I am making request on server , having spaces in URL
http://xxxxxxxx.com/api/api.php?func=showAllwedsdwewsdsd¶ms[]=Saudi%20Arab¶ms[]=all
I was getting the error Bad URL so ,
I used
downloadURL = [downloadURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
but due this I am getting strange URL as
http://sdsdsdsdsdsd.com/api/api.php?func=showAllsdsd¶ms5262721536=Saudi 0X0P+0rabia¶ms5 8288=All
I am also using
downloadURL= [downloadURL stringByReplacingOccurrencesOfString:#" " withString:#"%20"];
but again strange url like
http://xxxxxxxxx.com/api/api.php?func=showsdsdsd¶ms[]=Saudi 0X1.240DC0D824P-807rabia¶ms[]=All
Please help how can I solve this issue
Edit Pasting Big portion of code
PropertyXMLDownloader *download=[[PropertyXMLDownloader alloc]init];
[download setDelegate:self];
firstAppDelegate *del=(firstAppDelegate *)[[UIApplication sharedApplication]delegate];
NSLog(#"Country is %#",del.country);
NSLog(#"State is %#",del.state);
// del.country=[del.country stringByReplacingOccurrencesOfString:#" " withString:#"%20"];
NSString *downloadURL=[NSString stringWithFormat:#"http://xxxxxxxx.com/api/api.php?func=showAll¶ms[]=Saudi Arabia¶ms[]=%#",#"all"];
// downloadURL= [downloadURL stringByReplacingOccurrencesOfString:#" " withString:#"%20"];
//downloadURL = [downloadURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:#" "];
downloadURL = [[downloadURL componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString:#"%20"];
NSLog(downloadURL);
[download startDownloading:downloadURL];
try this.
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:#" "];
downloadURL = [[downloadURL componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString:#"%20"];
Perhaps the %20 is being seen as a data argument, like %# or %g. Try defining the NSString using
NSString *urlString = [NSString stringWithFormat:#"http://xxxxxxxx.com/api/api.php?func=showAllwedsdwewsdsd¶ms[]=Saudi%20Arab¶ms[]=all"];
and you'll see a warning. 'Escaping' the percent sign by adding another in front of it:
NSString *urlString = [NSString stringWithFormat:#"http://xxxxxxxx.com/api/api.php?func=showAllwedsdwewsdsd¶ms[]=Saudi**%**%20Arab¶ms[]=all"];
and the warning goes away.
Your problem is this:
NSLog(downloadURL);
Try replacing it by:
NSLog(#"%#", downloadURL);
and everything will work.
You can use stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding and forget about all the workarounds.
(Explanation: since downloadURL contains % signs, it will not play well with NSLog, which expect a format string as its first argument, where % signs identify placeholders to be replaced).
Related
I am having some issues in dealing with characters in NSStrings.
I read a XML file converted to NSData, it is okay, but when I transfer the "Element name" it has not converted to UTF-8.
I've tried here are some examples of the site, but with no success.
My Code is -
NSString * S = [NSString stringWithFormat: # "%#", D];
S = [S stringByReplacingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
Try this..
NSString *url = S;
NSString *check=[url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
check=[check stringByReplacingOccurrencesOfString:#"%0A" withString:#""];
for(int i= 0 ;i<[urlsArrray count]; i++)
{
NSString *urlString = [urlsArrray objectAtIndex:i];
NSString *escapedUrlString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:escapedUrlString];
NSString *urlstring1 = [url absoluteString];
NSArray *parts = [urlstring1 componentsSeparatedByString:#"/"];
NSString *fileName = [parts objectAtIndex:[parts count]-1];
NSMutableString *tempString = [NSMutableString stringWithString:fileName];
// [tempString replaceCharactersInRange:[tempString rangeOfString:#"%20"] withString:#" "];
NSLog(#"file name in temp string: %# word name: %#", tempString, wordNameDB);
NSRange match = [tempString rangeOfString:wordNameDB];
if(match.location != NSNotFound)
{
NSLog(#"match found at %u", match.location);
isAvailable = YES;
break;
}
Hi friends, now my problem is i am getting file name from server..., if file name is having any spaces then it replace '%20' ( i.e ex: "hello world" is actual name but i am getting file name like: "hello%20world") .
1. I am not sure all file names having spaces.
2. And also i am not sure a file may have only one space
so first i have to check the file is having spaces or not, if have then i want to replace all "%20" with #" " string. Please give me any suggestions or code snippets.
OR " THERE IA ANY OTHER WAY TO READ FILE NAMES WITHOUT GETTING '%20' IN THE PLACE OF SPACE(#" ")..... thank you
If you have your file name stored in fileName param, you can use the following:
fileName = [fileName stringByReplacingOccurrencesOfString:#"%20" withString:#" "];
The above code will replace all "%20" with " ". If there are no "%20" in the fileName, you will get back the same string.
Correction:
I was confused with stringByAddingPercentEscapesUsingEncoding mentioned in code and thought you have already used stringByReplacingPercentEscapesUsingEncoding. If you are not using stringByReplacingPercentEscapesUsingEncoding method, you should use that in this case. The above code is useful, only if that is not able to remove any particular string which you want to replace.
What you need is replacing the escape charcters, according to the encoding.
Use this and all your spaces and other URL encoded characters will be converted to what you need.
