Get the latest record from mongodb collection - mongodb

Question

I want to know the most recent record in a collection. How to do that?
Note: I know the following command line queries works:
1. db.test.find().sort({"idate":-1}).limit(1).forEach(printjson);
2. db.test.find().skip(db.test.count()-1).forEach(printjson)
where idate has the timestamp added.
The problem is longer the collection is the time to get back the data and my 'test' collection is really really huge. I need a query with constant time response.
If there is any better mongodb command line query, do let me know.

Answer 1

This is a rehash of the previous answer but it's more likely to work on different mongodb versions.
db.collection.find().limit(1).sort({$natural:-1})

Answer 2

This will give you one last document for a collection
db.collectionName.findOne({}, {sort:{$natural:-1}})
$natural:-1 means order opposite of the one that records are inserted in.
Edit: For all the downvoters, above is a Mongoose syntax,
mongo CLI syntax is: db.collectionName.find({}).sort({$natural:-1}).limit(1)

Answer 3

Yet another way of getting the last item from a MongoDB Collection (don't mind about the examples):
> db.collection.find().sort({'_id':-1}).limit(1)
Normal Projection
> db.Sports.find()
{ "_id" : ObjectId("5bfb5f82dea65504b456ab12"), "Type" : "NFL", "Head" : "Patriots Won SuperBowl 2017", "Body" : "Again, the Pats won the Super Bowl." }
{ "_id" : ObjectId("5bfb6011dea65504b456ab13"), "Type" : "World Cup 2018", "Head" : "Brazil Qualified for Round of 16", "Body" : "The Brazilians are happy today, due to the qualification of the Brazilian Team for the Round of 16 for the World Cup 2018." }
{ "_id" : ObjectId("5bfb60b1dea65504b456ab14"), "Type" : "F1", "Head" : "Ferrari Lost Championship", "Body" : "By two positions, Ferrari loses the F1 Championship, leaving the Italians in tears." }
Sorted Projection ( _id: reverse order )
> db.Sports.find().sort({'_id':-1})
{ "_id" : ObjectId("5bfb60b1dea65504b456ab14"), "Type" : "F1", "Head" : "Ferrari Lost Championship", "Body" : "By two positions, Ferrari loses the F1 Championship, leaving the Italians in tears." }
{ "_id" : ObjectId("5bfb6011dea65504b456ab13"), "Type" : "World Cup 2018", "Head" : "Brazil Qualified for Round of 16", "Body" : "The Brazilians are happy today, due to the qualification of the Brazilian Team for the Round of 16 for the World Cup 2018." }
{ "_id" : ObjectId("5bfb5f82dea65504b456ab12"), "Type" : "NFL", "Head" : "Patriots Won SuperBowl 2018", "Body" : "Again, the Pats won the Super Bowl" }
sort({'_id':-1}), defines a projection in descending order of all documents, based on their _ids.
Sorted Projection ( _id: reverse order ): getting the latest (last) document from a collection.
> db.Sports.find().sort({'_id':-1}).limit(1)
{ "_id" : ObjectId("5bfb60b1dea65504b456ab14"), "Type" : "F1", "Head" : "Ferrari Lost Championship", "Body" : "By two positions, Ferrari loses the F1 Championship, leaving the Italians in tears." }

Answer 4

I need a query with constant time response
By default, the indexes in MongoDB are B-Trees. Searching a B-Tree is a O(logN) operation, so even find({_id:...}) will not provide constant time, O(1) responses.
That stated, you can also sort by the _id if you are using ObjectId for you IDs. See here for details. Of course, even that is only good to the last second.
You may to resort to "writing twice". Write once to the main collection and write again to a "last updated" collection. Without transactions this will not be perfect, but with only one item in the "last updated" collection it will always be fast.

Answer 5

php7.1 mongoDB:
$data = $collection->findOne([],['sort' => ['_id' => -1],'projection' => ['_id' => 1]]);

Answer 6

My Solution :
db.collection("name of collection").find({}, {limit: 1}).sort({$natural: -1})

Answer 7

If you are using auto-generated Mongo Object Ids in your document, it contains timestamp in it as first 4 bytes using which latest doc inserted into the collection could be found out. I understand this is an old question, but if someone is still ending up here looking for one more alternative.
db.collectionName.aggregate(
[{$group: {_id: null, latestDocId: { $max: "$_id"}}}, {$project: {_id: 0, latestDocId: 1}}])
Above query would give the _id for the latest doc inserted into the collection

Answer 8

This is how to get the last record from all MongoDB documents from the "foo" collection.(change foo,x,y.. etc.)
db.foo.aggregate([{$sort:{ x : 1, date : 1 } },{$group: { _id: "$x" ,y: {$last:"$y"},yz: {$last:"$yz"},date: { $last : "$date" }}} ],{ allowDiskUse:true })
you can add or remove from the group
help articles: https://docs.mongodb.com/manual/reference/operator/aggregation/group/#pipe._S_group
https://docs.mongodb.com/manual/reference/operator/aggregation/last/

Answer 9

Mongo CLI syntax:
db.collectionName.find({}).sort({$natural:-1}).limit(1)

Answer 10

Let Mongo create the ID, it is an auto-incremented hash
mymongo:
self._collection.find().sort("_id",-1).limit(1)