPerms.
Okay,
Down and dirty for now, however, this is what I did...
I changed the NSArray+Permutations.m to be as follows:
- (NSArray *)allPermutationsArrayofStrings
{
NSInteger size = [self count];
NSInteger *perm = malloc(size * sizeof(NSInteger));
for (NSInteger idx = 0; idx < size; ++idx)
perm[idx] = idx;
NSInteger permutationCount = 0;
--size;
NSMutableArray *perms = [NSMutableArray array];
NSMutableDictionary *permsDict = [[NSMutableDictionary alloc] init];
do {
NSMutableString *newPerm = [[[NSMutableString alloc]initWithString:#"" ]autorelease];
for (NSInteger i = 0; i <= size; ++i)
{
[newPerm appendString:[self objectAtIndex:perm[i]]];
}
if ([permsDict objectForKey:newPerm] == nil)
{
[permsDict setObject:#"1" forKey:newPerm];
[perms addObject:newPerm];
}
for (NSInteger i = 1; i <= [newPerm length]; ++i)
{
NSRange theRange;
theRange.location = 0;
theRange.length = i;
if ([permsDict objectForKey:[newPerm substringToIndex:i]] == nil)
{
[permsDict setObject:#"1" forKey:[newPerm substringToIndex:i]];
[perms addObject:[newPerm substringToIndex:i]];
}
}
} while ((perm = pc_next_permutation(perm, size)) && ++permutationCount < MAX_PERMUTATION_COUNT);
free(perm);
[permsDict release];
return perms;
}
The major changes were the idea #PengOne had... Return the resulting lexically changed string but also shorten it by 1 character at a time and add that to the returned array if it did not exist already.
I chose to be "cheap" about it and keep track using a NSMutableDictionary. So if the lexically changed string was not listed in the dictionary, it was added.
Is that more-or-less what you thought I should do, #PengOne?
WAY faster than adding them all and dealing with the resulting duplicates later -- and I think it works like I need it to.

reading an array

I create random numbers using the following code and store them in an array.
NSMutableSet *aSet = [NSMutableSet setWithCapacity:6];
while([aSet count]<=6){
int Randnum = arc4random() % 12;
[aSet addObject:[NSNumber numberWithInt:Randnum]];
}
NSArray *arrayOfUniqueRandomNumbers = [aSet allObjects];
Now, I need to read the array to get the values one-by-one using a forloop like
for (int i = 0; i<6; i++);
Can anyone please help me to finish the code?
You can do:
for (NSNumber *val in arrayOfUniqueRandomNumbers) {
int i = [val intValue];
...
}