Select records but if null, show a message - tsql

I know this easy, just can't get the syntax right. If no results, show a message instead:
select COALESCE(select SomeField from SomeTable where [#SomeTableVariable].SomeID = #SomeID, 'none to delete')

if that query is only going to return one row then:
select COALESCE(
(select SomeField from SomeTable where [#SomeTableVariable].SomeID = #SomeID),
'none to delete'
)
should do it.

Related

SELECT CASE: more than one row returned by a subquery used as an expression

I got very good help for my question PostgreSQL: return message after count = 0
This query works fine:
SELECT CASE WHEN COUNT(*) = 0 THEN 'NO RESULT'
ELSE CAST(COUNT(*) as TEXT)
END as myfield from mytable
But today I need if some rows are in table, I need to show select result.
I tried:
SELECT CASE WHEN COUNT(*) = 0 THEN 'NO RESULT'
ELSE (select name from mytable)
END as myfield from mytable
And I got error:
ERROR: more than one row returned by a subquery used as an expression
I found that IN function but don't have any idea to improve it.
I think you can do something like this:
select name from mytable
UNION ALL
SELECT 'NO RESULT'
WHERE NOT EXISTS(SELECT NULL FROM mytable)

How do I avoid listing all the table columns in a PostgreSQL returns statement?

I have a PostgreSQL function similar to this:
CREATE OR REPLACE FUNCTION dbo.MyTestFunction(
_ID INT
)
RETURNS dbo.MyTable AS
$$
SELECT *,
(SELECT Name FROM dbo.MySecondTable WHERE RecordID = PersonID)
FROM dbo.MyTable
WHERE PersonID = _ID
$$ LANGUAGE SQL STABLE;
I would really like to NOT have to replace the RETURNS dbo.MyTable AS with something like:
RETURNS TABLE(
col1 INT,
col2 TEXT,
col3 BOOLEAN,
col4 TEXT
) AS
and list out all the columns of MyTable and Name of MySecondTable. Is this something that can be done? Thanks.
--EDIT--
To clarify I have to return ALL columns in MyTable and 1 column from MySecondTable. If MyTable has >15 columns, I don't want to have to list out all the columns in a RETURNS TABLE (col1.. coln).
You just list the columns that you want returned in the SELECT portion of your SQL statement:
SELECT t1.column1, t1.column2,
(SELECT Name FROM dbo.MySecondTable WHERE RecordID = PersonID)
FROM dbo.MyTable t1
WHERE PersonID = _ID
Now you'll just get column1, column3, and name returned
Furthermore, you'll probably find better performance using a LEFT OUTER JOIN in your FROM portion of the SQL statement as opposed to the correlated subquery you have now:
SELECT t1.column1, t1.column2, t2.Name
FROM dbo.MyTable t1
LEFT OUTER JOIN dbo.MySecondTable t2 ON
t2.RecordID = t1.PersonID
WHERE PersonID = _ID
Took a bit of a guess on where RecordID and PersonID were coming from, but that's the general idea.

postgresql where clause behavior

I made two queries that I thought should have the same result:
SELECT COUNT(*) FROM (
SELECT DISTINCT ON (id1) id1, value
FROM (
SELECT table1.id1, table2.value
FROM table1
JOIN table2 ON table1.id1=table2.id
WHERE table2.value = '1')
AS result1 ORDER BY id1)
AS result2;
SELECT COUNT(*) FROM (
SELECT DISTINCT ON (id1) id1, value
FROM (
SELECT table1.id1, table2.value
FROM table1
JOIN table2 ON table1.id1=table2.id
)
AS result1 ORDER BY id1)
AS result2
WHERE value = '1';
The only difference being that one had the WHERE clause inside SELECT DISTINCT ON, and the other outside that, but inside SELECT COUNT. But the results were not the same. I don't understand why the position of the WHERE clause should make a difference in this case. Can anyone explain? Or is there a better way to phrase this question?
here's a good way to look at this:
SELECT DISTINCT ON (id) id, value
FROM (select 1 as id, 1 as value
union
select 1 as id, 2 as value) a;
SELECT DISTINCT ON (id) id, value
FROM (select 1 as id, 1 as value
union
select 1 as id, 2 as value) a
WHERE value = 2;
The problem has to do with the unique conditions and what is visible where. It is behavior by design.

Most effective way to get value if select count(*) = 1 with grouping

Lets say I have table with ID int, VALUE string:
ID | VALUE
1 abc
2 abc
3 def
4 abc
5 abc
6 abc
If I do select value, count(*) group by value I should get
VALUE | COUNT
abc 5
def 1
Now the tricky part, if there is count == 1 I need to get that ID from first table. Should I be using CTE? creating resultset where I will add ID string == null and run update b.ID = a.ID where count == 1 ?
Or is there another easier way?
EDIT:
I want to have result table like this:
ID VALUE count
null abc 5
3 def 1
If your ID values are unique, you can simply check to see if the max(id) = min(id). If so, then use either one, otherwise you can return null. Like this:
Select Case When Min(id) = Max(id) Then Min(id) Else Null End As Id,
Value, Count(*) As [Count]
From YourTable
Group By Value
Since you are already performing an aggregate, including the MIN and Max function is not likely to take any extra (noticeable) time. I encourage you to give this a try.
The way I would do it would indeed be a CTE:
using #group AS (SELECT value, Count(*) as count from MyTable GROUP BY value HAVING count = 1)
SELECT MyTable.ID, #group.value, #group.count from MyTable
JOIN #group ON #group.value = MyTable.value
When using group by, after the group by statement you can use a having clause.
So
SELECT [ID]
FROM table
GROUP BY [VALUE]
HAVING COUNT(*) = 1
Edit: with regards to your edited question: this uses some fun joins and unions
CREATE TABLE #table
(ID int IDENTITY,
VALUE varchar(3))
INSERT INTO #table (VALUE)
VALUES('abc'),('abc'),('def'),('abc'),('abc'),('abc')
SELECT * FROM (
SELECT Null as ID,VALUE, COUNT(*) as [Count]
FROM #table
GROUP BY VALUE
HAVING COUNT(*) > 1
UNION ALL
SELECT t.ID,t.VALUE,p.Count FROM
#table t
JOIN
(SELECT VALUE, COUNT(*) as [Count]
FROM #table
GROUP BY VALUE
HAVING COUNT(*) = 1) p
ON t.VALUE=p.VALUE
) a
DROP TABLE #table
maybe not the most efficient but something like this works:
SELECT MAX(Id) as ID,Value FROM Table WHERE COUNT(*) = 1 GROUP BY Value

PostgreSQL Record Reordering using Update with a Sub-Select

I found this solution on the SQL Server forum on how to reorder records in a table.
UPDATE SomeTable
SET rankcol = SubQuery.Sort_Order
FROM
(
SELECT IDCol, Row_Number() OVER (ORDER BY ValueCOL) as SORT_ORDER
FROM SomeTable
) SubQuery
INNER JOIN SomeTable ON
SubQuery.IDCol = SomeTable.IDCol
When I try doing the same on PostgreSQL, I get an error message -
ERROR: table name "sometable" specified more than once
Any help will be appreciated.
Thanks!
You don`t need to explicitly join SomeTable, how cool is that? :)
UPDATE SomeTable
SET rankcol = SubQuery.Sort_Order
FROM
(
SELECT IDCol, Row_Number() OVER (ORDER BY ValueCOL) as SORT_ORDER
FROM SomeTable
) SubQuery
where SubQuery.IDCol = SomeTable.IDCol
remark: Postgres is case insensitive, better use lower-case, like row_number, sort_order, id_col , etc.