Is it possible to create a CronExpression with:
"fire every day every 20min but not on Saturday between 10:00 and 14:00"?
Something like "0 0/20 * ? * MON-SAT" is clear, but it is not the same...
You will have to use two expressions; One for saturdays, one for all other days:
0 0/20 * * * SUN-FRI command
0 0/20 0-9,14-23 * * SAT command
Related
I want to convert seconds to days, hours and minutes
Currently, it works just for hours and minutes but not for days. Can you please support me tell me what I did wrong:
<cfscript>
seconds = '87400';
midnight = CreateTime(0,0,0);
time = DateAdd("s", seconds, variables.midnight);
date= xxxxxxxxxxxxxxxxxxxxx???
</cfscript>
<cfoutput>
#DateFormat(variables.date, 'd')# not working
#TimeFormat(variables.time, 'HH:mm')#
</cfoutput>
For the value 87400 the expected result is
1 Days, 0 hours, 16 minutes
If I take 94152 seconds it will be:
1 days, 3 hours, 22 minutes
The only issue i have is to get the correct days ... hours and minutes are diplayed but not the correct days
thank you for all the support
A simple way to calculate the intervals is by taking advantage of the modulus operator:
totalSeconds = 94152;
days = int(totalSeconds / 86400);
hours = totalSeconds / 3600 % 24;
minutes = totalSeconds / 60 % 60;
seconds = totalSeconds % 60;
For 94152 seconds, the results would be:
Interval
Value
DAYS
1
HOURS
2
MINUTES
9
SECONDS
12
TOTALSECONDS
94152
demo trycf.com
I understand from your question that you don't need to get a certain date and time along a timeline, but convert a total amount of seconds in days, hours and minutes. To do that you don't necessary need to use cfml time and date functions like CreateTime() or DateAdd(). You just may need these in order to get a reference point of time or date along a timeline, which doesn't seem to be the case, otherwise you would know the value of your starting date variable. Thus, you can solve this with plain rule of three. There may be simpler methods, so I'm posting an alternative only.
We know that:
60 seconds is equivalent to 1 minute
60 minutes is equivalent to 1 hour
24 hours is equivalent to 1 day
Thus, your calcualtion within cfml could be like so:
<cfscript>
//Constants for calculation
secondsPerDay= 60*60*24;
secondsPerHour= 60*60;
secondsPerMinute= 60;
//Seconds to convert
secondsTotal=87400;
// temp variable
secondsRemain= secondsTotal;
days= int( secondsRemain / secondsPerDay);
secondsRemain= secondsRemain - days * secondsPerDay;
hours= int( secondsRemain / secondsPerHour);
secondsRemain= secondsRemain - hours * secondsPerHour;
minutes= int( secondsRemain / secondsPerMinute);
secondsRemain= secondsRemain - minutes * secondsPerMinute;
writeoutput( "#secondsTotal# seconds are: #days# days, #hours# hours, #minutes# minutes and #secondsRemain# seconds." );
</cfscript>
That outputs:
87400 seconds are: 1 days, 0 hours, 16 minutes and 40 seconds.
I'm looking for a way to run a Jenkins build every 2 hours, Monday through Friday only from 7 AM to 10PM. I got 7AM to 10PM and every 2 hours part down but how would I go about adding Monday through Friday to it?
Here is the schedule right now: H 07-22/2 * * *
If I add 1-5 to the above (1 for Monday and 5 for Friday), it gives me an error
" Invalid input: "H 07-22/2 * * * 1-5": line 1:16: expecting EOF,
found ' ' "
Please help me out.
Thanks.
You have too much element in your cron expression.
0 07-22/2 * * 1-5 instead of 0 07-22/2 * * * 1-5
Is it possible to create a CronExpression with: "fire every 5 min but not run at 00:05 and 00:10"?
org.quartz.CronScheduleBuilder.cronSchedule("0 0/5 * * * ?")
You will have to use two expressions:
0 15/5 0 * * ?
0 0/5 1-23 * * ?
The first expression is specific to 12 AM, the second is for the rest of the time.
I'm trying to write a cron expression for quartz that runs hourly everyday except every second Saturday of the month.
So, by using the '#' notation, I was trying to write the expression like:
0 0 * ? * SUN-FRI,SAT#1,SAT#3,SAT#4,SAT#5
This expression is not working properly. Also, quartz is not complaining about the cron format (quartz usually complains about cron expressions when they are wrong).
So I did some other experiments today. So, today is the third Thursday of the month, I was playing around with THU#N notation, and that's what I've found so far (I changed my expression to minute to make it easier for experimenting):
0 * * ? * SUN-FRI,SAT#1,SAT#3,SAT#4,SAT#5: not triggered
0 * * ? * THU#3: triggered
0 * * ? * THU#3,THU#4: not triggered
0 * * ? * THU#2,THU#3: triggered
I know I can simply split this into 4 additional expression but in my real scenario I have tons of expressions to change and this would increase my expression list to something 5 times longer.
In a brief: Does anyone knows how to condense these:
0 0 * ? * SUN-FRI / 0 0 * ? * SAT#1 / 0 0 * ? * SAT#3 / 0 0 * ? * SAT#4 / 0 0 * ? * SAT#5
...into a single cron expression?
Note: I'm using quartz scheduler 1.5 (I know, I know... pretty outdated)
I need to be able to compare the number of whole days between two dates in ActionScript, is this possible?
I'd like to test if one date is 7 days or less after today, and if so is it one day or less (if it's before today this also counts).
The workaround I have in place is using the .time part of the date field:
// Get the diffence between the current date and the due date
var dateDiff:Date = new Date();
dateDiff.setTime (dueDate.time - currentDate.time);
if (dateDiff.time < ( 1 * 24 * 60 * 60 * 1000 ))
return "Date is within 1 day");
else if (dateDiff.time < ( 7 * 24 * 60 * 60 * 1000 ))
return "Date is within 7 days");
As I say - this is only a workaround, I'd like a permanent solution to allow me to check the number of whole days between 2 dates. Is this possible?
Thanks
var daysDifference:Number = Math.floor((dueDate.time-currentDate.time)/(1000*60*60*24));
if (daysDifference < 2)
return "Date is within 1 day";
else if (daysDifference < 8)
return "Date is within 7 days";