This question already has answers here:
Formatting NSDate into particular styles for both year, month, day, and hour, minute, seconds
(8 answers)
Closed 9 years ago.
Am receiving date in this format (2012-07-13 09:22:22 +0000). I want to convert this date format to 13-Jul-2012 09:22. And also if the date is today means i want to change Today 09:22 and Yesterday 09:22. Can anyone please help to do this?
EDIT:
I have added some code what i have tried.
NSDateFormatter *dateFormatter1 = [[NSDateFormatter alloc] init];
[dateFormatter1 setDateFormat:#"dd-mm-yyyy hh:mm"];
[dateFormatter1 setFormatterBehavior:NSDateFormatterBehaviorDefault];
[dateFormatter1 setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSDate *date = [dateFormatter1 dateFromString:dateStr];// Change Date Format
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateStyle:NSDateFormatterShortStyle];
[formatter setTimeStyle:NSDateFormatterShortStyle];
[formatter setDoesRelativeDateFormatting:YES];
NSString *dateString1 = [formatter stringFromDate:date]; // Getting Today or Tomorrow
[formatter release];
NSLog(#"DateString1 : %#", dateString1);
First problem I see is that the date pattern your supplying to the Formatter does not match the date string you claim your getting. You might want to try this:
[dateFormatter1 setDateFormat:#"yyyy-mm-dd hh:mm:ss Z"];
The format your using in the code you supplied has year, month, day reversed and your not converting second.
You can try this:
NSDate *date = [NSDate date]; // date in this format 2012-07-14 17:32:09 +0000
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"dd-MMM-yyyy hh:mm"];
//[dateFormatter setTimeZone:[NSTimeZone localTimeZone]]; // Optional
NSString *dateStr = [dateFormatter stringFromDate:date];
And next compare your 'date' with current date using NSDate methods for eg. timeIntervalSinceReferenceDate and then based on the result display today/tomorrow.
Related
This question already has answers here:
What is the best way to deal with the NSDateFormatter locale "feature"?
(4 answers)
Closed 9 years ago.
I am converting the string into date with the help of below code :
NSDateFormatter *fDateFormat = [[NSDateFormatter alloc] init];
[fDateFormat setDateFormat:#"dd/MM/yyyy hh:mm a"];
[fDateFormat setTimeZone:[NSTimeZone timeZoneWithAbbreviation:#"GMT"]];
NSDate *dateFormat = [fDateFormat dateFromString:strDate];
And passing string like "02/09/2013 05:10 AM" and I will get date perfect. But when we use time format 24 hours, then date is nil.
Can you please me out of this problem ?
NSDateFormatter *fDateFormat = [[NSDateFormatter alloc] init];
[fDateFormat setDateFormat:#"dd/MM/yyyy hh:mm a"];
[fDateFormat setTimeZone:[NSTimeZone timeZoneWithAbbreviation:#"GMT"]];
NSDate *dateFormat = [fDateFormat dateFromString:strDate];
[fDateFormat setDateFormat:#"dd/MM/yyyy HH:mm"];
NSString *your24Format = [fDateFormat stringFromDate:dateFormat];
You can try above code, should be working fine :)
Wayne
This question already has answers here:
Convert string to date in my iPhone app
(4 answers)
Closed 10 years ago.
How to convert a string to date? I know we can use dateFormatter to do this but I am stuck in between. I have format 0512 which should be converted to May 2012.
Try this,
NSString *finalDate = #"0512";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MMyy"];
NSDate *date = [dateFormatter dateFromString:finalDate];
[dateFormatter setDateFormat:#"MMM yyyy"];
NSLog(#"%#",[dateFormatter stringFromDate:date]);
Try this
NSDateFormatter *dateFormatter=[[NSDateFormatter alloc]init];
[dateFormatter setDateFormat:#"MMyy"];
NSDate *dateObj= [dateFormatter dateFromString:#"0512"];
NSLog(#"%#",dateObj);
[dateFormatter setDateFormat:#"EEEE MMMM d, YYYY"];
NSLog(#"%#",[dateFormatter stringFromDate:dateObj]);
Try this code may be helped you..
NSString *dateStr = #"0512";
// Convert string to date object
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"MMyy"];
NSDate *date = [dateFormat dateFromString:dateStr];
// Convert date object to desired output format
[dateFormat setDateFormat:#"MMMM YYYY"];
dateStr = [dateFormat stringFromDate:date];
[dateFormat release];
NSLog(#"%#",dateStr);
What is so difficult about it?
1. Take out first 2 characters of string
2. Put if else/ convert string to int and use switch to make up month
3. Take the next 2 characters, add them to 2000 and you get year
Now user iOS functions to achieve this :)
This question already has an answer here:
dateformatter problem?
(1 answer)
Closed 8 years ago.
I have a time string, which is as shown below:
2/5/2013 12:00:00 AM
and i want to change this in to MM/dd/yyyy formate.
i used NSDateFormatter, but i am getting a null value. how can i change this??
check your code, must be doing something wrong, this is how you receive the right format..
