i had 2 arrays with objects and the same nameobject should be cancelled only one time - iphone

Question

I have input as two arrays shown below
NSArray *array1=[[NSArray alloc]initWithObjects:#"1",#"2",#"3", nil];
NSArray *array2=[[NSArray alloc]initWithObjects:#"1",#"2",#"1", nil];
the output should resemble like this.
the same element should be cancelled only one time.
NSArray *array3=[[NSArray alloc]initWithObjects:#"1",#"2", nil];
THANKS IN ADVANCE.....

Answer 1

NSArray *array1 = #[#"1",#"2",#"3"];
NSArray *array2 = #[#"1",#"2",#"1"];
NSMutableSet *allElemets = [NSSet setWithArray:array1];
[allElemets addObjectsFromArray:array2];
This will return you all elements without duplicates.
In this case it will be
#"1",#"2",#"3"
Edit:
This will return the intersection of the arrays
NSMutableSet *set1 = [NSMutableSet setWithArray:array1];
NSSet *set2 = [NSSet setWithArray:array2];
[set1 intersectSet:set2];

Answer 2

Use NSCountedSet for the above situation
NSMutableArray *array1=[[NSMutableArray alloc]initWithObjects:#"r",#"a",#"r",#"r",#"r", nil];
NSArray *array2=[[NSArray alloc]initWithObjects:#"b",#"c",#"r", nil];
NSMutableSet *setOne = [NSMutableSet setWithArray: array1];
NSSet *setTwo = [NSSet setWithArray: array2];
[setOne unionSet:setTwo];
NSArray *arrayOneResult = [setOne allObjects];
NSLog(#"%#",arrayOneResult);
NSMutableArray *resultArray = [[NSMutableArray alloc]init];
NSCountedSet *set = [[NSCountedSet alloc] initWithArray:arrayOneResult];
for (id item in set)
{
NSCountedSet *set1 = [[NSCountedSet alloc] initWithArray:array1];
NSCountedSet *set2 = [[NSCountedSet alloc]initWithArray:array2];
int diff = abs([set1 countForObject:item] - [set2 countForObject:item]);
for (int i = 0 ;i < diff ;i++ ) {
[resultArray addObject:item];
}
}
NSLog(#"the array : %#",resultArray );

Answer 3

f you are fine with sets instead of arrays, you can use NSMutableSet instead of NSArray. NSMutableSet has nice methods like intersectSet: and minusSet:

Answer 4

if([[array1 objectAtIndex:i] isEqualToString:[array2 objectAtIndex:i]])
{
[array2 removeObjectAtIndex: i];
NSLog(#"same element removed.");
}
array3 = [firstArray arrayByAddingObjectsFromArray:secondArray];
or
NSMutableSet *set = [NSMutableSet setWithArray:array1];
[set addObjectsFromArray:array2];
array3 = [set allObjects];
Two arrays are compared and duplicate values are removed, you get your values.

Answer 5

Here tHe Code goes
EDIt: This WOuld remove the Duplicate Value add Unique value.
NSArray *array1=[[NSArray alloc]initWithObjects:#"1",#"2",#"3", nil];
NSArray *array2=[[NSArray alloc]initWithObjects:#"1",#"2",#"1", nil];
//Here Create nEw Array with Arra1
NSMutableArray * newArray =[[NSMutableArray alloc] initWithArray:array1];
for(int index=0; index<[array2 count];index++)
{
id object =[array2 objectAtIndex:index];
if(![newArray containsObject:object])//this methods Returns YES/NO
{
[newArray addObject: object];
}
}