I am trying to pull 3 columns of data from one field. basically i have a field with for arguments sake a table with the following data:
Color,
Model,
Year of a car.
It is itemized as ID4 is Color, ID5 is Model and ID6 is Year. I can pull one data set with no problem using a filter, ex. Filter = 4, 5 or 6. But I cannot pull multiples as I just get the headers and no data at all.
Assuming you are using SQL Server 2005+, and your question really is "how do you break one column in a table into multiple named columns based on another field in the same table", here is a simple example patterned after your question.
Give this dataset:
declare #tbl table (id int, tag char(3), data varchar(255))
insert into #tbl values
(1, 'ID4', 'Red'), (1, 'ID5', 'Toyota'), (1, 'ID6', '1999'),
(2, 'ID4', 'Blue'), (2, 'ID5', 'Honda'), (2, 'ID6', '2000'),
(3, 'ID4', 'Green'), (3, 'ID5', 'Nissan'), (3, 'ID6', '2004'),
(4, 'ID4', 'Red'), (4, 'ID5', 'Nissan'), (4, 'ID6', '1990'),
(5, 'ID4', 'Black'), (5, 'ID5', 'Toyota'), (5, 'ID6', '2002')
A simple select statement returns this data:
select * from #tbl
id tag data
1 ID4 Red
1 ID5 Toyota
1 ID6 1999
2 ID4 Blue
2 ID5 Honda
2 ID6 2000
3 ID4 Green
3 ID5 Nissan
3 ID6 2004
4 ID4 Red
4 ID5 Nissan
4 ID6 1990
5 ID4 Black
5 ID5 Toyota
5 ID6 2002
This pivot query returns the data -- one row per car -- with Color, Model and Year as their own columns:
select id, [ID4] as 'Color', [ID5] as 'Model', [ID6] as 'Year'
from (select id, tag, data from #tbl) as p
pivot (max(data) for tag in ([ID4], [ID5], [ID6])) as pvt
order by pvt.id
This is how the output looks:
id Color Model Year
1 Red Toyota 1999
2 Blue Honda 2000
3 Green Nissan 2004
4 Red Nissan 1990
5 Black Toyota 2002
Related
Consider this testing data:
CREATE TABLE IF NOT EXISTS area (
id integer,
parent_id integer,
name text,
population integer
);
INSERT INTO area VALUES
(1, NULL, 'North America', 0),
(2, 1, 'United States', 0),
(3, 1, 'Canada', 39),
(4, 1, 'Mexico', 129),
(5, 2, 'Contiguous States', 331),
(6, 2, 'Non-contiguous States', 2);
id
parent_id
name
population
1
NULL
North America
0
2
1
United States
0
3
1
Canada
39
4
1
Mexico
129
5
2
Contiguous States
331
6
2
Non-contiguous States
2
Note that population (in millions) means here the additional population, excluding area's children.
How do I query the recursive sum for each row? I need to get something like this:
name
sum
North America
501
United States
333
Canada
39
Mexico
129
Contiguous States
331
Non-contiguous States
2
Here is how I solved it:
WITH RECURSIVE parent AS (
SELECT
*,
id AS root -- Emit the root ID
FROM area
-- No WHERE clause, since we treat every row as a possible root
UNION ALL
SELECT
area.*,
parent.root -- Pass the root ID to the children
FROM area
JOIN parent ON parent.id = area.parent_id
)
SELECT
name,
sum
FROM (
SELECT
root,
SUM(population)
FROM parent
GROUP BY root -- Here is where we need the root IDs
) cumulative
JOIN area ON area.id = cumulative.root; -- Use the nice names instead of IDs
I have a table like this
b.b_id fp.fp_id b.name
1 10 Dan
1
1
1
2 15 Michelle
2
3 20 Steve
3
3
Im trying to get this output
b.b_id fp.fp_id b.name
1 10 Dan
1 Dan
1 Dan
1 Dan
2 15 Michelle
2 Michelle
3 20 Steve
3 Steve
3 Steve
My idea was using the lag function but with this code i am only able to fill 1 row below.
select b.b_id,fp.fp_id,
case
when fp.fp_id is null then lag(b.name,1) over (partition by b.b_id order by b.b_id,fp.fp_id)
else b.name
end as name
from b
left join fp on fp.id = b.fp_id
Output at the moment
b.b_id fp.fp_id b.name
1 10 Dan
1 Dan
1
1
2 15 Michelle
2 Michelle
3 20 Steve
3 Steve
3
Is there some easy way to solve this?
CREATE temp TABLE test101 (
id bigint,
fp_id bigint,
name text
);
INSERT INTO test101
VALUES (1, 10, 'dan'),
(1, NULL, NULL),
(1, NULL, NULL),
(1, NULL, NULL),
(2, 15, 'Michelle'),
(2, NULL, NULL),
(3, 20, 'Steve'),
(3, NULL, NULL),
(3, NULL, NULL);
SELECT
id,
fp_id,
first_value(name) OVER (PARTITION BY id ORDER BY id ASC nulls LAST, fp_id NULLS LAST)
FROM
test101;
I would kindly ask if someone could make me a query which may SUM up values from numeric column and from hstore column. This is obviously too much for my SQL abbilities.
