Hi I would like to know how I can go about sending data from 4 UITextField's to a PHP script on a website using NSURLConnection or JSon. Whatever is easier, how can I do this exactly?
Thanks in advance!
Easiest way (synchronous)
NSString strForTextField1 = textField1.text;
NSString strForTextField2 = textField1.text;
NSString strForTextField3 = textField1.text;
NSString strForTextField4 = textField1.text;
//Build the request
NSString *stringOfRequest = [NSString stringWithFormat:#"www.yourserver.com?var1=%#&var2=%#&var3=%#&var4=%#", strForTextField1, strForTextField2, strForTextField3, strForTextField4];
NSURL *url = [NSURL URLWithString:stringOfRequest];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
NSURLResponse *response;
NSError *error;
//send it synchronous
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
if(!error)
{
//log response
NSLog(#"Response from server = %#", responseString);
}
Related
I have this link :
function new_message($chat_id,$user_id,$message,$recipient_ids)
http://www.demii.com/demo/dooponz/admin/index.php/chat/new_message/4/1/you/2%2C7
return chat_log_id
Can anyone please explain me how to call webserive by this get method or give me the
solution .
what i did with my code is below :
-(void)newMessage{
if ([self connectedToWiFi]){
NSString *urlString = [NSString stringWithFormat:#"www.demii.com/demo/dooponz/admin/index.php/chat/new_message/4/1/you/1,1,2"];
NSLog(#"urlString is %#", urlString);
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
NSURL *requestURL = [NSURL URLWithString:urlString];
[request setURL:requestURL];
[request setHTTPMethod:#"POST"];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue]
completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
NSLog(#"ERROR = %#",error.localizedDescription);
if(error.localizedDescription == NULL)
{
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"response >>>>>>>>> succ %#",returnString);
[delegate ConnectionDidFinishLoading:returnString : #"newMessage"];
}
else
{
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"response >>>>>>>>> fail %#",returnString);
[delegate ConnectiondidFailWithError:returnString : #"newMessage"];
}
}];
}
}
how can i handle this ?
Thanks in advance .
I am not sure from your post whether or not you want to "post" or "get." However, gauging from the fact that you set your method to post, and that you are creating something new on your server, I am assuming you want to post.
If you want to post you can use my wrapper method for a post request.
+ (NSData *) myPostRequest: (NSString *) requestString withURL: (NSURL *) url{
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:#"POST"];
[request setTimeoutInterval:15.0];
NSData *requestBody = [requestString dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
[request setHTTPBody:requestBody];
NSURLResponse *response = NULL;
NSError *requestError = NULL;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&requestError];
return responseData;
}
Where request string is formatted like this:
NSString * requestString = [[NSString alloc] initWithFormat:#"username=%#&password=%#", userInfo[#"username"], userInfo[#"password"]];
This will also shoot back the response data which you can turn into a string like this.
responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
If you are trying to grab data from the server in json format...
+ (NSArray *) myGetRequest: (NSURL *) url{
NSArray *json = [[NSArray alloc] init];
NSData* data = [NSData dataWithContentsOfURL:
url];
NSError *error;
if (data)
json = [[NSArray alloc] initWithArray:[NSJSONSerialization
JSONObjectWithData:data
options:kNilOptions
error:&error]];
//NSLog(#"get results: \n %#", json);
return json;
}
Pls change ur code like this
-(void)newMessage{
NSString *urlString = [NSString stringWithFormat:#"http://www.demii.com/demo/dooponz/admin/index.php/chat/new_message/4/1/you/27" ];
NSLog(#"urlString is %#", urlString);
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
NSURL *requestURL = [NSURL URLWithString:urlString];
[request setURL:requestURL];
[request setHTTPMethod:#"POST"];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue]
completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
NSLog(#"ERROR = %#",error.localizedDescription);
if(error.localizedDescription == NULL)
{
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"response >>>>>>>>> succ %#",returnString);
[self parseStringtoJSON:data];
//[delegate ConnectionDidFinishLoading:returnString : #"newMessage"];
}
else
{
NSString *returnString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"response >>>>>>>>> fail %#",returnString);
// [delegate ConnectiondidFailWithError:returnString : #"newMessage"];
}
}];
}
-(void)parseStringtoJSON:(NSData *)data{
NSDictionary *dict=[NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:nil];
NSLog(#"chat id %#",[dict objectForKey:#"chat_log_id"]);
}
u will get the JSON response string as result if u hit that url. If u r familiar with json parsing, u can get the value based on key.
