how to improve this perl/bash one-liner to deserialize json data - perl

Question

I have a little bash program that calls a webservice that returns JSON data.
I have written the webservice program myself, I have complete control over its data sources, and thus I can trust the data that is returned.
Now I want to do something with the data.
The data is a simple, short key-value structure without nesting, and looks like this:
{
"asciifile" : "../tmp/data_20120720_105746-01580.txt",
"excelfile" : "../tmp/data_01580-20120720_105746.xlsx",
"from" : "Jun 19, 2012",
"msg" : "some info message, for the admin",
"outfile" : "data--recent.txt",
"outfile_excel" : "data--recent.txt.xlsx",
"resolution" : "std"
"to" : "Jul 20, 2012",
"url_comment" : "another info message, for the screen/user",
"url_outfile" : "http://www.example.com/path/tmp_cached_files/data--recent.txt",
"url_outfile_excel" : "http://www.example.com/path/tmp_cached_files/data--recent.txt.xlsx",
}
Now I am using this one-liner to deserialize the json structure returned to perl code. See last line of this snippet:
#!/bin/bash
cmd=$(curl_or_wget_call_to_webservice)
output=$(eval $cmd)
outfile_excel=$(echo "$output"| json_xs -f json -t dumper | tee | perl -n0777 -E 'eval "%h=%{$_}"; warn $# if $#; say $h{outfile_excel}')
For example, I'm not sure why I came up with the %{$_} construct. Is there a better way to do this? Is there a shorter way or a safer way to write the last line?
SE Editors: if you wish, you may move this post to the codereview stackexchange site, but I don't have an account there.
Edit: After revisiting the post after 8 months, I'd like to add that these days I use this one liner for getting the name of my github repos:
wget --quiet --auth-no-challenge --user knbknb --password secret -O -
https://api.github.com/user/repos |
perl -MJSON -n0777 -E '$r = decode_json($_); map {say $_->{name}} #$r' -

Answer 1

Perl can decode JSON itself, so the next should give some idea, using LWP::Simple to get some json data.
perl -MLWP::Simple -MJSON \
-e '$ref = decode_json(get("http://your.url/to/webservice")); print $ref->{outfile_excel}'
The $ref contains a perl structure of all JSON data, print out as you want it..

Answer 2

There is jshon. You could simply call something like
curl http://somehere.tld/data.json | jshon -e url_outfile_excel
Which would print the value for the given key.
By the way. Having control over the webservice doesn't make the input trustworthy. Be careful when calling eval.