[#"yourString" stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
THERE IA ANY OTHER WAY TO READ FILE NAMES WITHOUT GETTING '%20' IN THE PLACE OF SPACE(#" ")
Yes, use this:
NSString *newString = [yourstring stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
Use this to remove spaces ..
urlString = [urlString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
You seem to already have a valid NSURL object representing the file. Getting the filename from a URL is easy:
...
NSURL *url = [NSURL URLWithString:escapedUrlString];
NSString *path = [url path];
NSString *filename = [path lastPathComponent];
No fiddling with unescaping percent escapes, URL parsing, and other error prone stuff.
So I check if the string starts with "http://" using the code below, and then I want to add "http://" so that I'm able to open the page in UIWebView.
NSString *firstString = [NSString stringWithFormat:#"%#", URL.text];
NSString *check = [NSString stringWithFormat:#"%#", #"http://"];
if (firstString != check) {
NSString *newString = [NSString stringWithFormat:#"http://%#", URL.text];
newString = [newString substringWithRange:NSMakeRange(7, newString.length - 7)];
URL.text = newString;
}
[WebView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:URL.text]]];`
This doesn't work for some reason.
Do you know why?
Somebody posted as I was writing, but either way, here's an answer:
You are making this too difficult. You simply need to use hasPrefix to check for "http". As an example, I use this for my unified search/url bar.
- (IBAction)go:(id)sender {
NSString *inputString = [searchField stringValue];
NSString *outputString = [inputString stringByReplacingOccurrencesOfString:#" " withString:#"+"];
if ([inputString hasPrefix:#"http://"]) {
//Has Prefix
[[webView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:inputString]]];
}
else
{
//Does not have prefix. Do what you want here. I google it.
NSString *googleString = #"http://google.com/search?q=";
NSString *searchString = [NSString stringWithFormat:#"%#%#", googleString, outputString];
[[webView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:searchString]]];
}
}
That is for googling instead, you could keep using NSString *newString = [NSString stringWithFormat:#"http://%#", URL.text];
You could add a few more checks as well if you wanted to. Good luck!
firstString != check checks to see if both objects point to the same location in memory. [firstString isEqualToString:check] checks if the two strings are equal. However, what you most likely want to do is if(![firstString hasPrefix:check]). This will check to make sure firstString does not start with check, then you can append check to the start of it. Alternatively, you can do firstString = [firstString stringByReplacingOccurrencesOfString:#"http://" withString:#""];, and then you know it will never start with #"http://"
Try printing what URL.text is before the loadRequest line via NSLog(#"%#",URL.text);
Also the preferred check condition would be if (![firstString isEqualToString:check]) {}
I have a text with http:// in NSString. I want to get that http link from the NSString. How can i get the link/url from the string? Eg: 'Stack over flow is very useful link for the beginners https://stackoverflow.com/'. I want to get the 'https://stackoverflow.com/' from the text. How can i do this? Thanks in advance.
I am not sure what you exactly mean by link but if you want to convert your NSString to NSURL than you can do the following:
NSString *urlString = #"http://somepage.com";
NSURL *url = [NSURL URLWithString:urlString];
EDIT
This is how to get all URLs in a given NSString:
NSString *str = #"This is a grate website http://xxx.xxx/xxx you must check it out";
NSArray *arrString = [str componentsSeparatedByString:#" "];
for(int i=0; i<arrString.count;i++){
if([[arrString objectAtIndex:i] rangeOfString:#"http://"].location != NSNotFound)
NSLog(#"%#", [arrString objectAtIndex:i]);
}
Rather than splitting the string into an array and messing about that way, you can just search for the substring beginning with #"http://":
NSString *str = #"Stack over flow is very useful link for the beginners http://stackoverflow.com/";
// get the range of the substring starting with #"http://"
NSRange rng = [str rangeOfString:#"http://" options:NSCaseInsensitiveSearch];
// Set up the NSURL variable to hold the created URL
NSURL *newURL = nil;
// Make sure that we actually have found the substring
if (rng.location == NSNotFound) {
NSLog(#"URL not found");
// newURL is initialised to nil already so nothing more to do.
} else {
// Get the substring from the start of the found substring to the end.
NSString *urlString = [str substringFromIndex:rng.location];
// Turn the string into an URL and put it into the declared variable
newURL = [NSURL URLWithString:urlString];
}
try this :
nsstring *str = #"Stack over flow is very useful link for the beginners http://stackoverflow.com/";
nsstring *http = #"http";
nsarray *arrURL = [str componentsSeparatedByString:#"http"];
this will give two objects in the nsarray. 1st object will be having:Stack over flow is very useful link for the beginners and 2nd will be : ://stackoverflow.com/ (i guess)
then you can do like:
NSString *u = [arrURL lastObject];
then do like:
nsstring *http = [http stringByAppendingFormat:#"%#",u];
Quite a lengthy,but i think that would work for you. Hope that helps you.
Why does this:
NSString *url = [NSString stringWithFormat:#"http://www.example.com/profile/%#/?s_iphone=true", author];
NSLog(#"url: %#", url);
Output this:
http://www.example.com/profile/AuthorName
/?s_iphone=true
Needless to say the url won't load b/c there is a newline added to the string by itself. I've tried removing whitesapces/newlines and still had the same output. Its driving me crazy.
Matt
Try this -
NSString *url = [NSString stringWithFormat:#"http://www.example.com/profile/%#/?s_iphone=true", [author stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]]];
NSLog(#"url: %#", url);
It will fix any new line characters at the beginning and end of your author string.
Author definitely has a new line in it. Try this:
NSLog(#"The author is %# on a new line?", author);