see this link: How do I deserialize a JSON string into an NSDictionary? (For iOS 5+)
Api Address：
http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone
return：
KISSY.Suggest.callback({"result": [["iphone4s", "9809"], ["iphone5", "13312"], ["iphone4 手机", "69494400"], ["iphone5 港行", "14267"], ["iphone5三网", "2271160"], ["iphone4手机壳", "6199679"], ["iphone 5手机壳", "2527284"], ["iphone 5 保护壳", "5727586"], ["iphone 4贴膜", "147271"], ["iphone5壳", "2628540"]]})
NSURL * url = [NSURL URLWithString:#"http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSHTTPURLResponse* urlResponse = nil;
NSError * error = nil;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];
NSData *date = [NSData alloc]init
SBJsonParser *jsonParser = [[SBJsonParser alloc] init];
// NSMutableArray *array=[NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableLeaves error:&error];
NSMutableArray *array = [jsonParser objectWithData:responseData];
NSLog(#"%#",array);
this array is null. i dont know the reason.
as i refer you request URL ,it has callback in it, if you keep it, it will not return you json as response, so remove "&callback=KISSY.Suggest.callback" from your URL
// Make sure you have include SBJSON files in your Project, as well you have imported header in your View Controller
#import "JSON.h"
// your request URL
NSURL * url = [NSURL URLWithString:#"http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone"];
// URL Request
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSHTTPURLResponse* urlResponse = nil;
NSError * error = nil;
// initiate Request to get Data
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];
// Encode your Response
NSString *content = [[NSString alloc] initWithBytes:[responseData bytes] length:[responseData length] encoding:NSUTF8StringEncoding];
// Now read a Dictionary from it using SBJSON Parser
NSDictionary *responseDict = [content JSONValue];
NSLog(#"Response [%#]",responseDict);
I'm not familiar with the SBJsonParser, but the format of the returned string looks like JSONP, not JSON. I would imagine simply cleaning out the wrapper call would get you what you are after.
Also, note that the 'root' of your response is a dictionary, not an array.
{"result": [[...
means that the code might should look like this:
NSDictionary *response = //... decode
NSArray *results = [response objectForKey:#"result"];
Edited
You just need to use http://suggest.taobao.com/sug?area=etao&code=utf-8&q=iphone instead of http://suggest.taobao.com/sug?area=etao&code=utf-8&callback=KISSY.Suggest.callback&q=iphone you own code will work..
I want to send the following request to the server. The server already knows what to do with it, but how can I send it?
http://www.********.com/ajax.php?script=logoutUser&username=****
For a synchronous request you would do the following:
NSURL *url = [NSURL URLWithString:#"http://www.********.com/ajax.php?script=logoutUser&username=****"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
NSURLResponse *response;
NSError *error;
//send it synchronous
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
// check for an error. If there is a network error, you should handle it here.
if(!error)
{
//log response
NSLog(#"Response from server = %#", responseString);
}
Update: for doing an asynchronous request please refere to this example
You can do:
NSString *resp = [NSString stringWithContentsOfURL:url usedEncoding:enc error: &error];
Below is my code..
NSString *strResponce = [[NSString alloc] initWithData:JsonData encoding:NSASCIIStringEncoding];
here string has some data.
[JsonData release];
NSError *error;
SBJSON *json = [[SBJSON new] autorelease];
ArrayWebContent=[json objectWithString:strResponce error:&error];
But array is null.
any suggestion....
check your json data first put the content of the string strResponce in to the url
Checking json data are proper for parsing
if it gonna generate the parse error than you should check the content of the ws as it may content special charactor for which iphone can not support parsing
good luck
Try with below functions.
- (id) objectWithUrl:(NSURL *)url
{
SBJSON *jsonParser = [SBJSON new];
NSString *jsonString = [self stringWithUrl:url];
// Parse the JSON into an Object
return [jsonParser objectWithString:jsonString error:NULL];
}
- (NSString *)stringWithUrl:(NSURL *)url
{
NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url
cachePolicy:NSURLRequestReturnCacheDataElseLoad
timeoutInterval:30];
// Fetch the JSON response
NSData *urlData;
NSURLResponse *response;
NSError *error;
// Make synchronous request
urlData = [NSURLConnection sendSynchronousRequest:urlRequest
returningResponse:&response
error:&error];
// Construct a String around the Data from the response
return [[NSString alloc] initWithData:urlData encoding:NSUTF8StringEncoding];
}
Let me know for any difficulty.
How can i have a uitextview value be taken and send to a predefined url using obj-c only without any html /php.
Take a look at NSURL. Use the text value of the UITextView as a parameter.
e.g.
NSURL *webURL = [NSURL URLWithString:MY_TEXTVIEW.text];
NSURLRequest *req = [NSURLRequest requestWithURL:webURL];
NSString *methodString = #"method";
NSString *parameterString = [NSString stringWithFormat:#"value=%#", textField.text];
NSString *apiRoot = #"http://www.domain.com";
NSURL *apiUrl = [NSURL URLWithString:[NSString stringWithFormat:#"%#/%#?%#", apiRoot,methodString,parameterString]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:apiUrl];
NSURLResponse *response = nil;
NSError *error = nil;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];