In my app I have a method that, when I press a button, adds a string to a NSMutableArray which is the model for a UITableView.
- (void)addPressed:(id)sender
{
NSString *string = #"aString";
[self.array addObject:string];
NSLog(#"Array count: %d",[self.array count]);
[self.tableView reloadData];
}
Problem is that the adding works the first time only if I press twice the button connected to this action I get this output:
2012-09-16 21:33:08.766 iUni[3066:c07] Array count: 1 //Which is fine since it worked
2012-09-16 21:33:08.952 iUni[3066:c07] Array count: 1 //Now count should be 2!!
Anyone has a guess on why is this happening?
I added the #property, synthesized it and lazy instatiated it this way:
- (NSMutableArray *)array
{
if (!_array) {
NSMutableArray *array = [NSMutableArray array];
_array = array;
}
return _array;
}
Your array is being created as an unowned (autoreleased, actually) object, which means that it is destroyed shortly after each time your accessor is called. It is then recreated the next time you access it, which gives you a new, empty array.
You need to create an owned version of the array to store into your instance variable:
if (!_array) {
_array = [[NSMutableArray alloc] init];
// Note no need to create a temp variable.
}
return _array;
You could also turn on ARC, which would have taken care of this for you and is a good idea anyways.
Related
I have an NSMutableArray with the following property:
#property (nonatomic, strong) NSMutableArray *alarmTableArray;
alarmTableArray = [[NSMutableArray alloc]init];
FMDBDatabaseAccess *db = [[FMDBDatabaseAccess alloc] init];
alarmTableArray = [db getAlarm];
I tried releasing this array but I end up with EXC_BAD_ACCESS.
I am really worried about this.
How to release this array?
You're using the descriptor of "strong" which is an ARC term. This should be retain and if you just set the property to nil it will release it automatically. You should set it to nil in your viewDidUnload since your ViewWillDissappear only means your viewcontroller is leaving visibility and not that it is being destroyed.
Updated Answer
I think I know what you're trying to do. You want grab an array of rows from your SQL and store it in one of your array.
One of the techniques for getting rows of data from SQL and storing into a class instance variable array is to NOT return a temporary array but pass the class instance variable array as a reference into your method and modify the array directly.
So instead of this pseudo-code
-(NSMutableArray *)doSomething
{
NSMutableArray *tempArray;
while (DB select statement has found rows)
{
CockTail *objCT = [[CockTail alloc] init];
objCT.name = #"...";
objCT.price = #"...";
[tempArray addObject:objCT];
[objCT release];
}
return [tempArray autorelease];
}
// class instance variable array
instanceVarArray = [[NSMutableArray alloc] init];
instanceVarArray = [self doSomething]; // here is where you confusion arise
You can do it this way:
-(void)doSomething:(NSMutableArray *)paramArray
{
// remove previously fetched data
[paramArray removeAllObjects];
SQL select statement
while(has rows)
{
CockTail *objCT = [[CockTail alloc] init];
objCT.name = #"...";
objCT.price = #"...";
// NOTE: we are directly modifying our class instance variable array
// here since it was passed by reference :D
// and so there is no need to worry about releasing the array
[paramArray addObject:objCT];
[objCT release];
}
}
// Now all you do is pass in your class instance variable array
instanceVarArray = [[NSMutableArray alloc] init];
[self doSomething:instanceVarArray];
Original Answer
Um, maybe I am wrong but aren't you essentially throwing away that "alloc init" on the first line here when you assign the array something from your FMDBDatabaseAccess:
// LINE 1: this instance of NSMutableArray here is allocated
alarmTableArray = [[NSMutableArray alloc]init];
// LINE 2
FMDBDatabaseAccess *db = [[FMDBDatabaseAccess alloc] init];
// LINE 3:this line here essential breaks the pointer link point to the NSMutableArray instance on line 1
alarmTableArray = [db getAlarm];
Now unless you do
// LINE 4
[alarmTableArray retain];
Otherwise, your alarmTableArray was never allocated (since you overwrote the pointer link). And as a result, you've caused a memory leak as your profiler told you.
Doing a release now would give your that EXEC_BAD_ACCESS
What I think you want to do is this:
alarmTableArray = [[NSMutableArray alloc]init];
FMDBDatabaseAccess *db = [[FMDBDatabaseAccess alloc] init];
// this now uses the setter method (mutator method generated by #property) to do the copy
self.alarmTableArray = [db getAlarm];
Looking at your while loop, I have to ask why are you releasing a local scope variable?
CockTail *cocktailValues = [[CockTail alloc] init];
...
