Overriding toString method in Scala Enumeration - scala

Question

How can I override "toString" to make this Scala code acts like the following Java code.
Code in Scala
object BIT extends Enumeration {
type BIT = Value
val ZERO, ONE, ANY = Value
override def toString() =
this match {
case ANY => "x "
case ZERO=> "0 "
case ONE => "1 "
}
}
val b = ONE
println(ONE) // returns ONE
Wanted toString behaviour should produce same output as the following Java code.
public enum BIT {
ZERO, ONE, ANY;
/** print BIT as 0,1, and X */
public String toString() {
switch (this) {
case ZERO:
return "0 ";
case ONE:
return "1 ";
default://ANY
return "X ";
}
}
}
BIT b = ONE;
System.out.println(b); // returns 1
I think I am overriding the wrong "toString" method.

Answer 1

First, yes you are overriding the wrong toString method. You're overriding the method on the BIT object itself, which is not very useful.
Second, you do this much easier by simply doing
object BIT extends Enumeration {
type BIT = Value
val ZERO = Value("0")
val ONE = Value("1")
val ANY = Value("x")
}
Then you can do
println(BIT.ONE) //prints "1"

Answer 2

If you want to set the value and the string you can do it like this:
scala> object BIT extends Enumeration {
| type BIT = Value
| val ZERO = Value(0, "0")
| val ONE = Value(1, "1")
| val ANY = Value("x")
| }
defined module BIT
scala> BIT.ZERO.toString
res2: String = 0
scala> BIT.ZERO.id
res3: Int = 0
scala> BIT.ANY.id
res4: Int = 2
scala> BIT.ANY.toString
res5: String = x