Scala Type Mismatch - scala

Question

I am having a problem with type mismatch.
type mismatch; found : Option[models.User] required: models.User
def authenticate = Action { implicit request =>
signinForm.bindFromRequest.fold(
formWithErrors => BadRequest(html.signin(formWithErrors)),
user => Redirect(routes.Application.active).withSession(Security.username -> User.getUserName(user))
)
}
How can I force the function to accept Option[models.User] or can I convert the models.User into an Option?
The error occurs here: User.getUserName(user). getUserName requires models.User types.
===============================================
Update with all code used:
From User.scala
def authenticate(email: String, password: String) : Option[User] = {
(findByEmail(email)).filter { (user => BCrypt.checkpw(password, user.password)) }
}
def findByEmail(email: String) : Option[User] = {
UserDAO.findOne(MongoDBObject("email" -> email))
}
From Application.scala
val signinForm = Form {
mapping(
"email" -> nonEmptyText,
"password" -> text)(User.authenticate)(_.map(user => (user.email, "")))
.verifying("Invalid email or password", result => result.isDefined)
}
def authenticate = Action { implicit request =>
signinForm.bindFromRequest.fold(
formWithErrors => BadRequest(html.signin(formWithErrors)),
user => Redirect(routes.Application.active).withSession(Security.username -> User.getUserName(user.get))
)
}

Answer 1

To de-option an Option[User] into a User, you can do one of the following:
1) The unsafe way. Only do this if you are sure that optUser is not None.
val optUser: Option[User] = ...
val user: User = optUser.get
2) The safe way
val optUser: Option[User] = ...
optUser match {
case Some(user) => // do something with user
case None => // do something to handle the absent user
}
3) The monadic safe way
val optUser: Option[User] = ...
optUser.map(user => doSomething(user))
The biggest thing is that, if it's possible that optUser might actually be None, you need to figure out what you actually want to happen in the case that there is no User object.
There's a lot more information about Option in other StackOverflow questions if you'd like to read more.