[cocktails addObject:cocktailValues];
[cocktailValues release];
Breakdown of each line of code above:
When you alloc and init the CockTail object the release/retain count is 0.
Adding the object to the NSMutableArray increases the release/retain count to 1.
Releasing the CockTail object after you added it to array reduce the release/retain count back down to 0.
Therefore, later when you release the NSMutableArray or try to access an object in it, the objects are already gone.
Remember the number one rule, only release what you retain.
How to write right in this situation:
I have some method, that return NSMutableArray*. Because method not started with init, new or alloc, how write in apple memory-management guide, i return autorealese object.
-(NSMutableArray*)someMethod {
NSMutableArray *array = [NSMutableArray alloc] init] autorealese];
//Some code here
return array;
}
And i have some another methods, that call this one:
-(NSMutableArray*)method1 {
NSMutableArray *array = nil;
if(condition){
array = [self someMethod];
}
return array;
}
-(NSMutableArray*)method2 {
NSMutableArray *array = nil;
array = [self method1];
}
Code work.But XCode analyze tool says that in method2 i get object with count 0. So, how to write this code good?
There is nothing wrong with your code, except that the method2 will return the array that is autoreleased. Thus whatever is calling this method should retain the return value.
Creating an autoreleased NSMutableArray and returning it.
-(NSMutableArray*)someMethod {
NSMutableArray *array = [NSMutableArray alloc] init] autorealese];
//Some code here
return array;
}
Method1 uses autorelease NSMutableArray from someMethod and for the life of Method1 the array will not be autoreleased. That's one of the rules of memory management in objective-c that object lives through the method cycle.
-(NSMutableArray*)method1 {
NSMutableArray *array = nil;
if(condition){
array = [self someMethod];
}
return array;
}
Method2 uses still waiting to be autoreleased NSMutableArray from method1. It's important to notice that b/c you have a condition in method2 the array might be nil.
-(NSMutableArray*)method2 {
NSMutableArray *array = nil;
array = [self method1];
}
So in another words, you are passing autoreleased object along your methods. There is nothing wrong with this. You just have to remember that if you want to store the value of method2 you need to retain it, or it will get autoreleased.
Because of your condition in method1 the analyzer will complain b/c it's not guaranteed that the method1 will return an object, there is a possibility it will return nil.
I'm having the code as below.
- (void)viewDidLoad
{
NSArray* myarr = [self createArray];
for (NSString* str in myarr)
{
NSLog(#"%#",str);
}
[myarr release];
}
-(NSArray*)createArray
{
NSArray* arr1 = [[NSArray alloc] initWithObjects:#"APPLE",#"MAC",#"IPHONE",nil];
return arr1;
}
When I "Build & Analyze", its showing two leaks. One at [myarr release] saying, incorrect decrement of the reference count of an object that is owned at this point. and Other at return arr1, saying, Potential leak of an object allocated on line 152 and stored into arr1.
From my above code, the method "createArray" is returning a pointer and I'm releasing it as well. Is my way of coding right or wrong?
From my above code, the method "createArray" is returning a pointer and I'm releasing it as well. Is my way of coding right or wrong?
that depends on how you look at it.
1) the ref counting looks ok
2) the static analyzer flags objc methods based on names, in some cases. so the issue will likely vanish if you rename createArray to newArray, or something named new*. so it expects a convention (the ones used by Apple) to be followed.
therefore, it's the message that's bit shallow, it doesn't really analyze the program, but bases its findings/results on convention -- and not an actual evident issue which a human can read.
If you're just using the array in your viewDidLoad method, then you don't need to alloc an array in there at all. You can just use an autoreleased array returned as 7KV7 suggested. You can return an autoreleased array in your -(void)createArray as well without alloc'ing an object. Here is an example.
- (void)viewDidLoad
{
NSArray* myarr = [self createArray];
for (NSString* str in myarr)
{
NSLog(#"%#",str);
}
}
-(NSArray*)createArray
{
return [NSArray arrayWithObjects:#"APPLE",#"MAC",#"IPHONE",nil];
}
If you don't have to alloc an object to use it, it makes for less, and cleaner code, IMO.
Try this
- (void)viewDidLoad
{
NSArray* myarr = [[NSArray alloc] initWithArray:[self createArray]];
for (NSString* str in myarr)
{
NSLog(#"%#",str);
}
[myarr release];
}
-(NSArray*)createArray
{
NSArray* arr1 = [[NSArray alloc] initWithObjects:#"APPLE",#"MAC",#"IPHONE",nil];
return [arr1 auotrelease];
}
The problem with your code is that
You do not allocate myarr using alloc or new so you do not take ownership of the object. Hence the issue in release.
