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Determine device (iPhone, iPod Touch) with iOS
(31 answers)
Closed 9 years ago.
I want to check whether my application is running in iphone or ipod. How can I do this?
use below code for finding current device
NSString *deviceStr = [UIDevice currentDevice].model;
NSLog(#"device:%#",deviceStr);
if your device is iPod then it will return
iPod touch
if your device is iPhone
iPhone
if your device is iPad
iPad
Yes,I found out answer for this
#define IS_IPHONE ([[[UIDevice currentDevice] model] isEqualToString:#"iPhone"])
#define IS_IPOD ([[[UIDevice currentDevice] model] isEqualToString:#"iPod touch"])
How can I determine if the device that is running my app is ios 5?
I'm trying to use the UIAppearance class but it will give an error if it's running on ios versions other than 5. so I want to have if statement that only runs this line of code if the device is ios5.
Thanks,
EDIT:
SO here is the solution,
float version = [[[UIDevice currentDevice] systemVersion] floatValue];
if (version >= 5.0){
[[UINavigationBar appearance] setBackgroundImage:image forBarMetrics:UIBarMetricsDefault];
}
You can get the OS version using
[[UIDevice currentDevice] systemVersion]
But a better way would be to check for specific features, Something along the lines of
if(NSProtocolFromString(#"UIAppearance")) {
// Do something
}
To see if that class is available, then perform you operations.
Failing that it is also possible to make sure you only build for iOS 5, and it will only install on iOS 5 devices.
How do I detect if my iOS device has an LED light or not?
I am trying to see the difference between an iPad 2 (front and back camera) and an iPhone 4 (front, back + LED light)
Turn on torch/flash on iPhone
Those should give information you needed.
[[UIDevice currentDevice] model];
[[UIDevice currentDevice] systemVersion];
[[UIDevice currentDevice] systemName];
When you know the device you know if it has a LED light or not.
How can I identify if the iOS device my app runs on is an iPhone 3G of an iPhone 4?
Thanks in advance.
Check out uidevice-extension by Erica Sadon.
You can use the following:
[[UIDevice currentDevice] platformType];
[[UIDevice currentDevice] platformString];
Apple advises using the following code to detect whether running on an iPad or iPhone/iPod Touch:
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
// The device is an iPad running iPhone 3.2 or later.
// [for example, load appropriate iPad nib file]
}
else {
// The device is an iPhone or iPod touch.
// [for example, load appropriate iPhone nib file]
}
The problem is that UI_USER_INTERFACE_IDIOM() and UIUserInterfaceIdiomPad are NOT defined in the SDKs prior to 3.2. This seems to completely defeat the purpose of such a function. They can only be compiled and run on iPhone OS 3.2 (iPhone OS 3.2 can only be run on iPad). So if you can use UI_USER_INTERFACE_IDIOM(), the result will always be to indicate an iPad.
If you include this code and target OS 3.1.3 (the most recent iPhone/iPod Touch OS) in order to test your iPhone-bound universal app code, you will get compiler errors since the symbols are not defined in 3.1.3 or earlier, when compiling for iPhone simulator 3.1.3.
If this is the recommended-by-Apple approach to runtime device-detection, what am I doing wrong? Has anyone succeeded using this approach to device-detection?
I do this to get the code to compile in both 3.1.3 and 3.2:
BOOL iPad = NO;
#ifdef UI_USER_INTERFACE_IDIOM
iPad = (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad);
#endif
if (iPad) {
// iPad specific code here
} else {
// iPhone/iPod specific code here
}
I also wrote a quick blog post about it here:
http://www.programbles.com/2010/04/03/compiling-conditional-code-in-universal-iphone-ipad-applications/
This is what I use:
- (BOOL) amIAnIPad {
#if (__IPHONE_OS_VERSION_MAX_ALLOWED >= 30200)
if ([[UIDevice currentDevice] respondsToSelector: #selector(userInterfaceIdiom)])
return ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad);
#endif
return NO;
}
This conditionally compiles, so you can still build for the 3.0 sim. It then checks to see if the UIDevice class responds to the selector. If either of these fail, it's not an iPad.
If this is the recommended-by-Apple approach to runtime
device-detection, what am I doing wrong? Has anyone succeeded using
this approach to device-detection?
This is solution for runtime detection:
#define isIPhone (![[UIDevice currentDevice] respondsToSelector:#selector(userInterfaceIdiom)] || [[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
After that you can easily test it anywhere in your code:
if (isIPhone) { ... }
The difference between this and using #if / #ifdef is that this is runtime testing, while #if is compile-time testing.
I think the runtime testing is better, because you can use one exactable for any OS version in this case. If you use compile-time check, you'll need to produce different executables for different OS versions.
If your problem is compile-time errors, you just should compile against last version of SDK (see also How to access weak linked framework in iOS?).
I believe the answer is simply do not attempt to run the code on iPhone simulator 3.1.3 or earlier. Always compile with a 3.2 SDK. The iPhone simulator 3.2 will get you the iPad simulator, or compile for iPhone Device 3.2 and put the app on a phone to test it.
There is no way to compile against 3.2 SDK and use a 3.1.3 or earlier simulator.
Instead of any compiler based stuff I use:
- (BOOL)deviceIsAnIPad {
if ([[UIDevice currentDevice] respondsToSelector:#selector(userInterfaceIdiom)])
//We can test if it's an iPad. Running iOS3.2+
if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPad)
return YES; //is an iPad
else
return NO; //is an iPhone
else
return NO; //does not respond to selector, therefore must be < iOS3.2, therefore is an iPhone
}
Declare using this
#ifdef UI_USER_INTERFACE_IDIOM
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#else
#define IS_IPAD false
#endif
then use check as below
#define DetailLabel_PosX (IS_IPAD ? 200 : 160)
There are also some define for checking iphone 5
#define IS_IPHONE5 (([[UIScreen mainScreen] bounds].size.height-568)?NO:YES)
#define IOS_OLDER_THAN_6 ([[[UIDevice currentDevice] systemVersion] floatValue] < 6.0 )
#define IOS_NEWER_OR_EQUAL_TO_6 ([[[UIDevice currentDevice] systemVersion] floatValue] >= 6.0 )
This seems to completely defeat the purpose of such a function. They
can only be compiled and run on iPhone
OS 3.2 (iPhone OS 3.2 can only be run
on iPad). So if you can use
UI_USER_INTERFACE_IDIOM(), the result
will always be to indicate an iPad.
This is completely incorrect. It can be compiled on Base SDK of 3.2, but it can be run on any OS, if you set the deployment target appropriately.
UI_USER_INTERFACE_IDIOM() and UIUserInterfaceIdiomPad can be used on iOS3.2 and upwards, the important part being the 'upwards'. Sure. iOS3.2 is only for iPad, but iOS4.0 and beyond run on both iPhones and iPads, so the check isn't as pointless as you think.