A table:
DROP TABLE IF EXISTS mytry;
CREATE TABLE IF NOT EXISTS mytry
(mybill int, price numeric, paym text, combined_paym hstore);
INSERT INTO mytry (mybill, price, paym, combined_paym)
VALUES (10, 10.14, '0', ''),
(11, 23.56, '0', ''),
(12, 12.16, '3', ''),
(13, 12.00, '6', '"0"=>"4","3"=>"4","2"=>"4"'),
(14, 14.15, '6', '"0"=>"2","1"=>"4","3"=>"4","4"=>"4.15"'),
(15, 13.00, '1', ''),
(16, 9.00, '4', ''),
(17, 4.00, '4', ''),
(18, 4.00, '1', '');
Here is a list of bills, price and payment method for each bill.
Some bills (here 13 and 14) could have combined payment. Payment methods are enumerated from 0 to 5 which describes specific payment method.
For this I make this query:
SELECT paym, SUM(price) FROM mytry WHERE paym::int<6 GROUP BY paym ORDER BY paym;
This sums prices for payment methods 0-5. 6 is not payment method but a flag which means that we should here consider payment methods and prices from hstore 'combined_paym'. This is what I don't know how to solve. To sum payment methods and prices from 'combined paym' with ones from 'paym' and 'price'.
This query gives result:
"0";33.70
"1";17.00
"3";12.16
"4";13.00
But result is incorrect because here are not summed data from bill's 13 and 14.
Real result should be:
"0";39.70
"1";21.00
"2";4.00
"3";20.16
"4";17.15
Please if someone can make me proper query which would give this last result from given data.
Unnest the hstore column:
select key, value::dec
from mytry, each(combined_paym)
where paym::int = 6
key | value
-----+-------
0 | 4
2 | 4
3 | 4
0 | 2
1 | 4
3 | 4
4 | 4.15
(7 rows)
and use it in union:
select paym, sum(price)
from (
select paym, price
from mytry
where paym::int < 6
union all
select key, value::dec
from mytry, each(combined_paym)
where paym::int = 6
) s
group by 1
order by 1;
paym | sum
------+-------
0 | 39.70
1 | 21.00
2 | 4
3 | 20.16
4 | 17.15
(5 rows)
I have a table where each record has an indicator and a range, and I want to know the total spread covered by the ranges for each indicator -- but not double-counting when ranges overlap for a certain indicator.
I can see that the wording is hard to follow, but the concept is pretty simple. Let me provide an illustrative example.
CREATE TABLE records(id int, spread int4range);
INSERT INTO records VALUES
(1, int4range(1, 4)),
(1, int4range(2, 7)),
(1, int4range(11, 15)),
(2, int4range(3, 5)),
(2, int4range(6, 10));
SELECT * FROM records;
Yielding the output:
id | spread
----+---------
1 | [1,4)
1 | [2,7)
1 | [11,15)
2 | [3,5)
2 | [6,10)
(5 rows)
I would now like a query which gives the following output:
id | total
---+--------
1 | 10
2 | 6
Where did the numbers 10 and 6 come from? For ID 1, we have ranges that include 1, 2, 3, 4, 5, 6, 11, 12, 13, and 14; a total of 10 distinct integers. For ID 2, we have ranges that include 3, 4, 6, 7, 8, and 9; a total of six distinct integers.
If it helps you understand the problem, you might imagine it as something like "if these records represent the day and time range for meetings on my calendar, how many total hours in each day are there where I'm booked at least once?"
Postgres version is 9.4.8, in case that matters.
select id, count(*)
from (
select distinct id, generate_series(lower(spread), upper(spread) - 1)
from records
) s
group by id
;
id | count
----+-------
1 | 10
2 | 6
I have a table with Clients and their Insurance Providers. There is a column called Priority that ranges from 1-8. I want to be able to select the lowest priority insurance into my 'master table' I have a query that provides Fees, Dates, Doctors etc. and I need a subquery that I can join to the Main query on Client_ID The priority doesn't always start with 1. The Insurance Table is the Many side of the relationship
Row# Client_id Insurance_id Priority active?
1 333 A 1 Y
2 333 B 2 Y
3 333 C 1 N
4 222 D 6 Y
5 222 A 8 Y
6 444 C 4 Y
7 444 A 5 Y
8 444 B 6 Y
Answer should be
Client_id Insurance_id Priority
333 A 1
222 D 6
444 C 4
I was able to achieve the results I think you're asking for pretty easily utilizing SQL's ROW_NUMBER() function:
declare #tbl table
(
Id int identity,
ClientId int,
InsuranceId char(1),
[Priority] int,
Active bit
)
insert into #tbl (ClientId, InsuranceId, [Priority], Active)
values (1, 'A', 1, 1),
(1, 'A', 2, 1),
(1, 'B', 3, 1),
(1, 'B', 4, 1),
(1, 'C', 1, 1),
(1, 'C', 2, 0),
(2, 'C', 1, 1),
(2, 'C', 2, 1)
select Id, ClientId, InsuranceId, [Priority]
from
(
select Id,
ClientId,
InsuranceId,
[Priority],
ROW_NUMBER() OVER (PARTITION BY ClientId, InsuranceId ORDER BY [Priority] desc) as RowNum
from #tbl
where Active = 1
) x
where x.RowNum = 1
Results:
(8 row(s) affected)
Id ClientId InsuranceId Priority
----------- ----------- ----------- -----------
2 1 A 2
4 1 B 4
5 1 C 1
8 2 C 2
(4 row(s) affected)