You allocate arr1 so you take ownership of the object and you return arr1. Hence you do not release it. That is the reason for the leak.
I was running Leaks tool and discovered a massive leak in my Dictionary mutableDeepCopy but I can't figure out what's wrong with the code. Any suggestions?
#interface RootViewController : UIViewController{
NSDictionary *immutableDictionary;
NSMutableDictionary *mutableDictionary;
}
Here is the line of code that's highlighted in Instruments
self.mutableDictionary = [self.immutableDictionary mutableDeepCopy];
Here is the method for creating a mutable copy of a Dictionary
#interface NSDictionary(MutableDeepCopy)
-(NSMutableDictionary *)mutableDeepCopy;
#end
Here is method implementation, I've highlighted the code that Leaks saids is leaking 100%
- (NSMutableDictionary *) mutableDeepCopy {
NSMutableDictionary *dictionaryToReturn = [NSMutableDictionary dictionaryWithCapacity:[self count]];
NSArray *keys = [self allKeys];
for(id key in keys) {
id value = [self valueForKey:key];
id copy = nil;
if ([value respondsToSelector:#selector(mutableDeepCopy)]) {
copy = [value mutableDeepCopy];
} else if ([value respondsToSelector:#selector(mutableCopy)]) {
copy = [value mutableCopy]; //This is the Leak
}
if (copy == nil) {
copy = [value copy];
}
[dictionaryToReturn setValue:copy forKey:key];
}
return dictionaryToReturn;
}
You need to analyse this in light of Apple's Memory Management Rules.
Starting with this line:
self.mutableDictionary = [self.immutableDictionary mutableDeepCopy];
I would expect mutableDeepCopy to return an object I own, so at some point I need to release or autorelease it. e.g.
NSMutableDeepCopy* temp = [self.immutableDictionary mutableDeepCopy];
self.mutableDictionary = temp;
[temp release];
or
self.mutableDictionary = [[self.immutableDictionary mutableDeepCopy] autorelease];
So now we need to look at mutableDeepCopy. Because it has 'copy' in the name it needs to returned an "owned" object which, in practice means "forgetting" to release the returned object. You have already failed to do that when you create the returned object in the first line, since dictionaryWithCapacity: gives you an object you do not own. Replace it with
NSMutableDictionary *dictionaryToReturn = [[NSMutableDictionary alloc] initWithCapacity:[self count]];
Now you own it.
It is important that you make your mutableDeepCopy obey the rules because it means you can treat the objects returned from mutableDeepCopy, mutableCopy and copy in exactly the same way. In all three cases you own the object copy that you insert into the array. Because you own it, you must release it or it'll leak as you found out. So, at the end of the loop, you need
[copy release];
That'll stop the leak.
How is your property declared? If is is retain or copy, then this doesn't leak.
Your problem is that the name mutableDeepCopy suggests that it returns a retained object, and not an autoreleased one as it actually does.
Edit:
And at the mutableDeepCopy itself, you need to release the copy variable after adding to the dictionary.
mutableCopy increments the retain count of the object, as does setValue:forKey:. This means that when dictionaryToReturn is dealloc'ed, the object that had mutableCopy called still has a retain count of one.
Try doing this instead:
copy = [[value mutableCopy] autorelease];
I have a NSMutableDictionary with the key being the first alphabet of the name of an object. The view is something like the 'Contacts' tab on iphone. Additionally user can select individual objects in the list.
In the code I find each selected object to process them further.
NSMutableArray *objectsToAdd = [[NSMutableArray alloc] init];
NSMutableArray *array = nil;
for (NSString *key in self.nameIndex) {
array = (NSMutableArray *)[searchedNameDictionary valueForKey:key];
for (Objects *eachObject in array) {
if (eachObject.objectIsSelected){
[objectsToAdd addObject:eachObject];
}
}
}
[array release];
-(void)dealloc()
{
[searchedNameDictionary release];
}
The app is crashing where I release searchedNameDictionary, with the message that the deallocated object is being referenced.
Now if in the code above, I remove [array release] the app works fine.
My question is does releasing 'array' is actually releasing the objects in searchedNameDictionary, which is what seems to be happening.
Would not releasing array cause memory leak?
You shouldn't release returned object unless they come from an alloc or copy method.
Returned objects are autoreleased otherwise, if you want to keep it around your should retain it right after receiving it.
array = (NSMutableArray *)[searchedNameDictionary valueForKey:key];
This returns an autoreleased object, thus you don't need to release it.
There are some other...issues with your code too, but mostly style things. Get rid of the [array release] and you're good to go as far as that issue is concerned.