I have been trying unsuccessfully to find a way to filter out records from a report.
I have a field titled time_period in a view that returns a date in the "MM/YYYY" format.
I have two parameters titled startMonth and endMonth which are in "MM/DD/YYYY".
Somehow I need to be able to make sure that the date_grouping field value is between the two parameters.
Here's what I have so far...
{location_total_kpi_view.time_period} >=
Date(Month({?startMonth}) + Year({?startMonth})) and
{location_total_kpi_view.time_period} <=
Date(Month({?endMonth}) + Year({?endMonth}))
It excludes all records. Any suggestions?
Try converting them both to yyyy/MM format and then into dates to make sure that the comparisons are equal, like this:
Date(ToText({location_total_kpi_view.time_period}, "yyyy/MM")) >=
Date(ToText({?startMonth}, "yyyy/MM")) and
Date(ToText({location_total_kpi_view.time_period}, "yyyy/MM")) <=
Date(ToText({?endMonth}, "yyyy/MM")) and
Related
I have a report that displays monthly and ytd amounts. I use start and enddate parameters that change according to the user. For example for startdate 4/1/2007 and enddate 2/28/2008
1. I need to display title as Monthly budget 2/1/2008 to 2/28/2008
2. I need to display title for YTD as YTD 4/1/2007 to 2/28/2008
I tried = Parameter!EndDate.value but it throws error
It looks like you may have missed a letter in your expression. It should be:
=Parameters!EndDate.Value
In the expression editor you can double click on the parameter name and it will insert it into the expression for you.
To get the full description that you mentioned, you'll need to use a combination of functions. One useful one to look at is DateAdd to add days and months to the specified date. Another one is FormatDateTime which allows you to use the standard "ShortDate" format.
If you run into further trouble, I would recommend posting a new question with the variations of code that you tried along with the specific error messages that you received.
You could try setting the Expression for a text box to:
="Monthly Budget " & FORMAT(Paramters!StartDate.Value, "MM/dd/yyyy") & " to " & "FORMAT(Paramters!EndDate.Value, "MM/dd/yyyy")
This will give you:
Monthly Budget 02/01/2008 to 02/28/2008
It is the same for your second requirement, just change the wording.
I am using Tableau Server version 10.4.3
I have a dimension rTime which has string value. the entries in rTime is of like this
May 10, 2019 8:59:56.303 PM UTC
I want to check whether the rTime is today or not. I cannot use DateParse since my server doesn't have this functionality.
I created a calculated field CheckrTime with below content :
STR(LEFT(SPLIT([rTime],':',1),LEN(SPLIT([rTime],':',1))-2))
When I am dragging CheckrTime into workspace area, the output is coming in below format which is what I wanted :
May 10, 2019
When I am checking ISDATE("May 10, 2019") (a normal string), it is outputting TRUE as expected but when I am checking ISDATE(CheckrTime) it is outputting FALSE . Why?
The reason I am checking above thing is I am looking to use DATEDIFF function of tableau in this way:
DATEDIFF('day', DATE(CheckrTime), TODAY()) == 0
NOTE
If someone is wondering ,I have taken care of the level of granularity.
If you have a better solution then the one I am following, please do tell me.
This is working for me. I would expect May 10 <> May 16 (today) and therefore return false. However, when I change your example to today's date it does in fact come back as true.
You could also try this formula for the date LEFT([rTime],FINDNTH([rTime],' ',3)). It is slightly less complicated but will give you the same answer.
Calculated field (date type) depends the locale used which defines date format. Are you able to use Date function?
In Tableau website there is a example using english locale
For string 06May2017
DATE (LEFT([Original Date], 2) + "/" + MID([Original Date],3,3) + "/" + RIGHT([Original Date],4))
Above mentioned highligts / character between digits which is depending on locale
Being new to Crystal could someone point me in the correct direction.
I have a field, in an SQL view which is datetime.
I have converted this to time only using
time ({rep_Sterling_YEARLYSHEETCOUNT.StartDateAndTime})
I now want to use this in a further formula to determine if the operation occurred on the day or the night shift
if {#Time Convert} > #06:00:00# and {#Time Convert} < #18:00:00#
Then 'Days'
Else 'Nights'
However I am told 'A Date-time is required here.
What have I got wrong?
When you enclose in betweed # it will be treated as datetime and hence the error.
So change like this:
if {#Time Convert} > Ctime("06:00:00") and
{#Time Convert} < Ctime("18:00:00")
Then 'Days'
Else 'Nights'
I have a DateTime property.
I want to check if a date is equal to the date in my property and it has to be done purely in the url query parameters available in OData v4.
This doesn't work :(
GET ~/odata/foo$filter=date(myProperty) eq date(1980-01-01)
Yes I can use greater then or equal but that's is already working as intended. It's equal and not equal that's the problem.
From ABNF rules, Date value is a value with format:
dateValue = year "-" month "-" day
So, I think you shouldn't add date prefix. That's:
GET ~/odata/foo$filter=date(myProperty) eq 1980-01-01
Here's some test cases provided by ODataTeam:
https://github.com/OData/WebApi/blob/master/OData/test/E2ETest/WebStack.QA.Test.OData/DateAndTimeOfDay/DateAndTimeOfDayTest.cs#L169-L171
and
https://github.com/OData/WebApi/blob/master/OData/test/E2ETest/WebStack.QA.Test.OData/DateAndTimeOfDay/DateAndTimeOfDayTest.cs#L208-L212
Besides, there's a simple tutorial you can refer to:
http://odata.github.io/WebApi/#04-04-date-and-timeofday-support
Thanks. Hope it can help.
I use a date picker that saves the date in a yyyy-mm-dd format in a database. It then automatically adds time that always appears as 00:00:00. So for example it displays the date like this : 2014-12-14 00:00:00. I want it to display just the date in a mm-dd-yyyy format.
I use the code below but something seems to be wrong with it because it simply doesn't change the way it is displayed. I want to split up each of the values, then display only the date in a different format.
var parts = value.split("/");
return parts[1] + "-" +parts[2] + "-" +parts[0];
What can I do to make it work? Javascript please.
Thanks in advance.
It's a wide variety of solutions. Depends on you server-side settings too, but I will assume, that you use common for most websites MySQL DB and PHP.
You can change you column type to DATE. As said in docs:
The DATE type is used for values with a date part but no time part.
MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The
supported range is '1000-01-01' to '9999-12-31'.
You can change your column type to VARCHAR and store a date in any format you like when INSERT it
You can convert it to proper format using MySQL built-in DATE_FORMAT()
SELECT DATE_FORMAT('2014-12-14 00:00:00', '%c-%e-%Y');
will give you 12-14-2014. Here is sqlfiddle,
just change first param to your column name in query
On server you can use PHP's date() function like this
$yourdate = '2014-12-14 00:00:00';
echo date("m-d-Y", strtotime($yourdate));
Closer to your question, how to do it in JS? It also has special object for this: Date(). Put your date in constructor, then use methods:
var yourdate = new Date('2014-12-14 00:00:00');
alert(yourdate.getMonth() + "-" + yourdate.getDate() + "-" + yourdate.getFullYear());
JSFiddle < - here
So, as far as almost every platform understands this datetime format - you can use any tool for converting it