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"MM/dd/yy"];
NSString *dateString = [dateFormatter stringFromDate: [NSDate date]];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MM/dd/yyyy HH:mm:ss a"];
NSDate *date = [formatter dateFromString:str];
Read this document for date formatters.
I am using following code to generate NSDate -> NSString
+(NSString *)getCurrentTime
{
NSDate *now = [NSDate date];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"dd-MM-yyyy hh:MM:SS a"];
[dateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSString* str =[dateFormatter stringFromDate:now];
[dateFormatter release];
NSLog(#"%#",str);
return str;
}
everything is fine in above code. I am using above code to store string in Database. Now while retrieving that string gives me NULL. Following is my code to retrieve date in specific format
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:#"hh:MM:SS a"];
[dateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSDate *dt =[dateFormatter dateFromString:crdInfo.swipeTime];
NSLog(#"Date : %#",dt);
[dateFormatter release];
How should I retrieve or store with particular format?? My crdInfo.swipeTime is retrieving String propertly...
First off, why not just store the NSDate object or epoch timestamp? This will give you much more flexibility in the future.
Now to your problem, I suspect it is due to your configuration of the NSDateFormatter, you're saving it in one format and trying to convert it to a date using a different format. Make the formats the same and try again. If you want to display it differently than it is stored you're likely going to need to convert it to and NSDate using the stored format and then again use another date formatter to get it in the format you want it as a string.
As Narayana suggested you need to retrieve the date with same format as you have stored. Retrieve it as below : -
NSDateFormatter *reDateFormatter = [[NSDateFormatter alloc] init];
[reDateFormatter setDateFormat:#"dd-MM-yyyy hh:MM:SS a"];
[reDateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];
NSDate *dt = [reDateFormatter dateFromString:str];
NSLog(#"The Date : %#",dt);
[reDateFormatter setDateFormat:#"hh:MM:SS a"];
NSString *currentTime = [reDateFormatter stringFromDate:dt];
NSLog(#"%#",currentTime);
Hope it helps you.
Try to format it to dd-MM-yyyy hh:mm:ss a.
You wrote dd-MM-yyyy hh:MM:SS a where MM in hh:MM:SS gives month which is unrecognized in this format and there is no point writing upercase SS for seconds
Hope you understand it.
NSDate *My_StartDate,*My_EndDate ;
NSDateFormatter * df= [[NSDateFormatter alloc]init];
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
My_StartDate = [df dateFromString:#"01/05/2010 10:15:33"];
My_EndDate = [df dateFromString:#"01/05/2010 10:45:33"];
NSLog(#"%#",My_StartDate);
NSLog(#"%#",My_EndDate);
In the log i get something like this for the my_startdate as 2010-05-01 04:45:33 +0000 and end date as 2010-05-01 05:15:33 +0000 instead i should have got value as for start date as 2010-05-01 10:15:33 +0000 and end date as 2010-05-01 10:45:33 +0000
Try with below function:
-(NSString *)getDateStringFromDate :(NSDate *)dateValue{
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];
NSDateFormatter *timeFormat = [[NSDateFormatter alloc] init];
[timeFormat setTimeStyle:NSDateFormatterShortStyle];
[timeFormat setDateFormat:#"HH:mm:ss"];
//[timeFormat setDateFormat:#"HH:mm"];
//[timeFormat setDateFormat:#"HH:mm a"];
////
NSString *theDate = [dateFormat stringFromDate:dateValue];
NSString *theTime = [timeFormat stringFromDate:dateValue];
NSLog(#"\n"
"theDate: |%#| \n"
"theTime: |%#| \n"
, theDate, theTime);
return theDate;
}
Change Format of data as per your need.
Let me know in case of any difficulty.
Cheers.
This shows date which follow American standard time string but by this reason you don't get any problem in making your logic.Also
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
this format using 12 hour format (means 2:03 pm and 2:03 am) and date object never use am and pm for showing date object value but when you convert it correctly then it gives you right date and time.
If you feel you get any problem then use different locale for that.
It is displaying asper the GMT+4.30 time.It displays like that only.When you are converting that date to string using the DateFormatter it gives the same date(Whichever you want like start date as 01/05/2010 10:15:33 and end date as 01/05/2010 10:45:33).
NSDateFormatter * dateformatter= [[NSDateFormatter alloc]init];
[dateformatter setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
NSString *dat = [dateformatter stringfromDate:My_StartDate];
then you will get the output as 01/05/2010 10:15:33
You might want to set the time zone of the date formatter to GMT here. Do it using
[df setTimeZone:[NSTimeZone timeZoneWithName:#"GMT"]];
before you do dateFromString: calls. This will give you what you want.
Just need to update here in your code:
I might be like that your time would be in 24 hours format, so at that time you need to use this ....other than that you need to set the timezone.
Follow this link for All zone : http://unicode.org/reports/tr35/tr35-6.html#Date%5FFormat%5FPatterns
[df setDateFormat:#"dd/MM/yyyy hh:mm:ss"];
to
[df setDateFormat:#"dd/MM/yyyy HH:mm:ss"];
You are Done ;)