I am writing a (terrible) CSS minifier and ran into some trouble when removing spaces.
I have the following to remove spaces generally but spaces matter in CSS. So to compensate I am trying to remove the spaces from between the curly braces only.
sed -i 's/ //g' screen.css #all spaces everywhere
trying
sed -i 's/{ }//g' screen.css #all spaces between brackets everywhere
does not work.
Can someone point me in the right direction.
(This command is running from a file/bash script)
Using sed with regex ranges:
sed -i '/{/,/}/{s/\s*//g}' screen.css
Related
Is there a way in (Gnu) sed to replace all characters in a matching part of a string? For example I might have a list of file paths with several (arbitrary number of) paths in each line, e.g.:
/a/b/c/d/e /f/g/XXX/h/i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
/z/XXX/a/b /c/d/e/f
I would like to replace all the slashes in paths containing XXX keping all the others untouched, e.g.:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
Unfortunately I cannot come up with a solution. Maybe it's even impossible with sed. But I'm curious if somebody find a way to solve the problem.
We can replace any / preceding XXX with no intervening spaces like this:
# Using extended regex syntax
s!/([^ ]*XXX)!#\1!
It's a very similar substitution for those that follow XXX.
Putting them together in a loop makes this program:
#!/bin/sed -rf
:loop
s!/([^ ]*XXX)!#\1!
s!(XXX[^ ]*)/!\1#!
tloop
Output:
/a/b/c/d/e #f#g#XXX#h#i /j/k/l/m
/n/o/p /q/r/s/t/u /v/x/x/y
#z#XXX#a#b /c/d/e/f
That said, it might be simpler to use a pipeline, to break the file paths into individual lines and then reassemble them after the substitution:
sed -e 's/ *$//;s/ */&\n/g' \
| sed -e '/XXX/y,/,#,' \
| sed -e ':a;/ $/{N;s/\n//;ba}'
how can I replace a tab or empty spaces with a single semicolon?
This is what I'm trying:
sed -i.bak 's/(\s)+|(\t)+/,/g' aws_lab.txt
+/ was unexpected at this time.
Thanks
Just use the appropriate POSIX character class:
sed 's/[[:space:]]\{1,\}/,/g' aws_lab.txt
Very few seds will recognize the \s shorthand for [[:space:]] and since a tab is one of the characters included in [:space:] you dont need to specify it separately. Also, + is an ERE metacharacter, not BRE as supported by sed by default so you'd need to add the -E arg to sed to use it (only supported by GNU and OSX sed variants).
This might work for you (GNU sed):
sed -i.bak 's/[ \t][ \t]*/:/' file
Or
sed -ri.bak 's/[ \t]+/:/' file
Where there is an explicit space infront of the tab:
sed -i.bak 's/[ \t][ \t]*/:/g' file
Will replace repeated patterns throughout a line.
I am trying to use sed to replace strings with special characters in a text file. The sed command is becoming too much complicated. If someone could please help me with the exact command.
Code -
sed -i 's;PS1='${HOSTNAME} [$ORACLE_SID] $PWD> ';PS1="${COL_YELLOW}'CUSTOMER TEST:${HOSTNAME}:[$ORACLE_SID]:$PWD> '${COL_END}";g'
I tried to escape the special characters as below but its not working.
sed -i 's;PS1=\'\${HOSTNAME} [\$ORACLE_SID] \$PWD> \';PS1="\${COL_YELLOW}\'CUSTOMER TEST:\${HOSTNAME}:[\$ORACLE_SID]:\$PWD> \'\${COL_END}";g' .bash_profile_backup
This might work for you (GNU sed):
sed -i 's|PS1='\''${HOSTNAME} \[$ORACLE_SID\] $PWD> '\''|PS1="${COL_YELLOW}'\''CUSTOMER TEST:${HOSTNAME}:[$ORACLE_SID]:$PWD> '\''${COL_END}"|g' file
N.B. ' need to be quoted in both the pattern and replacement whereas [] needs to be escaped in the pattern only.
I want to replace word with \word{sth} with sed.
I type in
sed -i s#word#\\word{sth}
but i am getting is word{sth} instead of \word{sth}
I tried with 1 slash also in the command
you should add four backslashes.
you need two to escape the backslash by the terminal, and two to escape it for sed. 2*2=4.
$ echo word|sed s#word#\\\\word{sth}#gi
\word{sth}
Consider enclosing sed expression with single-quotes '
sed -i 's#word#\\word{sth}#' file
I have a Solaris machine (SunOSsu1a 5.10 Generic_142900-15 sun 4vsparcSUNW,Netra-T2000).
The following sed syntax removes all leading and trailing whitespace from each line (I need to remove whitespace because it causes application problems).
sed 's/^[ \t]*//;s/[ \t]*$//' orig_file > new_file
But I noticed that sed also removes the "t" character from the end of each line.
Please advise how to fix the sed syntax/command in order to remove only the leading and trailing whitespace from each line (the solution can be also with Perl or AWK).
Examples (take a look at the last string - set_host)
1)
Original line before running sed command
pack/configuration/param[14]/action:set_host
another example (before I run sed)
+/etc/cp/config/Network-Configuration/Network-Configuration.xml:/cp-pack/configuration/param[8]/action:set_host
2)
the line after I run the sed command
pack/configuration/param[14]/action:set_hos
another example (after I run sed)
+/etc/cp/config/Network-Configuration/Network-Configuration.xml:/cp-pack/configuration/param[8]/action:set_hos
Just occurred to me you can use a character class:
sed 's/^[[:space:]]*//;s/[[:space:]]*$//'
This happens in your sed and gnu sed with the --posix option because (evidently) posix interprets the [ \t] as a space, a \, or a t. You can fix this by putting a literal tab instead of \t, easiest way is probably Ctrl+V Tab. If that doesn't work, put the patterns in a file (with the literal tabs) and use sed -f patterns.sed oldfile > newfile.
As #aix noted, the problem is undoubtedly that your sed doesn't understand \t. While the GNU sed does, many propriety Unix flavors don't. HP-UX is one and I believe Solaris is too. If you can't install a GNU sed I'd look to Perl:
perl -pi.old -e 's{^\s+}{};s{\s+$}{}' file
...will trim one or more leading white space (^\s+) [spaces and/or tabs] together with trailing white space (\s+$) updating the file in situ leaving a backup copy as "file.old".